{"id":732,"date":"2026-08-08T14:28:30","date_gmt":"2026-08-08T14:28:30","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=732"},"modified":"2026-08-08T14:28:32","modified_gmt":"2026-08-08T14:28:32","slug":"electricity-cost","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/electricity-cost\/","title":{"rendered":"Electricity Cost: kWh, Wattage and Rate Explained"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\n\nElectricity cost is the price you pay for the electrical energy an appliance consumes, calculated as Cost = kWh \u00d7 rate. Multiply the appliance&#8217;s power in kilowatts by the hours it runs to get kilowatt-hours, then multiply that by your tariff&#8217;s price per kilowatt-hour. Watts divided by 1000 gives kilowatts.\n\n<\/p><\/div>\n\n<p>Your kettle is rated 2000 W. The little box charging your headphones draws 5 W. One of them sounds expensive and one sounds trivial \u2014 and over a year, that instinct can be completely wrong.<\/p>\n\n<p>The bill doesn&#8217;t charge you for watts. It charges you for watts multiplied by time, and time is where the surprises hide. Once you can do that multiplication, every appliance in your home stops being a mystery and becomes a number you can predict.<\/p>\n\n<h2>What Is Electricity Cost?<\/h2>\n\n<p>Electricity cost is the amount of money charged for the electrical energy a device uses, found by multiplying the energy consumed in kilowatt-hours by the price your supplier charges per kilowatt-hour.<\/p>\n\n<p>Think of your meter as a taxi. The watt rating is how fast the fare ticks; the hours are how long you sit in the cab. A fast meter for thirty seconds costs less than a slow meter running all week.<\/p>\n\n<p>That distinction \u2014 rate versus total \u2014 is the whole subject. <strong>Power<\/strong> (watts) is how quickly energy is transferred. <strong>Energy<\/strong> (kilowatt-hours) is how much has been transferred in total. You are only ever billed for the second one.<\/p>\n\n<p>A quick note on currency before the numbers start. Rates below are written as plain figures, so 0.20 per kWh means 20 cents, 20 pence, or 20 of whatever minor unit appears on your bill. The arithmetic is identical everywhere.<\/p>\n\n<h2>The Electricity Cost Formula<\/h2>\n\n<p>The headline formula is short enough to memorise in one reading.<\/p>\n\n<div class=\"pf-formula\">Cost = kWh \u00d7 rate<\/div>\n\n<p>That version assumes you already know the kilowatt-hours. Most of the time you don&#8217;t \u2014 you have a wattage from a label and a rough idea of running time, so the working formula expands to this.<\/p>\n\n<div class=\"pf-formula\">Cost = (P \u00f7 1000) \u00d7 t \u00d7 r<\/div>\n\n<p>Every symbol, with its unit:<\/p>\n\n<ul>\n<li><strong>Cost<\/strong> \u2014 money charged, in your local currency<\/li>\n<li><strong>P<\/strong> \u2014 the appliance&#8217;s power rating, in watts (W)<\/li>\n<li><strong>t<\/strong> \u2014 time the appliance actually runs, in hours (h)<\/li>\n<li><strong>r<\/strong> \u2014 your tariff price, in currency per kilowatt-hour (per kWh)<\/li>\n<li><strong>1000<\/strong> \u2014 the conversion from watts to kilowatts (1 kW = 1000 W)<\/li>\n<\/ul>\n\n<p>The middle of that expression deserves its own name, because it is the quantity your meter physically counts:<\/p>\n\n<div class=\"pf-formula\">E (kWh) = P (W) \u00d7 t (h) \u00f7 1000<\/div>\n\n<p>Get <em>E<\/em> right and the rest is a single multiplication. If you&#8217;d rather skip the arithmetic on a real appliance, our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/electricity-cost\">Electricity Cost Calculator<\/a> takes a wattage, a run time and a rate and returns the running cost directly, with the working shown step by step.<\/p>\n\n<svg viewBox=\"0 0 720 300\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" role=\"img\" aria-label=\"Diagram showing how electricity cost is calculated: 1500 watts divided by 1000 gives 1.5 kilowatts, multiplied by 2 hours gives 3.0 kilowatt-hours, multiplied by a rate of 0.20 per kilowatt-hour gives a cost of 0.60\"><rect x=\"0\" y=\"0\" width=\"720\" height=\"300\" fill=\"#F5F2EA\"><\/rect><text x=\"360\" y=\"34\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"19\" font-weight=\"bold\" fill=\"#0A1628\">From Nameplate Watts to Money<\/text><text x=\"360\" y=\"56\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" fill=\"#7A1F2B\">Worked through for an appliance rated 1500 W, run for 2 hours<\/text><rect x=\"16\" y=\"92\" width=\"136\" height=\"80\" rx=\"4\" fill=\"#0A1628\" stroke=\"#C8932A\" stroke-width=\"1.5\"><\/rect><text x=\"84\" y=\"118\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#C5D0DC\">RATED POWER<\/text><text x=\"84\" y=\"146\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"24\" font-weight=\"bold\" fill=\"#C8932A\">1500 W<\/text><text x=\"84\" y=\"163\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#C5D0DC\">from the label<\/text><rect x=\"204\" y=\"92\" width=\"136\" height=\"80\" rx=\"4\" fill=\"#0A1628\" stroke=\"#C8932A\" stroke-width=\"1.5\"><\/rect><text x=\"272\" y=\"118\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#C5D0DC\">POWER IN kW<\/text><text x=\"272\" y=\"146\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"24\" font-weight=\"bold\" fill=\"#C8932A\">1.5 kW<\/text><text x=\"272\" y=\"163\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#C5D0DC\">billing units<\/text><rect x=\"392\" y=\"92\" width=\"136\" height=\"80\" rx=\"4\" fill=\"#0A1628\" stroke=\"#C8932A\" stroke-width=\"1.5\"><\/rect><text x=\"460\" y=\"118\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#C5D0DC\">ENERGY USED<\/text><text x=\"460\" y=\"146\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"24\" font-weight=\"bold\" fill=\"#C8932A\">3.0 kWh<\/text><text x=\"460\" y=\"163\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#C5D0DC\">what the meter counts<\/text><rect x=\"580\" y=\"92\" width=\"136\" height=\"80\" rx=\"4\" fill=\"#7A1F2B\" stroke=\"#C8932A\" stroke-width=\"1.5\"><\/rect><text x=\"648\" y=\"118\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#FAF6EE\">WHAT YOU PAY<\/text><text x=\"648\" y=\"146\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"24\" font-weight=\"bold\" fill=\"#FAF6EE\">0.60<\/text><text x=\"648\" y=\"163\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#FAF6EE\">per 2-hour run<\/text><line x1=\"152\" y1=\"132\" x2=\"196\" y2=\"132\" stroke=\"#0A1628\" stroke-width=\"2\"><\/line><polygon points=\"204,132 194,127 194,137\" fill=\"#0A1628\"><\/polygon><line x1=\"340\" y1=\"132\" x2=\"384\" y2=\"132\" stroke=\"#0A1628\" stroke-width=\"2\"><\/line><polygon points=\"392,132 382,127 382,137\" fill=\"#0A1628\"><\/polygon><line x1=\"528\" y1=\"132\" x2=\"572\" y2=\"132\" stroke=\"#0A1628\" stroke-width=\"2\"><\/line><polygon points=\"580,132 570,127 570,137\" fill=\"#0A1628\"><\/polygon><text x=\"178\" y=\"122\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#7A1F2B\">\u00f7 1000<\/text><text x=\"366\" y=\"122\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#7A1F2B\">\u00d7 2 h<\/text><text x=\"554\" y=\"122\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#7A1F2B\">\u00d7 rate<\/text><text x=\"178\" y=\"200\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#0A1628\">watts to<\/text><text x=\"178\" y=\"212\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#0A1628\">kilowatts<\/text><text x=\"366\" y=\"200\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#0A1628\">hours actually<\/text><text x=\"366\" y=\"212\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#0A1628\">running<\/text><text x=\"554\" y=\"200\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#0A1628\">your tariff<\/text><text x=\"554\" y=\"212\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"10\" fill=\"#0A1628\">per kWh<\/text><line x1=\"16\" y1=\"240\" x2=\"704\" y2=\"240\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/line><text x=\"360\" y=\"266\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"15\" fill=\"#0A1628\">Cost = (Watts \u00f7 1000) \u00d7 Hours \u00d7 Rate<\/text><text x=\"360\" y=\"286\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#7A1F2B\">Only the middle step is under your control on any given day<\/text><\/svg>\n\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;\">The three-step electricity cost pipeline: watts to kilowatts, kilowatts to kilowatt-hours, kilowatt-hours to money.<\/p>\n\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Electricity Cost Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/electricity-cost.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n<h2>How Does Your Meter Turn Watts Into Money?<\/h2>\n\n<p>Your meter measures the energy passing into your home and totals it in kilowatt-hours, and the supplier multiplies that total by the tariff rate. Nothing more mysterious than that is happening behind the little spinning display.<\/p>\n\n<p>Follow it in four steps for any single appliance.<\/p>\n\n<ol>\n<li><strong>Read the power rating.<\/strong> Look for the nameplate or rating label \u2014 a small silver or printed panel on the back or base \u2014 and find a figure in W or kW.<\/li>\n<li><strong>Convert to kilowatts.<\/strong> Divide watts by 1000. A 1500 W iron is 1.5 kW.<\/li>\n<li><strong>Multiply by real running hours.<\/strong> Not hours plugged in \u2014 hours actually drawing power. A fridge compressor cycles on and off; a toaster runs for two minutes.<\/li>\n<li><strong>Multiply by your rate.<\/strong> Take the price per kWh from your bill, not from a headline you half-remember.<\/li>\n<\/ol>\n\n<p>Step three is where most estimates go wrong, and it is worth being honest about the uncertainty. A thermostat-controlled device \u2014 fridge, freezer, electric heater, air conditioner \u2014 spends much of its plugged-in life idle.<\/p>\n\n<p>In practice, treat any thermostat appliance as running perhaps a third to a half of the time unless you have measured it. A plug-in energy monitor removes the guesswork entirely and usually costs less than one month of the error it corrects.<\/p>\n\n<figure style=\"margin:32px auto;max-width:640px;text-align:center;\">\n\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/08\/article-2561882-1B9A367500000578-146_636x382.jpg\"\n\n       alt=\"Appliance rating label showing the wattage used to work out electricity cost\"\n\n       loading=\"lazy\"\n\n       style=\"width:100%;height:auto;border-radius:4px;\" width=\"1908\" height=\"1146\">\n\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">The rating label is where every electricity cost calculation starts \u2014 look for a figure in W or kW.<\/figcaption>\n\n<\/figure>\n\n<h2>What Is a kWh, and Why Not Joules?<\/h2>\n\n<p>A kilowatt-hour is the energy transferred by a one-kilowatt device running for one hour, and it equals exactly 3.6 megajoules. Utilities bill in kWh rather than joules purely because the joule is inconveniently small for household quantities.<\/p>\n\n<p>The conversion falls straight out of the definitions. A watt is one joule per second, and an hour is 3600 seconds, so:<\/p>\n\n<div class=\"pf-formula\">1 kWh = 1000 W \u00d7 3600 s = 3 600 000 J = 3.6 MJ<\/div>\n\n<p>Bill a house in joules and a modest month becomes a nine-digit number. The kilowatt-hour keeps everyday consumption in the range of tens and hundreds \u2014 far friendlier on paper.<\/p>\n\n<p>Strictly, the kWh is not itself an SI unit. The joule is the SI unit of energy, and the kilowatt-hour combines the SI watt with the hour, which the <a href=\"https:\/\/www.nist.gov\/pml\/special-publication-811\/nist-guide-si-chapter-5-units-outside-si\" target=\"_blank\" rel=\"noopener\">NIST guide to the SI lists as a non-SI unit accepted for use with the SI<\/a> (1 h = 3600 s). If SI conventions are new to you, our guide to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/si-units-physics\/\">SI units and prefixes<\/a> covers the naming rules behind kilo-, mega- and the rest.<\/p>\n\n<p>One more reason the unit sticks: it makes a bill intuitive. A single kWh runs a 10 W LED lamp for exactly 100 hours, or a 2 kW kettle for exactly 30 minutes.<\/p>\n\n<h2>Real-World Examples of Electricity Cost<\/h2>\n\n<p>The fastest way to build intuition is a ready-reckoner you can read off, so here is the arithmetic done for a spread of common wattages at a rate of 0.20 per kWh.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#0A1628;color:#FAF6EE;\">\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Power rating<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Energy in 1 hour<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Cost per hour<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Energy for 4 h\/day, 30 days<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Cost for that month<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">10 W<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.010 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.002<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">1.2 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.24<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:10px;border:1px solid #D9CFB8;\">50 W<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.050 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.010<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">6.0 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">1.20<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">100 W<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.100 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.020<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">12.0 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">2.40<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:10px;border:1px solid #D9CFB8;\">500 W<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.500 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.100<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">60 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">12.00<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">1000 W (1 kW)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">1.000 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.200<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">120 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">24.00<\/td><\/tr>\n<tr style=\"background:#F5F2EA;\"><td style=\"padding:10px;border:1px solid #D9CFB8;\">2000 W (2 kW)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">2.000 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.400<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">240 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">48.00<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">3000 W (3 kW)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">3.000 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.600<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">360 kWh<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">72.00<\/td><\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>Read down that last column and the scaling is obvious: cost is directly proportional to wattage when the hours are held fixed. Double the watts, double the bill.<\/p>\n\n<p>But hold the <em>watts<\/em> fixed and vary the hours instead, and the ranking scrambles. Here is a year of running for five very different devices, all on one scale.<\/p>\n\n<svg viewBox=\"0 0 720 330\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" role=\"img\" aria-label=\"Bar chart comparing annual electricity use in kilowatt-hours: a 60 W bulb run 5 hours a day uses 109.5 kWh, a 2 kW kettle run 5 minutes a day uses 60.8 kWh, a 5 W standby load left on continuously uses 43.8 kWh, a 2 kW kettle run 3 minutes a day uses 36.5 kWh, and a 9 W LED run 5 hours a day uses 16.4 kWh\"><rect x=\"0\" y=\"0\" width=\"720\" height=\"330\" fill=\"#F5F2EA\"><\/rect><text x=\"360\" y=\"30\" text-anchor=\"middle\" font-family=\"Georgia,serif\" font-size=\"19\" font-weight=\"bold\" fill=\"#0A1628\">Why Hours Matter as Much as Watts<\/text><text x=\"360\" y=\"50\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" fill=\"#7A1F2B\">Energy used over one year (kWh), same scale throughout<\/text><line x1=\"250\" y1=\"62\" x2=\"250\" y2=\"290\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/line><line x1=\"350\" y1=\"62\" x2=\"350\" y2=\"290\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/line><line x1=\"450\" y1=\"62\" x2=\"450\" y2=\"290\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/line><line x1=\"550\" y1=\"62\" x2=\"550\" y2=\"290\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/line><line x1=\"650\" y1=\"62\" x2=\"650\" y2=\"290\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/line><rect x=\"250\" y=\"70\" width=\"365\" height=\"30\" fill=\"#7A1F2B\"><\/rect><rect x=\"250\" y=\"116\" width=\"202.8\" height=\"30\" fill=\"#C8932A\"><\/rect><rect x=\"250\" y=\"162\" width=\"146\" height=\"30\" fill=\"#0A1628\"><\/rect><rect x=\"250\" y=\"208\" width=\"121.7\" height=\"30\" fill=\"#C8932A\"><\/rect><rect x=\"250\" y=\"254\" width=\"54.8\" height=\"30\" fill=\"#C8932A\"><\/rect><text x=\"240\" y=\"84\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" font-weight=\"bold\" fill=\"#0A1628\">60 W bulb<\/text><text x=\"240\" y=\"97\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#7A1F2B\">5 h\/day<\/text><text x=\"240\" y=\"130\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" font-weight=\"bold\" fill=\"#0A1628\">2 kW kettle<\/text><text x=\"240\" y=\"143\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#7A1F2B\">5 min\/day<\/text><text x=\"240\" y=\"176\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" font-weight=\"bold\" fill=\"#0A1628\">5 W standby<\/text><text x=\"240\" y=\"189\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#7A1F2B\">24 h\/day<\/text><text x=\"240\" y=\"222\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" font-weight=\"bold\" fill=\"#0A1628\">2 kW kettle<\/text><text x=\"240\" y=\"235\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#7A1F2B\">3 min\/day<\/text><text x=\"240\" y=\"268\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" font-weight=\"bold\" fill=\"#0A1628\">9 W LED<\/text><text x=\"240\" y=\"281\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#7A1F2B\">5 h\/day<\/text><text x=\"625\" y=\"90\" font-family=\"Georgia,serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#0A1628\">109.5<\/text><text x=\"463\" y=\"136\" font-family=\"Georgia,serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#0A1628\">60.8<\/text><text x=\"406\" y=\"182\" font-family=\"Georgia,serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#0A1628\">43.8<\/text><text x=\"382\" y=\"228\" font-family=\"Georgia,serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#0A1628\">36.5<\/text><text x=\"315\" y=\"274\" font-family=\"Georgia,serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#0A1628\">16.4<\/text><line x1=\"250\" y1=\"290\" x2=\"660\" y2=\"290\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/line><text x=\"250\" y=\"306\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#0A1628\">0<\/text><text x=\"350\" y=\"306\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#0A1628\">30<\/text><text x=\"450\" y=\"306\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#0A1628\">60<\/text><text x=\"550\" y=\"306\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#0A1628\">90<\/text><text x=\"650\" y=\"306\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#0A1628\">120<\/text><text x=\"455\" y=\"324\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" font-style=\"italic\" fill=\"#7A1F2B\">kilowatt-hours per year<\/text><\/svg>\n\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;\">A 5 W device left on permanently uses more energy per year than a 2 kW kettle boiled for three minutes a day.<\/p>\n\n<h3>Three examples worth internalising<\/h3>\n\n<p><strong>The humble light bulb beats the kettle.<\/strong> A single 60 W incandescent bulb burning five hours a day gets through 109.5 kWh a year \u2014 more than a 2 kW kettle used for five minutes daily, which comes to 60.8 kWh. The kettle is 33 times more powerful and still loses.<\/p>\n\n<p><strong>Standby is small but permanent.<\/strong> A 5 W always-on load draws 43.8 kWh over a year. Matching that same five-minute daily kettle would take only about a 7 W permanent load \u2014 the sort of trickle a forgotten device in standby can easily supply.<\/p>\n\n<p><strong>Swapping the bulb is the biggest single win.<\/strong> Replace that 60 W incandescent with a 9 W LED at the same five hours a day and annual use falls from 109.5 kWh to 16.4 kWh. Same light, exactly 85% less energy.<\/p>\n<h2>Common Misconceptions About Electricity Cost<\/h2>\n\n<p>Four beliefs cause most of the wrong answers, and three of them are about confusing a rate with a total.<\/p>\n\n<h3>Misconception 1: &#8220;A kW and a kWh are basically the same thing&#8221;<\/h3>\n\n<p>They measure different quantities, and mixing them is the single most common error in this topic. A kilowatt is power \u2014 a rate of energy transfer. A kilowatt-hour is energy \u2014 an amount.<\/p>\n\n<p>The giveaway is that one contains a time and one doesn&#8217;t. Saying an appliance &#8220;used 3 kW yesterday&#8221; is like saying a car &#8220;travelled 60 km\/h yesterday&#8221;: the units answer a different question than the one asked.<\/p>\n\n<h3>Misconception 2: &#8220;High-wattage appliances are always the expensive ones&#8221;<\/h3>\n\n<p>Wattage alone tells you nothing about cost, because cost depends on the product of wattage and time. A 3 kW appliance run for 20 minutes and a 100 W appliance run for 10 hours consume identical energy \u2014 1.0 kWh each \u2014 and cost identical money.<\/p>\n\n<p>This is why the bar chart above matters more than any list of wattages. A small load that never switches off can quietly out-consume a monster that runs for two minutes.<\/p>\n\n<h3>Misconception 3: &#8220;Switching a device off at the socket saves nothing&#8221;<\/h3>\n\n<p>Standby draw is real, though usually modest, and it is genuinely continuous. A device idling at 5 W accumulates 43.8 kWh a year \u2014 small per hour, meaningful per decade.<\/p>\n\n<p>Be proportionate, though. Modern equipment often idles well under 1 W, in which case the saving is a rounding error and the effort is better spent on heating, hot water and lighting.<\/p>\n\n<h3>Misconception 4: &#8220;My appliance sums should add up to my bill&#8221;<\/h3>\n\n<p>They almost never will, because a bill contains charges that have nothing to do with energy consumed. Most tariffs add a fixed daily standing charge, and many add taxes or tiered rates on top.<\/p>\n\n<p>Work an example. Use 350 kWh in a month at 0.20 per kWh and the energy charge is 70.00 \u2014 but add a 12.00 standing charge and the total becomes 82.00, an effective 0.2343 per kWh.<\/p>\n\n<p>So always divide your actual bill total by your actual kWh to find what you are <em>really<\/em> paying. Published rates and the number on your statement are rarely the same figure, and the gap widens as consumption falls.<\/p>\n\n<h2>How Electricity Cost Relates to Power, Current and Voltage<\/h2>\n\n<p>Electricity cost sits at the end of a short chain: voltage and current set the power, power and time set the energy, energy and rate set the cost. Each link is a topic in its own right.<\/p>\n\n<p>When an appliance has no wattage printed on it \u2014 common on older equipment \u2014 you can still recover it from the voltage and current on the label. For a resistive load on mains supply:<\/p>\n\n<div class=\"pf-formula\">P = V \u00d7 I<\/div>\n\n<ul>\n<li><strong>P<\/strong> \u2014 power, in watts (W)<\/li>\n<li><strong>V<\/strong> \u2014 supply voltage, in volts (V)<\/li>\n<li><strong>I<\/strong> \u2014 current drawn, in amperes (A)<\/li>\n<\/ul>\n\n<p>That relationship comes straight out of the circuit fundamentals covered in our guide to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/ohms-law\/\">Ohm&#8217;s law<\/a>, which also derives the useful variants P = I\u00b2R and P = V\u00b2\/R for when you know the resistance instead.<\/p>\n\n<p>The <em>V<\/em> in that equation is the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/potential-difference\/\">potential difference<\/a> across the appliance \u2014 the energy each coulomb of charge delivers as it passes through. The <em>I<\/em> is the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/electric-current\/\">electric current<\/a>, the rate at which that charge flows.<\/p>\n\n<p>Multiply the two and you get the rate of energy delivery, which is exactly what physicists mean by <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/power-in-physics\/\">power<\/a>. Integrate power over time and you are back to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/what-is-energy-in-physics\/\">energy<\/a> \u2014 the quantity your meter has been counting all along.<\/p>\n\n<p>One caution for AC circuits. On alternating supply, V and I are quoted as RMS values, and for loads with motors or electronics the true power is lower than V \u00d7 I by a power factor. For domestic estimates the nameplate wattage already accounts for this, so use it when it is available.<\/p>\n\n<h3>Where the rate itself comes from<\/h3>\n\n<p>Your price per kWh is set by your supplier and varies enormously by country, region and time of day. National statistical agencies publish averages \u2014 the <a href=\"https:\/\/www.eia.gov\/electricity\/data.php\" target=\"_blank\" rel=\"noopener\">US Energy Information Administration&#8217;s electricity data<\/a> is one such source \u2014 but an average is a poor substitute for your own tariff.<\/p>\n\n<p>Time-of-use tariffs make the timing matter as much as the total. Shifting a dishwasher or an EV charge into an off-peak window can cut the cost of identical energy by half or more, as the last worked problem below shows.<\/p>\n<h2>Worked Problems<\/h2>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">A 60 W light bulb runs for 5 hours a day. At a rate of 0.17 per kWh, what does one day cost?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Energy in kilowatt-hours is E = P \u00d7 t \u00f7 1000, then Cost = E \u00d7 r.\n\nStep 2: E = 60 W \u00d7 5 h \u00f7 1000 = 0.3 kWh\n\nStep 3: Cost = 0.3 kWh \u00d7 0.17 per kWh = 0.051\n\n<strong>Answer: 0.051 per day \u2014 about 5 units of currency per hundred days (2 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A 1.5 kW electric heater runs 3 hours a day for 30 days. At 0.20 per kWh, what is the monthly cost?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: The rating is already in kilowatts, so no division by 1000 is needed.\n\nStep 2: Daily energy = 1.5 kW \u00d7 3 h = 4.5 kWh\n\nStep 3: Monthly energy = 4.5 kWh \u00d7 30 = 135 kWh\n\nStep 4: Cost = 135 kWh \u00d7 0.20 per kWh = 27.00\n\n<strong>Answer: 135 kWh, costing 27.00 for the month<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A device draws 5 W continuously in standby. Over a full 365-day year at 0.17 per kWh, what does leaving it on cost?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Running hours = 24 h\/day \u00d7 365 days = 8760 h\n\nStep 2: E = 5 W \u00d7 8760 h \u00f7 1000 = 43.8 kWh\n\nStep 3: Cost = 43.8 kWh \u00d7 0.17 per kWh = 7.446\n\n<strong>Answer: 43.8 kWh per year, costing 7.45 (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">A kettle label reads 230 V and 8.7 A. It is used for 4 minutes a day. At 0.25 per kWh, what is the annual cost?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Find power from P = V \u00d7 I.\n\nStep 2: P = 230 V \u00d7 8.7 A = 2001 W = 2.001 kW\n\nStep 3: Convert time to hours: t = 4 min \u00f7 60 = 0.06667 h\n\nStep 4: Daily energy = 2.001 kW \u00d7 0.06667 h = 0.1334 kWh\n\nStep 5: Annual energy = 0.1334 kWh \u00d7 365 = 48.69 kWh\n\nStep 6: Cost = 48.69 kWh \u00d7 0.25 per kWh = 12.17\n\n<strong>Answer: 48.7 kWh per year, costing 12.17 (4 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">A 60 W incandescent bulb is replaced with a 9 W LED giving the same light. Both run 5 hours a day. At 0.17 per kWh, how long does a 3.00 LED take to pay for itself?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Work with the power difference, since the running hours are identical.\n\nStep 2: \u0394P = 60 W &#8211; 9 W = 51 W\n\nStep 3: Annual energy saved = 51 W \u00d7 5 h \u00d7 365 \u00f7 1000 = 93.075 kWh\n\nStep 4: Annual money saved = 93.075 kWh \u00d7 0.17 per kWh = 15.82\n\nStep 5: Payback time = 3.00 \u00f7 15.82 per year = 0.1896 years\n\nStep 6: 0.1896 years \u00d7 365 days = 69.2 days\n\n<strong>Answer: about 69 days to pay back, then 15.82 saved every year after (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">A household used 135 kWh in a month. Express that energy in joules and in megajoules.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Use the exact conversion 1 kWh = 1000 W \u00d7 3600 s = 3.6 \u00d7 10<sup>6<\/sup> J.\n\nStep 2: E = 135 kWh \u00d7 3.6 \u00d7 10<sup>6<\/sup> J\/kWh = 4.86 \u00d7 10<sup>8<\/sup> J\n\nStep 3: Convert to megajoules: 4.86 \u00d7 10<sup>8<\/sup> J \u00f7 10<sup>6<\/sup> = 486 MJ\n\n<strong>Answer: 4.86 \u00d7 10<sup>8<\/sup> J, or 486 MJ<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">An electric water heater raises 150 kg of water from 15 \u00b0C to 60 \u00b0C. Taking the specific heat capacity of water as 4180 J\/(kg\u00b7K) and the heater as 90% efficient, find the cost at 0.17 per kWh.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Useful heat required is Q = mc\u0394T.\n\nStep 2: \u0394T = 60 \u00b0C &#8211; 15 \u00b0C = 45 K\n\nStep 3: Q = 150 kg \u00d7 4180 J\/(kg\u00b7K) \u00d7 45 K = 28 215 000 J = 28.215 MJ\n\nStep 4: Convert to kWh: 28 215 000 J \u00f7 3.6 \u00d7 10<sup>6<\/sup> J\/kWh = 7.8375 kWh of useful heat\n\nStep 5: Account for efficiency \u2014 the meter records the input, not the output: E = 7.8375 kWh \u00f7 0.90 = 8.708 kWh\n\nStep 6: Cost = 8.708 kWh \u00d7 0.17 per kWh = 1.480\n\n<strong>Answer: 8.71 kWh drawn from the supply, costing 1.48 (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 8<\/div><div class=\"pf-problem-question\">An electric car has a 60 kWh usable battery and charges at 92% efficiency. Compare a full charge at an off-peak rate of 0.09 per kWh with a peak rate of 0.28 per kWh.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: The battery stores 60 kWh, but losses mean the meter records more than that. Energy drawn = stored energy \u00f7 efficiency.\n\nStep 2: E = 60 kWh \u00f7 0.92 = 65.22 kWh\n\nStep 3: Off-peak cost = 65.22 kWh \u00d7 0.09 per kWh = 5.870\n\nStep 4: Peak cost = 65.22 kWh \u00d7 0.28 per kWh = 18.26\n\nStep 5: Saving = 18.26 &#8211; 5.87 = 12.39\n\n<strong>Answer: 65.2 kWh drawn; 5.87 off-peak against 18.26 at peak, a saving of 12.39 per charge (4 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<h2>Frequently Asked Questions<\/h2>\n\n<details class=\"pf-faq-item\"><summary>How do you calculate electricity cost?<\/summary><div class=\"pf-faq-item-answer\">\n\nMultiply the appliance&#8217;s power in kilowatts by the hours it runs, then multiply by your rate per kilowatt-hour: Cost = (W \u00f7 1000) \u00d7 hours \u00d7 rate. A 1500 W iron used for 2 hours at 0.20 per kWh uses 3.0 kWh and costs 0.60. Always divide watts by 1000 first.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>How much does it cost to run a 100 W bulb for 24 hours?<\/summary><div class=\"pf-faq-item-answer\">\n\nA 100 W bulb running 24 hours uses 2.4 kWh, because 100 \u00d7 24 \u00f7 1000 = 2.4. At 0.20 per kWh that costs 0.48, and at 0.30 per kWh it costs 0.72. Multiply the 2.4 kWh figure by whatever rate appears on your own bill.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What is a kWh in simple terms?<\/summary><div class=\"pf-faq-item-answer\">\n\nA kilowatt-hour is the energy used by a 1000 W appliance running for one hour. It equals exactly 3.6 million joules. In practical terms, one kWh runs a 10 W LED lamp for 100 hours or a 2 kW kettle for 30 minutes. It is the unit your meter counts and your supplier bills.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Is a kW the same as a kWh?<\/summary><div class=\"pf-faq-item-answer\">\n\nNo \u2014 a kilowatt measures power and a kilowatt-hour measures energy. A kilowatt is how fast energy is being used at this instant; a kilowatt-hour is how much has been used in total. A 2 kW heater running for 30 minutes uses 1 kWh. You are billed in kWh, never in kW.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Why is my electricity bill higher than my appliance calculations?<\/summary><div class=\"pf-faq-item-answer\">\n\nMost bills add a fixed daily standing charge, plus taxes and sometimes tiered rates, none of which depend on how much energy you use. Using 350 kWh at 0.20 per kWh gives 70.00 of energy charges, but a 12.00 standing charge lifts the total to 82.00 \u2014 an effective 0.2343 per kWh.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>How many joules are in a kilowatt-hour?<\/summary><div class=\"pf-faq-item-answer\">\n\nOne kilowatt-hour equals exactly 3 600 000 joules, or 3.6 megajoules. The conversion follows from the definitions: a watt is one joule per second, so 1000 watts sustained for 3600 seconds transfers 1000 \u00d7 3600 = 3.6 million joules. The joule is the SI unit of energy; the kilowatt-hour is simply a more convenient size for billing.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Does the wattage on the label mean the appliance always uses that much?<\/summary><div class=\"pf-faq-item-answer\">\n\nNo \u2014 a nameplate wattage is the maximum draw, and thermostat-controlled appliances spend much of their time idle. Fridges, freezers, heaters and air conditioners cycle on and off, so their average consumption can be a third to a half of the rated figure. A plug-in energy monitor gives the true average.\n\n<\/div><\/details>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Electricity cost is worked out by multiplying kilowatt-hours by your rate per kWh. 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