Efficiency is one division: the useful output over the total input, times 100 if you want a percentage. Both figures go in the same unit as each other and neither box carries a unit menu, because the ratio cancels whichever unit you chose — 9 over 12 is 75.00 % whether those are watts or joules. This free efficiency calculator solves that relation in all three directions and then does one more job the single formula cannot: switch the menu to Overall efficiency and it multiplies four stage efficiencies into one figure, which is at best the weakest of the four stages and usually below even that.
Beside every answer it prints the efficiency as a fraction, the useful output, the total input, what was wasted and what share of the input that waste was. None of the devices named in the presets is a product specification; every figure here is an arithmetic exercise with stated givens.
Every button sets the Solve for menu first and then writes all eight boxes, so whichever quantity the menu is pointing at, the rest already agree with it. The last button is there to be declined: an efficiency above 100 per cent is the one case the simulator cannot show you, because its slider stops at the input. The line underneath quotes back whatever the widget worked out, so nothing in it is stored text.
Pick a case above, or type your own numbers.

The efficiency calculator is a free online tool for the one division that sits behind every question about how good a device is at its job. Efficiency is the useful output divided by the total input, multiplied by 100 if you want a percentage, and it is a pure number: there is no unit on the answer and there need be no unit on either figure going in.
Four positions of the Solve for menu answer four different questions. The efficiency is the one almost everybody wants and the menu opens on it; the useful output is what a stated efficiency will actually deliver from a supply you have; the total input is how much has to go in for an output you have already fixed; and the overall efficiency is a whole chain of stages, which the single formula cannot reach.
Neither the useful-output box nor the total-input box carries a unit, and that is the physics rather than a shortcut. The two figures are quantities of the same kind, so whatever unit you measured them in appears in the numerator and the denominator of one fraction and cancels before the division is done. Joules over joules and watts over watts give the identical number, and doubling both figures changes nothing at all, so you can enter both in one unit of your own choosing and read the answer off.
The six efficiency boxes do carry a unit, and it has two settings: per cent and fraction. Entering 75 in per cent and 0.75 as a fraction are the same entry, because the shared engine converts between them, and every refusal below is written against the fraction. The overall efficiency box is the one quantity on the page that is only ever an output: the tool never reads it as an input, and its opening value is the exact product of the four stage boxes above it so that it can never contradict them.
Six readings sit beside every answer, and all six are worked out from the complete state with the solved value substituted back, which is what makes them the same six whichever quantity you asked for. For a single device they are the efficiency as a percentage, the efficiency as a fraction, the useful output, the total input, what was wasted, and what share of the input that waste was. The wasted figure is the one worth quoting: two devices at 90 per cent waste wildly different amounts if one draws ten times the power of the other, so a percentage on its own rarely changes a decision.
Some entries are declined rather than answered, and one of them is the whole reason this tool exists. A useful output larger than the total input would be an efficiency above 100 per cent, which would mean energy appearing from nowhere, so the page says so in words instead of printing a figure - and this is the one case the matching simulator cannot show you, because its slider stops at the input. A total input of zero or less, a negative useful output, an efficiency above 100 per cent typed as an input, and a stage outside 0 to 100 per cent are all refused the same way. The boundary case where the useful output exactly equals the input is allowed, and returns exactly 100 per cent for an ideal lossless device.
Two refusals are conditional, and they are worth reading twice. An efficiency of zero is a perfectly good input when you are asking for the useful output, because a device that wastes everything is a real device and the answer is exactly zero; the same zero is refused when the total input is the unknown, because that direction divides by it. A useful output of zero is refused in that same direction only, because the answer would be a total input of zero.
The chain mode is the half of the page the single formula cannot do, and it exists because stage efficiencies multiply. Each stage takes as its input whatever the stage before it managed to pass on, so two stages at 80 and 90 per cent leave 72.00 per cent - not 170 per cent, and not the average of 85.00 per cent. Multiplying numbers below one can only shrink the result, so a chain is never better than its worst stage and is usually worse: four stages at 38, 96, 92 and 88 per cent give 29.53 per cent, below the 38.00 per cent stage that was already the weakest.
Both of the wrong answers are printed beside the right one, on purpose. The readings count how many stages are below 100 per cent - a stage left at 100 is a stage that is not there - and show the average of those stages labelled as not the answer, because averaging is the commonest way a chain gets combined wrongly. And the chain must be built from the fractions rather than from percentages the page has already printed: two thirds times 0.850 is 56.67 per cent worked from the fractions and 56.70 per cent worked from a printed 66.7 per cent, a gap of 0.0283 percentage points that is invisible in the first decimal and wrong in the second.
No device named anywhere on this page is given a real-world efficiency as a fact. The lamp, the kettle and the hoist in the presets are arithmetic exercises with stated givens, chosen because they produce clean figures, and no manufacturer, model, standard or measured industry figure appears in any of them. If you need the real efficiency of a real device, verify it against that device before you use it.
What the page does not do, it says. There is no temperature-driven ceiling for a heat engine and no Carnot cycle, no coefficient of performance, and no ratio of two mechanical advantages; those are three different quantities that are also called efficiency, and each has its own guide and its own calculator linked from the page. There is no taxonomy of the ways energy moves from one place or form to another, and no rules for counting significant figures. The page does one division, two rearrangements of it and one product, and stops.
| Symbol | Quantity | Default unit | Also accepts | Example value |
|---|---|---|---|---|
| E_useful | Useful output | — | — | 9 |
| E_input | Total input | — | — | 12 |
| eta | Efficiency | % | fraction | 75 |
| eta1 | Stage 1 efficiency | % | fraction | 38 |
| eta2 | Stage 2 efficiency | % | fraction | 96 |
| eta3 | Stage 3 efficiency | % | fraction | 92 |
| eta4 | Stage 4 efficiency | % | fraction | 88 |
| eta_total | Overall efficiency | % | fraction | 29.534208 |
9 and 12, and they must be in the same unit as each other. Which unit that is never reaches the arithmetic — joules over joules and watts over watts give the identical number.75 %, which the working prints as 75.00 per cent.0.7500. A percentage the page has already printed has been rounded, and a rounded figure multiplied into the next step moves the answer.3.000 and 25.00 % at the opening boxes. That is the figure that changes a decision; the percentage on its own rarely is.75 in per cent and 0.75 as a fraction are the same entry.38, 96, 92 and 88. A stage at 100 per cent is a stage that is not there.38.00 % and the overall figure is 29.53 %. The chain is below its worst stage, which is the whole reason the mode exists.This page is the arithmetic, and the efficiency formula guide is where the method is set out with eight worked problems, the energy form against the power form, and the chain diagram. The two figures you type usually come from somewhere else: the guide to power in physics is where a power is worked out from work and time, and the work and power calculator is the tool for that step.
Three mistakes account for most wrong answers here. The first is mixing the two units: the ratio cancels one unit, not two different ones, so kilojoules over joules reads a thousand times out. The second is deciding the wrong figure is "useful" — a heater's waste heat is its useful output, and the guide to energy conversion examples is the page that hands this question over to this one.
The third is combining a chain by adding or averaging. Both wrong answers are printed beside the right one in the chain mode so that the gap is visible rather than described. Neither is close: two stages at 80 and 90 per cent give 72.00 %, where the average says 85.00 % and the sum says 1.700, which is above 1 and so cannot be an efficiency at all.
9 out of a total input of 12 gives 75 %, with readings of 0.7500 as a fraction, 3.000 wasted and a 25.00 % wasted share. The two boxes carry no unit, because the ratio cancels whichever one you used.The first table starts at the opening boxes, runs the three stated-given cases the page quotes, then changes one thing at a time: the same lamp over an interval, both sides doubled, the menu moved to each of the other two single-device directions, and finally the entries the calculator declines. Every answer and reading cell was read out of the running widget rather than worked out by hand, so where a cell and the tool ever part company, believe the tool.
| Case | Solving for | What you type | Headline answer | Efficiency | As a fraction | Wasted | Wasted share |
|---|---|---|---|---|---|---|---|
| The page as it opens: a lamp | Efficiency | useful 9, total 12 | 75 % | 75.00 % | 0.7500 | 3.000 | 25.00 % |
| A kettle heating water | Efficiency | useful 167200, total 190000 | 88 % | 88.00 % | 0.8800 | 22800 | 12.00 % |
| A motor hoisting a load | Efficiency | useful 981, total 1350 | 72.67 % | 72.67 % | 0.7267 | 369.0 | 27.33 % |
| An ideal lossless device | Efficiency | useful 5, total 5 | 100 % | 100.00 % | 1.000 | 0.000 | 0.00 % |
| The same lamp over 60 seconds | Efficiency | useful 540, total 720 | 75 % | 75.00 % | 0.7500 | 180.0 | 25.00 % |
| Twice the lamp, both sides doubled | Efficiency | useful 18, total 24 | 75 % | 75.00 % | 0.7500 | 6.000 | 25.00 % |
| The useful output at a stated efficiency | Useful output | efficiency 35 %, total 400000 | 140000 | 35.00 % | 0.3500 | 260000 | 65.00 % |
| The input a stated output needs | Total input | useful 500, efficiency 62.5 % | 800 | 62.50 % | 0.6250 | 300.0 | 37.50 % |
| A device that wastes everything | Useful output | efficiency 0 %, total 12 | 0 | 0.00 % | 0.000 | 12.00 | 100.00 % |
| The same state solved for the efficiency | Efficiency | useful 140000, total 400000 | 35 % | 35.00 % | 0.3500 | 260000 | 65.00 % |
| The same state solved for the input | Total input | useful 140000, efficiency 35 % | 400000 | 35.00 % | 0.3500 | 260000 | 65.00 % |
| More useful out than went in | Efficiency | useful 13, total 12 | no answer | - | - | - | - |
| A total input of zero | Efficiency | useful 9, total 0 | no answer | - | - | - | - |
| A negative total input | Efficiency | useful 9, total -12 | no answer | - | - | - | - |
| A negative useful output | Efficiency | useful -9, total 12 | no answer | - | - | - | - |
| An efficiency above 100 per cent | Useful output | efficiency 120 %, total 12 | no answer | - | - | - | - |
| An efficiency of zero, solving for the input | Total input | useful 500, efficiency 0 % | no answer | - | - | - | - |
| A useful output of zero, solving for the input | Total input | useful 0, efficiency 62.5 % | no answer | - | - | - | - |
Rows 1 to 4 are four stated givens and nothing more. The lamp, the kettle and the motor produce 75.00 %, 88.00 % and 72.67 % because those are the figures that were put in, not because any device was measured. Row 4 is the boundary the page allows: a useful output exactly equal to the input returns 100.00 %, the ideal lossless device.
Rows 5 and 6 change one thing each and neither moves the answer. Row 5 runs the lamp over 60 seconds instead of per second, so 540 joules useful out of 720 joules in — the interval appears top and bottom of the same fraction and cancels exactly. Row 6 doubles both figures and gets 75.00 % again, which is the scale-free property written out.
Rows 7 to 11 are the same relation rearranged. Row 7 asks for the useful output at a stated 35 % and gets 140000; row 8 asks what input a 500 useful output needs at 62.5 % and gets 800. Row 9 is the device that wastes everything, which is a real device and is answered rather than refused.
Rows 10 and 11 close the round trip on row 7's own state. Feeding 140000 and 400000 back in returns 35 %, and feeding 140000 at 35 % returns 400000. That is a tautology and it is worth saying so: one division rearranged three ways can only disagree with itself in the last floating-point digit.
Rows 12 to 18 sit outside the domain and are declined there rather than answered. Row 12 is the one that matters most: 13 useful out of 12 in would be an efficiency above 100 per cent, which would mean energy appearing from nowhere, so the page says so instead of printing a number. The conservation of energy guide is where that principle is set out properly.
The last three are the conditional ones. An efficiency above 100 per cent is refused as an input in row 16 for the same reason row 12 is refused as an output. An efficiency of zero is fine in row 9 and refused in row 17, because only one of those two directions divides by it — and a useful output of zero is refused in row 18 only, because there the answer would be a total input of zero.
The second table is the chain mode, which is the half of this page the single formula cannot do. Each row types four stage efficiencies and reads back the overall figure, the worst single stage, how many stages are actually doing anything, and the average of those stages — which the widget labels as not the answer, because it is the commonest wrong way to combine a chain.
| Case | Stages you type | Headline answer | Overall efficiency | Worst single stage | Stages in play | Average of those stages | Wasted share |
|---|---|---|---|---|---|---|---|
| Two stages, 80 then 90 per cent | 80, 90, 100, 100 | 72 % | 72.00 % | 80.00 % | 2 | 85.00 % (not the answer) | 28.00 % |
| Three stages, the 40 per cent one setting the scale | 40, 92, 85, 100 | 31.28 % | 31.28 % | 40.00 % | 3 | 72.33 % (not the answer) | 68.72 % |
| Four stages, end to end | 38, 96, 92, 88 | 29.53 % | 29.53 % | 38.00 % | 4 | 78.50 % (not the answer) | 70.47 % |
| The same four stages in another order | 88, 92, 96, 38 | 29.53 % | 29.53 % | 38.00 % | 4 | 78.50 % (not the answer) | 70.47 % |
| Three perfect stages and one bad last one | 100, 100, 100, 50 | 50 % | 50.00 % | 50.00 % | 1 | 50.00 % (not the answer) | 50.00 % |
| A lossless chain | 100, 100, 100, 100 | 100 % | 100.00 % | 100.00 % | 0 | no stage below 100 per cent | 0.00 % |
| One dead stage kills the chain | 38, 96, 0, 88 | 0 % | 0.00 % | 0.00 % | 4 | 55.50 % (not the answer) | 100.00 % |
| A stage above 100 per cent | 38, 96, 92, 120 | no answer | - | - | - | - | - |
| A negative stage | 38, 96, 92, -10 | no answer | - | - | - | - | - |
The first three rows are the whole lesson. Two stages at 80 and 90 per cent give 72.00 %, below both of them. Three stages give 31.28 %, below the 40.00 % one that was already the worst.
Four stages give 29.53 %, where the average of those same four stages reads 78.50 %. The chain is below its worst stage and nowhere near their average, which is the difference between multiplying and averaging.
Row 4 types the same four stages backwards and gets the same 29.53 %, because multiplication does not care about order. Row 5 puts three perfect stages in front of one bad one and still lands on 50.00 %: the overall figure is set by the size of the loss, not by where it sits or by how many stages surround it.
Rows 6 and 7 are the two ends. A chain with every stage at 100 per cent has no chain in it at all, so the reading says so in words rather than printing an average of nothing. One dead stage takes the whole chain to 0.00 % however good the other three are, which is why that reading counts the stages below 100 per cent rather than assuming four.
The last two rows are refused. A stage above 100 per cent or below zero is not an efficiency, so the chain is declined rather than multiplied out — the same ceiling as row 12 of the first table, applied one link at a time.
One division does nearly all the work. Efficiency is the useful output over the total input, eta = E_useful / E_input, and multiplying by 100 turns that pure number into a percentage. Rearranged for each of the other two unknowns it is E_useful = E_input × eta and E_input = E_useful / eta, which are the second and third positions of the Solve for menu.
The same two boxes take powers as happily as energies, and that is not a convenience but the reason the boxes carry no unit. If both figures are measured over the same interval then that interval sits top and bottom of one fraction and cancels exactly: a lamp at 9 watts useful out of 12 watts in is 75.00 %, and over 60 seconds it is 540 joules out of 720, which is 75.00 % again. The guide to what energy is in physics is where the joule itself is set out, and the power calculator turns work and time into the watts this page then divides.
The fourth position of the menu is a different equation. Stages in series multiply, eta_total = eta1 × eta2 × eta3 × eta4, because every stage takes as its input whatever the one before it passed on. The waste follows from the efficiency rather than needing its own measurement: E_waste = E_input - E_useful, which is the same as the input times one minus the efficiency, and it is the figure worth quoting.
Two neighbouring quantities are called efficiency on this site and are not this one. The ratio of two mechanical advantages is the mechanical advantage guide's quantity and has its own calculator; the temperature-driven ceiling on a heat engine is the Carnot efficiency guide's, and neither is computed anywhere on this page.
| Symbol | Meaning | Unit | Values used on this page |
|---|---|---|---|
| E_useful | Useful output — how much of the supply arrived in the form you wanted. A solve target. The same box takes a power, P_useful, because the ratio is identical either way | none: your own unit, the same one as the total | Opens on 9. Presets also use 167200, 981, 5, 500 and 140000. Must be zero or positive, and never larger than the total. |
| E_input | Total input — everything that went in, useful and wasted together. A solve target. The same box takes a power, P_input | none: your own unit, the same one as the useful output | Opens on 12. Presets also use 190000, 1350, 5 and 400000. Must be greater than zero. |
| eta | Efficiency — the useful output divided by the total input. A solve target, and the one the menu opens on | per cent by default; a fraction from 0 to 1 if you switch the menu | A result: 75.00 % at the opening boxes, 88.00 % for the kettle, 72.67 % for the hoist, 100.00 % for an ideal lossless device. |
| eta1 to eta4 | Stage 1 to stage 4 efficiency — the four links of a chain, in the chain mode only. A stage at 100 per cent is a stage that is not there | per cent by default; a fraction from 0 to 1 | Open on 38, 96, 92 and 88. Presets also use 80 and 90, 40 and 92 and 85, and 50. Each must sit between 0 and 100 per cent. |
| eta_total | Overall efficiency — the four stage efficiencies multiplied together. A solve target, and the only box this page never reads as an input | per cent by default; a fraction from 0 to 1 | A result: 29.53 % at the stage defaults, 72.00 % for two stages, 31.28 % for three. |
| E_waste | Wasted — the total input minus the useful output, which is the same as the input times one minus the efficiency. A reading rather than a box | the same unit as the two figures you typed | A reading: 3.000 at the opening boxes, 22800 for the kettle, 369.0 for the hoist, 0.000 for an ideal device. |
| Wasted share | What fraction of the input never arrived, as a percentage. One minus the efficiency, which is why it is a reading and not a second calculation | per cent | A reading: 25.00 % at the opening boxes, 12.00 % for the kettle, 70.47 % for the four-stage chain. |
| Average of the live stages | The arithmetic mean of the stages below 100 per cent, labelled on the page as not the answer. It is printed because it is the commonest wrong way to combine a chain | per cent | A reading: 85.00 % for two stages whose real answer is 72.00 %, and 78.50 % for four whose real answer is 29.53 %. |
The ceiling is not a property of machines but of the arithmetic the question is made of. The useful output is one part of the input, and the waste is the rest; a part cannot be bigger than the whole it was taken from. That is conservation of energy and nothing more, which is why this page refuses the entry rather than reporting a figure above 100.
It is worth being precise about what the ceiling is not. It is not the second law, and it is not a statement about heat. A heat engine does carry a further ceiling, set by the two temperatures it works between and lower than 100 per cent, but that is an extra restriction stacked on top of this general one — and it is computed by the Carnot efficiency calculator rather than here.
The other apparent counterexample is a heat pump quoted above 100 per cent, and it is a different ratio rather than a violation. What is being quoted there is heat moved per unit of work supplied, which compares two different quantities and has its own name and its own page. Nothing on this page computes one.
Which brings the weight back onto the one judgement this page cannot make for you: which figure is useful. A lamp's useful output is light and its heat is waste; an electric heater's useful output is the heat, and the same joules that were waste in one case are the whole point in the other. The arithmetic is identical and the answer is not, so it is the device in front of you and not the formula that settles the numerator — and where that numerator is a quantity of work, the guide to work done in physics is where the figure is worked out before this page ever sees it.
38, 96, 92 and 88 per cent multiply to 29.53 %, below the 38.00 % stage that is already the worst of the four. The average of those four stages reads 78.50 % and is labelled as not the answer.The arithmetic here is exact to the last digit a double can hold, and there is no physical constant in it to be uncertain about. What goes wrong is everything around the division: which figure you called useful, where the two numbers came from, and whether a single percentage was ever the thing worth knowing.
56.67 % from the fractions and 56.70 % from a stage printed as 66.7 per cent first. The gap is 0.0283 percentage points — invisible in the first decimal, wrong in the second — which is why the chain mode asks for stages rather than for a percentage you typed back in.300.0 difference is the cost of the inefficiency in the unit you care about.29.53 % against a worst stage of 38.00 %, so the three good stages are still taking a bite out of a chain that stage had already capped. Improving the worst link is nearly always worth more than improving any of the others.88.00 % leaves 22800 joules that went somewhere other than the water, and that figure is the one worth putting in a report. The percentage tells you how good something is; the waste tells you what it costs.
13 from a total input of 12 would be an efficiency above 100 per cent, so the calculator declines the combination in words instead of printing a figure. The simulator's slider stops at the input, so this state is unreachable there.For the method rather than the arithmetic — eight worked problems, the energy form against the power form, the chain diagram and the two wrong ways to combine one — read the efficiency formula guide, which this tool is the calculating half of. The energy conversion examples guide is the page that handed this question over, and the conservation of energy guide is where the ceiling comes from.
Four more guides pick up what this page leaves out. The mechanical advantage guide and the Carnot efficiency guide own the two neighbouring quantities that are also called efficiency, the guide to power in physics is where the watts come from, and the specific heat capacity guide is where the kettle problem gets its stated given.
Four tools sit next to this one. The work and power calculator and the power calculator produce the two figures this page divides; the mechanical advantage calculator and the Carnot efficiency calculator compute the two efficiencies this one deliberately does not.
The full physics lab library and calculator index are open too.
It solves the efficiency formula in three directions and then does one more job. Give it a useful output and a total input and it returns the efficiency as a percentage; give it an efficiency and either figure and it returns the other; and switch the menu to the chain and it multiplies four stage efficiencies into one overall figure. Beside every answer it prints the efficiency as a fraction, the useful output, the total input, what was wasted and what share of the input that waste was.
Because efficiency is a ratio of two quantities of the same kind, so whatever unit you measured them in cancels before the division is done. Joules over joules and watts over watts give the identical number, and doubling both figures changes nothing at all. Enter both in one unit of your own choosing - joules, kilojoules, watts, kilowatt hours - and the answer is the same. A single unit menu holding both joules and watts would be wrong, because those two have no common base, so none is offered.
Yes, and exactly rather than nearly. If you measure both the useful output and the total input over the same interval, that interval appears in the numerator and the denominator of the same fraction and cancels. A lamp at 9 watts useful out of 12 watts in is 75.00 per cent, and over 60 seconds that is 540.0 joules useful out of 720.0 joules in, which is also 75.00 per cent. The independent reference this cluster is checked against measures the cancellation rather than assuming it.
Because the answer would be an efficiency above 100 per cent, and no device can deliver more of something useful than was supplied to it in the first place. That is conservation of energy, not a limit of the arithmetic. The page declines the entry in words rather than printing a figure above 100, and this is the one refusal the simulator cannot show you, because its slider stops at the input. The boundary case where the useful output exactly equals the input is allowed, and returns exactly 100 per cent for an ideal lossless device.
In one direction yes and in the other no, and the asymmetry is worth understanding. A device that wastes everything is a real device, so asking for the useful output at an efficiency of zero returns exactly zero and is answered normally. Asking for the total input at an efficiency of zero is refused, because that direction divides by the efficiency and a device that delivers nothing tells you nothing about what went into it. A zero useful output is refused in that same direction, because the answer would be a total input of zero.
Because each stage takes as its input whatever the stage before it managed to pass on. Two stages at 80 per cent and 90 per cent leave 0.8 times 0.9, which is 72.00 per cent, not 170 per cent and not the average of 85.00 per cent. Adding fractions can take you above 1, which cannot be an efficiency at all, and averaging ignores the fact that the first loss has already shrunk everything that follows. The calculator prints both wrong answers beside the right one so the difference is visible rather than asserted.
No, and the most it can ever manage is to equal that stage. Multiplying by a number below 1 can only make a result smaller, so every further stage under 100 per cent pulls the product down again: four stages at 38, 96, 92 and 88 per cent give 29.53 per cent overall, below the 38.00 per cent stage that is already the worst of them. The overall figure draws level with the worst stage in only two situations - when every other stage sits at exactly 100 per cent, which means those stages are not really there, and when one stage sits at zero and takes the whole chain down with it. That is why the one bad stage sets the scale of the whole chain, and why finding it is usually worth more than improving any of the others.
The fractions, every time. A percentage you have already printed has been rounded to two decimal places, and multiplying a rounded figure carries that rounding into the result. Two thirds times 0.850 is 56.67 per cent worked from the fractions and 56.70 per cent worked from a printed 66.7 per cent - a gap of 0.0283 percentage points, invisible in the first decimal and wrong in the second. This calculator multiplies the full-precision fractions and formats once, at the end, which is why the chain mode asks for stages rather than for percentages you typed back in.
They are the same number to four significant figures. The shared calculator engine formats the headline with trailing zeros dropped, so an efficiency of exactly three quarters prints as 75 while the working and the readings keep the house two-decimal form. Nothing is rounded twice: every figure on the page is formatted once from the full-precision value behind it. An efficiency is never printed to three significant figures here, because that form can bury a real loss: a fraction of 0.99949 reads 99.95 per cent at the house two decimal places but 99.9 at three significant figures, and the device is still throwing away 0.00051 of its input in both.
No. Every figure on this page is an arithmetic exercise with stated givens, and none of them describes any manufacturer, model, standard or measured industry figure. The lamp at 75.00 per cent, the kettle at 88.00 per cent and the hoist at 72.67 per cent are there because they produce clean arithmetic, not because anything was measured. If you need a real efficiency for a real device, verify it against the device before you use it.
There is no temperature-driven ceiling for a heat engine and no coefficient of performance formula; both belong to the Carnot efficiency guide and its own calculator, and this page only notes in one sentence that a heat engine carries a further ceiling on top of the general one. There is no ratio of two mechanical advantages either, which is the mechanical advantage guide's quantity. There is no taxonomy of the ways energy moves, no list of transfer pathways and no significant-figure arithmetic: the page does one division, two rearrangements of it and one product, and stops.