Angular momentum is how much rotation an object carries about a stated axis: the moment of inertia about that axis times the spin rate, L = Iω, which for a single mass on a circle comes to L = mvr. This free angular momentum calculator evaluates both forms at one state, rearranges them for the spin rate, the moment of inertia or the speed, and prints the rotational energy and the turn time beside the answer.
Each button puts the Calculate toggle on the arrangement it needs, sets every unit menu back to SI and fills only that arrangement's boxes. Whatever the widget then works out is read back into the line underneath, so nothing there is stored text.
Pick a case above, or type your own numbers.

The angular momentum calculator is a free online tool built on the formula L = Iω, which for a single mass going round a circle is the same quantity written L = mvr. Enter a moment of inertia and a spin rate, or a mass, a speed and a radius, and it returns the angular momentum with every step of the substitution; three more arrangements give back the spin rate, the moment of inertia or the speed instead. Beside the answer it prints the moment of inertia behind it, that spin rate in both rad/s and rpm, the kinetic energy of the rotation and the time for one turn.
| Symbol | Quantity | Default unit | Also accepts | Example value |
|---|---|---|---|---|
| L | Angular momentum | kg·m²/s | g·cm²/s | 14.6 |
| I | Moment of inertia | kg·m² | g·cm² | 5.84 |
| ω | Angular velocity | rad/s | rev/s, rpm, deg/s | 2.5 |
| m | Mass | kg | g, t | 3 |
| v | Speed | m/s | km/h, cm/s | 2 |
| r | Radius | m | cm, mm, km | 0.8 |
The moment of inertia is the input most people have to find first, because it depends on shape as well as mass. A ring, a disc and a sphere of the same mass and radius all have different values, which is what the moment of inertia calculator is for; the guide to moment of inertia sets out where each shape factor comes from. Feed its answer straight into the first box here.
The spin rate has to be in radians per second before it multiplies anything, which is the second common stumble. A wheel quoted at 500 rpm is not turning at 500 rad/s, so either pick rpm from the menu and let the tool convert, or convert first with the angular velocity calculator; the angular velocity formula explained covers the radian-per-second convention in full. The extras always report the rate both ways so the conversion is visible.
The third slip is mixing the two arrangements in one sum. L from inertia and spin describes a whole body about its axis; L from mass, speed, radius describes one point mass on one circle. Adding a whole system's L to one of its own parts double-counts that part, and the worked table below shows the two figures side by side so the difference is obvious.
The table below starts at the defaults and moves one thing at a time: the arrangement, then the units, then which quantity is the unknown. Each Result and Rotation energy cell was copied out of the running widget rather than worked out by hand, so where a cell and the tool ever part company, believe the tool. A dash marks a box the chosen arrangement does not show.
| Step | What the toggle is on | Moment of inertia | Spin rate | Mass, speed and radius | Angular momentum | Result | Rotation energy |
|---|---|---|---|---|---|---|---|
| Open the page on its defaults | L from inertia and spin | 5.84 kg·m² | 2.5 rad/s | — | — | 14.6 kg·m²/s | 18.25 J |
| Switch to one mass on a circle | L from mass, speed, radius | — | — | 3 kg, 2 m/s, 0.8 m | — | 4.8 kg·m²/s | 6.000 J |
| Ask for the spin rate with the arms in | Spin rate | 2.24 kg·m² | — | — | 14.6 kg·m²/s | 6.518 rad/s | 47.58 J |
| Retype the same inertia in g·cm² | L from inertia and spin | 5.84e7 g·cm² | 2.5 rad/s | — | — | 14.6 kg·m²/s | 18.25 J |
| Ask for the speed of that one mass | Speed | — | — | 3 kg, 0.8 m | 4.8 kg·m²/s | 2 m/s | 6.000 J |
| Ask for the inertia that spin implies | Moment of inertia | — | 6.518 rad/s | — | 14.6 kg·m²/s | 2.24 kg·m² | 47.58 J |
| Put the arms-in state back in the first arrangement | L from inertia and spin | 2.24 kg·m² | 6.518 rad/s | — | — | 14.6 kg·m²/s | 47.58 J |
| Feed the one-mass extras back in | Spin rate | 1.920 kg·m² | — | — | 4.8 kg·m²/s | 2.5 rad/s | 6.000 J |
Rows 1 and 2 are the two ways of writing the same idea, applied to two different objects. The whole system carries 14.6 kg·m2/s; one of the two 3 kg masses on its rim carries 4.8 kg·m2/s of that total. Two such masses account for 9.600 kg·m2/s of it, and the turntable underneath them carries the remaining 5.000.
Rows 3 and 4 change the question and then the units. Asking for the spin rate that 14.6 kg·m2/s implies on 2.24 kg·m2 returns 6.518 rad/s, the figure the simulator reaches when the masses come in to 0.2 m. Retyping the original 5.84 kg·m2 as 5.84e7 g·cm2 changes nothing at all, because the menu converts and the physics does not care which unit you thought in.
Rows 5 and 6 solve backwards and land exactly where rows 1 and 2 started: 2 m/s for the mass, and 2.24 kg·m2 for the inertia. That round trip is the check worth doing whenever an answer looks surprising. Rows 7 and 8 close the last two loops — the arms-in pair multiplied out gives 14.6 kg·m2/s again, and the 1.920 kg·m2 the extras report as the inertia behind one mass, typed back in beside that mass's own 4.8 kg·m2/s, returns it to 2.5 rad/s.
Rotation energy is the column that does not stay put. The whole system reads 18.25 J at 2.5 rad/s and 47.58 J at 6.518 rad/s, for the same 14.6 kg·m2/s in both rows, and the difference of 29.33 J is work that has to be done by something. Watching where that work comes from is the job of the Angular Momentum Simulator, which moves the masses for you; this page only ever evaluates one state at a time, and those two rows were typed separately.
The calculator uses one relation in five arrangements: L = Iω, L = mvr, ω = L/I, I = L/ω and v = L/(mr). The extras come from L/ω, from ω itself, from ½Lω and from 2π/ω. No measured constant of nature enters any of them: apart from π in the period and in the rpm conversion, every figure here is arithmetic on the numbers you type.
| Symbol | Meaning | SI unit | Values used on this page |
|---|---|---|---|
| L | Angular momentum about the axis you name. The one quantity this page computes, however it is written | kilogram metre squared per second, kg·m2/s | Boxes take kg·m2/s or g·cm2/s: 14.6 for the whole system in the opening case, 4.8 for one mass on its rim. |
| I | Moment of inertia about that same axis: how the mass is spread out around it, not how much there is | kilogram metre squared, kg·m2 | Boxes take kg·m2 or g·cm2: 5.84 with the masses out at 0.8 m, 2.24 with them in at 0.2 m, 1.92 for one 3 kg mass at 0.8 m. |
| ω | Angular velocity, the spin rate. Radians per second internally, whatever the menu is set to | radian per second, rad/s | Boxes take rad/s, rev/s, rpm or deg/s: 2.5 rad/s in the opening case, which is 23.87 rpm, and 6.518 rad/s with the masses pulled in. |
| m | The mass being treated as a point on a circle, in the mass, speed and radius arrangement only | kilogram, kg | Boxes take kg, g or t: 3 kg for each of the two masses in the opening case. |
| v | Its speed along that circle. Related to the spin rate by v = ωr, which the working prints | metre per second, m/s | Boxes take m/s, km/h or cm/s: 2 m/s for a mass at 0.8 m turning at 2.5 rad/s. |
| r | The radius of that circle, measured from the axis the answer is quoted about | metre, m | Boxes take m, cm, mm or km: 0.8 m with the masses out, 0.2 m with them in. |
Take one mass m going round a circle of radius r at speed v. Its angular momentum about the centre is L = mvr, and its speed is tied to the spin rate by v = ωr. Substitute the second into the first and you get L = m(ωr)r = (mr2)ω, where mr2 is the moment of inertia of a point mass at radius r — so the two formulae are one formula written twice.
A real body is a great many such masses at a great many radii, so its moment of inertia is the sum of all their mr2 terms. That single number is what I stands for, and it is why the shape matters as much as the mass: move material outward and I grows as the square of the distance. The turntable in the opening case reads 5.84 kg·m2 with its two masses at 0.8 m and 2.24 kg·m2 with them at 0.2 m: only the masses move, so their 2mr2 share falls 16-fold from 3.84 to 0.24 kg·m2 while the 2.00 kg·m2 of the turntable itself stays put, which is why the total drops by 2.607 and not by 16.
What makes the quantity worth defining is that it only changes when something twists the object. With no net external torque about the axis, L stays put whatever the object does to itself — which is the argument behind every spinning-up skater, and the whole point of the full guide to angular momentum. Because I and ω must then trade off exactly, halving the moment of inertia doubles the spin rate.
The energy does not follow suit. KE = ½Iω2 = ½Lω, so at fixed L the energy rises in step with ω: the 2.607-fold spin-up between the two states above costs a 2.607-fold rise in rotational energy, from 18.25 to 47.58 J.
That extra 29.33 J is work done pulling the masses inward against the force that was holding them on their circles, and letting them back out returns it. Nothing is created, and the Angular Momentum Simulator is where you can watch the two bars move while the total stays where it was.
One more thing is worth saying plainly. Conservation is a statement about the net external torque being zero, not a promise about real objects: a real chair has bearing friction and a real skater has friction and air drag, and both slow down. This page never claims otherwise, because it never models a change at all.
mr2, and the spin rate and the period match the default state exactly, because it is the same turntable.Multiplying two numbers is hard to get wrong. What fails is the axis the numbers were measured about, the model the object is being squeezed into, or an expectation the arithmetic was never making.
mr2, which treats whatever you are holding as a point at distance r. A real dumbbell also has a moment of inertia of its own about its own centre, which this model ignores. The error is small while r is much larger than the object, and not otherwise.½Iω2 this page reports as the rotational energy. Doubling the spin rate quadruples the stored energy while only doubling the angular momentum, which is why the spin rate is the design lever.mvr. The same idea applied to a collapsing cloud is why compact remnants spin quickly. Momentum p = mv obeys a rule of the same shape when no outside force acts, which the conservation of momentum guide works through in a straight line.½mv2 from the kinetic energy calculator is a good way to see why that is not a contradiction.
For what the quantity means, why it is conserved and a set of worked problems, read Angular Momentum Explained. Take a shape to the moment of inertia calculator, a spin rate to the angular velocity calculator, or a twist to the torque calculator. To watch the trade-off happen instead of typing it, the Angular Momentum Simulator moves the masses for you, and the whole physics lab library is open beside it.
L = Iω for a body spinning about a symmetry axis, where I is the moment of inertia about that axis and ω is the angular velocity in radians per second. For a single mass going round a circle the same quantity is L = mvr, with v the speed along the circle and r the radius from the axis. They are not two laws: m·v·r = m·(ωr)·r = (m·r²)·ω, and m·r² is exactly the moment of inertia of a point mass at radius r.
Kilogram metre squared per second, kg·m²/s, in SI. A torque multiplied by a time, and an energy multiplied by a time, both land on that same combination, so N·m·s and J·s are the identical unit under other names. The calculator works in kg·m²/s throughout and also accepts g·cm²/s, which is 1e-7 of it. The joule second is also the unit of the Planck constant, which is a fact about units and not a quantum claim.
No, and it is worth being clear about that. This tool evaluates L at one state from the numbers you type; it never asks for a radius change and it conserves nothing. Conservation is what the simulator demonstrates, by moving two masses to a new radius and showing the same L coming out. A figure from this page and a figure from the simulator are the same arithmetic on the same numbers, not two independent results.
Because the two arrangements describe different objects. With 5.84 kg·m² at 2.5 rad/s you are describing a whole turntable and everything on it. With 3 kg at 2 m/s on 0.8 m you are describing one mass on that same turntable, whose own moment of inertia about the axis is m·r² = 1.920 kg·m². The extra always reports L divided by ω, so it answers for whatever object you just entered.
Yes, completely. One motion carries as many different angular momenta as there are points to measure it about, so a radius taken from the wrong point answers a different question from the one you asked. Every radius in the mass, speed and radius arrangement therefore has to come from the axis the answer is quoted about, and that axis belongs beside the value whenever you write it down.
All six quantities here are positive magnitudes, and four of them sit underneath a division in at least one arrangement, so a zero or a negative returns the message that the combination has no valid solution rather than an infinity. Text is handled differently, because every box is a number field: characters that cannot belong to a number are dropped as you type, so 2abc lands in the box as a plain 2 and is answered as 5 kg·m²/s against the default 2.5 rad/s. Anything with no number left in it, such as abc or a lone full stop, and anything pasted in that is not a number from end to end, empties the box instead, and the page asks you to fill it rather than answering. Check what the box is actually holding before you trust the answer; for the opposite sense of rotation, carry the sign yourself.
You can, provided you supply the moment of inertia yourself. Nothing on this page measures the moment of inertia of a person, a chair or a stool, and no number here is attached to a named real object. Enter a value you have measured or estimated and the arithmetic is exact; the answer is then only as good as that input.