Interactive Lab

Heat vs Temperature

Two beakers of water reach the same temperature — yet they absorb different amounts of energy, because heat scales with mass: Q = m c ΔT

Same ΔT · different mass → different heat

Liquid

Water c = 4,186 J/(kg·°C)

Mass

Beaker A2.0 kg
Beaker B0.5 kg

Temperature

Start20 °C
Change ΔT30 °C

Heat required (Q)

Beaker A —
Beaker B —

Comparison

A
—
B
—

Final temperature is identical in both beakers — only the heat differs.