Electromagnetism

The Right-Hand Rule in Physics: Three Clear Rules, One Hand

Definition

Right hand rule physics is the set of hand rules that turn a cross product into a direction. Lay the fingers of your right hand along the first vector, curl them towards the second, and your thumb gives the third: the magnetic force on a moving charge, the field circling a current, or the north end of a coil.

Almost every direction question in magnetism arrives in the same shape. You are handed two things that point somewhere — a velocity and a field, a current and a place to stand, a current and a coil — and asked for a third that sits at right angles to both. The algebra alone cannot finish the job, because a plane has two perpendicular sides and the equations treat them identically.

So fix the axes once, before a single direction word is used: x counts positive to your right across the screen, y counts positive upwards, and z counts positive straight out of the page towards your eye. Into the page is therefore negative z. Assume the opposite sense of z and every answer on this page comes out backwards, which is the single commonest way this topic goes wrong.

What Is the Right-Hand Rule in Physics?

The right-hand rule is a convention for reading the direction of a cross product off your own hand: fingers along the first vector, curled towards the second, thumb along the product.

That is the whole mechanism. What makes it feel like three separate tricks is that physics keeps writing cross products with different letters in them, and each version has picked up its own name and its own folklore.

It is worth being clear about what this page does and does not do. For what a magnetic field actually is, how it bends a charge onto a circle, and the whole of the F = qvB sinθ arithmetic, read our guide to the magnetic field, which answers how big; if you already have a speed, a field and the angle between them and simply want newtons, our Magnetic Force Calculator does that sum. This page answers which way.

Three rules, one piece of physics

  • The force rule. A charge moving through a magnetic field feels a push at right angles to both its velocity and the field.
  • The grip rule. A current in a straight wire wraps a magnetic field round itself in circles.
  • The coil rule. A current running round a coil makes one end of it a north pole.

All three are the same cross product wearing different clothes, and your hand is simply how you read a cross product off a flat page. Learn one properly and the other two cost you nothing.

The Right-Hand Rule Formula and What Every Symbol Means

The force rule is one equation, and it is a cross product rather than an ordinary multiplication.

F = q v × B

The cross is doing real work there. Written out one component at a time, the product of the velocity and the field is three separate subtractions, and that expansion is what a direction answer is actually made of.

(v × B)x = vyBz – vzBy, (v × B)y = vzBx – vxBz, (v × B)z = vxBy – vyBx

Doing those three subtractions by hand is where marks get lost, so if you only want the answer you can hand both vectors to our Right-Hand Rule Calculator, which returns the force vector, its size and its direction in words. The other two rules have their own one-line formulae for the size of the field.

B = μ0 I / 2πr
B = μ0 n I

And the motor rule, the force on a current-carrying wire, is the force rule again with the charge-times-velocity replaced by the current times the length of wire in the field.

F = I L × B
SymbolMeaningSI unitValues used on this page
Fforce on the charge or on the wire, a vectornewton, N1.923 × 10-13 N on a proton; 0.450 N on a wire; 0.200 N in problem 7; exactly 0 N wherever v lies along B
qcharge, with its sign keptcoulomb, C+1.602176634 × 10-19 C for a proton, minus that for an electron, and 2.0 × 10-6 C in problem 7
vvelocity of the charge, a vectormetre per second, m/s3.0 × 106 m/s, and the off-axis (3.0 × 105, 4.0 × 105, 0) m/s in problem 7
Bmagnetic flux density, a vectortesla, T0.40 T, 0.60 T, 0.20 T, 40.0 µT, 2.5133 mT, 5.0265 mT
Iconventional current, positive the way positive charge would flowampere, A10 A in a wire, 2.0 A in a coil, 3.0 A in a motor wire
Llength of wire inside the field, pointing the way the current runsmetre, m0.25 m
rdistance from the wire to the point you are standing atmetre, m0.050 m
nturns per metre along the coilper metre, /m1000 /m and 2000 /m
μ0magnetic constant, the permeability of free spacetesla metre per ampere, T·m/A4π × 10-7 T·m/A

One caution about that last row. Since the 2019 revision of the SI, μ0 is a measured quantity rather than a defined one, and 4π × 10-7 T·m/A agrees with the measured value to within about a part in 109. The bound is deliberately loose, because the measured figure has shifted between data releases and no value was sourced for this page; use 4π × 10-7, but do not call it exact.

Right-Hand Rule Lab

How to Point Your Hand: the Three Rules in Order

Hold your right hand flat, fingers together, thumb stuck out sideways at ninety degrees to them: that one shape, turned to face the problem, solves all three rules.

Three panels on a cream background, each using the same schematic right hand a different way. Panel one, headed force on a moving charge, carries the formula F equals q v cross B: the hand has its palm at the left, four finger bars pointing right and a thumb bar pointing down, with a dashed arc curving away from the fingertips towards the reader labelled curl towards B, out of the page. Beneath it a vector triad leaves one dot: a navy arrow pointing right labelled v right plus x, a thick black arrow pointing down labelled F down minus y, and three small circles each with a filled centre dot standing for a field coming out of the page. Panel two, headed field around a straight wire, carries B equals mu nought I over two pi r: the same hand with its fingers pointing down and its thumb pointing right along the current, and below it a horizontal wire with a solid arrowhead at its right end labelled I, a circled dot above the wire labelled B out of the page if you stand above, and a circled cross below the wire labelled B into the page if you stand below. Panel three, headed which end of a coil is north, carries B equals mu nought n I: the same hand with fingers down and thumb right, and below it a solenoid drawn as six turns, each turn a solid front strand carrying a downward arrowhead and a dashed back strand, with S at the left end, N at the right end and two wine arrows through the bore pointing right under the caption B inside runs S to N, so it points right. Three footnotes state that arrow lengths are indicative only and nothing is drawn to scale, that panel one is a positive charge and reversing the charge reverses F while the hand never changes, and that current downwards on the front of each turn is anticlockwise seen from the right-hand end, which puts north on the right.
The same right hand, used three ways. Nothing in the figure is drawn to scale, and the arrow lengths carry no information; what they carry is direction, and every direction in all three panels obeys the axis convention printed at the top.

Rule 1: the force on a moving charge

Point the fingers of your right hand the way the charge is moving, curl them towards the field, and your thumb now lies along the force on a positive charge. Keep the hand exactly as it is for a negative charge and simply reverse the answer at the end.

Work the standard case. A proton moving to your right through a field coming out of the page: fingers right, curl them towards you, and the thumb drops. The force is downwards, and nothing you do with your left hand will make it any more downwards.

Rule 2: the field around a straight wire

Grip the wire with your right hand so that your thumb lies along the conventional current, and your curled fingers now run the way the field circles the wire. Read the field at any point by seeing which way your fingers are heading as they pass it.

Conventional current is the one that matters here, and it runs the opposite way to the drift of the electrons that are really moving. Get that backwards and the field circles the wrong way; see our guide to electric current for why the convention is the way round it is.

Rule 3: which end of a coil is north

Wrap your right hand round the coil with your fingers curling the way the current runs round the turns, and your thumb sticks out of the north end. That is all there is to a solenoid: a bar magnet you can switch off, with its poles set by which way you wound it.

The size of the field inside a long coil needs no hand at all, only the turns per metre and the current, and our Magnetic Field Calculator will do that arithmetic for you.

The three rules side by side

All three rules differ only in which part of the hand you set and which part you read back off, which is why one grid holds them all. Notice that the input and the output swap places between the second rule and the third: the thumb is what you set for a wire, and what you read for a coil.

RuleThe thumbThe fingersFormulaWhat you read off
Force on a moving chargeLies along the force when the charge is positiveSet along the velocity, then curled towards the fieldF = q v × BThe thumb: which way the charge is pushed. Turn the answer round if q is negative.
Field around a straight wireSet along the conventional current in the wireWrapped round the wire, so they trace the field circlesB = μ0 I / 2πrThe fingers: which way the field heads as it passes the point you chose.
North end of a coilSticks out of whichever end is northCurled in the sense the current circulates round the windingsB = μ0 n IThe thumb: which end of the coil is north, and so which end is south.

The formula column is there to show that the size is a separate question with a separate answer. No hand position produces a number, and nothing in those three formulae tells you a direction.

Three ways to hold the same hand

You will meet the force rule in at least three forms, and students sometimes think they contradict each other. They do not: they are three ways of pointing the same hand.

  • Fingers then curl. Fingers along v, curl them towards B, thumb along F. The form used throughout this page.
  • Flat hand. Fingers along v, palm facing the way B points, thumb along F. Quicker once the field is coming straight at you.
  • Three fingers. Thumb along v, first finger along B, second finger along F, all three held at right angles. That is the same right-handed set as the x, y and z axes themselves, which is where the hand came from in the first place.

Fleming’s left-hand rule belongs in the same list, and it is the one place the hand genuinely changes. It assigns the thumb to the force, the first finger to the field and the second finger to the current — the three fingers above with two of them swapped over — and swapping two members of a right-handed set makes it left-handed, so it needs the other hand to come out right. A cyclic shuffle would have left it right-handed; this one is not cyclic.

The answers are identical either way. Fleming’s rule is a different mnemonic for the motor case, not a different physics, and nothing on this page contradicts it.

The Six Directions, and the 36 Pairs They Make

A two-panel reference figure on a cream background. The left panel, headed the six directions all from one origin, has four navy arrows leaving a single dot: one to the right labelled right plus x, one to the left labelled left minus x, one upwards labelled up plus y and one downwards labelled down minus y. Up and to the left of the origin a circle with a filled centre dot is labelled out of the page plus z; down and to the right a circle with a diagonal cross through it is labelled into the page minus z. A line underneath says that z points at you, so it is drawn as a symbol and never as an arrow in the plane. The right panel, headed right-handed so the order matters, lists four cross products in bold with the direction spelled out beneath each: x cross y equals plus z, out of the page; y cross z equals plus x, right; z cross x equals plus y, up; and, below a rule and marked swap the order and it reverses, y cross x equals minus z, into the page. Below a second rule, x cross x equals zero, with the note that a vector crossed with itself is zero and zero has no direction. Three footnotes state that 12 of the 36 ordered pairs of these six directions give a zero cross product, three axes by two senses of v by two senses of B; that every direction named in the article means exactly the arrow or symbol drawn here; and that the products above are geometry and do not depend on the charge, while it is the force q v cross B that reverses when q is negative.
The six directions this page ever names, and the three products that fix the sense of all the others. The z axis points at the reader, so it is drawn as a circled dot coming out and a circled cross going in, never as an arrow lying in the plane.

Restrict the velocity and the field to those six directions and there are 36 ordered pairs to consider. The table below gives the force direction for every one of them, for a positive charge.

v pointsB right (+x)B left (-x)B up (+y)B down (-y)B out of the page (+z)B into the page (-z)
right (+x)no forceno forceout of the page (+z)into the page (-z)down (-y)up (+y)
left (-x)no forceno forceinto the page (-z)out of the page (+z)up (+y)down (-y)
up (+y)into the page (-z)out of the page (+z)no forceno forceright (+x)left (-x)
down (-y)out of the page (+z)into the page (-z)no forceno forceleft (-x)right (+x)
out of the page (+z)up (+y)down (-y)left (-x)right (+x)no forceno force
into the page (-z)down (-y)up (+y)right (+x)left (-x)no forceno force

Two things in that table are worth more than the individual cells. The first is that 12 of the 36 pairs give no force at all — three axes, two senses of the velocity and two senses of the field. It is a third of the table, not a sixth, and the count catches people out because it is easy to forget that each axis can be travelled along in two directions.

The second is the symmetry. Every cell is reversed by reversing the sign of the charge, so one table serves for electrons too: read the cell, then turn the answer round. The simulator above is restricted to these same six directions on purpose, which keeps it a direction trainer; anything off-axis belongs in the calculator, and problem 7 below works one through by hand.

Why a Cross Product Needs a Hand

Two vectors can be combined in two quite different ways, and the difference is the whole of this topic. A dot product returns a number and does not care about the order. A cross product returns a vector perpendicular to both, and the order decides which of the two perpendicular ways it points.

That last sentence is the problem in miniature. Take any two vectors that are not parallel; they define a plane, and the plane has two faces. Nothing in the arithmetic of components prefers one face over the other — the preference has to be put in by hand, and it is put in by the right hand.

Done consistently in a left-handed coordinate system the left hand would serve just as well, and every answer would come out the same. The hand is bookkeeping about the axes, not a fact about hands, which is why it appears identically in torque and in angular velocity, neither of which involves magnetism at all.

Why the force never does any work

Because F is a cross product of v with something, it can never have a component along v. Over all 36 axis pairs the dot product F · v is exactly zero, with no rounding involved. The dot product is the honest way to put it, because in the 12 pairs where the force vanishes there is no angle to take the cosine of.

That has a consequence worth holding on to: a magnetic field can bend a charge’s path but can never change its speed. It is the same point our magnetic field guide makes when it says a field steers but never accelerates in the everyday sense.

A charge released into a steady uniform field therefore travels at constant speed round a circle, and a magnetic field can sort particles by bending them while leaving their kinetic energy untouched.

Crossing is not adding

One last distinction, because it trips people who are new to vectors. Adding two vectors gives you something that lies between them; crossing them gives you something that lies outside their plane altogether, perpendicular to both.

If what your problem actually wants is a resultant rather than a perpendicular, you need a different tool and a different idea — our Vector Addition Calculator handles that case, and the difference between the two is covered in our guide to scalar and vector quantities.

Common Mistakes With the Right-Hand Rule

Four mistakes account for most wrong answers, and three of them are about signs rather than about the hand.

Mistake 1: guessing the sense of z

A field drawn as a grid of crosses is going into the page and must be entered as a negative z component; a grid of dots is coming out at you and is positive. Swap those two and every direction you work out comes back reversed, which is why this page fixes the convention before it names a single direction.

Mistake 2: switching to the left hand for an electron

Changing hands for a negative charge happens to give the right answer, and that is exactly what makes it dangerous: it works until it is combined with another sign change, and then it quietly fails. Use the right hand always, then reverse the result once because q is negative.

Mistake 3: using electron flow instead of conventional current

The grip rule and the coil rule are both stated for conventional current, which flows from the positive terminal round to the negative. Electrons drift the other way. Trace the electrons with your thumb and you will get the field circling backwards and the coil’s poles swapped.

Mistake 4: thinking six of the 36 pairs give zero

Three axes suggests three zero cases, and remembering that parallel and antiparallel both count suggests six. The real figure is 12, because the velocity has two senses and the field has two senses, and 3 × 2 × 2 = 12. Count the italic cells in the table above if you want to check.

Where the Right-Hand Rule Breaks Down

The hand itself never breaks down — a cross product is a cross product. What has limits is the physics the three formulae describe, and it is worth knowing where those limits sit.

A zero force has no direction, and that is an answer

When the charge, the velocity or the field is zero, or when the velocity lies exactly along the field, the cross product is the zero vector. There is no axis to name and no angle to quote, so the honest output is the cause rather than an invented direction. Any tool that prints a direction here is telling you something it cannot know.

The straight-wire formula assumes an infinitely long wire

B = μ0 I / 2πr is derived for a wire of infinite length, and a real wire departs from it near its ends. The direction the grip rule gives is unaffected; it is the size that drifts, and only close to where the wire stops.

The solenoid formula is the ideal long-coil interior

B = μ0 n I is the field well inside a long, tightly wound coil. Near the ends it falls away, and for a short fat coil it is wrong everywhere. Which end is north does not depend on any of that — only the number does.

One charge, one uniform field, no relativity

Every figure on this page treats a single charge in a field that is the same everywhere, moving slowly enough that no relativistic correction is needed. At 3.0 × 106 m/s a charge is at about one per cent of the speed of light, where that is comfortably true.

There is also no electric field anywhere in these problems. The complete force on a charge is the Lorentz force, of which the magnetic half is what the hand gives you; if your problem has an electric field as well, its contribution has to be added separately, and unlike the magnetic part it does do work.

Where the Right-Hand Rule Is Actually Used

This is not a rule you learn and then file away. It decides which way real things move, and getting it backwards is the difference between a motor that spins and a motor that spins the wrong way.

Motors, and the direction a shaft turns

A motor is a loop of wire carrying current across a magnetic field, and the force on each side of the loop comes straight from F = I L × B. The two sides carry current in opposite directions, so the forces on them point opposite ways, and the loop turns. Which way it turns is the right-hand rule, applied twice.

A small brushed DC motor opened up, showing the wire coil of the rotor between two curved permanent magnets.
Every brushed DC motor is the right-hand rule made of metal: current through the coil, a field across it, and a force at right angles to both.

Reading the sign of the carriers in a Hall probe

Push a current through a thin strip in a transverse field and the moving carriers pile up on one edge. Which edge depends on the sign of the carriers, so measuring the voltage across the strip tells you whether the charge doing the moving is positive or negative. That is a direction question answered with a direction rule.

Electromagnets, relays and the pole you need

Any coil you wind becomes a magnet with its poles decided by the direction you wound it, and relays, solenoid valves and lifting magnets all depend on getting that right. Reverse the current and the poles swap, instantly.

Induction, and which way the induced current runs

When a field through a loop changes, the loop pushes back: the induced current runs the way that opposes the change, and the right-hand rule is how you turn “opposes” into an actual direction round the loop. Our guide to electromagnetic induction works that argument through. If you want to go further with the trainer above, the right-hand rule simulator page covers what each control changes and which preset to load first.

Worked Problems

Every problem below asks for a direction first and a size second, and every figure is quoted from the same physics contract the simulator and the calculator are both built against. Axes as before: +x right, +y up, +z out of the page.

Problem 1
A proton travels to the right (+x) at 3.0 x 10^6 m/s through a uniform 0.40 T field pointing out of the page (+z). Which way does the magnetic force on it point, and how large is that force?
Show Solution
Solution: Step 1: The force is the cross product F = q(v × B), so start from the component expansion. With v along +x only and B along +z only, two of the three components vanish and only the y component survives: (v × B)y = vzBx – vxBz. Step 2: Substitute, in SI units. (v × B)y = (0)(0) – (3.0 × 106)(0.40) = -1.2 × 106 T·m/s. Step 3: Multiply by the charge of a proton, q = +1.602176634 × 10-19 C. Fy = (1.602176634 × 10-19)(-1.2 × 106) = -1.92261 × 10-13 N, with Fx and Fz both zero. A negative y component means the force points down. Answer: 1.923 × 10-13 N, pointing down (-y).
Problem 2
Replace the proton in problem 1 with an electron, keeping the same velocity and the same field. What changes?
Show Solution
Solution: Step 1: Nothing about the hand changes, and nothing about the cross product changes either. The velocity and the field are the same, so (v × B)y = -1.2 × 106 T·m/s exactly as before. Step 2: Only the charge is different: q = -1.602176634 × 10-19 C. Step 3: Fy = (-1.602176634 × 10-19)(-1.2 × 106) = +1.92261 × 10-13 N. Two negatives have made a positive, so the force now points up. Answer: 1.923 × 10-13 N, pointing up (+y) — the same size as for the proton, the opposite way.
Problem 3
A proton again travels to the right (+x) at 3.0 x 10^6 m/s, but this time the 0.40 T field points into the page (-z). Which way is the force now?
Show Solution
Solution: Step 1: Into the page means a negative z component, so Bz = -0.40 T. The surviving component of the cross product is the same one: (v × B)y = vzBx – vxBz. Step 2: (v × B)y = (0)(0) – (3.0 × 106)(-0.40) = +1.2 × 106 T·m/s. Step 3: Fy = (1.602176634 × 10-19)(+1.2 × 106) = +1.92261 × 10-13 N. Reversing the field has reversed the force, and the size has not moved. Answer: 1.923 × 10-13 N, pointing up (+y). Half of this answer was the sense of z.
Problem 4
A long straight wire carries 10 A to the right (+x). Which way does its magnetic field point at a point 0.050 m directly above the wire, and at a point 0.050 m directly below it, and how strong is the field at each?
Show Solution
Solution: Step 1: Direction first, from the grip rule written as a cross product: B points along the current direction crossed with the direction from the wire to you. Standing above the wire that is (+x) crossed with (+y), which is +z, out of the page. Standing below it is (+x) crossed with (-y), which is -z, into the page. Step 2: Size next, from B = μ0 I / 2πr. Because μ0 = 4π × 10-7 T·m/A, the combination μ0 / 2π is 2 × 10-7 T·m/A, so B = (2 × 10-7)(10) / (0.050). Step 3: (2 × 10-7)(10) = 2 × 10-6, and 2 × 10-6 / 0.050 = 4.0 × 10-5 T. Both points are the same distance from the wire, so both get the same size. Answer: out of the page (+z) above the wire, into the page (-z) below it, and 40.0 µT at both points.
Problem 5
A straight wire 0.25 m long carries 3.0 A to the right (+x) through a 0.60 T field pointing into the page (-z). Which way is the force on the wire, and how big is it?
Show Solution
Solution: Step 1: For a current-carrying wire the rule is F = I L × B, which is the force rule with the charge-times-velocity replaced by current-times-length. Same hand, same expansion, so the surviving component is (L × B)y = LzBx – LxBz. Step 2: With Lx = 0.25 m and Bz = -0.60 T, (L × B)y = (0)(0) – (0.25)(-0.60) = +0.15 T·m. Step 3: Fy = I(L × B)y = (3.0)(0.15) = 0.450 N, upwards. Cross-check against the textbook size for a wire at right angles to the field, BIL: (0.60)(3.0)(0.25) = 0.450 N, the same figure. Answer: 0.450 N, straight up (+y).
Problem 6
A long solenoid has 1000 turns per metre and carries 2.0 A, running anticlockwise as seen from its right-hand end. Which end is the north pole, and what is the field inside? What happens if the winding density is doubled to 2000 turns per metre?
Show Solution
Solution: Step 1: Direction first. Curl the fingers of your right hand the way the conventional current runs round the turns and your thumb comes out of the north end. Anticlockwise as seen from the right-hand end sends the thumb towards +x, so north is the right-hand end and south is the left. Step 2: Size, from B = μ0 n I. B = (4π × 10-7)(1000)(2.0) = 2.51327 × 10-3 T. Step 3: Double the turns per metre and nothing about the geometry moves, so only the number changes: B = (4π × 10-7)(2000)(2.0) = 5.026548 × 10-3 T. The field has doubled; the north end has not moved. Answer: north at the right-hand end, with 2.5133 mT inside at 1000 turns per metre and 5.0265 mT at 2000.
Problem 7
A charge of 2.0 x 10^-6 C moves with velocity (3.0 x 10^5, 4.0 x 10^5, 0) m/s through a field (0, 0, 0.20) T. Find the force vector, its size, and show that the force does no work.
Show Solution
Solution: Step 1: Neither vector lies along an axis, so all three components of the cross product have to be worked out. (v × B)x = (4.0 × 105)(0.20) – (0)(0) = 8.0 × 104 T·m/s; (v × B)y = (0)(0) – (3.0 × 105)(0.20) = -6.0 × 104 T·m/s; (v × B)z = (3.0 × 105)(0) – (4.0 × 105)(0) = 0. Step 2: Multiply all three by q = 2.0 × 10-6 C. Fx = (2.0 × 10-6)(8.0 × 104) = 0.160 N; Fy = (2.0 × 10-6)(-6.0 × 104) = -0.120 N; Fz = 0. Step 3: The size is sqrt(Fx2 + Fy2 + Fz2) = sqrt(0.0256 + 0.0144 + 0) = sqrt(0.0400) = 0.200 N. Dividing the components by that size gives the unit vector (0.800, -0.600, 0.000), which is none of the six named directions. For the no-work check, multiply the force by the velocity component by component: (0.160)(3.0 × 105) + (-0.120)(4.0 × 105) + 0 = 48000 – 48000 = 0. Answer: F = (0.160, -0.120, 0) N, size 0.200 N, direction the unit vector (0.800, -0.600, 0.000), and the force does no work.
Problem 8
A proton travels to the right (+x) at 3.0 x 10^6 m/s. What is the magnetic force on it if the 0.40 T field also points to the right, and what if the field points to the left instead?
Show Solution
Solution: Step 1: Field to the right, so B = (0.40, 0, 0) T. Every component of the cross product has a zero in each of its terms: (v × B)x = (0)(0) – (0)(0) = 0; (v × B)y = (0)(0.40) – (3.0 × 106)(0) = 0; (v × B)z = (3.0 × 106)(0) – (0)(0.40) = 0. Step 2: Field to the left, so B = (-0.40, 0, 0) T. The same three lines give (v × B)x = (0)(0) – (0)(0) = 0, then (v × B)y = (0)(-0.40) – (3.0 × 106)(0) = 0 and (v × B)z = (3.0 × 106)(0) – (0)(-0.40) = 0, so the cross product is the zero vector again. Step 3: A zero vector has no direction, so the complete answer names the cause instead of an axis: in the first case the velocity is parallel to the field, at an angle of 0 degrees, and in the second it is antiparallel, at 180 degrees. This is also why the tools on this site take the force from the cross product rather than from the sine form: in double-precision arithmetic sin(180 degrees) evaluates to 1.2246 × 10-16 instead of zero, which turns an exact zero into 2.355 × 10-29 N of floating-point dust. Answer: zero force in both cases, and no direction in either.

Frequently Asked Questions

What is the right-hand rule in physics?
The right-hand rule is a convention for reading the direction of a cross product off your hand. Point your fingers along the first vector, curl them towards the second, and your thumb gives the third. It fixes the direction of the magnetic force on a moving charge, of the field circling a current-carrying wire, and of the north pole of a coil.
Which finger is which in the right-hand rule?
In the form used here the fingers go along the velocity, they curl towards the magnetic field, and the thumb gives the force on a positive charge. A three-finger version of the same rule puts the thumb along the velocity, the first finger along the field and the second finger along the force. Fleming’s left-hand rule reshuffles those three, which is exactly why it needs the other hand.
Why the right hand and not the left?
Because the standard coordinate axes are right-handed, and the hand is simply bookkeeping about that choice. A cross product has to pick one of the two sides of a plane, and nothing in the arithmetic picks for you. In a consistently left-handed system the left hand would work and every answer would agree. Fleming’s left-hand rule is the same physics with the fingers assigned differently.
How do you use the right-hand rule for an electron?
Use the right hand exactly as you would for a positive charge, then reverse the answer at the end. The charge sits outside the cross product in F = q v × B, so a negative q simply flips the vector the hand produced. Swapping to your left hand happens to work too, but it fails as soon as a second sign change is involved.
Does the right-hand rule work for a current-carrying wire as well as a moving charge?
Yes, and it is the same rule. Replace charge-times-velocity by current-times-length and the force on a wire is F = I L × B, read with the same hand and the same geometry. The grip rule for the field around a wire and the coil rule for a solenoid are also cross products, which is why one hand position covers all of them.
What happens when the velocity and the magnetic field point the same way?
The force is exactly zero, and a zero force has no direction. The same is true when they point in exactly opposite directions, and when the charge, the speed or the field is zero. Of the 36 pairs you can make from six axis directions, 12 give no force at all: three axes, two senses of the velocity, two senses of the field.
Is there more than one right-hand rule?
There are three common ones, and they are the same piece of physics each time. The force rule gives the push on a moving charge, the grip rule gives the field circling a straight wire, and the coil rule gives the north end of a solenoid. All three read a cross product off the hand; only the vectors you feed in are different.
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