{"id":767,"date":"2026-08-11T00:01:57","date_gmt":"2026-08-11T00:01:57","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=767"},"modified":"2026-08-24T13:03:45","modified_gmt":"2026-08-24T13:03:45","slug":"wave-speed-different-media","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/waves\/wave-speed-different-media\/","title":{"rendered":"Wave Speed in Different Media: Sound, Light and Strings"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\n \nWave speed is how fast a wave carries its energy through a medium, and it is set almost entirely by that medium rather than by whatever produced the wave. Sound travels at 343 m\/s in air but about 5,960 m\/s in steel, while light falls from 299,792,458 m\/s in a vacuum to roughly 124 million m\/s inside diamond.\n \n<\/p><\/div>\n \n<p>Watch a firework burst and you see it instantly, then wait \u2014 one, two, three \u2014 before the bang arrives. Both signals left the same point at the same moment. Only one of them was in a hurry.<\/p>\n \n<p>That gap is wave speed. Over a kilometre the light took about three microseconds; the sound needed nearly three seconds, because it had to shove air molecules along the way. Swap the material and both numbers change \u2014 and, strangely, they move in opposite directions.<\/p>\n \n<h2>What Is Wave Speed?<\/h2>\n \n<p>Wave speed is the distance a wave crest travels each second through a medium, measured in metres per second (m\/s). It describes how fast the disturbance moves, not how fast the material itself moves.<\/p>\n \n<p>That distinction trips up more students than any other part of the topic. When sound crosses a room at 343 m\/s, no air molecule makes that journey \u2014 each one jiggles back and forth by a fraction of a millimetre and passes the disturbance to its neighbour.<\/p>\n \n<p>Think of a stadium Mexican wave. The wave sweeps around the ground in seconds; every spectator simply stands up and sits down on the spot.<\/p>\n \n<p>So wave speed is a property of the <em>medium<\/em>, in the same way that density or stiffness is. Change the medium and you change the speed. Keep the medium fixed and the speed is essentially locked, no matter how the wave was made.<\/p>\n \n<h2>Wave Speed in Different Media: The Reference Table<\/h2>\n \n<p>Wave speed ranges from around 100 m\/s on a slack guitar string to 299,792,458 m\/s for light in a vacuum \u2014 a span of more than six orders of magnitude. The table below collects the values you are most likely to need, with the conditions that define them.<\/p>\n \n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;\">\n<thead>\n<tr style=\"background:#0A1628;color:#FAF6EE;\">\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Medium<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Wave<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Wave speed (m\/s)<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Conditions &amp; notes<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Guitar low-E string<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Transverse<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>about 107<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Tension 68 N, mass per metre 6.0 g\/m<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Carbon dioxide<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>268<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">20 \u00b0C; heavy molecules, so slower than air<\/td><\/tr>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Air<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>331<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">0 \u00b0C, dry \u2014 the freezing-point value<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Air<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>343<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">20 \u00b0C, dry \u2014 the standard exam value<\/td><\/tr>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Helium<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>1,007<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">20 \u00b0C; about 2.9 times faster than air<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Fresh water<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>1,482<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">20 \u00b0C; roughly 4.3 times the speed in air<\/td><\/tr>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Seawater<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>about 1,500<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Varies with depth, salinity and temperature<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Soft body tissue<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Ultrasound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>about 1,540<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">The value clinical scanners assume<\/td><\/tr>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Pyrex glass<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>about 5,640<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Bulk longitudinal wave<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Steel<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>about 5,960<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Bulk longitudinal; about 5,050 in a thin rod<\/td><\/tr>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Aluminium<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>about 6,420<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Bulk longitudinal wave<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Diamond<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Light<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>1.24 &times; 10<sup>8<\/sup><\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Refractive index n = 2.42<\/td><\/tr>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Crown glass<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Light<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>1.97 &times; 10<sup>8<\/sup><\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">n = 1.52 (varies with colour)<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Water<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Light<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>2.25 &times; 10<sup>8<\/sup><\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">n = 1.333<\/td><\/tr>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Air<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Light<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>2.997 &times; 10<sup>8<\/sup><\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">n = 1.0003; only 90 km\/s below vacuum speed<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Vacuum<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Light<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>299,792,458<\/strong><\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Exact by definition of the metre<\/td><\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n \n<p>Two patterns jump out of that table. Sound gets dramatically <em>faster<\/em> as you move from gas to liquid to solid, while light gets steadily <em>slower<\/em> as the material gets denser.<\/p>\n \n<p>The same word \u2014 denser \u2014 pushes the two families in opposite directions. Working out why is the whole point of the next two sections.<\/p>\n \n<figure class=\"pf-figure\" style=\"margin:1.6em 0;\"><img src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/08\/wave-speed-different-media-bar-comparing-guitar-string-sound.webp\" width=\"1440\" height=\"804\" alt=\"Bar chart comparing wave speed in different media: a guitar string and sound in air, helium, water and steel, then light in diamond, crown glass, water and vacuum on a separate scale\" loading=\"lazy\" decoding=\"async\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:0 auto;\" \/><\/figure>\n \n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:-6px;\">Wave speed across common media. Note the two rows use different scales \u2014 on a single axis, the light bars would be around 50,000 times longer than the steel bar.<\/p>\n \n<h2>The Wave Speed Formulas<\/h2>\n \n<p>Three equations cover almost every wave-speed problem you will meet. The first is universal; the other two tell you what the medium actually contributes.<\/p>\n \n<p>Start with the relationship every wave obeys, whatever it is made of:<\/p>\n \n<div class=\"pf-formula\">v = f \u03bb<\/div>\n \n<ul>\n<li><strong>v<\/strong> \u2014 wave speed, in metres per second (m\/s)<\/li>\n<li><strong>f<\/strong> \u2014 frequency, in hertz (Hz)<\/li>\n<li><strong>\u03bb<\/strong> \u2014 wavelength, in metres (m)<\/li>\n<\/ul>\n \n<p>Read this the right way round and it stops being misleading. The medium fixes <strong>v<\/strong>, the source fixes <strong>f<\/strong>, and <strong>\u03bb<\/strong> is whatever those two force it to be. If you need a refresher on the frequency side of that equation, our guide to the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/waves\/frequency-formula\/\">frequency formula<\/a> works through f = 1\/T and its variations.<\/p>\n \n<p>For light, the medium&#8217;s effect is bundled into a single number, the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/waves\/refractive-index\/\">refractive index<\/a>:<\/p>\n \n<div class=\"pf-formula\">v = c \/ n<\/div>\n \n<ul>\n<li><strong>v<\/strong> \u2014 speed of light in the medium (m\/s)<\/li>\n<li><strong>c<\/strong> \u2014 <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/modern-physics\/speed-of-light\/\">speed of light in a vacuum<\/a>, exactly 299,792,458 m\/s (<a href=\"https:\/\/www.nist.gov\/si-redefinition\/meet-constants\" target=\"_blank\" rel=\"noopener\">defined by NIST<\/a> as one of the seven constants that fix the SI)<\/li>\n<li><strong>n<\/strong> \u2014 refractive index of the medium, a pure number with no units, never less than 1<\/li>\n<\/ul>\n \n<p>And for a wave running along a stretched string or wire:<\/p>\n \n<div class=\"pf-formula\">v = sqrt(T \/ \u03bc)<\/div>\n \n<ul>\n<li><strong>v<\/strong> \u2014 wave speed along the string (m\/s)<\/li>\n<li><strong>T<\/strong> \u2014 tension in the string, in newtons (N)<\/li>\n<li><strong>\u03bc<\/strong> \u2014 mass per unit length, in kilograms per metre (kg\/m)<\/li>\n<\/ul>\n \n<p>Notice that neither v = c\/n nor v = sqrt(T\/\u03bc) contains a frequency term. That is not an accident \u2014 it is the clearest possible statement that the medium, not the source, is in charge. You can check any of these numbers against our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/wave-speed\">Wave Speed Calculator<\/a>, which rearranges v = f \u03bb for whichever quantity you are missing.<\/p>\n \n<h2>What Determines Wave Speed? Stiffness Versus Inertia<\/h2>\n \n<p>Wave speed in a mechanical medium is set by two competing properties: how hard the material springs back when you disturb it (stiffness) and how much mass has to be dragged along (inertia). Every mechanical wave speed is the square root of the first divided by the second.<\/p>\n \n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;\">\n<thead>\n<tr style=\"background:#0A1628;color:#FAF6EE;\">\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Wave<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Formula<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">The &#8220;springiness&#8221;<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">The &#8220;sluggishness&#8221;<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound in a gas<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">v = sqrt(\u03b3RT \/ M)<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Temperature T and the ratio \u03b3<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Molar mass M (kg\/mol)<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound in a liquid<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">v = sqrt(K \/ \u03c1)<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Bulk modulus K (Pa)<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Density \u03c1 (kg\/m<sup>3<\/sup>)<\/td><\/tr>\n<tr><td style=\"padding:9px;border:1px solid #D9CFB8;\">Sound in a thin solid rod<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">v = sqrt(E \/ \u03c1)<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Young&#8217;s modulus E (Pa)<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Density \u03c1 (kg\/m<sup>3<\/sup>)<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:9px;border:1px solid #D9CFB8;\">Wave on a string<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">v = sqrt(T \/ \u03bc)<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Tension T (N)<\/td><td style=\"padding:9px;border:1px solid #D9CFB8;\">Mass per length \u03bc (kg\/m)<\/td><\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n \n<p>Now the water-versus-air puzzle solves itself. Water is about 830 times denser than air, which should make it far slower \u2014 but water is roughly 15,000 times stiffer, and stiffness wins because both sit under the same square root.<\/p>\n \n<p>Run the numbers as a sanity check. Water&#8217;s bulk modulus is about 2.2 GPa and its density about 998 kg\/m<sup>3<\/sup>, so v = sqrt(2.2 \u00d7 10<sup>9<\/sup> \u00f7 998) = 1,485 m\/s \u2014 within 0.2% of the measured 1,482 m\/s.<\/p>\n \n<p>The same logic explains helium. A helium atom is seven times lighter than an average air molecule, so there is far less inertia to move, and sound races through at roughly 1,007 m\/s. NASA&#8217;s Glenn Research Center sets out <a href=\"https:\/\/www.grc.nasa.gov\/www\/k-12\/VirtualAero\/BottleRocket\/airplane\/sound.html\" target=\"_blank\" rel=\"noopener\">the full gas derivation<\/a> if you want the algebra.<\/p>\n \n<p>Solids complicate things pleasantly: they resist both squeezing and shearing, so they carry two sound speeds at once. That is why a single &#8220;speed of sound in steel&#8221; figure always needs a footnote \u2014 and why <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/waves\/transverse-vs-longitudinal-waves\/\">transverse and longitudinal waves<\/a> travel at different speeds through the same block of metal.<\/p>\n \n<p>Light refuses to play this game. It needs no medium at all, and inside matter it slows because the oscillating field keeps being absorbed and re-radiated by bound electrons \u2014 a delay, not a drag. So for light the rule inverts: more electrons packed more tightly means a higher refractive index and a <em>lower<\/em> speed.<\/p>\n \n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Wave Speed Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/wave-speed.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n \n<h2>Wave Speed on a String: v = sqrt(T \/ mu)<\/h2>\n \n<p>The speed of a wave on a string depends only on how tightly it is stretched and how heavy it is per metre \u2014 never on how hard you pluck it or how fast you shake it. Tighten the string and the wave speeds up; use a thicker string and it slows down.<\/p>\n \n<p>Both effects live under a square root, and that square root is where marks get lost. Doubling the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/tension-force\/\">tension in the string<\/a> does not double the speed \u2014 it multiplies it by sqrt(2), about 1.41.<\/p>\n \n<p>To genuinely double the wave speed you must <strong>quadruple<\/strong> the tension.<\/p>\n \n<p>You can hear this on any guitar. The six strings share almost the same length and similar tensions, so the low, thick strings sound low mainly because their larger \u03bc drags the wave speed down.<\/p>\n \n<p>In practice, a wound low-E string with \u03bc of about 6.0 g\/m under about 68 N of tension carries waves at roughly 107 m\/s. Fret it halfway and you halve the wavelength; the speed is unchanged, so the frequency doubles and you hear the octave.<\/p>\n \n<h2>What Changes When a Wave Crosses into a New Medium?<\/h2>\n \n<p>When a wave passes into a new medium its frequency stays exactly the same, its speed changes to whatever the new medium dictates, and its wavelength changes by the same factor as the speed. Frequency is set at the source and cannot be altered by the material.<\/p>\n \n<p>The reasoning is almost embarrassingly simple. Crests arrive at the boundary 256 times a second, so crests must leave it 256 times a second \u2014 otherwise they would pile up at the interface.<\/p>\n \n<p>Since v = f \u03bb and f is pinned, any change in v forces an identical change in \u03bb.<\/p>\n \n<figure class=\"pf-figure\" style=\"margin:1.6em 0;\"><img src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/08\/wave-speed-different-media-boundary-256-hz-crossing-air.webp\" width=\"1440\" height=\"640\" alt=\"Diagram of wave speed at a boundary: a 256 Hz wave crossing from air into water keeps the same frequency while its speed and wavelength both increase\" loading=\"lazy\" decoding=\"async\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:0 auto;\" \/><\/figure>\n \n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:-6px;\">A 256 Hz wave crossing from air into water: the frequency is identical on both sides, while the speed and the wavelength both rise by a factor of 4.3.<\/p>\n \n<p>This is the mechanism behind refraction. A wavefront striking a boundary at an angle has one edge slowing down before the other, so the whole front pivots \u2014 which is exactly why a straw looks broken at the surface of a glass of water.<\/p>\n \n<h2>Real-World Examples of Wave Speed<\/h2>\n \n<h3>1. Timing a thunderstorm<\/h3>\n \n<p>Light reaches you almost instantly, so the delay before the thunder is essentially the sound&#8217;s whole journey. At 343 m\/s, three seconds means roughly one kilometre \u2014 the old &#8220;count the seconds and divide by three&#8221; rule, and it is genuinely accurate.<\/p>\n \n<h3>2. Sonar and echo sounding<\/h3>\n \n<p>Ships map the seabed by timing a pulse&#8217;s round trip at about 1,500 m\/s. Because speed varies with temperature, salinity and depth, sound rays bend as they travel \u2014 creating the deep <a href=\"https:\/\/oceanservice.noaa.gov\/facts\/sound.html\" target=\"_blank\" rel=\"noopener\">sound channel NOAA describes<\/a>, in which whale calls carry for thousands of kilometres.<\/p>\n \n<h3>3. Medical ultrasound<\/h3>\n \n<p>A scanner converts echo delays into depths by assuming soft tissue carries sound at 1,540 m\/s. Every pixel position in the image depends on that single number being right.<\/p>\n \n<h3>4. Fibre-optic internet<\/h3>\n \n<p>Light in a glass fibre travels at roughly two-thirds of its vacuum speed, near 2.0 \u00d7 10<sup>8<\/sup> m\/s. That deficit is why a London-New York round trip cannot beat about 56 milliseconds, no matter how good the hardware is.<\/p>\n \n<h3>5. Earthquake early warning<\/h3>\n \n<p>Longitudinal P-waves outrun transverse S-waves through rock, typically about 6 km\/s against 3.5 km\/s. Warning systems detect the harmless P-wave first and issue an alert seconds before the destructive S-wave arrives.<\/p>\n \n<h2>Common Misconceptions About Wave Speed<\/h2>\n \n<h3>&#8220;Denser media always slow a wave down&#8221;<\/h3>\n \n<p>This is the single most common error, and the table above demolishes it \u2014 sound is more than seventeen times faster in steel than in air. Density does slow mechanical waves, but only when stiffness is held constant, and moving from gas to solid raises stiffness far more than density.<\/p>\n \n<p>Compare two metals instead and the rule reappears: lead is denser than aluminium and carries sound more slowly.<\/p>\n \n<h3>&#8220;Raising the frequency makes the wave travel faster&#8221;<\/h3>\n \n<p>Frequency and speed are independent for ordinary waves in ordinary media. Raise the frequency and the wavelength shrinks to compensate, leaving v = f \u03bb satisfied and v untouched.<\/p>\n \n<p>There is a neat proof in everyday life: an orchestra 50 metres away arrives in time. If high notes outran low ones, distant music would reach you scrambled.<\/p>\n \n<h3>&#8220;Wave speed is how fast the particles move&#8221;<\/h3>\n \n<p>Particle speed and wave speed are entirely different quantities. In normal conversation, air molecules oscillate at a fraction of a millimetre per second while the sound wave itself sprints along at 343 m\/s.<\/p>\n \n<h3>&#8220;Doubling the tension doubles the speed on a string&#8221;<\/h3>\n \n<p>It multiplies the speed by about 1.41, because tension sits inside a square root. This is also why tuning a guitar up by an octave requires four times the tension \u2014 a jump most strings will not survive.<\/p>\n \n<h2>How Wave Speed Relates to Frequency, Refraction and the Doppler Effect<\/h2>\n \n<p>Wave speed is the hinge that connects several topics that look separate on a syllabus. Once you know v is fixed by the medium, the rest tends to fall into place.<\/p>\n \n<p>Frequency and wavelength are the two quantities that must adjust around it, which is why v = f \u03bb appears in nearly every wave question. Refraction is simply what happens when v changes at a boundary and the wavefront pivots.<\/p>\n \n<p>The <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/waves\/doppler-effect\/\">Doppler effect<\/a> depends on wave speed too, but in a subtler way \u2014 the source&#8217;s motion shifts the observed frequency <em>relative to<\/em> a wave speed that stays constant in the medium. That is precisely why a passing siren changes pitch without the sound ever changing speed.<\/p>\n \n<h2>Worked Problems<\/h2>\n \n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">You see a lightning flash and hear the thunder 3.0 s later. Taking the speed of sound in air as 343 m\/s, how far away was the strike?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Light arrives almost instantly, so the 3.0 s is the sound&#8217;s travel time. Use distance = v \u00d7 t.<\/p>\n<p>Step 2: Substitute with units: distance = 343 m\/s \u00d7 3.0 s.<\/p>\n<p>Step 3: Solve: distance = 1,029 m.<\/p>\n<p><strong>Answer: about 1.0 km (1,029 m)<\/strong><\/p>\n<\/div><\/details><\/div>\n \n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A 256 Hz tuning fork sounds in air (v = 343 m\/s) and then underwater (v = 1482 m\/s). Find the wavelength in each medium.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Rearrange v = f \u03bb to give \u03bb = v \/ f. The frequency is set by the fork, so it is 256 Hz in both media.<\/p>\n<p>Step 2: In air, \u03bb = 343 m\/s \u00f7 256 Hz = 1.34 m.<\/p>\n<p>Step 3: In water, \u03bb = 1482 m\/s \u00f7 256 Hz = 5.79 m.<\/p>\n<p><strong>Answer: 1.34 m in air and 5.79 m in water \u2014 a factor of 4.32, exactly the ratio of the two speeds<\/strong><\/p>\n<\/div><\/details><\/div>\n \n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A ship&#039;s sonar pulse returns 0.40 s after transmission. Taking the speed of sound in seawater as 1500 m\/s, how deep is the water?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: The pulse travels down and back, so it covers twice the depth. Depth = v \u00d7 t \u00f7 2.<\/p>\n<p>Step 2: Substitute with units: depth = 1500 m\/s \u00d7 0.40 s \u00f7 2.<\/p>\n<p>Step 3: Solve: depth = 600 m \u00f7 2 = 300 m.<\/p>\n<p><strong>Answer: 300 m<\/strong><\/p>\n<\/div><\/details><\/div>\n \n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">Crown glass has a refractive index of 1.52. Find the speed of light inside it, and the time light needs to cross a 2.0 mm thick microscope slide.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Use v = c \/ n with c = 299,792,458 m\/s.<\/p>\n<p>Step 2: v = 299,792,458 m\/s \u00f7 1.52 = 1.97 \u00d7 10<sup>8<\/sup> m\/s.<\/p>\n<p>Step 3: Time = distance \u00f7 speed = 0.0020 m \u00f7 (1.97 \u00d7 10<sup>8<\/sup> m\/s) = 1.01 \u00d7 10<sup>-11<\/sup> s.<\/p>\n<p><strong>Answer: v = 1.97 \u00d7 10<sup>8<\/sup> m\/s, and the crossing takes about 10 picoseconds<\/strong><\/p>\n<\/div><\/details><\/div>\n \n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">A guitar&#039;s low-E string has a vibrating length of 0.648 m, a mass per unit length of 6.0 g\/m, and is tuned to 82.4 Hz. Find the wave speed and the tension.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: The fundamental fits half a wavelength between the fixed ends, so \u03bb = 2L = 2 \u00d7 0.648 m = 1.296 m.<\/p>\n<p>Step 2: v = f \u03bb = 82.4 Hz \u00d7 1.296 m = 106.8 m\/s.<\/p>\n<p>Step 3: Rearrange v = sqrt(T \/ \u03bc) to T = \u03bc v<sup>2<\/sup>, with \u03bc = 0.0060 kg\/m.<\/p>\n<p>Step 4: T = 0.0060 kg\/m \u00d7 (106.8 m\/s)<sup>2<\/sup> = 68 N.<\/p>\n<p><strong>Answer: v = 107 m\/s and T of about 68 N (about 7 kgf)<\/strong><\/p>\n<\/div><\/details><\/div>\n \n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">By what factor must the tension in a string be increased to double the wave speed along it?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Start from v = sqrt(T \/ \u03bc), with \u03bc unchanged.<\/p>\n<p>Step 2: Write the ratio: v<sub>2<\/sub> \/ v<sub>1<\/sub> = sqrt(T<sub>2<\/sub> \/ T<sub>1<\/sub>). We need v<sub>2<\/sub> \/ v<sub>1<\/sub> = 2.<\/p>\n<p>Step 3: Square both sides: T<sub>2<\/sub> \/ T<sub>1<\/sub> = 2<sup>2<\/sup> = 4.<\/p>\n<p><strong>Answer: the tension must be quadrupled<\/strong><\/p>\n<\/div><\/details><\/div>\n \n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">You tap one end of a 1.0 km steel rail. Sound reaches the far end through the steel (5960 m\/s) and through the air (343 m\/s). How far apart are the two arrivals?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Use t = d \/ v for each path.<\/p>\n<p>Step 2: Through steel: t = 1000 m \u00f7 5960 m\/s = 0.168 s.<\/p>\n<p>Step 3: Through air: t = 1000 m \u00f7 343 m\/s = 2.92 s.<\/p>\n<p>Step 4: Difference = 2.92 s &#8211; 0.168 s = 2.75 s.<\/p>\n<p><strong>Answer: about 2.7 s \u2014 you hear the rail-borne sound first, then the airborne one<\/strong><\/p>\n<\/div><\/details><\/div>\n \n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 8<\/div><div class=\"pf-problem-question\">On a hot day the air is 35 \u00b0C. Using the approximation v = 331 + 0.6T (T in \u00b0C), find the speed of sound and the wavelength of concert-pitch A at 440 Hz.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Substitute the temperature: v = 331 + 0.6 \u00d7 35.<\/p>\n<p>Step 2: v = 331 + 21 = 352 m\/s.<\/p>\n<p>Step 3: \u03bb = v \/ f = 352 m\/s \u00f7 440 Hz = 0.80 m.<\/p>\n<p><strong>Answer: v = 352 m\/s and \u03bb = 0.80 m (about 9 m\/s faster than at 20 \u00b0C)<\/strong><\/p>\n<\/div><\/details><\/div>\n \n<h2>Frequently Asked Questions<\/h2>\n \n<details class=\"pf-faq-item\"><summary>What is the formula for wave speed?<\/summary><div class=\"pf-faq-item-answer\">\n \nThe universal formula is v = f \u03bb, where v is wave speed in metres per second, f is frequency in hertz and \u03bb is wavelength in metres. Two medium-specific formulas complete the picture: v = c \/ n for light in a transparent material, and v = sqrt(T \/ \u03bc) for a wave on a stretched string.\n \n<\/div><\/details>\n \n<details class=\"pf-faq-item\"><summary>Does wave speed depend on frequency?<\/summary><div class=\"pf-faq-item-answer\">\n \nNo. For ordinary waves in ordinary media, wave speed is fixed by the medium alone, so raising the frequency simply shortens the wavelength and leaves v unchanged. The exception is dispersion, where a medium&#8217;s properties vary slightly with frequency \u2014 this is why a glass prism splits white light into colours.\n \n<\/div><\/details>\n \n<details class=\"pf-faq-item\"><summary>Why does sound travel faster in water than in air?<\/summary><div class=\"pf-faq-item-answer\">\n \nBecause water is far stiffer than air, and stiffness matters more than density. Water is about 830 times denser than air but roughly 15,000 times harder to compress, and since v = sqrt(stiffness \u00f7 density), the stiffness advantage wins. The result is about 1,482 m\/s in water against 343 m\/s in air.\n \n<\/div><\/details>\n \n<details class=\"pf-faq-item\"><summary>Why does light slow down in glass when sound speeds up in steel?<\/summary><div class=\"pf-faq-item-answer\">\n \nThey slow or speed up for completely different reasons. Sound is a mechanical wave, so a stiffer material passes the disturbance on faster. Light needs no medium at all, and inside matter it is repeatedly absorbed and re-radiated by bound electrons, which delays the wave \u2014 more tightly packed electrons mean a higher refractive index and a lower speed.\n \n<\/div><\/details>\n \n<details class=\"pf-faq-item\"><summary>What is the speed of sound in steel?<\/summary><div class=\"pf-faq-item-answer\">\n \nAbout 5,960 m\/s for a bulk longitudinal wave, which is roughly seventeen times the speed in air. The value depends on the alloy and on the shape of the metal: a long thin steel rod carries sound at around 5,050 m\/s, because a narrow rod can bulge sideways as the wave passes and a large block cannot.\n \n<\/div><\/details>\n \n<details class=\"pf-faq-item\"><summary>Is wave speed the same as the speed of the particles in the medium?<\/summary><div class=\"pf-faq-item-answer\">\n \nNo, and the two differ by orders of magnitude. In normal speech, individual air molecules oscillate back and forth at a fraction of a millimetre per second, while the sound wave itself travels at 343 m\/s. The wave transports energy and a pattern across the room; the molecules only jiggle about a fixed position.\n \n<\/div><\/details>\n\n\n","protected":false},"excerpt":{"rendered":"<p>Wave speed is set by the medium, not the source: sound travels at 343 m\/s in air but about 5,960 m\/s in steel, while light slows from 299,792,458 m\/s in a vacuum to roughly 124 million m\/s in diamond. A full reference table, three formulas and eight worked problems.<\/p>\n","protected":false},"author":1,"featured_media":768,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[4],"tags":[],"class_list":["post-767","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-waves"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/767","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=767"}],"version-history":[{"count":8,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/767\/revisions"}],"predecessor-version":[{"id":1472,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/767\/revisions\/1472"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/768"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=767"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=767"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=767"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}