{"id":575,"date":"2026-07-15T03:32:00","date_gmt":"2026-07-15T03:32:00","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=575"},"modified":"2026-07-15T03:32:02","modified_gmt":"2026-07-15T03:32:02","slug":"ac-vs-dc-current","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/ac-vs-dc-current\/","title":{"rendered":"AC vs DC Current: What&#8217;s the Difference?"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\nAC vs DC current is the difference between electricity that reverses direction and electricity that does not. Alternating current (AC) flows back and forth, completing 50 or 60 cycles every second in mains supplies. Direct current (DC) flows one way only, at a steady value. AC generates and transmits power efficiently; DC runs batteries, electronics and every USB device.\n<\/p><\/div>\n\n<p>Look at the plug on your laptop charger. There is a brick partway down the cable, and after an hour of use it is warm. That lump is not packaging \u2014 it is a translator, and it exists because the electricity in your wall and the electricity in your laptop are two different animals.<\/p>\n\n<p>One of them reverses direction a hundred times a second. The other never turns around at all. Every charger, phone and LED bulb in your house is quietly converting between the two, all day, without ever mentioning it.<\/p>\n\n<h2>What Is AC vs DC Current?<\/h2>\n\n<p>Alternating current (AC) reverses its direction of flow many times a second; direct current (DC) flows in one direction only and never reverses. Everything else \u2014 the sine wave, the frequency, the RMS rule, the transformers on the pole outside \u2014 follows from that single fact.<\/p>\n\n<h3>Direct current: one direction, one value<\/h3>\n\n<p>Wire a torch bulb to an AA cell and the current settles on a value and stays there. Charge leaves one terminal, crosses the filament, returns to the other, and never turns back. Plot it against time and you get a horizontal line.<\/p>\n\n<p>That flatness is the whole appeal. A microprocessor, an LED, a lithium cell \u2014 every one of them wants a voltage that sits still and behaves.<\/p>\n\n<h3>Alternating current: a flow that keeps changing its mind<\/h3>\n\n<p>Now switch on a lamp. The current in that flex rises to a peak, falls back through zero, reverses, reaches an equal peak the other way, and returns \u2014 over and over, 50 times a second across most of the world and 60 times a second in North America.<\/p>\n\n<p>Each round trip is one <strong>cycle<\/strong>, and the number of cycles per second is the frequency, measured in hertz (Hz). At 50 Hz a single cycle takes 20 milliseconds, which is why a filament bulb never has time to cool between reversals and simply looks steady.<\/p>\n<svg viewBox=\"0 0 720 500\" role=\"img\" aria-label=\"AC vs DC current comparison diagram: direct current is a flat constant line above zero, while alternating current is a sine wave that crosses zero and reverses direction twice per cycle, with the RMS level marked at 0.707 times the peak\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:0 auto;\">\n<rect x=\"0\" y=\"0\" width=\"720\" height=\"500\" rx=\"6\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"1.5\"><\/rect>\n\n<text x=\"90\" y=\"28\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#7A1F2B\">DIRECT CURRENT (DC)<\/text>\n<text x=\"90\" y=\"47\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" fill=\"#1F2E47\">Steady value \u00b7 one direction \u00b7 never crosses zero<\/text>\n\n<line x1=\"90\" y1=\"64\" x2=\"90\" y2=\"192\" stroke=\"#0A1628\" stroke-width=\"1.6\"><\/line>\n<polygon points=\"90,64 86,73 94,73\" fill=\"#0A1628\"><\/polygon>\n<line x1=\"90\" y1=\"175\" x2=\"697\" y2=\"175\" stroke=\"#0A1628\" stroke-width=\"1.6\"><\/line>\n<polygon points=\"697,175 688,171 688,179\" fill=\"#0A1628\"><\/polygon>\n<text x=\"78\" y=\"122\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#1F2E47\" text-anchor=\"end\">Current I<\/text>\n<text x=\"82\" y=\"179\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#1F2E47\" text-anchor=\"end\">0<\/text>\n<text x=\"697\" y=\"194\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#1F2E47\" text-anchor=\"end\">Time t<\/text>\n\n<line x1=\"90\" y1=\"100\" x2=\"680\" y2=\"100\" stroke=\"#C8932A\" stroke-width=\"4\"><\/line>\n<text x=\"385\" y=\"90\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" font-weight=\"600\" fill=\"#7A1F2B\" text-anchor=\"middle\">Same value at every instant<\/text>\n<polygon points=\"250,100 242,96 242,104\" fill=\"#C8932A\"><\/polygon>\n<polygon points=\"430,100 422,96 422,104\" fill=\"#C8932A\"><\/polygon>\n<polygon points=\"610,100 602,96 602,104\" fill=\"#C8932A\"><\/polygon>\n<text x=\"700\" y=\"105\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\">+<\/text>\n\n<line x1=\"30\" y1=\"213\" x2=\"690\" y2=\"213\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/line>\n\n<text x=\"90\" y=\"247\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#7A1F2B\">ALTERNATING CURRENT (AC)<\/text>\n<text x=\"90\" y=\"266\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" fill=\"#1F2E47\">Reverses twice per cycle \u00b7 50 or 60 complete cycles each second<\/text>\n\n<line x1=\"90\" y1=\"284\" x2=\"90\" y2=\"462\" stroke=\"#0A1628\" stroke-width=\"1.6\"><\/line>\n<polygon points=\"90,284 86,293 94,293\" fill=\"#0A1628\"><\/polygon>\n<line x1=\"90\" y1=\"372\" x2=\"697\" y2=\"372\" stroke=\"#0A1628\" stroke-width=\"1.6\"><\/line>\n<polygon points=\"697,372 688,368 688,376\" fill=\"#0A1628\"><\/polygon>\n<text x=\"78\" y=\"330\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#1F2E47\" text-anchor=\"end\">Current I<\/text>\n<text x=\"82\" y=\"376\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#1F2E47\" text-anchor=\"end\">0<\/text>\n<text x=\"697\" y=\"481\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#1F2E47\" text-anchor=\"end\">Time t<\/text>\n<text x=\"700\" y=\"329\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\">+<\/text>\n<text x=\"700\" y=\"422\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#0A1628\">\u2013<\/text>\n\n<line x1=\"90\" y1=\"322.5\" x2=\"660\" y2=\"322.5\" stroke=\"#C8932A\" stroke-width=\"1.6\" stroke-dasharray=\"7,4\"><\/line>\n<line x1=\"90\" y1=\"421.5\" x2=\"660\" y2=\"421.5\" stroke=\"#C8932A\" stroke-width=\"1.6\" stroke-dasharray=\"7,4\"><\/line>\n\n<path d=\"M 90.0,372.0 C 114.04,336.15 137.05,302.0 163.75,302.0 C 190.45,302.0 213.46,336.15 237.5,372.0 C 261.54,407.85 284.55,442.0 311.25,442.0 C 337.95,442.0 360.96,407.85 385.0,372.0 C 409.04,336.15 432.05,302.0 458.75,302.0 C 485.45,302.0 508.46,336.15 532.5,372.0 C 556.54,407.85 579.55,442.0 606.25,442.0 C 632.95,442.0 655.96,407.85 680.0,372.0\" fill=\"none\" stroke=\"#7A1F2B\" stroke-width=\"3.6\" stroke-linecap=\"round\"><\/path>\n<rect x=\"235\" y=\"313\" width=\"152\" height=\"17\" fill=\"#F5F2EA\"><\/rect>\n<text x=\"311\" y=\"326\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"11.5\" font-weight=\"700\" fill=\"#C8932A\" text-anchor=\"middle\">RMS = 0.707 \u00d7 peak<\/text>\n\n<circle cx=\"163.75\" cy=\"302\" r=\"4.5\" fill=\"#7A1F2B\"><\/circle>\n<circle cx=\"311.25\" cy=\"442\" r=\"4.5\" fill=\"#7A1F2B\"><\/circle>\n<circle cx=\"237.5\" cy=\"372\" r=\"4.2\" fill=\"#0A1628\"><\/circle>\n<circle cx=\"385\" cy=\"372\" r=\"4.2\" fill=\"#0A1628\"><\/circle>\n<circle cx=\"532.5\" cy=\"372\" r=\"4.2\" fill=\"#0A1628\"><\/circle>\n\n<text x=\"172\" y=\"297\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-weight=\"700\" fill=\"#7A1F2B\">peak<\/text>\n<text x=\"320\" y=\"458\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-weight=\"700\" fill=\"#7A1F2B\">trough \u2014 flowing backwards<\/text>\n<line x1=\"237.5\" y1=\"372\" x2=\"237.5\" y2=\"352\" stroke=\"#0A1628\" stroke-width=\"1\"><\/line>\n<text x=\"243\" y=\"349\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"11\" fill=\"#0A1628\">crosses zero, reverses<\/text>\n\n<line x1=\"90\" y1=\"490\" x2=\"385\" y2=\"490\" stroke=\"#0A1628\" stroke-width=\"1.2\"><\/line>\n<polygon points=\"90,490 99,486 99,494\" fill=\"#0A1628\"><\/polygon>\n<polygon points=\"385,490 376,486 376,494\" fill=\"#0A1628\"><\/polygon>\n<rect x=\"192\" y=\"482\" width=\"92\" height=\"16\" fill=\"#F5F2EA\"><\/rect>\n<text x=\"237\" y=\"494\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"11.5\" font-weight=\"600\" fill=\"#0A1628\" text-anchor=\"middle\">one cycle (T)<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:14px;font-style:italic;color:#1F2E47;margin-top:8px;\">The same idea drawn twice: DC holds one value in one direction, while AC sweeps between equal and opposite peaks \u2014 and the number written on the socket is the RMS level, not the peak.<\/p>\n\n<h2>The AC vs DC Current Formulas<\/h2>\n\n<p>Current itself is defined identically for both. It is the amount of charge passing a point each second, and that definition does not care which way the charge is heading.<\/p>\n\n<div class=\"pf-formula\">I = Q \/ t<\/div>\n\n<ul>\n<li><strong>I<\/strong> \u2014 current, in amperes (A)<\/li>\n<li><strong>Q<\/strong> \u2014 charge passing a point, in coulombs (C)<\/li>\n<li><strong>t<\/strong> \u2014 time taken, in seconds (s)<\/li>\n<\/ul>\n\n<p>For DC that is the end of the story: one number, good all day. If you want the arithmetic done for you, our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/electric-current\">Electric Current calculator<\/a> rearranges I = Q\/t for current, charge or time and counts the electrons involved.<\/p>\n\n<p>AC needs a second equation, because the current is a moving target. A mains supply is a sine wave, so its instantaneous value depends on where you are in the cycle.<\/p>\n\n<div class=\"pf-formula\">i(t) = I<sub>peak<\/sub> \u00b7 sin(2\u03c0ft)<\/div>\n\n<ul>\n<li><strong>i(t)<\/strong> \u2014 instantaneous current at time t, in amperes (A)<\/li>\n<li><strong>I<sub>peak<\/sub><\/strong> \u2014 peak (maximum) current, in amperes (A)<\/li>\n<li><strong>f<\/strong> \u2014 frequency, in hertz (Hz)<\/li>\n<li><strong>t<\/strong> \u2014 time, in seconds (s)<\/li>\n<\/ul>\n\n<h3>The RMS rule: why 230 V is not the peak<\/h3>\n\n<p>A quantity that swings from +325 V to \u2212325 V and averages exactly zero is useless for describing a kettle. So AC is quoted by its <strong>root-mean-square (RMS)<\/strong> value: square the waveform, average that over a whole cycle, then take the square root.<\/p>\n\n<p>Squaring is the trick. It makes the negative half positive, so the backward flow counts as work done rather than cancelling the forward flow. For a sine wave the average of sin\u00b2 over a full cycle is exactly 0.5, and taking the square root of a half gives the factor everyone memorises.<\/p>\n\n<div class=\"pf-formula\">V<sub>rms<\/sub> = V<sub>peak<\/sub> \/ sqrt(2) = 0.707 \u00b7 V<sub>peak<\/sub><\/div>\n\n<div class=\"pf-formula\">I<sub>rms<\/sub> = I<sub>peak<\/sub> \/ sqrt(2) = 0.707 \u00b7 I<sub>peak<\/sub><\/div>\n\n<ul>\n<li><strong>V<sub>rms<\/sub><\/strong>, <strong>I<sub>rms<\/sub><\/strong> \u2014 RMS (effective) voltage in volts (V) and current in amperes (A)<\/li>\n<li><strong>V<sub>peak<\/sub><\/strong>, <strong>I<sub>peak<\/sub><\/strong> \u2014 the maximum values reached each cycle, in volts (V) and amperes (A)<\/li>\n<li><strong>sqrt(2)<\/strong> \u2248 1.414, so 1\/sqrt(2) \u2248 0.707 \u2014 this factor applies to sine waves only<\/li>\n<\/ul>\n\n<p>Here is what that number actually means. An RMS value is defined so that the AC supply heats a resistor by exactly as much as a DC supply of the same figure would \u2014 230 V RMS delivers the same average power as a 230 V battery.<\/p>\n\n<p>That equivalence is why <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/ohms-law\/\">Ohm&#8217;s law<\/a> survives the jump to AC untouched, provided every quantity you put into it is an RMS value. <a href=\"http:\/\/hyperphysics.phy-astr.gsu.edu\/hbase\/electric\/acres.html\" target=\"_blank\" rel=\"noopener\">Georgia State University&#8217;s HyperPhysics<\/a> makes the same point from the circuit side: a resistor&#8217;s opposition to AC is simply its DC resistance, once effective values are used.<\/p>\n\n<div class=\"pf-formula\">P<sub>avg<\/sub> = V<sub>rms<\/sub> \u00b7 I<sub>rms<\/sub><\/div>\n\n<ul>\n<li><strong>P<sub>avg<\/sub><\/strong> \u2014 average power delivered to a resistive load, in watts (W)<\/li>\n<li><strong>V<sub>rms<\/sub><\/strong>, <strong>I<sub>rms<\/sub><\/strong> \u2014 RMS voltage (V) and RMS current (A)<\/li>\n<\/ul>\n\n<p>A common student slip is to multiply the peak voltage by the peak current and call it power. That answer is exactly twice too large, every time.<\/p>\n<h2>How AC and DC Are Actually Made<\/h2>\n\n<p>AC comes out of anything that spins; DC comes out of anything that pushes. That is the shortest honest summary of where the two kinds of current are born, and it explains why neither one was really a design choice.<\/p>\n\n<h3>A generator makes a sine wave by accident of geometry<\/h3>\n\n<p>Spin a coil of wire between the poles of a magnet. The magnetic flux threading that coil rises and falls as it turns, and a changing flux induces a voltage across the ends \u2014 Faraday&#8217;s law of induction.<\/p>\n\n<p>Because the coil&#8217;s orientation is following a rotation, the induced voltage traces the projection of that rotation onto a line. A circle seen edge-on is a sine wave. Half a turn later the coil faces the opposite way and the voltage flips sign.<\/p>\n\n<p>Nobody sat down and chose the alternation. It falls straight out of the turning.<\/p>\n\n<h3>Batteries, rectifiers and inverters<\/h3>\n\n<p>A battery has no rotation and no reversal. A chemical reaction shoves electrons out of one terminal and pulls them back into the other, and it will keep pushing that way until the chemistry runs down. Solar cells do the same job with photons instead of chemistry. Both are DC by construction.<\/p>\n\n<p>Traffic between the two worlds runs in both directions, and the two devices that manage it are worth knowing by name:<\/p>\n\n<ul>\n<li><strong>Rectifier<\/strong> \u2014 converts AC to DC. Diodes let current pass one way only, so the negative halves of the wave are flipped or blocked and then smoothed. This is what lives inside the warm brick on your charger.<\/li>\n<li><strong>Inverter<\/strong> \u2014 converts DC to AC. It chops and shapes a steady DC voltage into something the grid will accept, which is how a rooftop solar array or an electric car can push power back into the mains.<\/li>\n<\/ul>\n\n<p>In practice almost nothing you own is purely one or the other. The socket is AC, the chip is DC, and there is a rectifier somewhere in between doing the work.<\/p>\n\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">AC vs DC Current Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/ac-vs-dc-current.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n\n<h2>AC vs DC Current: 7 Differences Side by Side<\/h2>\n\n<p>AC and DC differ in seven ways that matter in practice: direction, waveform, frequency, what the quoted voltage means, how easily the voltage can be changed, where each one comes from, and how far each can be sent economically.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#0A1628;color:#FAF6EE;\">\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Property<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Alternating Current (AC)<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Direct Current (DC)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>1. Direction of flow<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Reverses periodically \u2014 twice in every cycle<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">One direction only; never reverses<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>2. Shape on a graph<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">A sine wave that crosses zero twice per cycle<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">A flat horizontal line above zero<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>3. Frequency<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">50 Hz or 60 Hz on mains supplies<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">0 Hz \u2014 there is no cycle to count<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>4. What the quoted voltage means<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">The RMS value; the peak is 1.414 times higher<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">The actual value, at every instant<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>5. Changing the voltage<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">A transformer does it cheaply and with very little loss<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Needs switching electronics \u2014 a DC-DC converter<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>6. Typical sources<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Power-station alternators, wall sockets, generators<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">Batteries, solar cells, USB ports, car electrics<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>7. Long-distance transmission<\/strong><\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">The grid standard \u2014 stepped up to hundreds of kilovolts<\/td>\n<td style=\"padding:10px;border:1px solid #D9CFB8;\">HVDC wins on very long links and undersea cables<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>Row four is the one that catches people out in exams, and row five is the one that decided the shape of the modern world.<\/p>\n<h2>Why the Grid Runs on AC but Your Devices Run on DC<\/h2>\n\n<p>The grid runs on AC because a transformer can change an AC voltage almost losslessly, and high voltage is the only affordable way to move power a long way. Your devices run on DC because transistors, LEDs and batteries all need a voltage that holds still.<\/p>\n\n<p>The villain in transmission is the resistance of the cable itself. Push current through it and some of your power is spent warming the countryside.<\/p>\n\n<div class=\"pf-formula\">P<sub>loss<\/sub> = I\u00b2 \u00b7 R<\/div>\n\n<ul>\n<li><strong>P<sub>loss<\/sub><\/strong> \u2014 power wasted as heat in the line, in watts (W)<\/li>\n<li><strong>I<\/strong> \u2014 current in the line, in amperes (A)<\/li>\n<li><strong>R<\/strong> \u2014 total resistance of the line, in ohms (\u03a9)<\/li>\n<\/ul>\n\n<p>Notice the square. Loss depends on current, not on voltage \u2014 and current is squared. So if you deliver the same power at a hundred times the voltage, the current drops by a factor of a hundred and the waste drops by a factor of ten thousand.<\/p>\n\n<p>Every watt burnt in those cables is <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/what-is-energy-in-physics\/\">energy<\/a> somebody paid to generate and then never sold. That is the entire economic argument, in one squared term.<\/p>\n<svg viewBox=\"0 0 720 360\" role=\"img\" aria-label=\"Diagram showing why the grid uses high voltage: sending 100 kilowatts down the same 0.5 ohm line at 250 volts wastes 80 kilowatts as heat, while sending it at 25 kilovolts wastes only 8 watts, because I squared R loss falls with the square of the current\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:0 auto;\">\n<rect x=\"0\" y=\"0\" width=\"720\" height=\"360\" rx=\"6\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"1.5\"><\/rect>\n\n<text x=\"24\" y=\"30\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#7A1F2B\">The same 100 kW, down the same 0.5 \u03a9 line<\/text>\n<text x=\"24\" y=\"50\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" fill=\"#1F2E47\">Transformers let AC choose its transmission voltage \u2014 and the voltage decides the waste.<\/text>\n\n<text x=\"24\" y=\"116\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13.5\" font-weight=\"700\" fill=\"#0A1628\">Sent at 250 V<\/text>\n<text x=\"24\" y=\"134\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#1F2E47\">I = P\/V = 400 A<\/text>\n<rect x=\"210.0\" y=\"98\" width=\"376.0\" height=\"44\" fill=\"#7A1F2B\"><\/rect>\n<rect x=\"586.0\" y=\"98\" width=\"94.0\" height=\"44\" fill=\"#C8932A\"><\/rect>\n<rect x=\"210.0\" y=\"98\" width=\"470.0\" height=\"44\" fill=\"none\" stroke=\"#0A1628\" stroke-width=\"1.2\"><\/rect>\n<text x=\"398.0\" y=\"126\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#FAF6EE\" text-anchor=\"middle\">80 kW wasted as heat<\/text>\n<text x=\"633.0\" y=\"126\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" font-weight=\"700\" fill=\"#0A1628\" text-anchor=\"middle\">20 kW<\/text>\n<text x=\"210.0\" y=\"162\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#7A1F2B\">Four-fifths of the power never reaches anyone.<\/text>\n\n<line x1=\"24\" y1=\"186\" x2=\"696\" y2=\"186\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/line>\n<text x=\"360\" y=\"209\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" font-weight=\"700\" fill=\"#0A1628\" text-anchor=\"middle\">Raise the voltage 100\u00d7 \u00b7 the current falls 100\u00d7 \u00b7 the I\u00b2R loss falls 10,000\u00d7<\/text>\n\n<text x=\"24\" y=\"262\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13.5\" font-weight=\"700\" fill=\"#0A1628\">Sent at 25 kV<\/text>\n<text x=\"24\" y=\"280\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#1F2E47\">I = P\/V = 4 A<\/text>\n<rect x=\"210.0\" y=\"244\" width=\"470.0\" height=\"44\" fill=\"#C8932A\"><\/rect>\n<rect x=\"210.0\" y=\"244\" width=\"2\" height=\"44\" fill=\"#7A1F2B\"><\/rect>\n<rect x=\"210.0\" y=\"244\" width=\"470.0\" height=\"44\" fill=\"none\" stroke=\"#0A1628\" stroke-width=\"1.2\"><\/rect>\n<text x=\"445.0\" y=\"272\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\" text-anchor=\"middle\">99.992 kW delivered<\/text>\n<text x=\"210.0\" y=\"308\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#7A1F2B\">Only 8 W wasted \u2014 a sliver 0.04 px wide, drawn here at 2 px so it shows at all.<\/text>\n\n<rect x=\"24\" y=\"330\" width=\"14\" height=\"14\" fill=\"#7A1F2B\"><\/rect>\n<text x=\"44\" y=\"342\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"11.5\" fill=\"#1F2E47\">Wasted in the wires (I\u00b2R)<\/text>\n<rect x=\"214\" y=\"330\" width=\"14\" height=\"14\" fill=\"#C8932A\"><\/rect>\n<text x=\"234\" y=\"342\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"11.5\" fill=\"#1F2E47\">Delivered to homes<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:14px;font-style:italic;color:#1F2E47;margin-top:8px;\">Same power, same cable, two choices of voltage. At 250 V the line eats four-fifths of what you generated; at 25 kV it eats eight watts.<\/p>\n\n<p>Which brings us to the transformer. Wind two coils onto one iron core, feed the first with AC, and the changing flux induces a voltage in the second \u2014 scaled by nothing more exotic than the ratio of the turns.<\/p>\n\n<div class=\"pf-formula\">V<sub>s<\/sub> \/ V<sub>p<\/sub> = N<sub>s<\/sub> \/ N<sub>p<\/sub><\/div>\n\n<ul>\n<li><strong>V<sub>p<\/sub><\/strong>, <strong>V<sub>s<\/sub><\/strong> \u2014 primary and secondary voltage, in volts (V)<\/li>\n<li><strong>N<sub>p<\/sub><\/strong>, <strong>N<sub>s<\/sub><\/strong> \u2014 number of turns on the primary and secondary coils (a pure number, no units)<\/li>\n<\/ul>\n\n<p>Now the punchline. A transformer needs a <em>changing<\/em> flux to do anything at all. Feed one with steady DC and, after a brief switch-on twitch, it just sits there: a warm lump of copper and iron.<\/p>\n\n<p>That one limitation settled the argument in the 1890s. The <a href=\"https:\/\/www.energy.gov\/articles\/war-currents-ac-vs-dc-power\" target=\"_blank\" rel=\"noopener\">US Department of Energy&#8217;s account of the War of the Currents<\/a> records the turning point: at the 1893 Chicago World&#8217;s Columbian Exposition, General Electric quoted $554,000 to light the fair with Edison&#8217;s DC and lost to Westinghouse, who did it for $399,000 using Tesla&#8217;s AC. On 16 November 1896, Buffalo was lit by alternating current generated at Niagara Falls.<\/p>\n\n<p>DC could not have made that trip. Not because it was worse electricity \u2014 because in 1896 nobody knew how to change its voltage.<\/p>\n<figure style=\"margin:32px auto;max-width:600px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/07\/Tesla_circa_1890.jpeg\"\n       alt=\"Nikola Tesla, whose polyphase patents settled the AC vs DC current debate\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">Westinghouse licensed Tesla&#8217;s polyphase AC induction motor patent and took the Niagara Falls contract in 1893.<\/figcaption>\n<\/figure>\n<h2>Real-World Examples of AC and DC Current<\/h2>\n\n<p>Most homes run both kinds of current simultaneously, separated by a few centimetres of plastic. Five everyday cases make the split obvious.<\/p>\n\n<ul>\n<li><strong>Your wall socket \u2014 AC.<\/strong> Around 230 V at 50 Hz across Europe, the UK, India and Pakistan; 120 V at 60 Hz in North America; 100 V in Japan, at 50 Hz in the east of the country and 60 Hz in the west.<\/li>\n<li><strong>Your phone \u2014 DC.<\/strong> A USB port supplies a steady 5 V. The charger is a rectifier that turns the wall&#8217;s alternating supply into something the battery can accept.<\/li>\n<li><strong>Your car \u2014 both, quietly.<\/strong> The 12 V battery and everything it feeds are DC, but the alternator under the bonnet actually generates AC and rectifies it on the spot with diodes.<\/li>\n<li><strong>Rooftop solar \u2014 DC becoming AC.<\/strong> Panels produce DC because photons only push one way. An inverter converts it before it reaches your consumer unit or the grid.<\/li>\n<li><strong>Undersea and cross-country links \u2014 DC again.<\/strong> Beyond a few hundred kilometres, and for almost any submarine cable, high-voltage DC becomes the cheaper option, so the grid converts, ships the power as DC, then converts back.<\/li>\n<\/ul>\n\n<p>The pattern is worth naming: <strong>AC for moving power, DC for using it.<\/strong> The charger in the middle is the tax you pay for living in both worlds.<\/p>\n<figure style=\"margin:32px auto;max-width:640px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/07\/ac-vs-dc-transmission-1024x559-1.webp\"\n       alt=\"High-voltage pylons carrying AC current, the transmission side of AC vs DC current\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">Transmission lines run at hundreds of kilovolts for one reason: line loss scales with the square of the current.<\/figcaption>\n<\/figure>\n<h2>Common Misconceptions About AC vs DC Current<\/h2>\n\n<p>Four beliefs about AC vs DC current are wrong often enough to cost marks and, occasionally, equipment.<\/p>\n\n<h3>Myth 1: &#8220;230 V is the peak voltage of the mains&#8221;<\/h3>\n\n<p>It is not. 230 V is the RMS value, and the waveform actually swings up to 325 V one way and 325 V the other \u2014 a peak-to-peak span of about 651 V.<\/p>\n\n<p>This is not academic. Insulation, capacitors and rectifier diodes have to survive the peak, not the number printed on the socket. In practice a designer who specifies parts for 230 V will watch them fail.<\/p>\n\n<h3>Myth 2: &#8220;AC reverses 50 times a second&#8221;<\/h3>\n\n<p>It reverses 100 times a second. A 50 Hz supply completes 50 <em>cycles<\/em> each second, and every cycle contains two reversals: once as the current passes through zero going negative, once on the way back.<\/p>\n\n<p>At 60 Hz it is 120 reversals a second. Count cycles or count reversals \u2014 just do not swap the two.<\/p>\n\n<h3>Myth 3: &#8220;The electrons in your socket travel from the power station&#8221;<\/h3>\n\n<p>They travel almost nowhere. In a 1.5 mm\u00b2 copper flex carrying 5 A at 50 Hz, the electrons shuffle back and forth with an amplitude of roughly one micrometre \u2014 a thousandth of a millimetre. They jiggle on the spot and get nowhere.<\/p>\n\n<p>Even on DC the drift is glacial, a fraction of a millimetre per second. What actually races down the cable is the electromagnetic field, at a good fraction of the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/modern-physics\/speed-of-light\/\">speed of light<\/a>. The electrons are the medium, not the messenger.<\/p>\n\n<h3>Myth 4: &#8220;AC won, so DC is obsolete&#8221;<\/h3>\n\n<p>DC never left, and it is gaining ground. Every phone, laptop, LED, data-centre server and electric vehicle runs on DC internally, and solar panels generate it directly.<\/p>\n\n<p>The DOE&#8217;s own account of the War of the Currents notes that direct current has been enjoying a revival. The honest verdict is that AC did not beat DC \u2014 the two divided the work, and the boundary between them is still moving.<\/p>\n<h2>How AC vs DC Current Relates to Ohm&#8217;s Law, Frequency and Induction<\/h2>\n\n<p>AC and DC obey exactly the same physics; AC simply adds a clock to it. Three neighbouring ideas do most of the connecting work.<\/p>\n\n<h3>Frequency and period<\/h3>\n\n<p>The only new number AC introduces is how often it repeats, and that comes straight from the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/waves\/frequency-formula\/\">frequency formula<\/a>, f = 1\/T. A 50 Hz supply has a period of 20 ms; a 60 Hz supply, 16.7 ms. DC is simply the f = 0 case \u2014 a wave with nothing left to repeat.<\/p>\n\n<h3>Simple harmonic motion<\/h3>\n\n<p>The mains sine wave is not a coincidence or a convenience. It is <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/simple-harmonic-motion\/\">simple harmonic motion<\/a> wearing electrical clothing: a rotating generator projected onto one axis, exactly as a pendulum&#8217;s swing is a circle seen edge-on.<\/p>\n\n<p>That is why the RMS factor of 0.707 is specific to sine waves. Feed a square wave in and the ratio changes, because the maths was never about electricity \u2014 it was about the shape.<\/p>\n\n<h3>Ohm&#8217;s law and induction<\/h3>\n\n<p>Ohm&#8217;s law needs no modification for AC across a resistor, provided you keep every value in RMS. Add coils or capacitors and it generalises to impedance, where the current no longer peaks at the same instant as the voltage.<\/p>\n\n<p>Induction is the deeper link. It is what builds AC in the generator, what lets the transformer rescale it, and what makes an induction motor turn \u2014 three jobs steady DC cannot do at all.<\/p>\n<h2>Worked Problems<\/h2>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">A torch runs from a 1.5 V AA cell and draws a steady 0.30 A. How much charge passes through the bulb in 2.0 minutes, and is this AC or DC?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Current is the rate of charge flow, I = Q \/ t, so Q = I \u00d7 t.\nStep 2: Convert the time first: t = 2.0 min \u00d7 60 s\/min = 120 s. Then Q = 0.30 A \u00d7 120 s.\nStep 3: Q = 36 C. The current holds one value in one direction, so it is direct current.\n<strong>Answer: Q = 36 C, and the current is DC.<\/strong>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A mains supply alternates at 50 Hz. Find the period of one cycle, and state how many times the current reverses direction each second.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Period and frequency are reciprocals, T = 1 \/ f.\nStep 2: T = 1 \/ 50 Hz = 0.020 s = 20 ms.\nStep 3: Each cycle contains two reversals, so reversals per second = 50 \u00d7 2 = 100.\n<strong>Answer: T = 20 ms, and the current reverses 100 times per second (not 50).<\/strong>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A European socket is rated at 230 V. Calculate the peak voltage and the peak-to-peak voltage of the waveform.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: The rated figure is RMS, so V<sub>rms<\/sub> = V<sub>peak<\/sub> \/ sqrt(2), which rearranges to V<sub>peak<\/sub> = V<sub>rms<\/sub> \u00d7 sqrt(2).\nStep 2: V<sub>peak<\/sub> = 230 V \u00d7 1.414 = 325.3 V.\nStep 3: The wave reaches that peak on both sides of zero, so V<sub>pp<\/sub> = 2 \u00d7 325.3 V = 650.5 V.\n<strong>Answer: V<sub>peak<\/sub> = 325 V and V<sub>pp<\/sub> = 651 V (3 s.f.).<\/strong>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">A 60 W filament lamp runs on a 230 V RMS supply. Find the RMS current, the resistance of the filament, and the peak current.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: For a resistive load, P<sub>avg<\/sub> = V<sub>rms<\/sub> \u00d7 I<sub>rms<\/sub>, so I<sub>rms<\/sub> = P<sub>avg<\/sub> \/ V<sub>rms<\/sub>.\nStep 2: I<sub>rms<\/sub> = 60 W \/ 230 V = 0.2609 A. Ohm&#8217;s law then gives R = V<sub>rms<\/sub> \/ I<sub>rms<\/sub> = 230 V \/ 0.2609 A = 881.7 \u03a9.\nStep 3: I<sub>peak<\/sub> = I<sub>rms<\/sub> \u00d7 sqrt(2) = 0.2609 A \u00d7 1.414 = 0.3689 A.\n<strong>Answer: I<sub>rms<\/sub> = 0.261 A, R = 882 \u03a9, I<sub>peak<\/sub> = 0.369 A (3 s.f.).<\/strong>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">100 kW must travel down a line of total resistance 0.50 ohm. Find the power lost as heat if it is sent at 250 V, and again if a transformer first steps it up to 25 kV.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Find the current from I = P \/ V, then the loss from P<sub>loss<\/sub> = I\u00b2 \u00d7 R.\nStep 2: At 250 V: I = 100 000 W \/ 250 V = 400 A, so P<sub>loss<\/sub> = (400 A)\u00b2 \u00d7 0.50 \u03a9 = 80 000 W.\nStep 3: At 25 kV: I = 100 000 W \/ 25 000 V = 4.0 A, so P<sub>loss<\/sub> = (4.0 A)\u00b2 \u00d7 0.50 \u03a9 = 8.0 W.\n<strong>Answer: 80 kW is lost at 250 V (80% of the power); only 8.0 W is lost at 25 kV (0.008%). Raising the voltage 100 times cut the waste 10 000 times.<\/strong>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">A step-down transformer takes 11 kV to 220 V. Its primary has 5000 turns. Find the number of secondary turns, and explain why the same transformer does nothing on a steady 11 kV DC supply.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: The turns ratio matches the voltage ratio, V<sub>s<\/sub> \/ V<sub>p<\/sub> = N<sub>s<\/sub> \/ N<sub>p<\/sub>, so N<sub>s<\/sub> = N<sub>p<\/sub> \u00d7 (V<sub>s<\/sub> \/ V<sub>p<\/sub>).\nStep 2: N<sub>s<\/sub> = 5000 \u00d7 (220 V \/ 11 000 V) = 5000 \u00d7 0.020.\nStep 3: N<sub>s<\/sub> = 100 turns. On steady DC the flux in the core is constant, and a constant flux induces no emf, so the secondary voltage is zero once the switch-on transient dies away.\n<strong>Answer: N<sub>s<\/sub> = 100 turns; on DC the output is 0 V, because transformers need a changing flux.<\/strong>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">A copper flex of cross-section 1.5 mm^2 carries 5.0 A RMS at 50 Hz. Taking n = 8.5 x 10^28 free electrons per cubic metre and e = 1.60 x 10^-19 C, find the peak drift speed and the amplitude of an electron&#039;s back-and-forth motion.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Convert to SI and find the peak current: A = 1.5 mm\u00b2 = 1.5 \u00d7 10<sup>\u22126<\/sup> m\u00b2, and I<sub>peak<\/sub> = 5.0 A \u00d7 sqrt(2) = 7.071 A.\nStep 2: Drift speed comes from I = n \u00d7 e \u00d7 A \u00d7 v, so v<sub>peak<\/sub> = I<sub>peak<\/sub> \/ (n \u00d7 e \u00d7 A) = 7.071 \/ (8.5 \u00d7 10<sup>28<\/sup> \u00d7 1.60 \u00d7 10<sup>\u221219<\/sup> \u00d7 1.5 \u00d7 10<sup>\u22126<\/sup>) = 3.46 \u00d7 10<sup>\u22124<\/sup> m\/s.\nStep 3: The drift is sinusoidal, so its displacement amplitude is v<sub>peak<\/sub> \/ \u03c9, where \u03c9 = 2\u03c0f = 2\u03c0 \u00d7 50 = 314 rad\/s. Amplitude = 3.46 \u00d7 10<sup>\u22124<\/sup> \/ 314 = 1.10 \u00d7 10<sup>\u22126<\/sup> m.\n<strong>Answer: v<sub>peak<\/sub> = 3.46 \u00d7 10<sup>\u22124<\/sup> m\/s (0.346 mm\/s), and the electrons oscillate with an amplitude of just 1.10 \u03bcm.<\/strong>\n<\/div><\/details><\/div>\n<h2>Frequently Asked Questions<\/h2>\n\n<details class=\"pf-faq-item\"><summary>Is AC or DC used in homes?<\/summary><div class=\"pf-faq-item-answer\">\nHomes are wired for AC. Every ordinary wall socket delivers alternating current \u2014 roughly 230 V at 50 Hz across Europe, the UK, India and Pakistan, and 120 V at 60 Hz in North America. Almost everything you plug in then converts that AC into DC internally, which is exactly what the charger brick or the power supply inside an appliance is doing.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Is a battery AC or DC?<\/summary><div class=\"pf-faq-item-answer\">\nA battery is always DC. Its chemistry drives charge out of one terminal in a single direction, so the voltage holds a steady value and never reverses \u2014 about 1.5 V for an AA cell and 12 V for a car battery. Solar panels and USB ports are DC for the same reason: nothing inside them rotates or flips direction.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Why is AC used for power transmission instead of DC?<\/summary><div class=\"pf-faq-item-answer\">\nAC is used because a transformer can change its voltage cheaply and with very little loss, and nothing could do that for DC when the grid was built. High voltage means low current, and line loss depends on the square of the current, so stepping the voltage up 100 times cuts the wasted heat 10 000 times. Modern electronics have narrowed the gap, and high-voltage DC now wins on very long links.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Can AC be converted to DC?<\/summary><div class=\"pf-faq-item-answer\">\nYes \u2014 a rectifier does it. Diodes conduct in one direction only, so they block or flip the negative half of the wave, and a capacitor smooths what is left into a nearly steady DC voltage. That circuit sits inside every phone charger and laptop supply. An inverter runs the conversion the other way, turning battery or solar DC back into grid-compatible AC.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Is AC or DC more dangerous?<\/summary><div class=\"pf-faq-item-answer\">\nAt the same voltage, AC at mains frequency is generally treated as the more dangerous of the two. Alternating current at 50 or 60 Hz is unusually effective at disrupting the heart&#8217;s rhythm, and it can lock muscles so the victim cannot let go. DC tends to cause one strong contraction instead. Both are lethal at mains levels, and neither is safe to experiment with.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Why is mains voltage quoted as 230 V when the peak is 325 V?<\/summary><div class=\"pf-faq-item-answer\">\nBecause 230 V is the RMS value, not the peak. RMS is defined so that an AC supply heats a resistor by exactly as much as a DC supply of the same figure, which makes it the honest number for rating kettles and heaters. The waveform still climbs to about 325 V at the top of every cycle, so insulation and components must be specified for that peak.\n<\/div><\/details>\n","protected":false},"excerpt":{"rendered":"<p>AC reverses direction 100 times a second; DC flows steadily one way. Here are the 7 key differences, the RMS formula behind the 230 V on your plug, and why the grid runs on AC while everything plugged into it runs on DC.<\/p>\n","protected":false},"author":1,"featured_media":576,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"class_list":["post-575","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-electromagnetism"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/575","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=575"}],"version-history":[{"count":2,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/575\/revisions"}],"predecessor-version":[{"id":582,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/575\/revisions\/582"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/576"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=575"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=575"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=575"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}