{"id":572,"date":"2026-07-15T03:28:09","date_gmt":"2026-07-15T03:28:09","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=572"},"modified":"2026-07-15T03:28:11","modified_gmt":"2026-07-15T03:28:11","slug":"kirchhoffs-law","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/kirchhoffs-law\/","title":{"rendered":"Kirchhoff&#8217;s Laws (Current &amp; Voltage)"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\nKirchhoff&#8217;s law comes in two parts: the current law says the currents arriving at any junction equal those leaving it, and the voltage law says the potential differences around any closed loop sum to zero. Written compactly, \u03a3I = 0 and \u03a3V = 0 \u2014 conservation of charge and conservation of energy, applied to circuits.\n<\/p><\/div>\n\n<p>Somewhere in every physics course there is a circuit that breaks you. It has two batteries pointing at each other, a resistor shared between two loops, and no amount of squinting turns it into &#8220;series&#8221; or &#8220;parallel&#8221;. Ohm&#8217;s law, which has served faithfully until this exact moment, simply has nothing to say about it.<\/p>\n\n<p>That circuit is not a trick. It is the ordinary case \u2014 your phone charger, a car&#8217;s electrical system, the power supply on your desk \u2014 and it is what Kirchhoff&#8217;s laws were built for. Two rules. Both of them things you already believe.<\/p>\n\n<h2>What Is Kirchhoff&#8217;s Law?<\/h2>\n\n<p><strong>Kirchhoff&#8217;s law is a pair of rules for electrical circuits: the current law (KCL) states that the sum of currents at any junction is zero, and the voltage law (KVL) states that the sum of potential differences around any closed loop is zero.<\/strong> Together they let you solve any circuit made of ordinary components, however tangled.<\/p>\n\n<p>Here is the thing worth noticing. Neither law is really about electricity.<\/p>\n\n<p>The current law is a statement that charge does not pile up or vanish at a wire junction \u2014 whatever arrives must leave, because there is nowhere else for it to go. The voltage law is a statement that if you walk around a closed loop and return to where you started, you are back at the same potential. You cannot gain energy by walking in a circle. Both are conservation laws wearing a circuit diagram as a disguise.<\/p>\n\n<p>That is why they are so powerful. Conservation of charge and conservation of energy do not care whether your resistors are in series, in parallel, or in a knot no textbook has a name for.<\/p>\n\n<h3>A Note on the Names<\/h3>\n\n<p>The same two laws travel under several names, which trips people up when they compare sources. The current law is also the <strong>first law<\/strong>, the <strong>junction rule<\/strong>, the <strong>node rule<\/strong>, or <strong>KCL<\/strong>. The voltage law is also the <strong>second law<\/strong>, the <strong>loop rule<\/strong>, the <strong>mesh rule<\/strong>, or <strong>KVL<\/strong>. Same physics, different textbook.<\/p>\n\n<p>Gustav Robert Kirchhoff announced both laws in <strong>1845<\/strong>, aged 21 and still a student at Albertus University of K\u00f6nigsberg. He developed them in the mathematics-physics seminar run by Franz Neumann and Carl Jacobi, which he attended from 1843 to 1846, and they extended Georg Ohm&#8217;s work from single components to whole networks. He graduated in 1847, and later did major work in spectroscopy and black-body radiation. <a href=\"https:\/\/mathshistory.st-andrews.ac.uk\/Biographies\/Kirchhoff\/\" target=\"_blank\" rel=\"noopener\">The MacTutor archive at St Andrews<\/a> carries the fuller biography.<\/p>\n\n<figure style=\"margin:32px auto;max-width:600px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/07\/Gustav_Robert_Kirchhoff.jpg\"\n       alt=\"Gustav Kirchhoff, who formulated Kirchhoff's law of current and voltage in 1845\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">Gustav Robert Kirchhoff (1824-1887). He worked out both circuit laws as a student, before he had a doctorate.<\/figcaption>\n<\/figure>\n\n<h2>The Kirchhoff&#8217;s Law Formulas<\/h2>\n\n<p>Both laws are sums set equal to zero. That is the whole of the notation.<\/p>\n\n<p><strong>Kirchhoff&#8217;s Current Law (KCL) \u2014 the junction rule:<\/strong><\/p>\n\n<div class=\"pf-formula\">\u03a3I = 0   (at any junction)<\/div>\n\n<p>The algebraic sum of all currents at a junction is zero. Count currents flowing in as positive and currents flowing out as negative. Equivalently, and more usefully in practice:<\/p>\n\n<div class=\"pf-formula\">\u03a3I(in) = \u03a3I(out)<\/div>\n\n<p><strong>Kirchhoff&#8217;s Voltage Law (KVL) \u2014 the loop rule:<\/strong><\/p>\n\n<div class=\"pf-formula\">\u03a3V = 0   (around any closed loop)<\/div>\n\n<p>The algebraic sum of all potential differences around any closed loop is zero. Sources count as rises, resistors count as drops, and the signs are set by the direction you walk.<\/p>\n\n<h3>Every Symbol, With Its SI Unit<\/h3>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr>\n<th style=\"text-align:left;padding:10px;border-bottom:2px solid #C8932A;\">Symbol<\/th>\n<th style=\"text-align:left;padding:10px;border-bottom:2px solid #C8932A;\">Quantity<\/th>\n<th style=\"text-align:left;padding:10px;border-bottom:2px solid #C8932A;\">SI unit<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>I<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Electric current \u2014 rate of charge flow<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">ampere (A)<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>V<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Potential difference across a component<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">volt (V)<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>\u03b5<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">EMF \u2014 the voltage a source supplies<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">volt (V)<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>R<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Resistance<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">ohm (\u03a9)<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>Q<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Electric charge<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">coulomb (C)<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>\u03a3<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">&#8220;The sum of&#8221; \u2014 add every term, with its sign<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">\u2014<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>Notice that Kirchhoff&#8217;s laws never mention resistance. They constrain currents and voltages only. Every loop equation you write becomes solvable because you substitute <strong>V = IR<\/strong> for each resistor \u2014 so Ohm&#8217;s law is the engine and Kirchhoff&#8217;s laws are the steering. If you want to check a single V, I or R value while you work, our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/ohms-law\">Ohm&#8217;s Law Calculator<\/a> handles that one substitution instantly; the loop bookkeeping is still yours.<\/p>\n\n<h2>Kirchhoff&#8217;s Current Law: The Junction Rule<\/h2>\n\n<p><strong>Kirchhoff&#8217;s current law states that the total current flowing into any junction equals the total current flowing out of it.<\/strong> Charge is conserved, and a junction is just a point in a wire \u2014 it has no storage.<\/p>\n\n<p>Think of a road fork. Eight cars per minute arrive; eight cars per minute must leave, split however the roads dictate. Nothing accumulates at the fork itself, because a fork is not a car park.<\/p>\n\n<svg viewBox=\"0 0 640 330\" role=\"img\" aria-label=\"Kirchhoff's current law diagram: a junction with 5 A and 3 A flowing in and 2 A and 6 A flowing out, showing that current in equals current out\" style=\"width:100%;height:auto;max-width:640px;display:block;margin:0 auto;\"><rect width=\"640\" height=\"330\" fill=\"#0A1628\" rx=\"4\"><\/rect><text x=\"320\" y=\"30\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#C8932A\" letter-spacing=\"1.2\">KIRCHHOFF&#8217;S CURRENT LAW AT A JUNCTION<\/text><line x1=\"40\" y1=\"180\" x2=\"300\" y2=\"180\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><line x1=\"320\" y1=\"70\" x2=\"320\" y2=\"160\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><line x1=\"340\" y1=\"180\" x2=\"600\" y2=\"180\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><line x1=\"320\" y1=\"200\" x2=\"320\" y2=\"290\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><polygon points=\"248,180 228,169 228,191\" fill=\"#C8932A\"><\/polygon><polygon points=\"320,128 309,108 331,108\" fill=\"#C8932A\"><\/polygon><polygon points=\"540,180 520,169 520,191\" fill=\"#7A1F2B\"><\/polygon><polygon points=\"320,266 309,246 331,246\" fill=\"#7A1F2B\"><\/polygon><circle cx=\"320\" cy=\"180\" r=\"11\" fill=\"#C8932A\"><\/circle><circle cx=\"320\" cy=\"180\" r=\"11\" fill=\"none\" stroke=\"#FAF6EE\" stroke-width=\"1.5\"><\/circle><text x=\"150\" y=\"163\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"19\" font-weight=\"700\" fill=\"#C8932A\">I<tspan dy=\"5\" font-size=\"13\">1<\/tspan><tspan dy=\"-5\" font-size=\"19\"> = 5 A<\/tspan><\/text><text x=\"150\" y=\"207\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" fill=\"#C5D0DC\" font-style=\"italic\">in<\/text><text x=\"392\" y=\"96\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"19\" font-weight=\"700\" fill=\"#C8932A\">I<tspan dy=\"5\" font-size=\"13\">2<\/tspan><tspan dy=\"-5\" font-size=\"19\"> = 3 A<\/tspan><\/text><text x=\"392\" y=\"116\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" fill=\"#C5D0DC\" font-style=\"italic\">in<\/text><text x=\"470\" y=\"163\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"19\" font-weight=\"700\" fill=\"#FAF6EE\">I<tspan dy=\"5\" font-size=\"13\">3<\/tspan><tspan dy=\"-5\" font-size=\"19\"> = 2 A<\/tspan><\/text><text x=\"470\" y=\"207\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" fill=\"#C5D0DC\" font-style=\"italic\">out<\/text><text x=\"392\" y=\"258\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"19\" font-weight=\"700\" fill=\"#FAF6EE\">I<tspan dy=\"5\" font-size=\"13\">4<\/tspan><tspan dy=\"-5\" font-size=\"19\"> = 6 A<\/tspan><\/text><text x=\"392\" y=\"278\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" fill=\"#C5D0DC\" font-style=\"italic\">out<\/text><text x=\"320\" y=\"315\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"700\" fill=\"#FAF6EE\">5 A + 3 A = 2 A + 6 A   so   \u03a3I = 0<\/text><text x=\"60\" y=\"315\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#C5D0DC\">charge in<\/text><text x=\"580\" y=\"315\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#C5D0DC\">charge out<\/text><\/svg>\n\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;margin-top:8px;\">Kirchhoff&#8217;s current law at a junction: 5 A and 3 A arrive, 2 A and 6 A leave. Eight amperes in, eight amperes out.<\/p>\n\n<p>Write it with signs and the two forms agree. Taking &#8220;in&#8221; as positive: (+5) + (+3) + (\u22122) + (\u22126) = 0. Taking in equals out: 5 + 3 = 2 + 6. Use whichever you find less error-prone \u2014 most people find &#8220;in equals out&#8221; harder to get wrong.<\/p>\n\n<h3>Why It Has to Be True<\/h3>\n\n<p>Charge is conserved, and a junction has no capacity to store it. If more charge arrived than left, charge would accumulate at that point in the wire \u2014 building an electric field that would immediately push back and stop the imbalance. In practice this happens so fast, and at such vanishingly small charge, that the junction is always balanced for any circuit you will meet in a lab.<\/p>\n\n<p>That &#8220;in practice&#8221; hides a real limit, and we return to it below. A capacitor plate <em>is<\/em> a node where charge genuinely accumulates.<\/p>\n\n<h2>Kirchhoff&#8217;s Voltage Law: The Loop Rule<\/h2>\n\n<p><strong>Kirchhoff&#8217;s voltage law states that the sum of all potential differences around any closed loop is zero.<\/strong> Every rise is paid for by a drop somewhere else in the loop.<\/p>\n\n<p>Picture a walk through a hilly town that ends at your front door. Climb, descend, climb again, wander as much as you like \u2014 the moment you are back at the door, your net change in altitude is exactly zero. It has to be. It is the same door.<\/p>\n\n<p>Electric potential behaves identically. A battery lifts charge to a higher potential; resistors let it fall back down. Return to your starting point and the rises and drops must cancel exactly.<\/p>\n\n<h3>The Four Sign Cases \u2014 This Is Where Marks Are Lost<\/h3>\n\n<p>KVL is arithmetic. The only difficulty is the sign of each term, and there are exactly four cases to know.<\/p>\n\n<svg viewBox=\"0 0 720 410\" role=\"img\" aria-label=\"Kirchhoff's voltage law sign convention chart: walking with the current across a resistor gives minus I R, walking against it gives plus I R, walking from the minus to the plus terminal of a battery gives plus EMF, and walking from plus to minus gives minus EMF\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:0 auto;\"><rect width=\"720\" height=\"410\" fill=\"#0A1628\" rx=\"4\"><\/rect><text x=\"360\" y=\"30\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#C8932A\" letter-spacing=\"1.2\">THE FOUR KVL SIGN CASES \u2014 THE ONLY THING YOU MUST GET RIGHT<\/text><rect x=\"20\" y=\"52\" width=\"330\" height=\"160\" fill=\"#142139\" stroke=\"#D9CFB8\" stroke-width=\"1\" opacity=\"0.95\" rx=\"4\"><\/rect><text x=\"185\" y=\"76\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-weight=\"700\" fill=\"#C5D0DC\" letter-spacing=\"0.6\">RESISTOR \u2014 WALK WITH THE CURRENT<\/text><line x1=\"62\" y1=\"102\" x2=\"112\" y2=\"102\" stroke=\"#C8932A\" stroke-width=\"2\"><\/line><polygon points=\"122,102 110,96 110,108\" fill=\"#C8932A\"><\/polygon><text x=\"54\" y=\"107\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-style=\"italic\" font-weight=\"700\" fill=\"#C8932A\">I<\/text><line x1=\"45\" y1=\"126\" x2=\"150\" y2=\"126\" stroke=\"#C5D0DC\" stroke-width=\"2.5\"><\/line><rect x=\"150\" y=\"112\" width=\"60\" height=\"28\" fill=\"#0A1628\" stroke=\"#C8932A\" stroke-width=\"2\" rx=\"2\"><\/rect><line x1=\"210\" y1=\"126\" x2=\"325\" y2=\"126\" stroke=\"#C5D0DC\" stroke-width=\"2.5\"><\/line><text x=\"180\" y=\"131\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#FAF6EE\">R<\/text><line x1=\"240\" y1=\"152\" x2=\"296\" y2=\"152\" stroke=\"#FAF6EE\" stroke-width=\"1.5\" stroke-dasharray=\"4 3\"><\/line><polygon points=\"306,152 294,146 294,158\" fill=\"#FAF6EE\"><\/polygon><text x=\"232\" y=\"157\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#FAF6EE\">walk<\/text><text x=\"185\" y=\"186\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"26\" font-weight=\"700\" fill=\"#C8932A\">-IR<\/text><text x=\"185\" y=\"203\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-style=\"italic\" fill=\"#C5D0DC\">potential DROPS<\/text><rect x=\"370\" y=\"52\" width=\"330\" height=\"160\" fill=\"#142139\" stroke=\"#D9CFB8\" stroke-width=\"1\" opacity=\"0.95\" rx=\"4\"><\/rect><text x=\"535\" y=\"76\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-weight=\"700\" fill=\"#C5D0DC\" letter-spacing=\"0.6\">RESISTOR \u2014 WALK AGAINST THE CURRENT<\/text><line x1=\"412\" y1=\"102\" x2=\"462\" y2=\"102\" stroke=\"#C8932A\" stroke-width=\"2\"><\/line><polygon points=\"472,102 460,96 460,108\" fill=\"#C8932A\"><\/polygon><text x=\"404\" y=\"107\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-style=\"italic\" font-weight=\"700\" fill=\"#C8932A\">I<\/text><line x1=\"395\" y1=\"126\" x2=\"500\" y2=\"126\" stroke=\"#C5D0DC\" stroke-width=\"2.5\"><\/line><rect x=\"500\" y=\"112\" width=\"60\" height=\"28\" fill=\"#0A1628\" stroke=\"#C8932A\" stroke-width=\"2\" rx=\"2\"><\/rect><line x1=\"560\" y1=\"126\" x2=\"675\" y2=\"126\" stroke=\"#C5D0DC\" stroke-width=\"2.5\"><\/line><text x=\"530\" y=\"131\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#FAF6EE\">R<\/text><line x1=\"656\" y1=\"152\" x2=\"600\" y2=\"152\" stroke=\"#FAF6EE\" stroke-width=\"1.5\" stroke-dasharray=\"4 3\"><\/line><polygon points=\"590,152 602,146 602,158\" fill=\"#FAF6EE\"><\/polygon><text x=\"664\" y=\"157\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#FAF6EE\">walk<\/text><text x=\"535\" y=\"186\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"26\" font-weight=\"700\" fill=\"#C8932A\">+IR<\/text><text x=\"535\" y=\"203\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-style=\"italic\" fill=\"#C5D0DC\">potential RISES<\/text><rect x=\"20\" y=\"228\" width=\"330\" height=\"160\" fill=\"#142139\" stroke=\"#D9CFB8\" stroke-width=\"1\" opacity=\"0.95\" rx=\"4\"><\/rect><text x=\"185\" y=\"252\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-weight=\"700\" fill=\"#C5D0DC\" letter-spacing=\"0.6\">BATTERY \u2014 WALK FROM MINUS TO PLUS<\/text><line x1=\"45\" y1=\"302\" x2=\"178\" y2=\"302\" stroke=\"#C5D0DC\" stroke-width=\"2.5\"><\/line><line x1=\"178\" y1=\"290\" x2=\"178\" y2=\"314\" stroke=\"#FAF6EE\" stroke-width=\"6\"><\/line><line x1=\"192\" y1=\"284\" x2=\"192\" y2=\"320\" stroke=\"#FAF6EE\" stroke-width=\"2.5\"><\/line><line x1=\"192\" y1=\"302\" x2=\"325\" y2=\"302\" stroke=\"#C5D0DC\" stroke-width=\"2.5\"><\/line><text x=\"172\" y=\"277\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"700\" fill=\"#FAF6EE\">&#8211;<\/text><text x=\"198\" y=\"277\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"700\" fill=\"#FAF6EE\">+<\/text><line x1=\"240\" y1=\"330\" x2=\"296\" y2=\"330\" stroke=\"#FAF6EE\" stroke-width=\"1.5\" stroke-dasharray=\"4 3\"><\/line><polygon points=\"306,330 294,324 294,336\" fill=\"#FAF6EE\"><\/polygon><text x=\"232\" y=\"335\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#FAF6EE\">walk<\/text><text x=\"185\" y=\"362\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"26\" font-weight=\"700\" fill=\"#C8932A\">+\u03b5<\/text><text x=\"185\" y=\"379\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-style=\"italic\" fill=\"#C5D0DC\">potential RISES<\/text><rect x=\"370\" y=\"228\" width=\"330\" height=\"160\" fill=\"#142139\" stroke=\"#D9CFB8\" stroke-width=\"1\" opacity=\"0.95\" rx=\"4\"><\/rect><text x=\"535\" y=\"252\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-weight=\"700\" fill=\"#C5D0DC\" letter-spacing=\"0.6\">BATTERY \u2014 WALK FROM PLUS TO MINUS<\/text><line x1=\"395\" y1=\"302\" x2=\"528\" y2=\"302\" stroke=\"#C5D0DC\" stroke-width=\"2.5\"><\/line><line x1=\"528\" y1=\"284\" x2=\"528\" y2=\"320\" stroke=\"#FAF6EE\" stroke-width=\"2.5\"><\/line><line x1=\"542\" y1=\"290\" x2=\"542\" y2=\"314\" stroke=\"#FAF6EE\" stroke-width=\"6\"><\/line><line x1=\"542\" y1=\"302\" x2=\"675\" y2=\"302\" stroke=\"#C5D0DC\" stroke-width=\"2.5\"><\/line><text x=\"522\" y=\"277\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"700\" fill=\"#FAF6EE\">+<\/text><text x=\"548\" y=\"277\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"700\" fill=\"#FAF6EE\">&#8211;<\/text><line x1=\"590\" y1=\"330\" x2=\"646\" y2=\"330\" stroke=\"#FAF6EE\" stroke-width=\"1.5\" stroke-dasharray=\"4 3\"><\/line><polygon points=\"656,330 644,324 644,336\" fill=\"#FAF6EE\"><\/polygon><text x=\"582\" y=\"335\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" fill=\"#FAF6EE\">walk<\/text><text x=\"535\" y=\"362\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"26\" font-weight=\"700\" fill=\"#C8932A\">-\u03b5<\/text><text x=\"535\" y=\"379\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-style=\"italic\" fill=\"#C5D0DC\">potential DROPS<\/text><\/svg>\n\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;margin-top:8px;\">The four sign cases for Kirchhoff&#8217;s voltage law. The sign depends on the direction you walk, not on the component.<\/p>\n\n<p>The rule in one line: <strong>the sign is decided by your direction of travel, not by the component.<\/strong> Walk downhill and the term is negative; walk uphill and it is positive.<\/p>\n\n<ul>\n<li><strong>Resistor, walking with the current:<\/strong> \u2212IR (you are going downhill, with the flow)<\/li>\n<li><strong>Resistor, walking against the current:<\/strong> +IR<\/li>\n<li><strong>Battery, entering \u2212 and leaving +:<\/strong> +\u03b5 (you climbed the battery)<\/li>\n<li><strong>Battery, entering + and leaving \u2212:<\/strong> \u2212\u03b5<\/li>\n<\/ul>\n\n<p>A common student slip: reading the battery&#8217;s own label instead of the direction of travel. The same 12 V battery contributes +12 V or \u221212 V depending purely on which way your loop happens to cross it. Pick a loop direction, mark it on the diagram, and never change it mid-equation.<\/p>\n\n<h3>KCL vs KVL at a Glance<\/h3>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr>\n<th style=\"text-align:left;padding:10px;border-bottom:2px solid #C8932A;\"> <\/th>\n<th style=\"text-align:left;padding:10px;border-bottom:2px solid #C8932A;\">Current Law (KCL)<\/th>\n<th style=\"text-align:left;padding:10px;border-bottom:2px solid #C8932A;\">Voltage Law (KVL)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>Also called<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">First law, junction rule, node rule<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Second law, loop rule, mesh rule<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>Statement<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">\u03a3I = 0 at a junction<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">\u03a3V = 0 around a loop<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>Applied where<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">At a point (a node)<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Around a path (a closed loop)<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>Conservation of<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Charge<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Energy<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>Sign set by<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Whether current enters or leaves<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Your chosen direction of travel<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>Fails when<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Charge accumulates at the node<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">Magnetic flux through the loop changes<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\"><strong>Equations you get<\/strong><\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">(number of nodes) \u2212 1<\/td>\n<td style=\"padding:10px;border-bottom:1px solid #D9CFB8;\">One per independent loop<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<h2>How to Apply Kirchhoff&#8217;s Laws in 5 Steps<\/h2>\n\n<p><strong>Apply Kirchhoff&#8217;s laws by labelling the currents, writing one junction equation, walking each loop to write its voltage equation, and solving the simultaneous equations.<\/strong> The method never changes, no matter how ugly the circuit.<\/p>\n\n<ol>\n<li><strong>Label every branch current<\/strong> \u2014 I<sub>1<\/sub>, I<sub>2<\/sub>, I<sub>3<\/sub>\u2026 and draw an arrow for each. <strong>Guess the directions.<\/strong> Genuinely \u2014 guess. The maths will correct you.<\/li>\n<li><strong>Write the junction equations.<\/strong> With <em>n<\/em> junctions you get <em>n<\/em> \u2212 1 useful ones; the last is a repeat of the others and tells you nothing new.<\/li>\n<li><strong>Choose a loop and a direction.<\/strong> Mark the direction on the diagram with an arrow. Clockwise for everything is a fine habit.<\/li>\n<li><strong>Walk the loop and write \u03a3V = 0<\/strong>, using the four sign cases. Substitute V = IR at each resistor.<\/li>\n<li><strong>Solve the simultaneous equations.<\/strong> A negative answer is not an error \u2014 it means that current runs opposite to your arrow, at exactly that magnitude.<\/li>\n<\/ol>\n\n<p>You need as many independent equations as unknown currents. Three unknowns, three equations: usually one junction equation and two loop equations.<\/p>\n\n<h3>The Method on a Real Circuit<\/h3>\n\n<p>Here is the canonical case \u2014 two batteries, three branches, one shared resistor. It cannot be reduced by series or parallel rules, so Ohm&#8217;s law alone is helpless. Kirchhoff&#8217;s laws solve it in three lines.<\/p>\n\n<svg viewBox=\"0 0 760 400\" role=\"img\" aria-label=\"Kirchhoff's law two-loop circuit diagram showing a 12 V battery with a 3 ohm resistor, a 10 V battery with a 4 ohm resistor, and a shared 2 ohm resistor, with loop 1 and loop 2 traversal arrows and solved currents of 2 A, 1 A and 3 A\" style=\"width:100%;height:auto;max-width:760px;display:block;margin:0 auto;\"><rect width=\"760\" height=\"400\" fill=\"#0A1628\" rx=\"4\"><\/rect><text x=\"380\" y=\"30\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#C8932A\" letter-spacing=\"1.2\">A TWO-LOOP CIRCUIT: ONE JUNCTION EQUATION, TWO LOOP EQUATIONS<\/text><line x1=\"150\" y1=\"80\" x2=\"610\" y2=\"80\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><line x1=\"150\" y1=\"320\" x2=\"610\" y2=\"320\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><line x1=\"150\" y1=\"80\" x2=\"150\" y2=\"138\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><line x1=\"124\" y1=\"138\" x2=\"176\" y2=\"138\" stroke=\"#FAF6EE\" stroke-width=\"2.5\"><\/line><line x1=\"136\" y1=\"152\" x2=\"164\" y2=\"152\" stroke=\"#FAF6EE\" stroke-width=\"6\"><\/line><line x1=\"150\" y1=\"152\" x2=\"150\" y2=\"213\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><rect x=\"137\" y=\"213\" width=\"26\" height=\"54\" fill=\"#142139\" stroke=\"#C8932A\" stroke-width=\"2.5\" rx=\"2\"><\/rect><line x1=\"150\" y1=\"267\" x2=\"150\" y2=\"320\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><text x=\"184\" y=\"143\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#FAF6EE\">+<\/text><text x=\"184\" y=\"158\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#FAF6EE\">&#8211;<\/text><text x=\"116\" y=\"150\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"700\" fill=\"#C8932A\">\u03b5<tspan dy=\"4\" font-size=\"12\">1<\/tspan><tspan dy=\"-4\" font-size=\"17\"> = 12 V<\/tspan><\/text><text x=\"128\" y=\"246\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"700\" fill=\"#C8932A\">R<tspan dy=\"4\" font-size=\"12\">1<\/tspan><tspan dy=\"-4\" font-size=\"17\"> = 3 \u03a9<\/tspan><\/text><line x1=\"610\" y1=\"80\" x2=\"610\" y2=\"138\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><line x1=\"584\" y1=\"138\" x2=\"636\" y2=\"138\" stroke=\"#FAF6EE\" stroke-width=\"2.5\"><\/line><line x1=\"596\" y1=\"152\" x2=\"624\" y2=\"152\" stroke=\"#FAF6EE\" stroke-width=\"6\"><\/line><line x1=\"610\" y1=\"152\" x2=\"610\" y2=\"213\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><rect x=\"597\" y=\"213\" width=\"26\" height=\"54\" fill=\"#142139\" stroke=\"#C8932A\" stroke-width=\"2.5\" rx=\"2\"><\/rect><line x1=\"610\" y1=\"267\" x2=\"610\" y2=\"320\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><text x=\"576\" y=\"143\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#FAF6EE\">+<\/text><text x=\"576\" y=\"158\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" font-weight=\"700\" fill=\"#FAF6EE\">&#8211;<\/text><text x=\"644\" y=\"150\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"700\" fill=\"#C8932A\">\u03b5<tspan dy=\"4\" font-size=\"12\">2<\/tspan><tspan dy=\"-4\" font-size=\"17\"> = 10 V<\/tspan><\/text><text x=\"632\" y=\"246\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"700\" fill=\"#C8932A\">R<tspan dy=\"4\" font-size=\"12\">2<\/tspan><tspan dy=\"-4\" font-size=\"17\"> = 4 \u03a9<\/tspan><\/text><line x1=\"380\" y1=\"80\" x2=\"380\" y2=\"173\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><rect x=\"367\" y=\"173\" width=\"26\" height=\"54\" fill=\"#142139\" stroke=\"#C8932A\" stroke-width=\"2.5\" rx=\"2\"><\/rect><line x1=\"380\" y1=\"227\" x2=\"380\" y2=\"320\" stroke=\"#C5D0DC\" stroke-width=\"3\"><\/line><text x=\"404\" y=\"205\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"700\" fill=\"#C8932A\">R<tspan dy=\"4\" font-size=\"12\">3<\/tspan><tspan dy=\"-4\" font-size=\"17\"> = 2 \u03a9<\/tspan><\/text><path d=\"M 269 167.1 A 38 38 0 1 1 231 167.1\" fill=\"none\" stroke=\"#C8932A\" stroke-width=\"2\" opacity=\"0.75\" stroke-dasharray=\"5 4\"><\/path><polygon points=\"231,167.1 222.4,180.2 215.4,168\" fill=\"#C8932A\" opacity=\"0.85\"><\/polygon><text x=\"250\" y=\"206\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-weight=\"700\" fill=\"#C5D0DC\" letter-spacing=\"0.8\">LOOP 1<\/text><path d=\"M 491 167.1 A 38 38 0 1 0 529 167.1\" fill=\"none\" stroke=\"#C8932A\" stroke-width=\"2\" opacity=\"0.75\" stroke-dasharray=\"5 4\"><\/path><polygon points=\"529,167.1 544.6,168 537.6,180.2\" fill=\"#C8932A\" opacity=\"0.85\"><\/polygon><text x=\"510\" y=\"206\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12\" font-weight=\"700\" fill=\"#C5D0DC\" letter-spacing=\"0.8\">LOOP 2<\/text><polygon points=\"277,80 263,74 263,86\" fill=\"#7A1F2B\"><\/polygon><polygon points=\"277,80 263,74 263,86\" fill=\"none\" stroke=\"#FAF6EE\" stroke-width=\"1\"><\/polygon><text x=\"265\" y=\"64\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"700\" fill=\"#FAF6EE\">I<tspan dy=\"4\" font-size=\"11\">1<\/tspan><tspan dy=\"-4\" font-size=\"16\"> = 2 A<\/tspan><\/text><polygon points=\"483,80 497,74 497,86\" fill=\"#7A1F2B\"><\/polygon><polygon points=\"483,80 497,74 497,86\" fill=\"none\" stroke=\"#FAF6EE\" stroke-width=\"1\"><\/polygon><text x=\"495\" y=\"64\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"700\" fill=\"#FAF6EE\">I<tspan dy=\"4\" font-size=\"11\">2<\/tspan><tspan dy=\"-4\" font-size=\"16\"> = 1 A<\/tspan><\/text><polygon points=\"380,144 374,130 386,130\" fill=\"#7A1F2B\"><\/polygon><polygon points=\"380,144 374,130 386,130\" fill=\"none\" stroke=\"#FAF6EE\" stroke-width=\"1\"><\/polygon><text x=\"398\" y=\"127\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"700\" fill=\"#FAF6EE\">I<tspan dy=\"4\" font-size=\"11\">3<\/tspan><tspan dy=\"-4\" font-size=\"16\"> = 3 A<\/tspan><\/text><circle cx=\"380\" cy=\"80\" r=\"8\" fill=\"#C8932A\" stroke=\"#FAF6EE\" stroke-width=\"1.5\"><\/circle><circle cx=\"380\" cy=\"320\" r=\"8\" fill=\"#C8932A\" stroke=\"#FAF6EE\" stroke-width=\"1.5\"><\/circle><text x=\"348\" y=\"60\" text-anchor=\"end\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"700\" fill=\"#C8932A\">node A<\/text><text x=\"380\" y=\"346\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"700\" fill=\"#C8932A\">node B<\/text><text x=\"380\" y=\"378\" text-anchor=\"middle\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" fill=\"#C5D0DC\">Junction: I<tspan dy=\"3\" font-size=\"10\">1<\/tspan><tspan dy=\"-3\" font-size=\"14\"> + I<\/tspan><tspan dy=\"3\" font-size=\"10\">2<\/tspan><tspan dy=\"-3\" font-size=\"14\"> = I<\/tspan><tspan dy=\"3\" font-size=\"10\">3<\/tspan><tspan dy=\"-3\" font-size=\"14\">    \u00b7    Loop 1: \u03b5<\/tspan><tspan dy=\"3\" font-size=\"10\">1<\/tspan><tspan dy=\"-3\" font-size=\"14\"> = I<\/tspan><tspan dy=\"3\" font-size=\"10\">1<\/tspan><tspan dy=\"-3\" font-size=\"14\">R<\/tspan><tspan dy=\"3\" font-size=\"10\">1<\/tspan><tspan dy=\"-3\" font-size=\"14\"> + I<\/tspan><tspan dy=\"3\" font-size=\"10\">3<\/tspan><tspan dy=\"-3\" font-size=\"14\">R<\/tspan><tspan dy=\"3\" font-size=\"10\">3<\/tspan><tspan dy=\"-3\" font-size=\"14\">    \u00b7    Loop 2: \u03b5<\/tspan><tspan dy=\"3\" font-size=\"10\">2<\/tspan><tspan dy=\"-3\" font-size=\"14\"> = I<\/tspan><tspan dy=\"3\" font-size=\"10\">2<\/tspan><tspan dy=\"-3\" font-size=\"14\">R<\/tspan><tspan dy=\"3\" font-size=\"10\">2<\/tspan><tspan dy=\"-3\" font-size=\"14\"> + I<\/tspan><tspan dy=\"3\" font-size=\"10\">3<\/tspan><tspan dy=\"-3\" font-size=\"14\">R<\/tspan><tspan dy=\"3\" font-size=\"10\">3<\/tspan><\/text><\/svg>\n\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;margin-top:8px;\">The two-loop circuit solved by Kirchhoff&#8217;s law: one junction equation and two loop equations give I<sub>1<\/sub> = 2 A, I<sub>2<\/sub> = 1 A and I<sub>3<\/sub> = 3 A. This is Worked Problem 5 below.<\/p>\n\n<p>Three unknowns, three equations, no cleverness required. MIT OpenCourseWare&#8217;s <a href=\"https:\/\/ocw.mit.edu\/courses\/8-02-physics-ii-electricity-and-magnetism-spring-2007\/889322bd4426984d161121cf5cf2cb31_chap7dc_circuits.pdf\" target=\"_blank\" rel=\"noopener\">8.02 chapter on DC circuits<\/a> sets out the same procedure formally in its problem-solving strategy section, if you want the university-level statement of it.<\/p>\n\n<p>Now change the numbers and watch the currents move. The lab below solves the same topology live \u2014 drag the EMFs and resistances and see which way the currents actually flow.<\/p>\n\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Kirchhoff&#039;s Law Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/kirchhoffs-law.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n\n<h2>Real-World Examples of Kirchhoff&#8217;s Laws<\/h2>\n\n<p><strong>Kirchhoff&#8217;s laws are used anywhere current has more than one path to take<\/strong> \u2014 which is to say, in essentially every circuit built since 1845.<\/p>\n\n<p><strong>Every circuit simulator you have ever used.<\/strong> SPICE, the engine inside most electronics design software, is at heart a machine that writes Kirchhoff&#8217;s current law at every node and solves the resulting matrix. Every chip in your phone was verified this way before it was ever fabricated.<\/p>\n\n<p><strong>Your car&#8217;s electrical system.<\/strong> Alternator and battery both feed the same bus while headlights, ignition and heated seats all draw from it. When the alternator wins, current flows backwards into the battery and charges it \u2014 a negative current in exactly the sense the loop rule predicts.<\/p>\n\n<p><strong>The national grid.<\/strong> Power stations feed a mesh with thousands of nodes and no series-parallel structure at all. Load-flow analysis \u2014 the calculation that keeps the lights on \u2014 is Kirchhoff&#8217;s laws at industrial scale.<\/p>\n\n<p><strong>The Wheatstone bridge.<\/strong> Five resistors in a diamond, and not one pair is in series or parallel. It is the classic circuit that Ohm&#8217;s law alone cannot touch, and it is still the standard way to read a strain gauge or a platinum thermometer.<\/p>\n\n<p><strong>Battery packs in parallel.<\/strong> Wire two cells with unequal charge together and current flows between them. KCL tells you how much, and it is the reason mixing old and new cells is a bad idea.<\/p>\n\n<h2>Common Misconceptions About Kirchhoff&#8217;s Laws<\/h2>\n\n<p>Four beliefs cause most of the lost marks. Each is worth correcting precisely.<\/p>\n\n<h3>&#8220;Current gets used up as it goes round&#8221;<\/h3>\n\n<p>It does not. Current is charge flow, and charge is conserved \u2014 the current leaving a bulb is identical to the current entering it. What gets used up is <strong>energy<\/strong>, not charge. The bulb drops the potential; it does not consume the electrons.<\/p>\n\n<h3>&#8220;If I guess a current&#8217;s direction wrong, my answer is wrong&#8221;<\/h3>\n\n<p>This is the big one, and the opposite is true. Guess every direction backwards and the algebra will hand you every current with a minus sign \u2014 correct magnitudes, and a sign telling you to flip the arrow. That is not damage control; it is the method working as designed. Worked Problem 6 does this deliberately.<\/p>\n\n<h3>&#8220;KVL means the voltages are all equal&#8221;<\/h3>\n\n<p>KVL says the rises and drops <em>cancel<\/em>, not that they match one another. A 12 V battery driving a 3 \u03a9 and a 9 \u03a9 resistor in series gives drops of 3 V and 9 V. Unequal \u2014 but they sum to 12 V, and that is what the loop rule demands.<\/p>\n\n<h3>&#8220;Kirchhoff&#8217;s laws replace Ohm&#8217;s law&#8221;<\/h3>\n\n<p>They need each other. Kirchhoff&#8217;s laws relate currents to currents and voltages to voltages; nothing in them connects the two. Ohm&#8217;s law is what turns a loop equation into something solvable. Kirchhoff without Ohm gives you a system with more unknowns than equations.<\/p>\n\n<h2>When Kirchhoff&#8217;s Laws Break Down<\/h2>\n\n<p><strong>Kirchhoff&#8217;s laws are approximations, and both fail under conditions you can state exactly.<\/strong> This is not a footnote \u2014 it is the boundary of the whole lumped-element model, and knowing it separates a student from an engineer.<\/p>\n\n<p><strong>KCL fails when charge really does accumulate at a node.<\/strong> The law assumes a junction cannot store charge. A capacitor plate is precisely a node that stores charge \u2014 which is why, strictly, the current flowing into a capacitor does not equal the current flowing out of that plate. The standard fix is to treat the capacitor as a component with the displacement current running through it, restoring the balance.<\/p>\n\n<p><strong>KVL fails when magnetic flux through the loop is changing.<\/strong> The loop rule rests on the electric field being conservative \u2014 that \u222eE\u00b7dl = 0 around any closed path. Faraday&#8217;s law says otherwise the moment flux changes: \u222eE\u00b7dl = \u2212d\u03a6\/dt. Put a loop of wire near a transformer and walk it with KVL, and you will get an answer that is simply wrong, because energy is entering the loop through the field rather than through any component.<\/p>\n\n<p>Both failures have the same root: <strong>the lumped-element approximation<\/strong>. Kirchhoff&#8217;s laws hold when the circuit is small compared with the wavelength of the signals in it, so that changes propagate across it effectively instantly. Feynman treats exactly this point in his lectures on <a href=\"https:\/\/www.feynmanlectures.caltech.edu\/II_22.html\" target=\"_blank\" rel=\"noopener\">AC circuits and networks of ideal elements<\/a>, where the rules are derived as the limit in which fields stay confined to components.<\/p>\n\n<p>A magnitude check makes it concrete. At 50 Hz mains, the wavelength is thousands of kilometres \u2014 a circuit board is nothing, and Kirchhoff&#8217;s laws are effectively exact. At 5 GHz the wavelength is about 6 cm, and a 3 cm trace is no longer a wire but an antenna. This is why high-frequency design uses transmission-line theory instead.<\/p>\n\n<p>So: for every circuit in your course, and almost every circuit on your bench, the laws hold to far better than your components&#8217; tolerances.<\/p>\n\n<h2>How Kirchhoff&#8217;s Laws Relate to Ohm&#8217;s Law and Energy Conservation<\/h2>\n\n<p><strong>Kirchhoff&#8217;s laws are the circuit-sized expression of two conservation laws, and they need Ohm&#8217;s law to become solvable.<\/strong> Three familiar ideas, one structure.<\/p>\n\n<p>Start with <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/ohms-law\/\">Ohm&#8217;s law<\/a>. V = IR describes a single component; it says nothing about how components share a network. Kirchhoff&#8217;s laws describe the network but say nothing about components. Neither is complete alone \u2014 every loop equation is Kirchhoff&#8217;s structure with Ohm&#8217;s law substituted in at each resistor.<\/p>\n\n<p>The voltage law is <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/what-is-energy-in-physics\/\">conservation of energy<\/a> in disguise. Voltage is <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/work-done-in-physics\/\">work done<\/a> per unit charge, so \u03a3V = 0 around a loop says the work done on a charge by the sources exactly equals the work it gives up in the resistors. Take a charge around and hand it back unchanged.<\/p>\n\n<p>The current law is conservation of charge \u2014 the same conserved quantity that <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/coulombs-law\/\">Coulomb&#8217;s law<\/a> is built on. Charge cannot be created or destroyed, so it cannot pool at a junction.<\/p>\n\n<p>Follow the energy one step further and you land in thermodynamics. The energy the resistors take does not disappear; it becomes heat, and it does not come back. That is the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/thermodynamics\/laws-of-thermodynamics\/\">first and second laws of thermodynamics<\/a> arriving in your circuit \u2014 KVL is the bookkeeping, and the warm resistor is the receipt.<\/p>\n\n<h2>Worked Problems<\/h2>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">At a junction, 5 A and 3 A flow in, and 2 A flows out along one branch. What is the current in the fourth branch, and which way does it flow?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Apply Kirchhoff&#8217;s current law. \u03a3I(in) = \u03a3I(out).<\/p>\n<p>Step 2: Substitute. 5 A + 3 A = 2 A + I<sub>4<\/sub><\/p>\n<p>Step 3: Solve. 8 A = 2 A + I<sub>4<\/sub>, so I<sub>4<\/sub> = 6 A.<\/p>\n<p>Step 4: Check the sign. The result is positive, so the assumed direction was right: it flows out of the junction. Total in = 8 A, total out = 2 + 6 = 8 A. \u2714<\/p>\n<p><strong>Answer: I<sub>4<\/sub> = 6 A, flowing out of the junction.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A 9 V battery drives a single loop containing R1 = 2 \u03a9 and R2 = 4 \u03a9 in series. Find the current, and verify with Kirchhoff&#039;s voltage law.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Walk the loop clockwise, in the direction of the current. Crossing the battery from \u2212 to + gives +9 V; each resistor is crossed with the current, so each contributes \u2212IR. KVL: +9 \u2212 I(2) \u2212 I(4) = 0<\/p>\n<p>Step 2: Collect terms. 9 = I(2 + 4) = 6I<\/p>\n<p>Step 3: Solve. I = 9\/6 = 1.5 A<\/p>\n<p>Step 4: Verify the drops. V<sub>1<\/sub> = 1.5 \u00d7 2 = 3 V; V<sub>2<\/sub> = 1.5 \u00d7 4 = 6 V. Sum = 9 V, exactly the EMF. \u2714<\/p>\n<p><strong>Answer: I = 1.5 A; the drops are 3 V and 6 V, summing to the 9 V supplied.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A 12 V battery feeds three resistors in parallel: 2 \u03a9, 3 \u03a9 and 6 \u03a9. Use Kirchhoff&#039;s laws to find the total current and the equivalent resistance.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Apply KVL to each of the three loops. Each resistor sits directly across the battery, so each has the full 12 V across it.<\/p>\n<p>Step 2: Apply Ohm&#8217;s law to each branch. I<sub>1<\/sub> = 12\/2 = 6 A; I<sub>2<\/sub> = 12\/3 = 4 A; I<sub>3<\/sub> = 12\/6 = 2 A<\/p>\n<p>Step 3: Apply KCL at the junction where the branches rejoin. I<sub>total<\/sub> = 6 + 4 + 2 = 12 A<\/p>\n<p>Step 4: Find the equivalent resistance. R<sub>eq<\/sub> = V\/I<sub>total<\/sub> = 12\/12 = 1 \u03a9<\/p>\n<p>Step 5: Cross-check against the parallel formula. 1\/R<sub>eq<\/sub> = 1\/2 + 1\/3 + 1\/6 = 1, so R<sub>eq<\/sub> = 1 \u03a9. \u2714 The parallel rule is not a separate law \u2014 it is KCL in a hat.<\/p>\n<p><strong>Answer: I<sub>total<\/sub> = 12 A and R<sub>eq<\/sub> = 1 \u03a9.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">Two batteries are wired in one loop with their terminals opposing: a 12 V battery drives forward, a 4 V battery opposes it. Two 2 \u03a9 resistors are in the loop. Find the current.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Assume the current flows clockwise, driven by the 12 V battery, and walk the loop clockwise. The 12 V battery is crossed \u2212 to +, giving +12 V. The 4 V battery is crossed + to \u2212, giving \u22124 V. Each resistor is crossed with the current: \u2212I(2) each.<\/p>\n<p>Step 2: Write KVL. +12 \u2212 4 \u2212 2I \u2212 2I = 0<\/p>\n<p>Step 3: Collect and solve. 8 = 4I, so I = 2 A<\/p>\n<p>Step 4: Verify. Drops are 2 \u00d7 2 = 4 V each. Walking round: 12 \u2212 4 \u2212 4 \u2212 4 = 0. \u2714 The 4 V battery is being charged by the 12 V one.<\/p>\n<p><strong>Answer: I = 2 A, flowing clockwise; the 4 V battery is being charged.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">In the two-loop circuit above: battery 1 is 12 V with R1 = 3 \u03a9, battery 2 is 10 V with R2 = 4 \u03a9, and both branches meet at node A and share R3 = 2 \u03a9 back to node B. Find all three currents.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Label and guess. I<sub>1<\/sub> flows from battery 1 into node A; I<sub>2<\/sub> flows from battery 2 into node A; I<sub>3<\/sub> flows from node A down through R<sub>3<\/sub>.<\/p>\n<p>Step 2: Apply KCL at node A. I<sub>1<\/sub> + I<sub>2<\/sub> = I<sub>3<\/sub><\/p>\n<p>Step 3: Walk loop 1 (battery 1, R<sub>1<\/sub>, R<sub>3<\/sub>). 12 = 3I<sub>1<\/sub> + 2I<sub>3<\/sub><\/p>\n<p>Step 4: Walk loop 2 (battery 2, R<sub>2<\/sub>, R<sub>3<\/sub>). 10 = 4I<sub>2<\/sub> + 2I<sub>3<\/sub><\/p>\n<p>Step 5: Substitute I<sub>3<\/sub> = I<sub>1<\/sub> + I<sub>2<\/sub> into both loop equations.<br>12 = 3I<sub>1<\/sub> + 2(I<sub>1<\/sub> + I<sub>2<\/sub>) = 5I<sub>1<\/sub> + 2I<sub>2<\/sub><br>10 = 4I<sub>2<\/sub> + 2(I<sub>1<\/sub> + I<sub>2<\/sub>) = 2I<sub>1<\/sub> + 6I<sub>2<\/sub><\/p>\n<p>Step 6: Solve the pair. Multiply the first by 3 to match the I<sub>2<\/sub> terms: 36 = 15I<sub>1<\/sub> + 6I<sub>2<\/sub>. Subtracting the second equation gives 26 = 13I<sub>1<\/sub>, so I<sub>1<\/sub> = 2 A.<\/p>\n<p>Step 7: Back-substitute. 12 = 5(2) + 2I<sub>2<\/sub> gives I<sub>2<\/sub> = 1 A, and KCL then gives I<sub>3<\/sub> = 2 + 1 = 3 A.<\/p>\n<p>Step 8: Check both loops. Loop 1: 3(2) + 2(3) = 6 + 6 = 12 \u2714. Loop 2: 4(1) + 2(3) = 4 + 6 = 10 \u2714<\/p>\n<p><strong>Answer: I<sub>1<\/sub> = 2 A, I<sub>2<\/sub> = 1 A, I<sub>3<\/sub> = 3 A.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">Same circuit shape, harsher numbers: battery 1 is 12 V with R1 = 2 \u03a9, battery 2 is only 2 V with R2 = 4 \u03a9, and the shared branch is R3 = 3 \u03a9. Find all three currents and explain the sign.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Assume the same directions as before \u2014 both I<sub>1<\/sub> and I<sub>2<\/sub> flowing into node A, I<sub>3<\/sub> flowing out through R<sub>3<\/sub>. KCL: I<sub>1<\/sub> + I<sub>2<\/sub> = I<sub>3<\/sub><\/p>\n<p>Step 2: Walk loop 1. 12 = 2I<sub>1<\/sub> + 3I<sub>3<\/sub><\/p>\n<p>Step 3: Walk loop 2. 2 = 4I<sub>2<\/sub> + 3I<sub>3<\/sub><\/p>\n<p>Step 4: Substitute I<sub>3<\/sub> = I<sub>1<\/sub> + I<sub>2<\/sub>.<br>12 = 5I<sub>1<\/sub> + 3I<sub>2<\/sub><br>2 = 3I<sub>1<\/sub> + 7I<sub>2<\/sub><\/p>\n<p>Step 5: Solve. Multiply the first by 7 and the second by 3, giving 84 = 35I<sub>1<\/sub> + 21I<sub>2<\/sub> and 6 = 9I<sub>1<\/sub> + 21I<sub>2<\/sub>. Subtracting leaves 78 = 26I<sub>1<\/sub>, so I<sub>1<\/sub> = 3 A.<\/p>\n<p>Step 6: Back-substitute. 12 = 5(3) + 3I<sub>2<\/sub> gives I<sub>2<\/sub> = \u22121 A, and KCL then gives I<sub>3<\/sub> = 3 + (\u22121) = 2 A.<\/p>\n<p>Step 7: Read the minus sign. I<sub>2<\/sub> = \u22121 A means 1 A flows in the direction <em>opposite<\/em> to the arrow drawn \u2014 out of node A and back into battery 2. The 12 V battery is charging the 2 V one. Nothing was done wrong; the algebra simply corrected the guess.<\/p>\n<p>Step 8: Check. Loop 1: 2(3) + 3(2) = 12 \u2714. Loop 2: 4(\u22121) + 3(2) = \u22124 + 6 = 2 \u2714<\/p>\n<p><strong>Answer: I<sub>1<\/sub> = 3 A, I<sub>2<\/sub> = \u22121 A (1 A flowing the other way, charging battery 2), I<sub>3<\/sub> = 2 A.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">For the circuit in Problem 6, audit the power: show that the power delivered equals the power absorbed.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Use P = \u03b5I for each source, with the currents from Problem 6.<\/p>\n<p>Step 2: Battery 1 delivers P<sub>1<\/sub> = 12 \u00d7 3 = 36 W.<\/p>\n<p>Step 3: Battery 2 gives P<sub>2<\/sub> = 2 \u00d7 (\u22121) = \u22122 W. Negative power for a source means it is absorbing, not delivering \u2014 it is being charged at 2 W.<\/p>\n<p>Step 4: Use P = I\u00b2R for each resistor.<br>R<sub>1<\/sub>: (3)\u00b2 \u00d7 2 = 18 W<br>R<sub>2<\/sub>: (\u22121)\u00b2 \u00d7 4 = 4 W<br>R<sub>3<\/sub>: (2)\u00b2 \u00d7 3 = 12 W<br>Resistor total = 18 + 4 + 12 = 34 W<\/p>\n<p>Step 5: Balance the books. In: 36 W from battery 1. Out: 2 W into battery 2, plus 34 W as heat in the resistors \u2014 36 W total.<\/p>\n<p>Step 6: Note that R<sub>2<\/sub> dissipates 4 W whichever way its current flows, because the current is squared. A negative current still heats a resistor.<\/p>\n<p><strong>Answer: 36 W delivered = 2 W stored in battery 2 + 34 W dissipated as heat. Energy balances exactly, which is KVL in power form.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<h2>Frequently Asked Questions<\/h2>\n\n<details class=\"pf-faq-item\"><summary>What are Kirchhoff&#039;s two laws?<\/summary><div class=\"pf-faq-item-answer\">\nKirchhoff&#8217;s two laws are the current law and the voltage law. The current law (KCL) states that the currents entering any junction equal the currents leaving it, written \u03a3I = 0. The voltage law (KVL) states that the potential differences around any closed loop sum to zero, written \u03a3V = 0. They express conservation of charge and conservation of energy respectively.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Does it matter which direction I assume the current flows?<\/summary><div class=\"pf-faq-item-answer\">\nNo \u2014 you can assume any direction you like. If your guess is wrong, the algebra returns a negative value for that current, which means the magnitude is correct but the real flow is opposite to your arrow. This is the single most useful feature of the method. Just be consistent: once an arrow is drawn, use that same direction in every equation.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What is the difference between Kirchhoff&#039;s law and Ohm&#039;s law?<\/summary><div class=\"pf-faq-item-answer\">\nOhm&#8217;s law describes one component, relating the voltage across a resistor to the current through it via V = IR. Kirchhoff&#8217;s laws describe the whole network, constraining how currents combine at junctions and how voltages add around loops. Kirchhoff&#8217;s laws cannot be solved without substituting Ohm&#8217;s law at each resistor, so the two are used together rather than as alternatives.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>How many equations do I need to solve a circuit?<\/summary><div class=\"pf-faq-item-answer\">\nYou need as many independent equations as you have unknown currents. With n junctions, you get n \u2212 1 useful junction equations; the remaining ones repeat information you already have. Make up the shortfall with loop equations, one per independent loop. A typical two-loop circuit has three unknown currents and needs one junction equation plus two loop equations.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Do Kirchhoff&#039;s laws work for AC circuits?<\/summary><div class=\"pf-faq-item-answer\">\nYes, provided the circuit is small compared with the signal&#8217;s wavelength. For AC you work with instantaneous values, or with phasors and complex impedance instead of plain resistance, and both laws hold in the same form. They begin to fail only at high frequencies, where the circuit becomes comparable in size to the wavelength and stops behaving as lumped components.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Why does Kirchhoff&#039;s voltage law fail near a transformer?<\/summary><div class=\"pf-faq-item-answer\">\nKVL fails when magnetic flux through the loop is changing. The loop rule assumes the electric field is conservative, so that walking a closed path returns you to the same potential. Faraday&#8217;s law of induction says a changing magnetic flux drives an EMF around the loop itself, not through any component, so the voltages no longer sum to zero. Near a transformer, that flux is exactly what is changing.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Who discovered Kirchhoff&#039;s laws and when?<\/summary><div class=\"pf-faq-item-answer\">\nGustav Robert Kirchhoff announced both circuit laws in 1845, aged 21 and still a student at Albertus University of K\u00f6nigsberg. He developed them in the mathematics-physics seminar run by Franz Neumann and Carl Jacobi, extending Georg Ohm&#8217;s results from single components to networks with multiple loops. He graduated in 1847 and went on to major work in spectroscopy and black-body radiation.\n<\/div><\/details>\n","protected":false},"excerpt":{"rendered":"<p>Kirchhoff&#8217;s law is two rules, not one: the current arriving at a junction equals the current leaving it, and the voltages around any closed loop sum to zero. This guide explains both with original diagrams, a clear sign convention, and 7 fully worked examples.<\/p>\n","protected":false},"author":1,"featured_media":574,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"class_list":["post-572","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-electromagnetism"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/572","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=572"}],"version-history":[{"count":1,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/572\/revisions"}],"predecessor-version":[{"id":579,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/572\/revisions\/579"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/574"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=572"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=572"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=572"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}