{"id":591,"date":"2026-07-17T11:34:31","date_gmt":"2026-07-17T11:34:31","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=591"},"modified":"2026-07-17T11:34:32","modified_gmt":"2026-07-17T11:34:32","slug":"free-fall-physics","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/kinematics\/free-fall-physics\/","title":{"rendered":"Free Fall Physics: Formula &amp; Real Examples"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\n\nFree fall physics describes any motion in which gravity is the only force acting on an object, so every object accelerates downward at the same rate g \u2014 about 9.81 m\/s\u00b2 on Earth \u2014 no matter how heavy it is. Distance fallen from rest equals half g times time squared; speed equals g times time. Air resistance must be negligible.\n\n<\/p><\/div>\n\n<p>Hold a coin in one hand and your phone in the other, then open both hands at the same instant. They hit the floor together \u2014 and some part of you still expects the phone to win, because it is roughly forty times heavier.<\/p>\n\n<p>That instinct is ancient, and it is wrong. Settling it took two thousand years, a set of grooved wooden ramps, and eventually an astronaut standing on the Moon with a hammer in one glove and a falcon feather in the other. The physics that explains all of it fits into two short equations.<\/p>\n\n<h2>What Is Free Fall in Physics?<\/h2>\n\n<p>Free fall is motion in which gravity is the only force acting on an object. Nothing else \u2014 no air resistance, no rope, no table, no thrust \u2014 is allowed to push or pull on it.<\/p>\n\n<p>Notice what that definition does <em>not<\/em> say. It says nothing about moving downward, and nothing about starting from rest.<\/p>\n\n<p>A ball you throw straight up is in free fall from the moment it leaves your fingers until the moment you catch it \u2014 rising, hanging, and dropping. Its speed changes constantly, but throughout that whole flight only gravity acts on it, so it qualifies. The everyday word &#8220;falling&#8221; is a poor guide here; the physics test is simply <em>what forces are acting?<\/em><\/p>\n\n<p>And free fall is defined by an <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/kinematics\/acceleration-in-physics\/\">acceleration<\/a>, not a speed. An object in free fall does not fall at 9.81 m\/s. It falls with its speed <em>increasing<\/em> by 9.81 m\/s during every second it keeps falling \u2014 a very different claim, and the one students most often garble in an exam.<\/p>\n\n<p>Run any scenario through the single test below and the answer falls out.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#0A1628;color:#FAF6EE;\">\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Scenario<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Forces acting<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Free fall?<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Ball dropped inside a vacuum tube<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Gravity only<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>Yes<\/strong> \u2014 the textbook case<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Ball thrown straight up, still in the air<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Gravity only<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>Yes<\/strong> \u2014 rising counts too<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Astronaut orbiting inside the ISS<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Gravity only<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>Yes<\/strong> \u2014 permanently falling<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Skydiver in the first moment after jumping<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Gravity, plus a tiny drag force<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Near enough, briefly<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Skydiver at steady terminal velocity<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Gravity balanced by drag<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>No<\/strong> \u2014 zero acceleration<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Feather drifting down through air<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Gravity, and drag almost as large<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>No<\/strong> \u2014 drag dominates<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Apple sitting on a table<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Gravity balanced by the normal force<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>No<\/strong> \u2014 not even moving<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;\">The free-fall test: strip away every force except gravity. If anything is left, it is not free fall.<\/p>\n\n<h2>The Free Fall Formulas<\/h2>\n\n<p>Free fall from rest is described by three equations, and each one answers a different question. Start with the distance fallen after a given time:<\/p>\n\n<div class=\"pf-formula\">h = \u00bdgt\u00b2<\/div>\n\n<p>Then the speed reached after that time:<\/p>\n\n<div class=\"pf-formula\">v = gt<\/div>\n\n<p>And the one that skips time entirely, when you know the height but not the clock:<\/p>\n\n<div class=\"pf-formula\">v\u00b2 = 2gh<\/div>\n\n<p>Every symbol, with its SI unit:<\/p>\n\n<ul>\n<li><strong>h<\/strong> \u2014 distance fallen from the release point, in metres (m). Not the height of the building: the distance actually covered.<\/li>\n<li><strong>v<\/strong> \u2014 speed at that moment, in metres per second (m\/s).<\/li>\n<li><strong>t<\/strong> \u2014 time since release, in seconds (s).<\/li>\n<li><strong>g<\/strong> \u2014 acceleration due to gravity, in metres per second squared (m\/s\u00b2). Take g = 9.81 m\/s\u00b2 on Earth unless a question says otherwise.<\/li>\n<\/ul>\n\n<p>Two conditions are baked into all three. The object must start from rest, and air resistance must be negligible \u2014 break either one and the formulas quietly stop being true.<\/p>\n\n<p>If the object does <em>not<\/em> start from rest \u2014 you threw it rather than dropped it \u2014 swap in the general constant-acceleration forms with initial speed u:<\/p>\n\n<div class=\"pf-formula\">h = ut + \u00bdgt\u00b2,  v = u + gt,  v\u00b2 = u\u00b2 + 2gh<\/div>\n\n<p>These are simply the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/kinematics\/suvat-equations\/\">SUVAT equations<\/a> with the acceleration set to g. Free fall is not a special branch of physics; it is ordinary constant-acceleration motion that happens to have gravity supplying the acceleration.<\/p>\n\n<p>One sign convention saves enormous grief: pick a positive direction <em>before<\/em> you substitute anything, then stay loyal to it. Call down positive and a dropped stone gives all-positive numbers, while a thrown ball starts with a negative u. Get this backwards and the algebra will still run \u2014 it will simply hand you a confident wrong answer. If you would rather check a result than grind it out, our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/free-fall\">Free Fall Calculator<\/a> solves for distance, speed, time or gravity from whichever two you already know.<\/p>\n\n<h2>How Free Fall Works: Why the Mass Cancels<\/h2>\n\n<p>Mass disappears from free fall because the force pulling an object down and the inertia resisting that pull both scale with mass by exactly the same factor. Here is the whole argument in three lines.<\/p>\n\n<p>The gravitational pull on a mass m \u2014 its weight \u2014 is:<\/p>\n\n<div class=\"pf-formula\">W = mg<\/div>\n\n<p>And <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/newtons-second-law\/\">Newton&#8217;s second law<\/a> says that whatever net force acts produces an acceleration:<\/p>\n\n<div class=\"pf-formula\">F = ma<\/div>\n\n<p>In free fall, weight <em>is<\/em> the net force. So set them equal:<\/p>\n\n<div class=\"pf-formula\">ma = mg, so a = g<\/div>\n\n<p>The mass cancels. Not approximately, not for most objects \u2014 it cancels exactly, and it cancels for every object.<\/p>\n\n<p>Think about what that means physically. A bowling ball is pulled toward Earth far harder than a marble, and that extra pull should win. But the bowling ball is also far more stubborn: it takes proportionally more force to shift it.<\/p>\n\n<p>Double the mass and you double the pull <em>and<\/em> double the reluctance, in the same breath. The two effects divide out perfectly, and everything falls at the same rate.<\/p>\n\n<p>That perfect cancellation is not a coincidence, and physicists have never treated it as one. It requires that the mass appearing in W = mg (how strongly gravity grabs you) is identical to the mass in F = ma (how strongly you resist being pushed). There is no obvious reason those two properties should be the same number \u2014 yet every experiment ever performed says they are, to extraordinary precision. That fact is the seed Einstein grew general relativity from.<\/p>\n\n<p>So the honest answer to &#8220;why does a hammer fall as fast as a feather?&#8221; is not really about hammers. It is that gravity, uniquely among forces, cares about mass in exactly the way inertia does \u2014 so mass never gets a vote.<\/p>\n\n<p>The picture below is what that looks like second by second.<\/p>\n<svg viewBox=\"0 0 700 490\" role=\"img\" aria-label=\"Free fall physics strobe diagram: a ball released from rest has fallen 4.9 m after 1 second, 19.6 m after 2 seconds and 44.1 m after 3 seconds, with the gaps growing in the ratio 1 to 3 to 5\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:700px;display:block;margin:28px auto;\">\n<rect x=\"0.5\" y=\"0.5\" width=\"699\" height=\"489\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/rect>\n<text x=\"350\" y=\"27\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#0A1628\">Free fall from rest, photographed once a second (g = 9.81 m\/s\u00b2)<\/text>\n<line x1=\"120\" y1=\"40\" x2=\"600\" y2=\"40\" stroke=\"#D9CFB8\" stroke-width=\"1\" stroke-dasharray=\"4 4\"><\/line>\n<line x1=\"240\" y1=\"40\" x2=\"240\" y2=\"450\" stroke=\"#C5D0DC\" stroke-width=\"2\" stroke-dasharray=\"6 6\"><\/line>\n<line x1=\"150\" y1=\"40\" x2=\"150\" y2=\"420\" stroke=\"#7A1F2B\" stroke-width=\"1.5\"><\/line>\n<line x1=\"142\" y1=\"40\" x2=\"158\" y2=\"40\" stroke=\"#7A1F2B\" stroke-width=\"1.5\"><\/line>\n<line x1=\"142\" y1=\"82\" x2=\"158\" y2=\"82\" stroke=\"#7A1F2B\" stroke-width=\"1.5\"><\/line>\n<line x1=\"142\" y1=\"209\" x2=\"158\" y2=\"209\" stroke=\"#7A1F2B\" stroke-width=\"1.5\"><\/line>\n<line x1=\"142\" y1=\"420\" x2=\"158\" y2=\"420\" stroke=\"#7A1F2B\" stroke-width=\"1.5\"><\/line>\n<text x=\"134\" y=\"66\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#7A1F2B\">4.9 m<\/text>\n<text x=\"134\" y=\"151\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#7A1F2B\">14.7 m<\/text>\n<text x=\"134\" y=\"320\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#7A1F2B\">24.5 m<\/text>\n<text x=\"150\" y=\"443\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" font-style=\"italic\" fill=\"#1F2E47\">covered in each second<\/text>\n<circle cx=\"240\" cy=\"40\" r=\"11\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/circle>\n<circle cx=\"240\" cy=\"82\" r=\"11\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/circle>\n<circle cx=\"240\" cy=\"209\" r=\"11\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/circle>\n<circle cx=\"240\" cy=\"420\" r=\"11\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/circle>\n<text x=\"262\" y=\"45\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" fill=\"#0A1628\"><tspan font-weight=\"700\">t = 0 s<\/tspan>  \u00b7  v = 0  \u00b7  fallen 0 m<\/text>\n<text x=\"262\" y=\"87\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" fill=\"#0A1628\"><tspan font-weight=\"700\">t = 1 s<\/tspan>  \u00b7  v = 9.8 m\/s  \u00b7  fallen 4.9 m<\/text>\n<text x=\"262\" y=\"214\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" fill=\"#0A1628\"><tspan font-weight=\"700\">t = 2 s<\/tspan>  \u00b7  v = 19.6 m\/s  \u00b7  fallen 19.6 m<\/text>\n<text x=\"262\" y=\"425\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" fill=\"#0A1628\"><tspan font-weight=\"700\">t = 3 s<\/tspan>  \u00b7  v = 29.4 m\/s  \u00b7  fallen 44.1 m<\/text>\n<text x=\"605\" y=\"45\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" font-style=\"italic\" fill=\"#1F2E47\">released<\/text>\n<text x=\"350\" y=\"472\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\">The gaps grow 1 : 3 : 5 \u2014 five times more ground in the third second than in the first.<\/text>\n<\/svg>\n\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:0;\">Free fall physics in one image: equal time steps, wildly unequal distances. That widening is the t\u00b2 in h = \u00bdgt\u00b2.<\/p>\n\n<p>Look at the gaps rather than the ball. In the first second it covers 4.9 m; in the third, 24.5 m. The <em>speed<\/em> is climbing at a steady, boring 9.81 m\/s every second \u2014 but distance depends on t\u00b2, so it snowballs. This is exactly why a fall from 40 m is far more than twice as dangerous as a fall from 20 m.<\/p>\n\n<p>Plot the same fall two ways and the split personality is obvious.<\/p>\n\n<svg viewBox=\"0 0 700 330\" role=\"img\" aria-label=\"Two free fall physics graphs side by side: distance against time curves upward as a parabola reaching 44.1 m at 3 seconds, while speed against time is a straight line of slope 9.81 reaching 29.4 metres per second\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:700px;display:block;margin:28px auto;\">\n<rect x=\"0.5\" y=\"0.5\" width=\"699\" height=\"329\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/rect>\n<text x=\"185\" y=\"26\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"14\" font-weight=\"700\" fill=\"#0A1628\">Distance vs time \u2014 a curve<\/text>\n<line x1=\"60\" y1=\"36\" x2=\"60\" y2=\"260\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/line>\n<line x1=\"60\" y1=\"260\" x2=\"315\" y2=\"260\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/line>\n<line x1=\"60\" y1=\"236\" x2=\"300\" y2=\"236\" stroke=\"#C5D0DC\" stroke-width=\"1\" stroke-dasharray=\"3 3\"><\/line>\n<line x1=\"60\" y1=\"164\" x2=\"300\" y2=\"164\" stroke=\"#C5D0DC\" stroke-width=\"1\" stroke-dasharray=\"3 3\"><\/line>\n<line x1=\"60\" y1=\"44\" x2=\"300\" y2=\"44\" stroke=\"#C5D0DC\" stroke-width=\"1\" stroke-dasharray=\"3 3\"><\/line>\n<path d=\"M60 260 Q180 260 300 44.2\" fill=\"none\" stroke=\"#7A1F2B\" stroke-width=\"2.5\"><\/path>\n<circle cx=\"140\" cy=\"236\" r=\"4.5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1\"><\/circle>\n<circle cx=\"220\" cy=\"164\" r=\"4.5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1\"><\/circle>\n<circle cx=\"300\" cy=\"44\" r=\"4.5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1\"><\/circle>\n<text x=\"52\" y=\"240\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">4.9<\/text>\n<text x=\"52\" y=\"168\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">19.6<\/text>\n<text x=\"52\" y=\"48\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">44.1<\/text>\n<text x=\"140\" y=\"277\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">1<\/text>\n<text x=\"220\" y=\"277\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">2<\/text>\n<text x=\"300\" y=\"277\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">3<\/text>\n<text x=\"60\" y=\"30\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" font-weight=\"700\" fill=\"#0A1628\">h (m)<\/text>\n<text x=\"335\" y=\"264\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" font-weight=\"700\" fill=\"#0A1628\">t (s)<\/text>\n<text x=\"185\" y=\"300\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" fill=\"#1F2E47\">h = \u00bdgt\u00b2 \u2014 steepening<\/text>\n<text x=\"520\" y=\"26\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"14\" font-weight=\"700\" fill=\"#0A1628\">Speed vs time \u2014 a straight line<\/text>\n<line x1=\"400\" y1=\"36\" x2=\"400\" y2=\"260\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/line>\n<line x1=\"400\" y1=\"260\" x2=\"655\" y2=\"260\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/line>\n<path d=\"M400 260 L640 44.2 L640 260 Z\" fill=\"#C8932A\" fill-opacity=\"0.28\" stroke=\"none\"><\/path>\n<line x1=\"400\" y1=\"260\" x2=\"640\" y2=\"44.2\" stroke=\"#7A1F2B\" stroke-width=\"2.5\"><\/line>\n<circle cx=\"480\" cy=\"188\" r=\"4.5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1\"><\/circle>\n<circle cx=\"560\" cy=\"116\" r=\"4.5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1\"><\/circle>\n<circle cx=\"640\" cy=\"44\" r=\"4.5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1\"><\/circle>\n<text x=\"392\" y=\"192\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">9.8<\/text>\n<text x=\"392\" y=\"120\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">19.6<\/text>\n<text x=\"392\" y=\"48\" text-anchor=\"end\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">29.4<\/text>\n<text x=\"480\" y=\"277\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">1<\/text>\n<text x=\"560\" y=\"277\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">2<\/text>\n<text x=\"640\" y=\"277\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" fill=\"#1F2E47\">3<\/text>\n<text x=\"400\" y=\"30\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" font-weight=\"700\" fill=\"#0A1628\">v (m\/s)<\/text>\n<text x=\"675\" y=\"264\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" font-weight=\"700\" fill=\"#0A1628\">t (s)<\/text>\n<text x=\"424\" y=\"86\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" font-style=\"italic\" fill=\"#7A1F2B\">slope = g = 9.81 m\/s\u00b2<\/text>\n<text x=\"566\" y=\"222\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"11\" font-weight=\"700\" fill=\"#0A1628\">shaded area = 44.1 m<\/text>\n<text x=\"520\" y=\"300\" text-anchor=\"middle\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\" fill=\"#1F2E47\">v = gt \u2014 constant slope<\/text>\n<\/svg>\n\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:0;\">The same three seconds, two views. Speed rises in a straight line; the area beneath that line is the distance fallen.<\/p>\n\n<p>The right-hand graph carries a bonus. The area under a speed\u2013time line always equals the distance travelled, and here that area is a triangle: \u00bd \u00d7 3 s \u00d7 29.43 m\/s = 44.1 m. That is h = \u00bdgt\u00b2 falling out of pure geometry \u2014 no calculus required.<\/p>\n\n<p>Drop the two masses in the lab below and watch the readouts. The weights differ. The fall times refuse to.<\/p>\n\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Free Fall Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/free-fall.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n\n<h2>Real-World Examples of Free Fall<\/h2>\n\n<p>True free fall is rarer than the textbooks imply \u2014 Earth&#8217;s atmosphere spoils almost every case. These five are the ones worth knowing.<\/p>\n\n<h3>1. A hammer and a feather on the Moon<\/h3>\n\n<p>At the end of the final Apollo 15 moonwalk in 1971, Commander David Scott held out a geology hammer and a falcon feather and let go of both. NASA&#8217;s account records <a href=\"https:\/\/science.nasa.gov\/resource\/the-apollo-15-hammer-feather-drop\/\" target=\"_blank\" rel=\"noopener\">a 1.32 kg aluminium hammer and a 0.03 kg feather released from roughly 1.6 m<\/a>, which struck the surface together.<\/p>\n\n<p>The hammer outweighed the feather forty-four times over. With no lunar atmosphere to interfere, that counted for precisely nothing.<\/p>\n\n<figure style=\"margin:32px auto;max-width:640px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/07\/HammerAndFeather1a.jpg\"\n       alt=\"Apollo 15 hammer and feather drop demonstrating free fall physics on the Moon\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">Apollo 15, 1971: with no air to slow the feather, both objects hit the lunar surface together.<\/figcaption>\n<\/figure>\n\n<h3>2. The ruler-drop reaction test<\/h3>\n\n<p>Have someone hold a ruler vertically, hover your fingers at the zero mark, and catch it the instant they release. The distance it fell tells you your reaction time, because a free-falling ruler is a clock.<\/p>\n\n<p>Catch it at 18 cm and your reaction time was about 0.19 s. It is the cheapest free-fall experiment in existence, and problem 5 below works the number through.<\/p>\n\n<h3>3. The first second of a skydive<\/h3>\n\n<p>Step out of the aircraft and, for a brief moment, you genuinely are in free fall \u2014 drag needs speed to build, and at the instant you leave you have none. After one second you are falling at about 9.8 m\/s and have dropped roughly 4.9 m, near enough exactly what the formulas predict.<\/p>\n\n<p>The agreement then rots. Drag climbs with the square of your speed, and within a few seconds it is large enough that the equations on this page no longer describe you.<\/p>\n\n<h3>4. Astronauts on the space station<\/h3>\n\n<p>Everyone on the ISS is in free fall, all the time. That is the whole reason they float \u2014 not an absence of gravity, which at roughly 400 km up is still about 88% as strong as at ground level.<\/p>\n\n<p>The station is moving sideways so fast that its constant fall toward Earth keeps missing. Astronauts, station and floating pens all fall together at the same rate, so nothing presses on anything else, and everything drifts.<\/p>\n\n<h3>5. A stone dropped down a well<\/h3>\n\n<p>Drop a stone, count until the splash, and h = \u00bdgt\u00b2 hands you the depth. Two seconds implies about 19.6 m.<\/p>\n\n<p>In practice that answer is a little too deep, and here is the experience note most sources skip: your 2.0 s includes the time the <em>sound<\/em> took to climb back out. Solve it properly and the stone falls for 1.95 s to a depth of 18.6 m, with the remaining 0.05 s spent on the noise travelling up. The naive answer overshoots by about 1 m \u2014 around 6%.<\/p>\n<h2>Common Misconceptions About Free Fall<\/h2>\n\n<h3>Myth 1: Heavier objects fall faster<\/h3>\n\n<p>In free fall they do not \u2014 mass cancels out of the equations entirely, as the derivation above shows. Yet the myth survives because everyday experience appears to confirm it every single day.<\/p>\n\n<p>Drop a hammer and a feather in your kitchen and the hammer does win. The mistake is in the diagnosis. What you are watching is not gravity favouring the heavy object; it is <strong>air resistance<\/strong> punishing the light one. Gravity is treating them identically, and always was.<\/p>\n\n<p>Where mass sneaks back in is drag. A heavy, compact object has more weight to overcome the same drag force, so it holds its acceleration for longer. That is a story about air \u2014 not about gravity \u2014 and it belongs to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/terminal-velocity\/\">terminal velocity<\/a>, not to free fall.<\/p>\n\n<h3>Myth 2: Free fall means moving downward<\/h3>\n\n<p>Free fall means gravity is the only force acting \u2014 direction is irrelevant. A ball rising after you throw it is in free fall; so is one hanging momentarily at the top of its arc.<\/p>\n\n<p>The trap at that top point is worth spelling out, because examiners love it. At the peak the ball&#8217;s <em>velocity<\/em> is zero, and students duly write a = 0. But acceleration is not velocity. Gravity has not paused for the ball \u2014 the acceleration there is still 9.81 m\/s\u00b2 downward, which is precisely why the ball does not hover.<\/p>\n\n<h3>Myth 3: Astronauts float because there is no gravity in space<\/h3>\n\n<p>There is plenty of gravity in orbit \u2014 around 88% of surface strength at the ISS \u2014 and that gravity is exactly what holds the station in its orbit rather than letting it drift off into the solar system.<\/p>\n\n<p>Half the confusion lives in the word itself. Weight is a force, not a property you carry around: NIST <a href=\"https:\/\/www.nist.gov\/pml\/owm\/si-units-mass\" target=\"_blank\" rel=\"noopener\">defines weight as the force<\/a> that gives a body the local acceleration of free fall, and measures it in newtons. Your <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/weight-vs-mass\/\">mass<\/a>, in kilograms, does not change by a single gram on the way to orbit.<\/p>\n\n<p>So weightlessness is not the absence of gravity. It is the absence of everything <em>else<\/em>. You feel your weight only because a floor shoves up at you; remove the floor and let gravity act alone, and the sensation vanishes. Astronauts are not escaping gravity \u2014 they are in permanent free fall, which is the closest thing to a physics demonstration that lasts for years.<\/p>\n\n<h3>Myth 4: Galileo proved it by dropping balls off the Leaning Tower of Pisa<\/h3>\n\n<p>The tower story is almost certainly a legend, and it is worth retiring. Historians have long been sceptical that the famous drop ever happened; the tale traces mainly to a biography written by Galileo&#8217;s assistant decades later.<\/p>\n\n<p>His real evidence was cleverer. Falling bodies were far too quick for a 16th-century clock, so he rolled balls down gently inclined ramps instead \u2014 diluting gravity until the motion was slow enough to time by hand. Same physics, stretched out. From the ramps he extracted the pattern that distance grows with the square of time, which is h = \u00bdgt\u00b2 in disguise.<\/p>\n\n<h2>Free Fall on Other Worlds: g Changes Everything<\/h2>\n\n<p>Mass does not affect a free fall, but gravity certainly does \u2014 and g is a local number, not a universal one. Drop the same object from 10 m on four different worlds and you get four different answers.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#0A1628;color:#FAF6EE;\">\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">World<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">g (m\/s\u00b2)<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Time to fall 10 m<\/th>\n<th style=\"padding:10px;text-align:left;border:1px solid #D9CFB8;\">Impact speed<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Moon<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">1.62<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">3.51 s<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">5.69 m\/s<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Mars<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">3.72<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">2.32 s<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">8.63 m\/s<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>Earth<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>9.81<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>1.43 s<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>14.0 m\/s<\/strong><\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Jupiter*<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">24.79<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">0.90 s<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">22.3 m\/s<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;\">Same 10 m drop, same object, four worlds. *Jupiter has no solid surface; its g is quoted at the cloud tops.<\/p>\n\n<p>Notice the asymmetry. Jupiter&#8217;s gravity is fifteen times the Moon&#8217;s, but the fall is only about four times quicker \u2014 because t = \u221a(2h\/g) puts g under a square root. Quadruple the gravity and you halve the time, no more.<\/p>\n\n<p>Even Earth&#8217;s own g is not one number. The <a href=\"https:\/\/physics.nist.gov\/cgi-bin\/cuu\/Value?gn\" target=\"_blank\" rel=\"noopener\">standard acceleration of gravity<\/a> is defined as exactly 9.80665 m\/s\u00b2 \u2014 a convention agreed by committee, not a measurement of anywhere \u2014 while the real local value runs from roughly 9.78 m\/s\u00b2 near the equator to about 9.83 m\/s\u00b2 at the poles. You are marginally heavier in Oslo than in Singapore. For schoolwork, 9.81 m\/s\u00b2 is close enough for every problem on this page.<\/p>\n\n<h2>How Free Fall Relates to Terminal Velocity, Projectiles and SUVAT<\/h2>\n\n<p>Free fall is the idealised centre of a family of topics, and each neighbour is what you get by adding one ingredient back.<\/p>\n\n<p><strong>Add air resistance and you get terminal velocity.<\/strong> Drag grows as the falling object speeds up until it exactly balances weight; the net force hits zero, acceleration stops, and the fall settles at a constant speed. Everything on this page describes the first seconds of that story \u2014 the terminal-velocity article describes how it ends. Together they cover the whole drop.<\/p>\n\n<p><strong>Add sideways motion and you get projectile motion.<\/strong> Throw a stone horizontally instead of dropping it and the vertical half of the problem is unchanged: it still falls 4.9 m in the first second. Horizontal and vertical motion simply do not talk to each other, which is why a bullet fired level and a bullet dropped from the same height land at the same moment. Free fall is <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/projectile-motion-guide\/\">projectile motion<\/a> with the horizontal component set to zero.<\/p>\n\n<p><strong>Zoom out and you get SUVAT.<\/strong> Free fall is the constant-acceleration equations with a = g \u2014 no new physics, just a value substituted in.<\/p>\n\n<p><strong>Take the energy route and you get the same answers.<\/strong> Gravitational potential energy mgh converts into kinetic energy \u00bdmv\u00b2, so mgh = \u00bdmv\u00b2, and the m cancels again to give v = \u221a(2gh). That is v\u00b2 = 2gh arriving by a different road \u2014 a useful cross-check when a problem gives you height but no time.<\/p>\n\n<h2>Worked Problems<\/h2>\n\n<p>Eight problems, increasing in difficulty. Take g = 9.81 m\/s\u00b2 and ignore air resistance throughout.<\/p>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">A stone is dropped from rest off a bridge and hits the water 2.0 s later. How far did it fall?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Dropped from rest, so use h = \u00bdgt\u00b2.\n\nStep 2: Substitute \u2014 h = \u00bd \u00d7 9.81 m\/s\u00b2 \u00d7 (2.0 s)\u00b2 = \u00bd \u00d7 9.81 \u00d7 4.0 m.\n\nStep 3: Solve \u2014 h = 19.62 m.\n\n<strong>Answer: h = 19.6 m (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">How fast is a ball falling 3.0 s after being released from rest?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Speed from time in free fall uses v = gt.\n\nStep 2: Substitute \u2014 v = 9.81 m\/s\u00b2 \u00d7 3.0 s.\n\nStep 3: Solve \u2014 v = 29.43 m\/s.\n\n<strong>Answer: v = 29.4 m\/s (3 s.f.), directed downward<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A coin is dropped from a 45 m tower. How long does it take to land, and how fast is it going on impact?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Rearrange h = \u00bdgt\u00b2 for time \u2014 t = \u221a(2h\/g).\n\nStep 2: Substitute \u2014 t = \u221a(2 \u00d7 45 m \u00f7 9.81 m\/s\u00b2) = \u221a(9.174 s\u00b2).\n\nStep 3: Solve \u2014 t = 3.029 s.\n\nStep 4: Now the speed \u2014 v = gt = 9.81 \u00d7 3.029 = 29.71 m\/s.\n\nStep 5: Check it independently with v\u00b2 = 2gh = 2 \u00d7 9.81 \u00d7 45 = 882.9 m\u00b2\/s\u00b2, so v = 29.71 m\/s. The two routes agree.\n\n<strong>Answer: t = 3.03 s and v = 29.7 m\/s (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">A 0.15 kg baseball and a 7.3 kg bowling ball are released together from 20 m inside a vacuum chamber. Which lands first, and how fast is each moving on impact?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Check whether mass appears in t = \u221a(2h\/g) or v = \u221a(2gh). It does not \u2014 so the two objects must behave identically.\n\nStep 2: Time to fall \u2014 t = \u221a(2 \u00d7 20 \u00f7 9.81) = \u221a(4.077 s\u00b2) = 2.019 s, for both.\n\nStep 3: Impact speed \u2014 v = \u221a(2 \u00d7 9.81 \u00d7 20) = \u221a(392.4 m\u00b2\/s\u00b2) = 19.81 m\/s, for both.\n\nStep 4: Sanity-check the difference. Their weights are wildly unequal \u2014 1.47 N versus 71.6 N \u2014 but so are their inertias, in the same ratio of about 49:1. The accelerations come out equal.\n\n<strong>Answer: neither lands first \u2014 both take t = 2.02 s and arrive at v = 19.8 m\/s (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">In the ruler-drop reaction test, a ruler falls 18 cm before you catch it. What was your reaction time?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: The ruler starts from rest, so t = \u221a(2h\/g). Convert first: 18 cm = 0.18 m.\n\nStep 2: Substitute \u2014 t = \u221a(2 \u00d7 0.18 m \u00f7 9.81 m\/s\u00b2) = \u221a(0.03670 s\u00b2).\n\nStep 3: Solve \u2014 t = 0.1916 s.\n\nStep 4: Sanity-check the magnitude \u2014 typical human reaction times are around 0.15\u20130.25 s, so this is believable.\n\n<strong>Answer: t = 0.19 s (2 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">A ball is thrown straight up at 12 m\/s. How high does it rise, and how long until it returns to the thrower&#039;s hand?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: It does not start from rest, so use the general forms. Take up as positive, making the acceleration \u22129.81 m\/s\u00b2.\n\nStep 2: At the highest point v = 0. Use v\u00b2 = u\u00b2 + 2ah \u2014 0 = (12)\u00b2 + 2(\u22129.81)h.\n\nStep 3: Solve \u2014 h = 144 \u00f7 19.62 = 7.339 m.\n\nStep 4: Time to the top from v = u + at \u2014 0 = 12 \u2212 9.81t, so t = 1.223 s.\n\nStep 5: The rise and the fall are mirror images, so the round trip is 2 \u00d7 1.223 s = 2.446 s.\n\n<strong>Answer: it rises 7.34 m and returns after 2.45 s (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">A stone is thrown downward at 5.0 m\/s from a 30 m cliff. How long does it take to land, and at what speed?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Non-zero start again, and this time down is positive, so u = +5.0 m\/s. Use h = ut + \u00bdgt\u00b2.\n\nStep 2: Substitute \u2014 30 = 5.0t + 4.905t\u00b2, giving the quadratic 4.905t\u00b2 + 5.0t \u2212 30 = 0.\n\nStep 3: Apply the quadratic formula \u2014 t = [\u22125.0 + \u221a(25 + 588.6)] \u00f7 9.81 = (\u22125.0 + 24.77) \u00f7 9.81.\n\nStep 4: Solve \u2014 t = 2.015 s. (The negative root is discarded: it describes a time before the throw.)\n\nStep 5: Impact speed from v\u00b2 = u\u00b2 + 2gh = 25 + 588.6 = 613.6 m\u00b2\/s\u00b2, so v = 24.77 m\/s.\n\n<strong>Answer: t = 2.02 s and v = 24.8 m\/s (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 8<\/div><div class=\"pf-problem-question\">On the Moon (g = 1.62 m\/s\u00b2) an astronaut drops a hammer from 1.6 m, as on Apollo 15. How long does it take to land, and how much longer is that than the same drop on Earth?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: The hammer&#8217;s mass is not needed \u2014 free fall never uses it. Use t = \u221a(2h\/g).\n\nStep 2: On the Moon \u2014 t = \u221a(2 \u00d7 1.6 \u00f7 1.62) = \u221a(1.975 s\u00b2) = 1.406 s.\n\nStep 3: On Earth \u2014 t = \u221a(2 \u00d7 1.6 \u00f7 9.81) = \u221a(0.3262 s\u00b2) = 0.5711 s.\n\nStep 4: Take the ratio \u2014 1.406 \u00f7 0.5711 = 2.46. Confirm it algebraically: the ratio must be \u221a(g<sub>Earth<\/sub>\/g<sub>Moon<\/sub>) = \u221a(9.81\/1.62) = \u221a6.056 = 2.46. It matches.\n\n<strong>Answer: 1.41 s on the Moon against 0.571 s on Earth \u2014 about 2.5 times longer (3 s.f.)<\/strong>\n\n<\/div><\/details><\/div>\n\n<h2>Frequently Asked Questions<\/h2>\n\n<details class=\"pf-faq-item\"><summary>Do heavier objects fall faster than lighter ones?<\/summary><div class=\"pf-faq-item-answer\">\n\nNo \u2014 in free fall every object accelerates at the same rate g, regardless of mass. The mass cancels out because gravity pulls a heavy object harder but that object also resists acceleration proportionally more. Heavy things appear to fall faster only in air, where drag slows light objects far more than heavy ones.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Is an object thrown upwards still in free fall?<\/summary><div class=\"pf-faq-item-answer\">\n\nYes. Free fall means gravity is the only force acting, which says nothing about direction. A ball thrown straight up is in free fall for its entire flight \u2014 rising, at the peak, and falling. Even at the highest point, where its velocity is momentarily zero, its acceleration is still 9.81 m\/s\u00b2 downward.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What is the value of g in free fall?<\/summary><div class=\"pf-faq-item-answer\">\n\nOn Earth, g is about 9.81 m\/s\u00b2, and the internationally defined standard value is exactly 9.80665 m\/s\u00b2. The real local value varies with latitude and altitude, from roughly 9.78 m\/s\u00b2 at the equator to about 9.83 m\/s\u00b2 at the poles. Elsewhere it differs entirely: 1.62 m\/s\u00b2 on the Moon and 3.72 m\/s\u00b2 on Mars.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Is free fall the same as weightlessness?<\/summary><div class=\"pf-faq-item-answer\">\n\nFree fall causes the sensation of weightlessness, but the two are not the same thing. Weight still exists in free fall \u2014 gravity is still pulling. What disappears is the contact force from a floor or seat pushing back, and that push is what you actually feel. Remove it and you feel weightless while gravity carries on working.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What is the difference between free fall and terminal velocity?<\/summary><div class=\"pf-faq-item-answer\">\n\nFree fall has gravity acting alone, so acceleration stays constant at g and speed keeps climbing. Terminal velocity is the opposite endpoint: air resistance has grown until it exactly balances weight, the net force is zero, acceleration is zero, and speed stops changing. A real fall through air starts near free fall and ends at terminal velocity.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>How far does an object fall in 1 second?<\/summary><div class=\"pf-faq-item-answer\">\n\nAn object dropped from rest falls 4.9 m in the first second on Earth, from h = \u00bd \u00d7 9.81 \u00d7 1\u00b2 = 4.905 m. It reaches 9.81 m\/s at that moment. Distances do not repeat each second: the second second covers 14.7 m and the third 24.5 m, because distance grows with the square of time.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Why does mass not affect free fall?<\/summary><div class=\"pf-faq-item-answer\">\n\nMass cancels algebraically. The force is weight, W = mg, and Newton&#8217;s second law gives F = ma, so ma = mg and therefore a = g with the mass gone. Physically, doubling the mass doubles the gravitational pull and doubles the resistance to acceleration in the same stroke, so the two effects cancel exactly.\n\n<\/div><\/details>\n","protected":false},"excerpt":{"rendered":"<p>Free fall is motion under gravity alone. Learn the h = 0.5gt\u00b2 and v = gt formulas, why every object falls at the same rate, and how to solve free-fall problems step by step.<\/p>\n","protected":false},"author":1,"featured_media":593,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[7],"tags":[],"class_list":["post-591","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kinematics"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/591","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=591"}],"version-history":[{"count":2,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/591\/revisions"}],"predecessor-version":[{"id":595,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/591\/revisions\/595"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/593"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=591"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=591"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=591"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}