Kinematics

What Is Acceleration in Physics?

Definition

Acceleration in physics is the rate at which an object’s velocity changes with time. It is calculated as a = Δv/Δt — the change in velocity divided by the time taken — and measured in metres per second squared (m/s²). Because velocity includes direction, speeding up, slowing down and turning all count as acceleration.

Feel that push into your seat as a plane begins its take-off run? That is acceleration making itself felt — your velocity is climbing by several metres per second, every second, and your body registers every one of them.

A speedometer tells you how fast you are going. Acceleration tells you how quickly “how fast” is changing — and once that one idea clicks, half of mechanics falls into place.

What Is Acceleration in Physics?

Hold the idea this way: speed describes how quickly your position changes; acceleration describes how quickly your velocity changes. A cruising airliner doing 900 km/h in a straight line has zero acceleration. A sprinter exploding off the blocks — moving far slower — has plenty.

Formally, acceleration is the rate of change of velocity with time. It is a vector: it has a size and a direction, and both matter.

Average vs instantaneous acceleration

Average acceleration takes the total change in velocity and divides it by the total time — ideal for whole journeys. Instantaneous acceleration is the value at one exact moment, found by shrinking that time interval until it is vanishingly small.

If you go on to calculus, you will meet the instantaneous version as a = dv/dt, the derivative of velocity with respect to time. In a first physics course, the average form does almost all of the work.

The Acceleration Formula (and What m/s² Means)

Everything starts from one definition. Memorise this and you can rebuild the rest.

a = Δv / Δt = (v − u) / t
SymbolMeaningSI unit
aaccelerationmetres per second squared (m/s²)
Δvchange in velocity (v − u)metres per second (m/s)
uinitial velocitym/s
vfinal velocitym/s
t (Δt)time taken for the changeseconds (s)
sdisplacement (used below)metres (m)

So what does m/s² actually mean? Read it as “(metres per second) per second”: an acceleration of 3 m/s² adds 3 m/s of velocity during every second that passes. One second in, you have gained 3 m/s; two seconds in, 6 m/s.

The constant-acceleration toolkit

Rearrange the definition and you get the most-used equation in kinematics — final velocity from initial velocity, acceleration and time:

v = u + at

And when you know the distance but not the time, this companion equation — valid only while acceleration is constant — closes the gap:

v² = u² + 2as
  • s is the displacement in metres (m); all other symbols are exactly as in the table above.
  • Both equations assume uniform acceleration — a straight line on a velocity–time graph.

Reading acceleration from a velocity–time graph

Plot velocity against time and acceleration stops being abstract: it is simply the slope of the line. A straight line means constant acceleration; a horizontal line means none at all.

Δt = 2 s Δv = 6 m/s slope = Δv ÷ Δt = 3 m/s² = the acceleration 0 2 4 6 8 0 6 12 18 24 time (s) velocity (m/s)

On a velocity–time graph, acceleration is the slope: this line climbs 6 m/s every 2 s, so a = 3 m/s².

This is the car from Worked Problem 1 below: 0 to 24 m/s in 8 seconds. Pick any triangle on the line and rise over run gives the same answer — 3 m/s².

How Acceleration Works: Speed, Direction and Vectors

Velocity is a vector — a speed plus a direction. Change either ingredient and you have accelerated. That single fact unifies three situations students often treat as separate.

Speeding up and slowing down

When acceleration points the same way as velocity, the object speeds up. When it points the opposite way — brakes, or friction dragging on a sliding box — it slows down. Everyday language calls the slowing case deceleration, but to a physicist it is simply acceleration with a negative sign along the chosen direction.

Changing direction counts too

Here is the one that catches nearly everyone: an object turning at constant speed is still accelerating, because its direction — and therefore its velocity — is changing. For motion in a circle, the acceleration points toward the centre and has size:

a = v² / r
  • a — centripetal acceleration, directed toward the centre of the circle (m/s²)
  • v — speed along the circular path (m/s)
  • r — radius of the circle (m)

That centre-pointing pull is the sideways press you feel on a roundabout. The speedometer never moves — yet you accelerate the whole way round.

Speeding up v a a points with v Braking v a a points against v Turning, constant speed v a a points to the centre

Three faces of one quantity: acceleration is any change in velocity — magnitude, direction, or both.

Sliders beat sentences here. Set an initial velocity and an acceleration below, press run, and watch the velocity–time line draw itself — the slope is exactly the acceleration you chose.

Acceleration Lab

Acceleration vs Velocity: What’s the Difference?

Velocity is where your motion stands right now; acceleration is where it is heading. Confusing the two is the single most common error in introductory mechanics, so it pays to nail the distinction once and for all.

If speed vs velocity is still fuzzy, start with our guide to velocity vs speed — this comparison builds directly on it.

VelocityAcceleration
Definitionrate of change of positionrate of change of velocity
Formuladisplacement ÷ timechange in velocity ÷ time
SI unitm/sm/s²
Vector?yes — magnitude and directionyes — magnitude and direction
Zero when…the object is (momentarily) at restvelocity is constant — steady speed in a straight line
On the roadthe speedometer reading, plus your headingthe push you feel — throttle, brakes, corners

One classic trap: a ball thrown straight up has zero velocity at the very top of its flight — yet its acceleration there is still 9.81 m/s² downward. Velocity can pass through zero while acceleration carries on regardless.

Acceleration Due to Gravity

Drop anything near Earth’s surface and — air resistance aside — it gains speed at the same steady rate: about 9.81 m/s², a value so important it earns its own symbol, g. One second into free fall you are moving at roughly 9.8 m/s; two seconds in, 19.6 m/s.

g is not perfectly uniform. It runs from about 9.78 m/s² at the equator to about 9.83 m/s² at the poles, which is why exam papers happily round it to 9.8 — or even 10 — m/s².

Mass makes no difference: a hammer and a feather fall together in vacuum, as the Apollo 15 crew famously demonstrated on the Moon, where g is only about 1.6 m/s². And once gravity pulls a ball sideways as well as down, you are into projectile motion.

Real-World Examples of Acceleration

Numbers turn a definition into intuition. Here are five accelerations you have personally felt, with realistic magnitudes.

Sprinter accelerating off the starting blocks — real-world acceleration in physics
Off the blocks, a sprinter’s velocity climbs by several metres per second every second.
  • Pulling away from the lights: a family car reaching 100 km/h (27.8 m/s) in about 9 s averages roughly 3 m/s² — brisk but comfortable.
  • An emergency stop: good tyres on a dry road can decelerate a car at 8–9 m/s², close to the strength of gravity itself.
  • A lift setting off: that brief heavy-in-the-knees moment is only about 1 m/s² — small, but your inner ear notices instantly.
  • Cornering at a steady 25 m/s around a 125 m bend produces a centripetal acceleration of 5 m/s², aimed at the centre — constant speed, genuine acceleration.
  • Your phone, constantly: its accelerometer chip senses accelerations to rotate the screen and count your steps. Physics in your pocket.
SituationTypical acceleration
Passenger lift setting off≈ 1 m/s²
Family car, brisk pull-away≈ 3 m/s²
Hard emergency braking, dry road≈ 8–9 m/s²
Free fall near Earth’s surface9.81 m/s²
Crewed rocket launch (held to ~3g for the crew)≈ 29 m/s²
Formula 1 car under heavy braking (~5g)≈ 50 m/s²

Keep this table as a sanity check. If your homework answer says a pushbike accelerates at 60 m/s², it has just out-braked a Formula 1 car — go hunting for the slipped unit or sign.

Common Misconceptions About Acceleration

“Acceleration just means speeding up”

It means any change in velocity. Slowing down is acceleration directed against the motion, and turning is acceleration directed sideways. The speedometer can sit perfectly still while you accelerate around an entire roundabout.

“Zero velocity means zero acceleration”

A ball at the top of its throw is momentarily stationary, yet gravity accelerates it at 9.81 m/s² the whole time — which is precisely why it does not stay up there. Velocity describes the instant; acceleration describes the trend.

“Heavier objects fall faster”

Remove air resistance and a bowling ball and a feather accelerate identically at g. Heavier objects do feel a larger gravitational force, but they also need more force to accelerate — and the two effects cancel exactly.

“A negative acceleration always means slowing down”

The sign only tells you the direction relative to the axis you chose as positive. An object already moving in the negative direction with a negative acceleration is speeding up. Always read the sign against the velocity, never on its own.

How Acceleration Relates to Force and Newton’s Laws

So far we have described acceleration; Newton tells us what causes it — a net force. His second law is the bridge between the two ideas:

F = ma
  • F — net (resultant) force, in newtons (N)
  • m — mass, in kilograms (kg)
  • a — acceleration, in metres per second squared (m/s²)

Read it both ways. A larger net force means proportionally more acceleration; more mass means proportionally less — mass is, quite literally, resistance to being accelerated. One newton is defined as the force that accelerates 1 kg at exactly 1 m/s².

In practice the force you apply is rarely the net force: friction and air resistance push back, and only the leftover accelerates the object. For the full story, see our guides to Newton’s second law and all three of Newton’s laws of motion.

Worked Problems

These climb from the bare definition up to a force calculation. Cover the solutions and attempt each one first — that is where the learning happens.

Problem 1
A car pulls away from traffic lights and reaches 24 m/s from rest in 8.0 s. What is its average acceleration?
Show Solution
Solution: Step 1: Acceleration is change in velocity over time: a = (v − u) / t. Step 2: Substitute: a = (24 m/s − 0 m/s) / 8.0 s. Step 3: Solve: a = 24 / 8.0 = 3.0 m/s². Answer: 3.0 m/s² in the direction of travel
Problem 2
A cyclist travelling at 12 m/s brakes and comes to rest in 4.0 s. Find the acceleration and interpret its sign.
Show Solution
Solution: Step 1: a = (v − u) / t with v = 0 m/s, u = 12 m/s, t = 4.0 s. Step 2: Substitute: a = (0 m/s − 12 m/s) / 4.0 s. Step 3: Solve: a = −12 / 4.0 = −3.0 m/s². Answer: −3.0 m/s² — magnitude 3.0 m/s², directed opposite to the motion (a deceleration)
Problem 3
A train moving at 6.0 m/s accelerates uniformly at 0.80 m/s² for 15 s. What is its final velocity?
Show Solution
Solution: Step 1: Use v = u + at. Step 2: Substitute: v = 6.0 m/s + (0.80 m/s² × 15 s). Step 3: Solve: v = 6.0 + 12 = 18 m/s. Answer: 18 m/s
Problem 4
A car accelerates from rest to 108 km/h in 6.0 s. Find its average acceleration in m/s².
Show Solution
Solution: Step 1: Convert units first: 108 km/h × (1000 m / 3600 s) = 30 m/s. Step 2: Apply a = (v − u) / t = (30 m/s − 0 m/s) / 6.0 s. Step 3: Solve: a = 30 / 6.0 = 5.0 m/s². A common student slip is skipping the conversion and dividing 108 by 6 — always work in m/s before applying the formula. Answer: 5.0 m/s²
Problem 5
A stone is dropped from rest off a high cliff. Taking g = 9.81 m/s² and ignoring air resistance, find (a) its speed and (b) the distance fallen after 2.5 s.
Show Solution
Solution: Step 1: For (a), use v = u + at with u = 0, a = g: v = 9.81 m/s² × 2.5 s = 24.5 m/s. Step 2: For (b), use s = ut + ½at² with u = 0: s = ½ × 9.81 m/s² × (2.5 s)². Step 3: Solve: s = 0.5 × 9.81 × 6.25 = 30.7 m. Answer: (a) 24.5 m/s downward; (b) 30.7 m (both to 3 s.f.)
Problem 6
A car travelling at 20 m/s brakes uniformly and stops in a distance of 50 m. What is its acceleration?
Show Solution
Solution: Step 1: No time given, so use v² = u² + 2as. Step 2: Substitute: 0² = (20 m/s)² + 2 × a × 50 m, so 0 = 400 + 100a. Step 3: Solve: a = −400 / 100 = −4.0 m/s². Answer: −4.0 m/s² — a deceleration of 4.0 m/s²
Problem 7
A car rounds a bend of radius 125 m at a constant speed of 25 m/s. What is its acceleration?
Show Solution
Solution: Step 1: Constant speed on a curve means centripetal acceleration: a = v² / r. Step 2: Substitute: a = (25 m/s)² / 125 m = 625 / 125. Step 3: Solve: a = 5.0 m/s², directed toward the centre of the bend. Answer: 5.0 m/s² toward the centre of the curve
Problem 8
A 1,200 kg car accelerates from rest to 27 m/s in 9.0 s. Find the acceleration and the net force required.
Show Solution
Solution: Step 1: a = (v − u) / t = (27 m/s − 0 m/s) / 9.0 s = 3.0 m/s². Step 2: Apply Newton’s second law: F = ma = 1,200 kg × 3.0 m/s². Step 3: Solve: F = 3,600 N. In practice the engine must supply more than this, because drag and rolling resistance push back — 3,600 N is the net force. Answer: a = 3.0 m/s²; net force = 3,600 N (3.6 kN)

Frequently Asked Questions

What is acceleration in simple terms?
Acceleration is how quickly velocity changes. If a car gains 3 metres per second of speed every second, its acceleration is 3 m/s². Slowing down and changing direction count too, because both change velocity. The bigger the change in velocity — or the shorter the time it happens in — the larger the acceleration.
How do you calculate acceleration?
Divide the change in velocity by the time taken: a = (v − u) / t, where v is final velocity, u is initial velocity and t is time. For example, going from 4 m/s to 16 m/s in 3 s gives a = (16 − 4) / 3 = 4 m/s². Keep velocities in m/s and time in seconds for SI units.
Can acceleration be negative?
Yes. A negative sign means the acceleration points opposite to the direction you chose as positive. A car slowing from 12 m/s to rest in 4 s has a = −3 m/s². Be careful, though: negative acceleration only means “slowing down” when the object moves in the positive direction — it can equally mean speeding up the other way.
Is acceleration a vector or a scalar?
Acceleration is a vector: it has both magnitude and direction. Two cars can each accelerate at 5 m/s² yet behave completely differently if one points north and the other east. Direction matters in calculations too — it is why slowing down carries a negative sign, and why circular motion at constant speed still counts as accelerating.
Can something accelerate without changing speed?
Yes — by changing direction. Velocity includes direction, so an object moving in a circle at constant speed accelerates the whole time, with the acceleration pointing toward the centre of the circle and a magnitude of a = v²/r. This centripetal acceleration is the sideways press you feel going round a roundabout.
What is the acceleration due to gravity on Earth?
Near Earth’s surface, objects in free fall accelerate downward at about 9.81 m/s², a value physicists call g. It varies slightly with location — roughly 9.78 m/s² at the equator to 9.83 m/s² at the poles — and exam boards often round it to 9.8 or 10 m/s². Without air resistance, every object falls with the same g.
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