{"id":713,"date":"2026-08-06T14:29:03","date_gmt":"2026-08-06T14:29:03","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=713"},"modified":"2026-08-06T15:24:34","modified_gmt":"2026-08-06T15:24:34","slug":"fouriers-law","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/thermodynamics\/fouriers-law\/","title":{"rendered":"Fourier&#8217;s Law of Thermal Conduction (Q\/t = kA\u0394T\/d)"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\nFourier&#8217;s law states that the rate of heat conduction through a material is proportional to its thermal conductivity, its cross-sectional area and the temperature difference across it, and inversely proportional to its thickness. In one dimension it is written Q\/t = kA\u0394T\/d, giving the heat-flow rate in watts.\n<\/p><\/div>\n\n<p>Rest your hand on a metal railing on a January morning and it bites. Rest it on the wooden bench beside it and nothing much happens. Same air, same temperature, wildly different sensation \u2014 and the entire difference is one number in one equation.<\/p>\n\n<p>That number is thermal conductivity, and the equation is Fourier&#8217;s law. It is the piece of physics that decides how much heat leaks out of your walls tonight, how fast a saucepan browns an onion, and whether a processor survives its own workload. Get comfortable with it and you can put a watt figure on almost anything warm.<\/p>\n\n<h2>What Is Fourier&#8217;s Law?<\/h2>\n\n<p>Fourier&#8217;s law is the rule that fixes how fast heat flows by conduction through a solid material. It says the flow rate rises with the material&#8217;s conductivity, with the area heat can cross, and with the temperature difference driving it \u2014 and falls as the material gets thicker.<\/p>\n\n<p>Think of it as an electrical circuit. Temperature difference is the voltage that pushes; thickness divided by conductivity is the resistance that holds back; the heat-flow rate is the current that results. Physicists lean on that analogy constantly, and once you see it you cannot unsee it.<\/p>\n\n<p>Joseph Fourier first set the law out in an 1807 memoir to the Institut de France, then published it in mature form in his 1822 <em>Th\u00e9orie analytique de la chaleur<\/em>. To crack it he had to invent a new branch of mathematics along the way \u2014 Fourier series \u2014 which now underpins everything from MP3 compression to MRI scanners.<\/p>\n\n<p>One thing to be clear about from the start: this law describes <strong>conduction only<\/strong>. It is silent on heat carried by moving fluids or beamed across empty space.<\/p>\n\n<h2>The Fourier&#8217;s Law Formula<\/h2>\n\n<p>The steady-state, one-dimensional form of Fourier&#8217;s law is written like this:<\/p>\n\n<div class=\"pf-formula\">Q\/t = k \u00b7 A \u00b7 \u0394T \/ d<\/div>\n\n<p>Every symbol, with its SI unit:<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#142139;color:#FAF6EE;\">\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Symbol<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Quantity<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">SI unit<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Notes<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>Q\/t<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Rate of heat transfer<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">watt (W) = J\/s<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Often written as <em>P<\/em>; it is a power, not an energy<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>k<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Thermal conductivity<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">W\/(m\u00b7K)<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">A property of the material, not the object<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>A<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Cross-sectional area<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">m\u00b2<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Measured perpendicular to the heat flow<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>\u0394T<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Temperature difference<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">K (or \u00b0C)<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Hot face minus cold face; a difference, so K and \u00b0C match<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>d<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Thickness<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">m<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Measured along the direction of heat flow<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>Three of those four inputs scale the answer directly: double the area, double the loss. Only thickness works the other way, sitting in the denominator where it divides the loss down.<\/p>\n\n<p>Once the physics is clear, the arithmetic is the boring part \u2014 you can hand the numbers to our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/thermal-conduction\">Thermal Conduction (Fourier&#8217;s Law) Calculator<\/a>, which also rearranges the formula to solve for k, A, \u0394T or d without you doing the algebra.<\/p>\n\n<h3>Rearranging the equation<\/h3>\n\n<p>Exam questions rarely hand you the variable you want. The four rearrangements worth memorising:<\/p>\n\n<ul>\n<li><strong>k<\/strong> = (Q\/t)\u00b7d \/ (A\u00b7\u0394T)<\/li>\n<li><strong>A<\/strong> = (Q\/t)\u00b7d \/ (k\u00b7\u0394T)<\/li>\n<li><strong>\u0394T<\/strong> = (Q\/t)\u00b7d \/ (k\u00b7A)<\/li>\n<li><strong>d<\/strong> = k\u00b7A\u00b7\u0394T \/ (Q\/t)<\/li>\n<\/ul>\n\n<h2>Thermal Conductivity (k) Values for Common Materials<\/h2>\n\n<p>Thermal conductivity is the number that tells you how readily a material passes heat along, measured in watts per metre per kelvin. It is the only material-specific term in Fourier&#8217;s law, which makes it the number worth knowing by heart.<\/p>\n\n<p>The range is enormous. Copper carries heat about 27,000 times better than silica aerogel \u2014 a spread of more than four orders of magnitude across everyday solids.<\/p>\n\n<svg role=\"img\" aria-label=\"Thermal conductivity spectrum for Fourier's law: a logarithmic scale from silica aerogel at 0.015 W per metre per kelvin to diamond above 1000, with insulation, building materials and metals marked\" viewBox=\"0 0 720 250\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:1.5em auto;\">\n<rect x=\"0\" y=\"0\" width=\"720\" height=\"250\" rx=\"8\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/rect>\n<text x=\"360\" y=\"30\" text-anchor=\"middle\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"17\" font-weight=\"bold\" fill=\"#7A1F2B\">Thermal conductivity k \u2014 log scale, W\/(m\u00b7K)<\/text>\n<rect x=\"70\" y=\"112\" width=\"70\" height=\"18\" fill=\"#C5D0DC\"><\/rect>\n<rect x=\"140\" y=\"112\" width=\"180\" height=\"18\" fill=\"#C8932A\" opacity=\"0.45\"><\/rect>\n<rect x=\"320\" y=\"112\" width=\"370\" height=\"18\" fill=\"#7A1F2B\" opacity=\"0.65\"><\/rect>\n<line x1=\"70\" y1=\"130\" x2=\"690\" y2=\"130\" stroke=\"#142139\" stroke-width=\"2\"><\/line>\n<g font-family=\"Arial, Helvetica, sans-serif\" font-size=\"11\" fill=\"#142139\" text-anchor=\"middle\">\n<line x1=\"70\" y1=\"130\" x2=\"70\" y2=\"139\" stroke=\"#142139\" stroke-width=\"1.5\"><\/line><text x=\"70\" y=\"153\">0.01<\/text>\n<line x1=\"184.8\" y1=\"130\" x2=\"184.8\" y2=\"139\" stroke=\"#142139\" stroke-width=\"1.5\"><\/line><text x=\"184.8\" y=\"153\">0.1<\/text>\n<line x1=\"299.6\" y1=\"130\" x2=\"299.6\" y2=\"139\" stroke=\"#142139\" stroke-width=\"1.5\"><\/line><text x=\"299.6\" y=\"153\">1<\/text>\n<line x1=\"414.4\" y1=\"130\" x2=\"414.4\" y2=\"139\" stroke=\"#142139\" stroke-width=\"1.5\"><\/line><text x=\"414.4\" y=\"153\">10<\/text>\n<line x1=\"529.3\" y1=\"130\" x2=\"529.3\" y2=\"139\" stroke=\"#142139\" stroke-width=\"1.5\"><\/line><text x=\"529.3\" y=\"153\">100<\/text>\n<line x1=\"644.1\" y1=\"130\" x2=\"644.1\" y2=\"139\" stroke=\"#142139\" stroke-width=\"1.5\"><\/line><text x=\"644.1\" y=\"153\">1000<\/text>\n<\/g>\n<g font-family=\"Arial, Helvetica, sans-serif\" font-size=\"10.5\" fill=\"#1F2E47\">\n<circle cx=\"90.2\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"90.2\" y=\"103\" text-anchor=\"middle\">aerogel<\/text>\n<circle cx=\"117.6\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"117.6\" y=\"86\" text-anchor=\"middle\">still air<\/text>\n<line x1=\"117.6\" y1=\"108\" x2=\"117.6\" y2=\"92\" stroke=\"#142139\" stroke-width=\"0.8\"><\/line>\n<circle cx=\"139.1\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"139.1\" y=\"103\" text-anchor=\"middle\">wool<\/text>\n<circle cx=\"197.9\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"197.9\" y=\"103\" text-anchor=\"middle\">wood<\/text>\n<circle cx=\"283.2\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"283.2\" y=\"86\" text-anchor=\"middle\">brick<\/text>\n<line x1=\"283.2\" y1=\"108\" x2=\"283.2\" y2=\"92\" stroke=\"#142139\" stroke-width=\"0.8\"><\/line>\n<circle cx=\"299.6\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"308\" y=\"103\" text-anchor=\"middle\">glass<\/text>\n<circle cx=\"434.7\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"434.7\" y=\"103\" text-anchor=\"middle\">steel<\/text>\n<circle cx=\"518.1\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"518.1\" y=\"103\" text-anchor=\"middle\">iron<\/text>\n<circle cx=\"572.3\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"572.3\" y=\"86\" text-anchor=\"middle\">aluminium<\/text>\n<line x1=\"572.3\" y1=\"108\" x2=\"572.3\" y2=\"92\" stroke=\"#142139\" stroke-width=\"0.8\"><\/line>\n<circle cx=\"598.5\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"606\" y=\"103\" text-anchor=\"middle\">copper<\/text>\n<circle cx=\"678.6\" cy=\"112\" r=\"3.5\" fill=\"#142139\"><\/circle><text x=\"678.6\" y=\"86\" text-anchor=\"middle\">diamond<\/text>\n<line x1=\"678.6\" y1=\"108\" x2=\"678.6\" y2=\"92\" stroke=\"#142139\" stroke-width=\"0.8\"><\/line>\n<\/g>\n<g font-family=\"Arial, Helvetica, sans-serif\" font-size=\"12\" font-weight=\"bold\" text-anchor=\"middle\">\n<text x=\"105\" y=\"181\" fill=\"#1F2E47\">INSULATORS<\/text>\n<text x=\"230\" y=\"181\" fill=\"#8A6A1E\">BUILDING FABRIC<\/text>\n<text x=\"505\" y=\"181\" fill=\"#7A1F2B\">METALS<\/text>\n<\/g>\n<text x=\"360\" y=\"212\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"11.5\" fill=\"#1F2E47\">Each step along the axis is a factor of ten \u2014 copper conducts roughly 27,000\u00d7 better than aerogel.<\/text>\n<text x=\"360\" y=\"231\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"11\" fill=\"#7A1F2B\">Low k = good insulator \u00b7 High k = good conductor<\/text>\n<\/svg>\n\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;\">Thermal conductivity of common materials on a logarithmic scale \u2014 the single term in Fourier&#8217;s law that changes with the material.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#142139;color:#FAF6EE;\">\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Material<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">k, W\/(m\u00b7K)<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Class<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Why it matters<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Diamond (natural)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">1000\u20132200<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Crystal<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Best bulk conductor known; used as a heat spreader<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Silver<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">429<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Metal<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Best common metal, but too costly for bulk use<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>Copper<\/strong><\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>401<\/strong><\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Metal<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">The benchmark for heat sinks, pipes and pan bases<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Gold<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">317<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Metal<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Used in electronics for corrosion resistance, not k<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>Aluminium<\/strong><\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>237<\/strong><\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Metal<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Light and cheap \u2014 the default heat-sink material<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Iron<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">80<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Metal<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Five times worse than copper \u2014 cast iron holds heat, it does not spread it<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Stainless steel (304)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">\u224815<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Alloy<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Why steel pan handles stay touchable and steel pans burn food<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Ice (0 \u00b0C)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">2.2<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Solid<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Almost four times more conductive than liquid water<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Concrete (dense)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">1.0\u20131.8<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Building<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Great thermal mass, hopeless insulator<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Glass (soda-lime)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">0.8\u20131.0<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Building<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Thin panes leak badly \u2014 see the worked problems<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Brick (common)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">0.6\u20130.8<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Building<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Structural, never the insulating layer<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Water (20 \u00b0C)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">0.60<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Liquid<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Roughly 23\u00d7 worse than still air \u2014 wet insulation is ruined insulation<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Plasterboard<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">\u22480.16<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Building<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Contributes almost nothing to a wall&#8217;s resistance<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Wood (softwood, across grain)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">0.12\u20130.15<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Building<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Why a wooden spoon in a hot pan stays holdable<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>Mineral wool \/ glass-fibre batt<\/strong><\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>0.035\u20130.045<\/strong><\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Insulation<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">The workhorse of loft and cavity insulation<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">EPS (expanded polystyrene)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">0.033\u20130.038<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Insulation<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Cheap rigid board; also the coffee-cup material<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>Still air (25 \u00b0C)<\/strong><\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\"><strong>0.026<\/strong><\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Gas<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">The reason almost every insulator works at all<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">PIR \/ polyurethane board<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">0.022\u20130.028<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Insulation<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Beats still air \u2014 see the note below<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Argon (glazing fill)<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">0.018<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Gas<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Heavier, slower molecules than air; fills good double glazing<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Silica aerogel<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">0.013\u20130.020<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Advanced<\/td>\n<td style=\"padding:9px;border:1px solid #D9CFB8;\">Nanopores stop air molecules moving freely<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>Values are for room temperature, roughly 20\u201325 \u00b0C. Building-material figures are genuinely variable \u2014 density, moisture and manufacturer all shift them, which is why NIST maintains a whole measured database of them in its <a href=\"https:\/\/srdata.nist.gov\/insulation\/\" target=\"_blank\" rel=\"noopener\">Heat Transmission Properties of Insulating and Building Materials<\/a> reference collection.<\/p>\n\n<p>Here is the detail most tables skip. PIR foam beats still air, which sounds impossible for something made of plastic and gas. The trick is that its closed cells are small enough to stop convection currents forming <em>and<\/em> they are filled with a heavy blowing gas whose fat, sluggish molecules carry less energy than nitrogen and oxygen do.<\/p>\n\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Fourier&#039;s Law Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/fouriers-law.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n\n<h2>How Fourier&#8217;s Law Works<\/h2>\n\n<p>Heat conduction works because temperature is really just molecular agitation. Where a solid is hot its atoms jiggle hard about their lattice positions; where it is cool they jiggle gently. Neighbouring atoms are coupled, so the vigorous ones knock energy into the sluggish ones and the disturbance ripples along.<\/p>\n\n<p>In metals a second, much faster channel opens up: free electrons drift through the lattice carrying energy with them. That extra channel is exactly why metals conduct both heat and electricity so well, and why the two abilities track each other so closely across the periodic table.<\/p>\n\n<svg role=\"img\" aria-label=\"Fourier's law slab diagram: heat conducting through a wall of thickness d and area A from a hot face at temperature T1 to a cold face at T2, with a linear temperature profile and the formula Q over t equals kA delta T over d\" viewBox=\"0 0 720 340\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:1.5em auto;\">\n<defs>\n<linearGradient id=\"flSlab\" x1=\"0\" y1=\"0\" x2=\"1\" y2=\"0\">\n<stop offset=\"0\" stop-color=\"#7A1F2B\" stop-opacity=\"0.75\"><\/stop>\n<stop offset=\"1\" stop-color=\"#142139\" stop-opacity=\"0.75\"><\/stop>\n<\/linearGradient>\n<marker id=\"flArr\" markerWidth=\"10\" markerHeight=\"10\" refX=\"7\" refY=\"3.5\" orient=\"auto\"><path d=\"M0,0 L7,3.5 L0,7 Z\" fill=\"#C8932A\"><\/path><\/marker>\n<marker id=\"flDim\" markerWidth=\"9\" markerHeight=\"9\" refX=\"4.5\" refY=\"3\" orient=\"auto\"><path d=\"M0,0 L6,3 L0,6 Z\" fill=\"#142139\"><\/path><\/marker>\n<marker id=\"flDimS\" markerWidth=\"9\" markerHeight=\"9\" refX=\"1.5\" refY=\"3\" orient=\"auto\"><path d=\"M6,0 L0,3 L6,6 Z\" fill=\"#142139\"><\/path><\/marker>\n<\/defs>\n<rect x=\"0\" y=\"0\" width=\"720\" height=\"340\" rx=\"8\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/rect>\n<text x=\"360\" y=\"30\" text-anchor=\"middle\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"18\" font-weight=\"bold\" fill=\"#7A1F2B\">Conduction through a slab<\/text>\n\n<rect x=\"250\" y=\"60\" width=\"180\" height=\"180\" fill=\"url(#flSlab)\" stroke=\"#142139\" stroke-width=\"2\"><\/rect>\n<text x=\"340\" y=\"156\" text-anchor=\"middle\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"22\" font-weight=\"bold\" fill=\"#FAF6EE\">k<\/text>\n<text x=\"340\" y=\"176\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"11\" fill=\"#FAF6EE\">conductivity<\/text>\n\n<rect x=\"120\" y=\"60\" width=\"130\" height=\"180\" fill=\"#7A1F2B\" opacity=\"0.14\"><\/rect>\n<rect x=\"430\" y=\"60\" width=\"130\" height=\"180\" fill=\"#142139\" opacity=\"0.12\"><\/rect>\n<text x=\"185\" y=\"88\" text-anchor=\"middle\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"15\" font-weight=\"bold\" fill=\"#7A1F2B\">HOT SIDE<\/text>\n<text x=\"185\" y=\"108\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#1F2E47\">T<tspan font-size=\"9\" dy=\"3\">1<\/tspan><\/text>\n<text x=\"495\" y=\"88\" text-anchor=\"middle\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"15\" font-weight=\"bold\" fill=\"#142139\">COLD SIDE<\/text>\n<text x=\"495\" y=\"108\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#1F2E47\">T<tspan font-size=\"9\" dy=\"3\">2<\/tspan><\/text>\n\n<line x1=\"180\" y1=\"140\" x2=\"600\" y2=\"140\" stroke=\"#C8932A\" stroke-width=\"3\" marker-end=\"url(#flArr)\"><\/line>\n<line x1=\"180\" y1=\"180\" x2=\"600\" y2=\"180\" stroke=\"#C8932A\" stroke-width=\"3\" marker-end=\"url(#flArr)\"><\/line>\n<line x1=\"180\" y1=\"100\" x2=\"600\" y2=\"100\" stroke=\"#C8932A\" stroke-width=\"3\" marker-end=\"url(#flArr)\"><\/line>\n<text x=\"620\" y=\"146\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"16\" font-weight=\"bold\" fill=\"#8A6A1E\">Q\/t<\/text>\n<text x=\"620\" y=\"164\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"11\" fill=\"#1F2E47\">watts<\/text>\n\n<line x1=\"250\" y1=\"262\" x2=\"430\" y2=\"262\" stroke=\"#142139\" stroke-width=\"1.5\" marker-start=\"url(#flDimS)\" marker-end=\"url(#flDim)\"><\/line>\n<text x=\"340\" y=\"281\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#142139\">thickness d<\/text>\n\n<line x1=\"232\" y1=\"60\" x2=\"232\" y2=\"240\" stroke=\"#142139\" stroke-width=\"1.5\" marker-start=\"url(#flDimS)\" marker-end=\"url(#flDim)\"><\/line>\n<text x=\"222\" y=\"155\" text-anchor=\"end\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" font-weight=\"bold\" fill=\"#142139\">area A<\/text>\n\n<path d=\"M250,215 L430,235\" stroke=\"#7A1F2B\" stroke-width=\"2\" stroke-dasharray=\"5,4\" fill=\"none\"><\/path>\n<text x=\"340\" y=\"252\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"10.5\" fill=\"#7A1F2B\">temperature falls linearly in steady state<\/text>\n\n<rect x=\"150\" y=\"296\" width=\"420\" height=\"30\" rx=\"4\" fill=\"#142139\"><\/rect>\n<text x=\"360\" y=\"317\" text-anchor=\"middle\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"17\" font-weight=\"bold\" fill=\"#C8932A\">Q\/t = k \u00b7 A \u00b7 \u0394T \/ d<\/text>\n<\/svg>\n\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;\">Fourier&#8217;s law for a flat slab: heat crosses area A, driven by the temperature difference and slowed by thickness d.<\/p>\n\n<h3>Why thickness divides rather than multiplies<\/h3>\n\n<p>Picture the slab as a queue heat has to shuffle through. Each extra millimetre adds another stretch of jostling to get past, so the flow slows.<\/p>\n\n<p>What actually drives conduction is the temperature <em>gradient<\/em> \u2014 how sharply temperature changes per metre, \u0394T\/d. Spread the same 20-degree drop over a thicker wall and the gradient flattens, so the push at every point weakens. In its general differential form the law is written q = \u2212k\u00b7(dT\/dx), where the minus sign encodes the direction: heat always flows down the temperature gradient, never up it. <a href=\"https:\/\/ocw.mit.edu\/courses\/16-050-thermal-energy-fall-2002\/87d9f4544b7fd64a77201382500d057c_10_part3.pdf\" target=\"_blank\" rel=\"noopener\">MIT OpenCourseWare&#8217;s heat-transfer notes<\/a> derive this form from first principles if you want the full argument (PDF).<\/p>\n\n<h3>What &#8220;steady state&#8221; actually assumes<\/h3>\n\n<p>The Q\/t = kA\u0394T\/d form applies once the temperature profile has stopped changing \u2014 the dashed line in the diagram above has settled into a straight slope. Before that, the wall is still soaking up heat and storing it.<\/p>\n\n<p>In practice a thin metal sheet reaches steady state in seconds; a thick masonry wall can take many hours. That lag is why heavy stone buildings stay cool through a hot afternoon, and it is governed by a different quantity \u2014 thermal diffusivity \u2014 not by Fourier&#8217;s law alone.<\/p>\n\n<h2>How to Calculate Heat Loss Through a Wall<\/h2>\n\n<p>Calculating heat loss through a wall means applying Fourier&#8217;s law to each layer, adding the layers&#8217; thermal resistances, and multiplying by area and temperature difference. Four steps get you there.<\/p>\n\n<ol>\n<li><strong>Convert every unit to SI.<\/strong> Thickness in metres, not millimetres \u2014 this single slip causes more wrong answers than anything else.<\/li>\n<li><strong>Find the thermal resistance of each layer:<\/strong> R = d\/k, in m\u00b2\u00b7K\/W.<\/li>\n<li><strong>Add the resistances<\/strong> in series, plus the inside and outside surface films.<\/li>\n<li><strong>Compute the loss:<\/strong> Q\/t = A\u00b7\u0394T \/ R<sub>total<\/sub>.<\/li>\n<\/ol>\n\n<h3>R-value, U-value and how they connect to k<\/h3>\n\n<p>Insulation is rarely sold by conductivity. It is sold by <strong>R-value<\/strong> \u2014 thermal resistance \u2014 because resistances of stacked layers simply add up, which conductivities do not. The <a href=\"https:\/\/www.energy.gov\/energysaver\/insulation\" target=\"_blank\" rel=\"noopener\">US Department of Energy&#8217;s Energy Saver guidance<\/a> uses exactly this quantity to set recommended insulation levels by climate zone.<\/p>\n\n<div class=\"pf-formula\">R = d \/ k        U = 1 \/ R_total        Q\/t = U \u00b7 A \u00b7 \u0394T<\/div>\n\n<ul>\n<li><strong>R<\/strong> \u2014 thermal resistance of a layer, m\u00b2\u00b7K\/W. Higher is better.<\/li>\n<li><strong>U<\/strong> \u2014 thermal transmittance of the whole build-up, W\/(m\u00b2\u00b7K). Lower is better.<\/li>\n<li>Metric R and US R-values differ: an <strong>SI R of 2.5 m\u00b2\u00b7K\/W equals about R-14<\/strong> in US units, a factor of roughly 5.68.<\/li>\n<\/ul>\n\n<p>Two extra resistances belong in any honest wall calculation: thin, near-stagnant films of air clinging to each surface. The ISO 6946 standard values for horizontal heat flow are R<sub>si<\/sub> = 0.13 m\u00b2\u00b7K\/W inside and R<sub>se<\/sub> = 0.04 m\u00b2\u00b7K\/W outside.<\/p>\n\n<p>Those films sound trivial. For a single-glazed window they are not \u2014 they contribute far more resistance than the 4 mm of glass itself, which is precisely why Problem 2 below produces such an absurd-looking answer.<\/p>\n\n<figure style=\"margin:32px auto;max-width:640px;text-align:center;\">\n\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/08\/images.jpg\"\n\n       alt=\"Thermal image of a house showing heat loss by conduction through walls and windows, the effect described by Fourier's law\"\n\n       loading=\"lazy\"\n\n       style=\"width:100%;height:auto;border-radius:4px;\" width=\"745\" height=\"412\">\n\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">An infrared camera makes Fourier&#8217;s law visible: bright patches are where kA\u0394T\/d is largest.<\/figcaption>\n\n<\/figure>\n\n<h2>Real-World Examples of Fourier&#8217;s Law<\/h2>\n\n<p>Fourier&#8217;s law shows up wherever someone wants heat to move fast \u2014 or wants it to stop. Five cases where the four variables are being deliberately tuned:<\/p>\n\n<h3>1. Cookware<\/h3>\n\n<p>A pan base is a deliberate high-k, low-d design: copper or aluminium, a few millimetres thick, so heat crosses almost instantly and no hot spots survive. The handle inverts every choice \u2014 stainless steel or wood, long and thin, so barely any heat reaches your fingers.<\/p>\n\n<h3>2. Double and triple glazing<\/h3>\n\n<p>The glass is not the insulator. A sealed 16 mm gap of argon is, at k \u2248 0.018 against glass&#8217;s \u22481.0 \u2014 a fiftyfold improvement per millimetre. The panes exist only to hold the gas still, because a gas that can circulate stops conducting and starts convecting.<\/p>\n\n<h3>3. Computer heat sinks and thermal paste<\/h3>\n\n<p>A processor pushes 100 W or more through a chip the size of a thumbnail, so d must be tiny and k enormous. Thermal paste is the unglamorous hero here: it displaces microscopic air pockets between chip and heat sink, and air at k = 0.026 would otherwise throttle the entire path.<\/p>\n\n<h3>4. Winter clothing and duvets<\/h3>\n\n<p>Down, fleece and wool are not good insulators \u2014 the air they trap is. Loft the fibres and you thicken a still-air layer; compress them and you collapse d, which is exactly why a sleeping bag insulates almost nothing underneath you.<\/p>\n\n<h3>5. Building insulation and the heating bill<\/h3>\n\n<p>Every watt Fourier&#8217;s law lets escape has to be replaced by your boiler or heat pump. Because Q\/t is a <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/power-in-physics\/\">power<\/a>, multiplying it by hours converts it straight into kilowatt-hours and money \u2014 Problem 6 walks through that conversion.<\/p>\n\n<h2>Common Misconceptions About Fourier&#8217;s Law<\/h2>\n\n<h3>&#8220;\u0394T has to be converted to kelvin&#8221;<\/h3>\n\n<p>It does not, and this trips up a surprising number of students. A one-degree change on the Celsius scale <em>is<\/em> a one-kelvin change, so a difference of 20 \u00b0C equals a difference of 20 K exactly.<\/p>\n\n<p>Contrast that with radiation, where the Stefan-Boltzmann law needs absolute temperatures raised to the fourth power. There, kelvin is compulsory. Here, only the gap matters.<\/p>\n\n<h3>&#8220;Doubling the insulation halves the heat loss&#8221;<\/h3>\n\n<p>True for a bare slab in isolation. False for a real wall, because the other layers and the surface films do not double with it.<\/p>\n\n<p>Take the wall in Problem 7: going from 100 mm to 200 mm of mineral wool takes R from 2.89 to 5.39 m\u00b2\u00b7K\/W, cutting the loss by 46% rather than 50%. Push to 400 mm and the extra 200 mm buys only another 32%. Insulation obeys steep diminishing returns.<\/p>\n\n<h3>&#8220;k is a fixed constant for each material&#8221;<\/h3>\n\n<p>Conductivity drifts with temperature, density and \u2014 above all \u2014 moisture. Water conducts about 23 times better than still air, so insulation that gets damp loses much of its point.<\/p>\n\n<p>In practice this is why building codes specify moisture control alongside insulation, and why textbook k values are quoted at a stated temperature rather than as universal constants.<\/p>\n\n<h3>&#8220;Fourier&#8217;s law tells you how long something takes to heat up&#8221;<\/h3>\n\n<p>It does not. The law gives a rate of flow once conditions are steady, not the time to reach that state.<\/p>\n\n<p>How quickly a temperature front moves through a material is set by thermal diffusivity, \u03b1 = k\/(\u03c1c) \u2014 conductivity divided by density and <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/thermodynamics\/specific-heat-capacity\/\">specific heat capacity<\/a>. A material can conduct well yet warm through slowly if it stores a lot of energy per degree.<\/p>\n\n<h2>How Fourier&#8217;s Law Relates to the Rest of Thermodynamics<\/h2>\n\n<p>Fourier&#8217;s law is one of three heat-transfer rate laws, and it only governs conduction. Heat also moves by fluid motion and by electromagnetic waves, each with its own equation \u2014 our guide to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/thermodynamics\/conduction-convection-radiation\/\">conduction, convection and radiation<\/a> sets the three side by side.<\/p>\n\n<p>It also sits downstream of a deeper principle. The <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/thermodynamics\/laws-of-thermodynamics\/\">second law of thermodynamics<\/a> insists heat flows from hot to cold and never spontaneously back; Fourier&#8217;s law simply puts a number on how fast. That is what the minus sign in q = \u2212k\u00b7(dT\/dx) is quietly enforcing.<\/p>\n\n<p>Two more connections are worth holding onto. Fourier&#8217;s law concerns energy <em>in transit<\/em>, which is why the distinction between <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/thermodynamics\/heat-vs-temperature\/\">heat and temperature<\/a> matters so much here \u2014 temperature difference is the driver, heat is what moves. And because Q\/t is measured in watts, every answer you get is a power, directly comparable to a light bulb or a kettle.<\/p>\n\n<h2>Worked Problems<\/h2>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">An aluminium saucepan base has k = 237 W\/(m\u00b7K), area 0.030 m\u00b2 and thickness 5.0 mm. The hob-side face sits at 103 \u00b0C while the water side is at 100 \u00b0C. Find the rate of heat conduction through the base.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Use Fourier&#8217;s law, Q\/t = k\u00b7A\u00b7\u0394T \/ d.\nStep 2: Convert thickness to metres: d = 5.0 mm = 0.0050 m. \u0394T = 103 \u2212 100 = 3.0 K.\nStep 3: Q\/t = (237 \u00d7 0.030 \u00d7 3.0) \/ 0.0050 = 21.33 \/ 0.0050.\n<strong>Answer: 4.3 \u00d7 10\u00b3 W (about 4.3 kW)<\/strong>\nSanity check: a domestic hob ring delivers 1\u20133 kW, so a 3-degree gradient is more than enough to carry it. That is why the base can be thin and the water still boils.\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A single-glazed window pane is 1.5 m\u00b2 in area and 4.0 mm thick, with glass of k = 1.0 W\/(m\u00b7K). The inner glass surface is at 20 \u00b0C and the outer surface at 5 \u00b0C. Calculate the conduction rate through the glass, then comment on the result.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Q\/t = k\u00b7A\u00b7\u0394T \/ d, with d = 4.0 mm = 0.0040 m and \u0394T = 15 K.\nStep 2: Q\/t = (1.0 \u00d7 1.5 \u00d7 15) \/ 0.0040 = 22.5 \/ 0.0040.\nStep 3: Q\/t = 5625 W.\n<strong>Answer: 5.6 \u00d7 10\u00b3 W<\/strong>\nComment: no real window loses 5.6 kW. The calculation assumed the glass surfaces themselves sit at 20 \u00b0C and 5 \u00b0C, but the still-air films either side hold most of the resistance, so the true glass-surface \u0394T is only a fraction of a degree. Glass is such a poor barrier that the air does the insulating.\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A 5.0 mm thick sheet of unknown plastic with area 0.020 m\u00b2 conducts heat at 25 W when a 50 K temperature difference is applied across it. Find its thermal conductivity.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Rearrange Fourier&#8217;s law for k: k = (Q\/t)\u00b7d \/ (A\u00b7\u0394T).\nStep 2: Substitute with units: k = (25 W \u00d7 0.0050 m) \/ (0.020 m\u00b2 \u00d7 50 K).\nStep 3: k = 0.125 \/ 1.00 = 0.125 W\/(m\u00b7K).\n<strong>Answer: k = 0.13 W\/(m\u00b7K) to 2 s.f.<\/strong>\nThat sits between wood and plasterboard, which is a plausible value for a rigid plastic.\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">How thick must a layer of mineral wool with k = 0.040 W\/(m\u00b7K) be to limit the conduction loss through a 10 m\u00b2 ceiling to 50 W when the temperature difference is 20 K?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Rearrange for thickness: d = k\u00b7A\u00b7\u0394T \/ (Q\/t).\nStep 2: Substitute: d = (0.040 \u00d7 10 \u00d7 20) \/ 50 = 8.0 \/ 50.\nStep 3: d = 0.16 m.\n<strong>Answer: d = 0.16 m (160 mm)<\/strong>\nIn practice loft insulation is laid far thicker than this \u2014 typically 270\u2013300 mm \u2014 because the target loss is much lower than 50 W and because settling reduces the effective depth.\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">A wall is built from 100 mm of brick (k = 0.72) against 100 mm of EPS insulation (k = 0.035). Its area is 15 m\u00b2 and the temperature difference across it is 20 K. Find the heat-loss rate, and work out how much of the temperature drop occurs across each layer.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Layers in series add their thermal resistances, R = d\/k.\nStep 2: R(brick) = 0.100 \/ 0.72 = 0.1389 m\u00b2\u00b7K\/W. R(EPS) = 0.100 \/ 0.035 = 2.857 m\u00b2\u00b7K\/W. R(total) = 2.996 m\u00b2\u00b7K\/W.\nStep 3: Q\/t = A\u00b7\u0394T \/ R(total) = (15 \u00d7 20) \/ 2.996 = 300 \/ 2.996 = 100.1 W.\nStep 4: Heat flux q = \u0394T \/ R(total) = 20 \/ 2.996 = 6.68 W\/m\u00b2. Drop across brick = q \u00d7 R(brick) = 6.68 \u00d7 0.1389 = 0.93 K. Drop across EPS = 6.68 \u00d7 2.857 = 19.07 K.\n<strong>Answer: Q\/t = 100 W; about 0.9 K falls across the brick and 19.1 K across the insulation<\/strong>\nThe 100 mm of insulation does 95% of the work. Identical thicknesses, twentyfold difference in effect.\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">Using the wall from Problem 5 losing 100.1 W, calculate the energy lost in 24 hours in joules and in kilowatt-hours, and the cost at 0.30 per kWh.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Energy = power \u00d7 time, so E = (Q\/t) \u00d7 t.\nStep 2: In SI: E = 100.1 W \u00d7 86,400 s = 8.65 \u00d7 10\u2076 J = 8.65 MJ.\nStep 3: In kWh: E = 100.1 W \u00d7 24 h = 2403 Wh = 2.40 kWh.\nStep 4: Cost = 2.40 kWh \u00d7 0.30 = 0.72.\n<strong>Answer: 8.65 MJ, or 2.40 kWh, costing about 0.72 per day<\/strong>\nA kilowatt-hour is simply 1000 W sustained for one hour, which is 3.6 MJ. Note this is one wall only, in steady state, ignoring air leakage.\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">A cavity wall is built up as follows: 12.5 mm plasterboard (k = 0.16), 100 mm mineral wool (k = 0.040), 102 mm brick (k = 0.72). Include surface resistances Rsi = 0.13 and Rse = 0.04 m\u00b2\u00b7K\/W. Find the U-value and the heat loss for a 20 m\u00b2 wall with a 21 K temperature difference.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Total resistance is the sum of every layer plus both surface films.\nStep 2: R(si) = 0.13; R(plasterboard) = 0.0125 \/ 0.16 = 0.0781; R(wool) = 0.100 \/ 0.040 = 2.500; R(brick) = 0.102 \/ 0.72 = 0.1417; R(se) = 0.04.\nStep 3: R(total) = 0.13 + 0.0781 + 2.500 + 0.1417 + 0.04 = 2.890 m\u00b2\u00b7K\/W.\nStep 4: U = 1 \/ R(total) = 1 \/ 2.890 = 0.346 W\/(m\u00b2\u00b7K).\nStep 5: Q\/t = U\u00b7A\u00b7\u0394T = 0.346 \u00d7 20 \u00d7 21 = 145 W.\n<strong>Answer: U = 0.35 W\/(m\u00b2\u00b7K) and Q\/t = 145 W<\/strong>\nThat U-value is typical of a modern insulated cavity wall. Note the mineral wool alone supplies 87% of the total resistance \u2014 the brick contributes under 5%.\n<\/div><\/details><\/div>\n\n<h2>Frequently Asked Questions<\/h2>\n\n<details class=\"pf-faq-item\"><summary>What is Fourier&#039;s law in simple terms?<\/summary><div class=\"pf-faq-item-answer\">\nFourier&#8217;s law says heat flows through a material faster when the material conducts well, when there is more area for it to cross, and when the temperature difference is larger \u2014 and slower when the material is thicker. Written as Q\/t = kA\u0394T\/d, it turns those four factors into a heat-flow rate in watts.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What are the units of thermal conductivity?<\/summary><div class=\"pf-faq-item-answer\">\nThermal conductivity k is measured in watts per metre per kelvin, W\/(m\u00b7K). Read it as the watts crossing one square metre of a one-metre-thick slab for each kelvin of temperature difference. Copper is about 401 W\/(m\u00b7K), still air about 0.026, and mineral wool around 0.040.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Do I need to convert \u0394T to kelvin in Fourier&#039;s law?<\/summary><div class=\"pf-faq-item-answer\">\nNo. Because the equation uses a temperature difference rather than an absolute temperature, and one Celsius degree is the same size as one kelvin, a difference of 20 \u00b0C is identical to 20 K. Absolute temperatures are only required in laws that use T itself, such as the Stefan-Boltzmann radiation law.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What is the difference between thermal conductivity and R-value?<\/summary><div class=\"pf-faq-item-answer\">\nThermal conductivity k is a property of the material alone, while R-value describes a specific layer of a given thickness, calculated as R = d\/k. Conductivity cannot be added between layers, but resistances can, which is why insulation is sold by R-value. Lower k and higher R both mean better insulation.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Does doubling insulation thickness halve the heat loss?<\/summary><div class=\"pf-faq-item-answer\">\nOnly for that layer in isolation. In a real wall the other layers and the surface air films stay unchanged, so the total resistance rises by less than a factor of two. Doubling a typical 100 mm mineral-wool layer cuts the whole-wall loss by roughly 46%, and further additions give steadily smaller gains.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Why does Fourier&#039;s law have a minus sign in some textbooks?<\/summary><div class=\"pf-faq-item-answer\">\nThe differential form is written q = \u2212k\u00b7(dT\/dx), where the minus sign records direction rather than magnitude. Temperature decreases in the direction heat travels, so the gradient is negative while the heat flow is positive. The simplified Q\/t = kA\u0394T\/d form drops the sign by taking \u0394T as hot minus cold.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>How do I convert a heat loss in watts into kilowatt-hours?<\/summary><div class=\"pf-faq-item-answer\">\nMultiply the power in watts by the number of hours, then divide by 1000. A wall losing 100 W for 24 hours uses 100 \u00d7 24 \/ 1000 = 2.4 kWh. One kilowatt-hour equals 3.6 million joules, so that same figure is about 8.6 MJ of energy your heating system has to replace.\n<\/div><\/details>\n\n<h2>Key Takeaways<\/h2>\n\n<ul>\n<li>Fourier&#8217;s law gives the steady-state conduction rate: <strong>Q\/t = kA\u0394T\/d<\/strong>, in watts.<\/li>\n<li><strong>k<\/strong>, thermal conductivity, spans four orders of magnitude \u2014 from about 0.015 W\/(m\u00b7K) for aerogel to 401 for copper.<\/li>\n<li>Area and temperature difference scale the loss directly; <strong>thickness divides it<\/strong>, so insulation shows diminishing returns.<\/li>\n<li>For layered walls, convert to resistances (R = d\/k), add them in series, and use Q\/t = A\u00b7\u0394T\/R<sub>total<\/sub>.<\/li>\n<li>\u0394T can be in \u00b0C or K \u2014 but the law covers <strong>conduction only<\/strong>, and only once conditions are steady.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Fourier&#8217;s law sets the steady rate of heat conduction through a slab. This guide covers the formula, thermal conductivity values for common materials, and seven worked heat-loss problems.<\/p>\n","protected":false},"author":1,"featured_media":716,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[],"class_list":["post-713","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-thermodynamics"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/713","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=713"}],"version-history":[{"count":2,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/713\/revisions"}],"predecessor-version":[{"id":717,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/713\/revisions\/717"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/716"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=713"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=713"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=713"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}