{"id":408,"date":"2026-07-03T02:50:19","date_gmt":"2026-07-03T02:50:19","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=408"},"modified":"2026-07-13T23:30:05","modified_gmt":"2026-07-13T23:30:05","slug":"snells-law-explained","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/snells-law-explained\/","title":{"rendered":"Snell&#8217;s Law Explained"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\n\nSnell&#8217;s law states that when light passes from one transparent medium into another, n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> = n<sub>2<\/sub> sin \u03b8<sub>2<\/sub>: the refractive index of each medium multiplied by the sine of its ray&#8217;s angle from the normal is equal on both sides of the boundary. It predicts exactly how much a light ray bends when it crosses between materials.\n\n<\/p><\/div>\n\n<p>Push a straw into a glass of water and it appears to snap sideways at the surface. Kneel at the edge of a swimming pool and the bottom looks temptingly close \u2014 then you jump in and discover it is a good third deeper than it looked.<\/p>\n\n<p>Neither the straw nor the pool is broken. Light simply changes direction the instant it crosses between water and air, and Snell&#8217;s law is the rule that says exactly how far it swings. By the end of this guide you will be able to calculate that swing in seconds \u2014 and spot the traps that catch most students.<\/p>\n\n<h2>What Is Snell&#8217;s Law?<\/h2>\n\n<p>Strip away the Greek letters and Snell&#8217;s law says something surprisingly tidy: every transparent material gets a number, and that number decides how sharply light bends on the way in or out. The number is the <strong>refractive index<\/strong>, n \u2014 a measure of how much a material slows light down.<\/p>\n\n<p>Formally, Snell&#8217;s law (also called the <strong>law of refraction<\/strong>) states that for a ray crossing the boundary between two media, the product of refractive index and the sine of the ray&#8217;s angle \u2014 always measured from the <em>normal<\/em>, the line perpendicular to the surface \u2014 is the same on both sides. One boundary, one equation, one unknown: that is why examiners love it.<\/p>\n\n<p>The direction of the bend follows a simple pattern. Entering a slower, optically denser medium (air into water, say), the ray bends <strong>toward<\/strong> the normal; heading back out into a faster medium, it bends <strong>away<\/strong> from it.<\/p>\n\n<h3>Who Discovered Snell&#8217;s Law?<\/h3>\n\n<p>The name is an accident of history. The law was first accurately described in 984 CE by Ibn Sahl, a mathematician working in Baghdad, who used it in his treatise on burning mirrors and lenses to design lens shapes that focus light without geometric aberration.<\/p>\n\n<p>It was then rediscovered independently several times: by Thomas Harriot in 1602 (unpublished), by the Dutch astronomer Willebrord Snellius in 1621 (also unpublished in his lifetime), and by Ren\u00e9 Descartes, who finally published it in 1637 \u2014 which is why in France it is known as the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Snell%27s_law\" target=\"_blank\" rel=\"noopener\">Snell\u2013Descartes law<\/a>.<\/p>\n\n<h2>The Snell&#8217;s Law Formula<\/h2>\n\n<p>Here is the equation in its standard form:<\/p>\n\n<div class=\"pf-formula\">n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> = n<sub>2<\/sub> sin \u03b8<sub>2<\/sub><\/div>\n\n<ul>\n  <li><strong>n<sub>1<\/sub><\/strong> \u2014 refractive index of the first medium, the one the ray starts in (dimensionless)<\/li>\n  <li><strong>\u03b8<sub>1<\/sub><\/strong> \u2014 angle of incidence, measured from the normal, not the surface (degrees or radians)<\/li>\n  <li><strong>n<sub>2<\/sub><\/strong> \u2014 refractive index of the second medium, the one the ray enters (dimensionless)<\/li>\n  <li><strong>\u03b8<sub>2<\/sub><\/strong> \u2014 angle of refraction, again measured from the normal (degrees or radians)<\/li>\n<\/ul>\n\n<p>The refractive index itself comes from a second, equally important relation:<\/p>\n\n<div class=\"pf-formula\">n = c \/ v<\/div>\n\n<p>Here c is <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/modern-physics\/speed-of-light\/\">the speed of light<\/a> in a vacuum (exactly 299,792,458 m\/s) and v is the speed of light inside the material. Water has n = 1.33 because light travels 1.33 times slower in water than in a vacuum. An index can never make light bend past the surface itself, so a quick sanity check on any answer: a real refracted angle always lands between 0\u00b0 and 90\u00b0.<\/p>\n\n<svg viewBox=\"0 0 640 400\" role=\"img\" aria-label=\"Ray diagram of Snell's law showing a light ray refracting from air into water and bending toward the normal\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"max-width:640px;width:100%;height:auto;display:block;margin:24px auto;\">\n  <defs>\n    <marker id=\"pfArrGoldA\" markerWidth=\"9\" markerHeight=\"9\" refX=\"7\" refY=\"4\" orient=\"auto\">\n      <path d=\"M0,0 L8,4 L0,8 z\" fill=\"#C8932A\"\/>\n    <\/marker>\n  <\/defs>\n  <rect x=\"0\" y=\"0\" width=\"640\" height=\"200\" fill=\"#FAF6EE\"\/>\n  <rect x=\"0\" y=\"200\" width=\"640\" height=\"200\" fill=\"#C5D0DC\"\/>\n  <rect x=\"0.5\" y=\"0.5\" width=\"639\" height=\"399\" fill=\"none\" stroke=\"#D9CFB8\" stroke-width=\"1\"\/>\n  <line x1=\"0\" y1=\"200\" x2=\"640\" y2=\"200\" stroke=\"#0A1628\" stroke-width=\"2\"\/>\n  <line x1=\"320\" y1=\"40\" x2=\"320\" y2=\"360\" stroke=\"#0A1628\" stroke-width=\"1.5\" stroke-dasharray=\"6 6\" opacity=\"0.65\"\/>\n  <text x=\"330\" y=\"56\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" fill=\"#0A1628\" opacity=\"0.75\">normal<\/text>\n  <line x1=\"193\" y1=\"73\" x2=\"320\" y2=\"200\" stroke=\"#C8932A\" stroke-width=\"3.5\" marker-end=\"url(#pfArrGoldA)\"\/>\n  <text x=\"88\" y=\"64\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"600\" fill=\"#0A1628\">incident ray<\/text>\n  <line x1=\"320\" y1=\"200\" x2=\"447\" y2=\"73\" stroke=\"#C8932A\" stroke-width=\"2\" opacity=\"0.45\" marker-end=\"url(#pfArrGoldA)\"\/>\n  <text x=\"452\" y=\"64\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" fill=\"#0A1628\" opacity=\"0.6\">partial reflection<\/text>\n  <line x1=\"320\" y1=\"200\" x2=\"405\" y2=\"336\" stroke=\"#C8932A\" stroke-width=\"3.5\" marker-end=\"url(#pfArrGoldA)\"\/>\n  <text x=\"416\" y=\"336\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"600\" fill=\"#0A1628\">refracted ray<\/text>\n  <path d=\"M 320 152 A 48 48 0 0 0 286 166\" fill=\"none\" stroke=\"#7A1F2B\" stroke-width=\"2\"\/>\n  <text x=\"238\" y=\"140\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"600\" fill=\"#7A1F2B\">\u03b8<tspan baseline-shift=\"sub\" font-size=\"70%\">1<\/tspan> = 45\u00b0<\/text>\n  <path d=\"M 320 248 A 48 48 0 0 0 346 241\" fill=\"none\" stroke=\"#7A1F2B\" stroke-width=\"2\"\/>\n  <text x=\"348\" y=\"268\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"600\" fill=\"#7A1F2B\">\u03b8<tspan baseline-shift=\"sub\" font-size=\"70%\">2<\/tspan> \u2248 32.1\u00b0<\/text>\n  <circle cx=\"320\" cy=\"200\" r=\"4\" fill=\"#0A1628\"\/>\n  <text x=\"24\" y=\"40\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"700\" fill=\"#0A1628\">AIR  n<tspan baseline-shift=\"sub\" font-size=\"70%\">1<\/tspan> = 1.00<\/text>\n  <text x=\"24\" y=\"382\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"700\" fill=\"#142139\">WATER  n<tspan baseline-shift=\"sub\" font-size=\"70%\">2<\/tspan> = 1.33<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;\">A ray crossing from air into water at 45\u00b0 bends to about 32.1\u00b0 \u2014 toward the normal, exactly as n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> = n<sub>2<\/sub> sin \u03b8<sub>2<\/sub> predicts.<\/p>\n\n<h3>Refractive Indices of Common Materials<\/h3>\n\n<p>The table below gives typical values for yellow light (589 nm). The index drifts slightly with colour \u2014 that drift is called dispersion, and it is the reason prisms split white light.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr>\n  <th style=\"border:1px solid #D9CFB8;padding:8px;text-align:left;\">Material<\/th>\n  <th style=\"border:1px solid #D9CFB8;padding:8px;text-align:left;\">Refractive index n<\/th>\n  <th style=\"border:1px solid #D9CFB8;padding:8px;text-align:left;\">Speed of light inside<\/th>\n  <th style=\"border:1px solid #D9CFB8;padding:8px;text-align:left;\">Critical angle (to air)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Vacuum<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">1 (exactly)<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">299,792 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2014<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Air<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">1.0003<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 299,700 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2014<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Ice<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">1.31<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 229,000 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">49.8\u00b0<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Water<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">1.33<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 225,000 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">48.8\u00b0<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Ethanol<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">1.36<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 220,000 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">47.3\u00b0<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Acrylic (Perspex)<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">1.49<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 201,000 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">42.2\u00b0<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Crown glass<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 1.52<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 197,000 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">41.1\u00b0<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Flint glass<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 1.62<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 185,000 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">38.1\u00b0<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Sapphire<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">1.77<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 169,000 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">34.4\u00b0<\/td>\n<\/tr>\n<tr>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">Diamond<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">2.42<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">\u2248 124,000 km\/s<\/td>\n  <td style=\"border:1px solid #D9CFB8;padding:8px;\">24.4\u00b0<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>Glass values vary by recipe, which is why crown and flint are quoted as typical figures. Measured indices for hundreds of materials are collated in university references such as the <a href=\"http:\/\/hyperphysics.phy-astr.gsu.edu\/hbase\/geoopt\/refr.html\" target=\"_blank\" rel=\"noopener\">refraction pages at HyperPhysics<\/a> (Georgia State University).<\/p>\n\n<h2>How Snell&#8217;s Law Works<\/h2>\n\n<p>A ray does not bend because the surface deflects it, the way a ball ricochets off a wall. It bends because its <em>speed<\/em> changes \u2014 and if the ray arrives at an angle, one side of the light wave slows down before the other.<\/p>\n\n<p>Picture a marching band striding off firm tarmac into soft mud at an angle. The marchers who hit the mud first slow down while their row-mates on tarmac keep full stride, so the whole column pivots toward the mud-side. Light wavefronts do precisely this at a boundary, and the geometry of that pivot is Snell&#8217;s law.<\/p>\n\n<p>Work through the wavefront geometry and a clean ratio drops out: sin \u03b8<sub>1<\/sub> \/ sin \u03b8<sub>2<\/sub> = v<sub>1<\/sub> \/ v<sub>2<\/sub> = n<sub>2<\/sub> \/ n<sub>1<\/sub>. Rearranged, that is n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> = n<sub>2<\/sub> sin \u03b8<sub>2<\/sub> \u2014 the speed picture and the formula are the same statement.<\/p>\n\n<p>There is a deeper way to see it, too. Fermat showed that light takes the path of least time between two points, like a lifeguard who runs along the beach before angling into the slower water; do the calculus and Snell&#8217;s law falls straight out. Feynman devotes a whole lecture to the idea \u2014 <a href=\"https:\/\/www.feynmanlectures.caltech.edu\/I_26.html\" target=\"_blank\" rel=\"noopener\">Optics: The Principle of Least Time<\/a> \u2014 and it remains one of the great reads in physics.<\/p>\n\n<p>Better than reading about it, though, is bending the ray yourself. Drag the angle in the lab below and watch the refracted and reflected rays respond in real time.<\/p>\n\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Reflection &amp; Refraction Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:560px}@media(max-width:760px){.pf-sim-frame{height:840px}}<\/style><iframe src=\"\/labs\/reflection-refraction.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n\n<h2>How to Use Snell&#8217;s Law: A 5-Step Method<\/h2>\n\n<p>Most lost marks on refraction questions come from setup, not algebra. This routine removes the guesswork:<\/p>\n\n<ol>\n  <li><strong>Sketch the boundary and draw the normal.<\/strong> Label medium 1 (where the ray starts) and medium 2 (where it is heading) \u2014 getting these backwards flips the whole answer.<\/li>\n  <li><strong>Write down n<sub>1<\/sub>, n<sub>2<\/sub> and the known angle.<\/strong> Angles are measured from the normal, never from the surface. If a question gives the angle to the surface, subtract it from 90\u00b0 first.<\/li>\n  <li><strong>Rearrange and substitute:<\/strong> sin \u03b8<sub>2<\/sub> = (n<sub>1<\/sub> \/ n<sub>2<\/sub>) sin \u03b8<sub>1<\/sub>.<\/li>\n  <li><strong>Pause before pressing inverse sine.<\/strong> If (n<sub>1<\/sub> \/ n<sub>2<\/sub>) sin \u03b8<sub>1<\/sub> comes out greater than 1, stop \u2014 no refracted ray exists and you have found total internal reflection (more below).<\/li>\n  <li><strong>Take arcsin and sanity-check the direction.<\/strong> Into a slower medium the ray should bend toward the normal; into a faster one, away from it. If your answer breaks that rule, revisit step 1.<\/li>\n<\/ol>\n\n<p>A common student slip: leaving the calculator in radian mode, which turns a tidy 22\u00b0 answer into nonsense. Check the mode before the exam starts, not during. You can also verify any answer instantly with our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/snells-law\">Snell&#8217;s Law Calculator<\/a>, which handles refraction angles, indices and the critical angle in one place.<\/p>\n\n<h2>Critical Angle and Total Internal Reflection<\/h2>\n\n<p>Send light from a slow medium toward a fast one \u2014 water toward air \u2014 and something dramatic happens as you steepen the angle. The refracted ray bends further and further from the normal until, at one particular incidence angle, it skims along the surface at exactly 90\u00b0. That incidence angle is the <strong>critical angle<\/strong>, \u03b8<sub>c<\/sub>.<\/p>\n\n<div class=\"pf-formula\">sin \u03b8c = n<sub>2<\/sub> \/ n<sub>1<\/sub><\/div>\n\n<p>The formula only makes sense when n<sub>1<\/sub> is greater than n<sub>2<\/sub> \u2014 the sine of an angle cannot exceed 1. For water to air, sin \u03b8<sub>c<\/sub> = 1.00 \/ 1.33 = 0.752, giving \u03b8<sub>c<\/sub> \u2248 48.8\u00b0. For crown glass it is about 41\u00b0, and for diamond a remarkably small 24.4\u00b0.<\/p>\n\n<p>Beyond the critical angle, refraction switches off entirely and the boundary behaves like a perfect mirror: <strong>total internal reflection<\/strong> (TIR). Not 95% reflection \u2014 total. No everyday mirror, with its metal coating, reflects as cleanly as a humble glass\u2013air boundary past \u03b8<sub>c<\/sub>.<\/p>\n\n<svg viewBox=\"0 0 640 360\" role=\"img\" aria-label=\"Three light rays travelling from water toward air: below the critical angle the ray escapes, at the critical angle it grazes the surface, and beyond it total internal reflection occurs\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"max-width:640px;width:100%;height:auto;display:block;margin:24px auto;\">\n  <defs>\n    <marker id=\"pfArrGoldB\" markerWidth=\"9\" markerHeight=\"9\" refX=\"7\" refY=\"4\" orient=\"auto\">\n      <path d=\"M0,0 L8,4 L0,8 z\" fill=\"#C8932A\"\/>\n    <\/marker>\n    <marker id=\"pfArrWineB\" markerWidth=\"9\" markerHeight=\"9\" refX=\"7\" refY=\"4\" orient=\"auto\">\n      <path d=\"M0,0 L8,4 L0,8 z\" fill=\"#7A1F2B\"\/>\n    <\/marker>\n  <\/defs>\n  <rect x=\"0\" y=\"0\" width=\"640\" height=\"150\" fill=\"#FAF6EE\"\/>\n  <rect x=\"0\" y=\"150\" width=\"640\" height=\"210\" fill=\"#C5D0DC\"\/>\n  <rect x=\"0.5\" y=\"0.5\" width=\"639\" height=\"359\" fill=\"none\" stroke=\"#D9CFB8\" stroke-width=\"1\"\/>\n  <line x1=\"0\" y1=\"150\" x2=\"640\" y2=\"150\" stroke=\"#0A1628\" stroke-width=\"2\"\/>\n  <line x1=\"238\" y1=\"112\" x2=\"238\" y2=\"192\" stroke=\"#0A1628\" stroke-width=\"1\" stroke-dasharray=\"5 5\" opacity=\"0.5\"\/>\n  <line x1=\"505\" y1=\"112\" x2=\"505\" y2=\"230\" stroke=\"#0A1628\" stroke-width=\"1\" stroke-dasharray=\"5 5\" opacity=\"0.5\"\/>\n  <line x1=\"140\" y1=\"320\" x2=\"238\" y2=\"150\" stroke=\"#C8932A\" stroke-width=\"2.5\"\/>\n  <line x1=\"238\" y1=\"150\" x2=\"311\" y2=\"68\" stroke=\"#C8932A\" stroke-width=\"2.5\" marker-end=\"url(#pfArrGoldB)\"\/>\n  <text x=\"252\" y=\"52\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" font-weight=\"600\" fill=\"#0A1628\">escapes (\u03b8 below \u03b8c)<\/text>\n  <line x1=\"140\" y1=\"320\" x2=\"334\" y2=\"150\" stroke=\"#C8932A\" stroke-width=\"2.5\"\/>\n  <line x1=\"334\" y1=\"147\" x2=\"452\" y2=\"147\" stroke=\"#C8932A\" stroke-width=\"2.5\" marker-end=\"url(#pfArrGoldB)\"\/>\n  <text x=\"392\" y=\"132\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" font-weight=\"600\" fill=\"#0A1628\">grazes at 90\u00b0 (\u03b8 = \u03b8c \u2248 48.8\u00b0)<\/text>\n  <line x1=\"140\" y1=\"320\" x2=\"505\" y2=\"150\" stroke=\"#C8932A\" stroke-width=\"2.5\"\/>\n  <line x1=\"505\" y1=\"150\" x2=\"605\" y2=\"196\" stroke=\"#7A1F2B\" stroke-width=\"3\" marker-end=\"url(#pfArrWineB)\"\/>\n  <text x=\"408\" y=\"236\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" font-weight=\"700\" fill=\"#7A1F2B\">total internal reflection (\u03b8 above \u03b8c)<\/text>\n  <circle cx=\"140\" cy=\"320\" r=\"5\" fill=\"#7A1F2B\"\/>\n  <text x=\"52\" y=\"344\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"12.5\" fill=\"#142139\">light source under water<\/text>\n  <text x=\"20\" y=\"30\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"700\" fill=\"#0A1628\">AIR  n = 1.00<\/text>\n  <text x=\"20\" y=\"182\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"700\" fill=\"#142139\">WATER  n = 1.33<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;font-style:italic;color:#1F2E47;\">One underwater source, three fates: escape below the critical angle, a 90\u00b0 graze at it, and total internal reflection beyond it.<\/p>\n\n<p>TIR is not a curiosity \u2014 it is infrastructure. Optical fibres trap laser pulses by making every internal bounce steeper than the critical angle, so the light ricochets down the glass core for kilometres with barely any loss. Every video call you make rides on Snell&#8217;s law failing on purpose.<\/p>\n\n<h2>Real-World Examples of Snell&#8217;s Law<\/h2>\n\n<p><strong>Pools, straws and archerfish.<\/strong> Refraction makes water look about three-quarters of its true depth and shifts the apparent position of everything beneath the surface. Archerfish, which spit jets of water to knock insects off branches, instinctively correct for the bend \u2014 a spear fisher must learn the same trick: aim below where the fish appears.<\/p>\n\n<figure style=\"margin:32px auto;max-width:640px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/07\/Pencil_in_glass_of_water_showing_refraction.jpg\"\n       alt=\"Snell's law in everyday life: a pencil appears bent where light refracts at the water surface\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">The pencil is straight; the light is not.<\/figcaption>\n<\/figure>\n\n<p><strong>Glasses, cameras and your own eyes.<\/strong> A lens is nothing more than Snell&#8217;s law applied millions of times across a curved surface, engineered so every ray converges at one focus. Your cornea does most of your eye&#8217;s bending; spectacles simply add or subtract a little refraction to land the focus on the retina.<\/p>\n\n<p><strong>Fibre-optic internet.<\/strong> As above \u2014 hair-thin glass strands use total internal reflection to pipe data as light across oceans. Endoscopes use the same trick to carry an image around corners inside the human body.<\/p>\n\n<p><strong>Diamond sparkle.<\/strong> With n = 2.42, diamond&#8217;s critical angle is only 24.4\u00b0, so light entering a well-cut stone gets trapped, bounces between facets, and finally erupts out of the top toward your eye. Cutters angle facets specifically to exploit that tiny \u03b8<sub>c<\/sub> \u2014 brilliance is applied Snell&#8217;s law.<\/p>\n\n<p><strong>Mirages.<\/strong> Hot air just above summer tarmac is less optically dense than the cooler air higher up, so n changes gradually with height and light from the sky curves upward into your eye. The shimmering &#8220;water&#8221; on the road is a refracted patch of sky.<\/p>\n\n<h2>4 Common Misconceptions About Snell&#8217;s Law<\/h2>\n\n<h3>1. &#8220;Light always bends toward the normal&#8221;<\/h3>\n\n<p>Only when it enters a slower medium. Travelling from glass or water back into air, the ray bends <em>away<\/em> from the normal \u2014 that is precisely why a critical angle exists in that direction. Always check which side of the boundary is optically denser before predicting the bend.<\/p>\n\n<h3>2. &#8220;Refraction changes the light&#8217;s frequency&#8221;<\/h3>\n\n<p>It never does. Frequency is set by the source and stays fixed across the boundary; it is the speed and the wavelength that change together, keeping v = f\u03bb balanced. Blue light entering water is still blue \u2014 its waves are simply packed closer while they travel slower.<\/p>\n\n<h3>3. &#8220;Optical density is just ordinary density&#8221;<\/h3>\n\n<p>Tempting, but wrong. Ethanol is physically less dense than water (it floats on it), yet its refractive index, 1.36, is higher than water&#8217;s 1.33. Optical density is about how a material&#8217;s electrons interact with light, not how much mass is packed into it.<\/p>\n\n<h3>4. &#8220;Total internal reflection can happen in either direction&#8221;<\/h3>\n\n<p>TIR only occurs going from a higher index to a lower one \u2014 water to air, glass to air. Light entering a denser medium always gets in, no matter how glancing the angle. That is why you can always see down into a pool, while a fish looking up sees the world squeezed into a bright circle.<\/p>\n\n<h2>How Snell&#8217;s Law Connects to Other Physics<\/h2>\n\n<p>Because n = c \/ v, refraction is really a chapter in the story of light&#8217;s speed \u2014 Snell&#8217;s law is what that speed change looks like from the outside. Historically it ran the other way: indices were measured from bending angles long before anyone could clock light in water directly.<\/p>\n\n<p>What survives the crossing untouched is frequency. Since wave speed, frequency and wavelength are locked together by <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/waves\/frequency-formula\/\">the frequency formula<\/a> (v = f\u03bb), a fixed f means the wavelength shrinks in exact proportion to the slowdown: \u03bb<sub>2<\/sub> = \u03bb<sub>1<\/sub> \u00d7 (n<sub>1<\/sub> \/ n<sub>2<\/sub>).<\/p>\n\n<p>It also matters that light is a transverse electromagnetic wave \u2014 if wave types are new to you, start with our guide to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/waves\/transverse-vs-longitudinal-waves\/\">transverse and longitudinal waves<\/a>. Being transverse is what lets reflected light become polarised, which is how polarising sunglasses kill glare off water.<\/p>\n\n<p>Two more threads lead onward. Every refraction is accompanied by a weak partial reflection (glance back at the first diagram) \u2014 the reason windows turn mirror-like at night. And because n drifts slightly with colour, a prism fans white light into a spectrum: dispersion, the physics behind every rainbow.<\/p>\n\n<h2>Worked Problems<\/h2>\n\n<p>Grab a calculator \u2014 in degree mode \u2014 and work through these in order. Each one adds a wrinkle the previous one lacked.<\/p>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">A ray of light travels from air (n = 1.00) into water (n = 1.33) with an angle of incidence of 30.0\u00b0. Find the angle of refraction.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Apply Snell&#8217;s law, n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> = n<sub>2<\/sub> sin \u03b8<sub>2<\/sub>, with n<sub>1<\/sub> = 1.00, \u03b8<sub>1<\/sub> = 30.0\u00b0, n<sub>2<\/sub> = 1.33.\n\nStep 2: sin \u03b8<sub>2<\/sub> = (n<sub>1<\/sub> \/ n<sub>2<\/sub>) sin \u03b8<sub>1<\/sub> = (1.00 \/ 1.33) \u00d7 sin 30.0\u00b0 = 0.500 \/ 1.33 = 0.376.\n\nStep 3: \u03b8<sub>2<\/sub> = arcsin(0.376) = 22.1\u00b0. The ray bends toward the normal, as expected entering a denser medium.\n\n<strong>Answer: \u03b8<sub>2<\/sub> \u2248 22.1\u00b0<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">Light strikes a crown glass block (n = 1.52) from air at 45.0\u00b0 to the normal. What is the angle of refraction inside the glass?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> = n<sub>2<\/sub> sin \u03b8<sub>2<\/sub> with n<sub>1<\/sub> = 1.00, \u03b8<sub>1<\/sub> = 45.0\u00b0, n<sub>2<\/sub> = 1.52.\n\nStep 2: sin \u03b8<sub>2<\/sub> = (1.00 \u00d7 sin 45.0\u00b0) \/ 1.52 = 0.7071 \/ 1.52 = 0.465.\n\nStep 3: \u03b8<sub>2<\/sub> = arcsin(0.465) = 27.7\u00b0.\n\n<strong>Answer: \u03b8<sub>2<\/sub> \u2248 27.7\u00b0<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A laser passes from air into an unknown liquid. The angle of incidence is 50.0\u00b0 and the angle of refraction is 32.0\u00b0. Find the refractive index of the liquid.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Rearrange Snell&#8217;s law for the unknown index: n<sub>2<\/sub> = n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> \/ sin \u03b8<sub>2<\/sub>.\n\nStep 2: n<sub>2<\/sub> = (1.00 \u00d7 sin 50.0\u00b0) \/ sin 32.0\u00b0 = 0.766 \/ 0.530.\n\nStep 3: n<sub>2<\/sub> = 1.45 \u2014 consistent with a typical oil. This reverse use of Snell&#8217;s law is exactly how indices are measured in the lab.\n\n<strong>Answer: n<sub>2<\/sub> \u2248 1.45<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">A ray inside a glass block (n = 1.50) reaches the glass\u2013air boundary at 28.0\u00b0 to the normal. At what angle does it leave the glass?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Now the glass is medium 1: n<sub>1<\/sub> = 1.50, \u03b8<sub>1<\/sub> = 28.0\u00b0, n<sub>2<\/sub> = 1.00.\n\nStep 2: sin \u03b8<sub>2<\/sub> = (1.50 \u00d7 sin 28.0\u00b0) \/ 1.00 = 1.50 \u00d7 0.469 = 0.704. This is below 1, so the ray does escape.\n\nStep 3: \u03b8<sub>2<\/sub> = arcsin(0.704) = 44.8\u00b0. Leaving a denser medium, the ray bends away from the normal \u2014 44.8\u00b0 is larger than 28.0\u00b0, as it must be.\n\n<strong>Answer: \u03b8<sub>2<\/sub> \u2248 44.8\u00b0<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">Calculate the critical angle for light travelling from water (n = 1.33) toward air (n = 1.00).<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: At the critical angle the refracted ray grazes the surface, so \u03b8<sub>2<\/sub> = 90\u00b0 and sin \u03b8<sub>2<\/sub> = 1.\n\nStep 2: sin \u03b8<sub>c<\/sub> = n<sub>2<\/sub> \/ n<sub>1<\/sub> = 1.00 \/ 1.33 = 0.752.\n\nStep 3: \u03b8<sub>c<\/sub> = arcsin(0.752) = 48.8\u00b0.\n\n<strong>Answer: \u03b8<sub>c<\/sub> \u2248 48.8\u00b0<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">Inside a diamond (n = 2.42), a ray strikes a facet at 35.0\u00b0 to the normal, heading toward the air outside. Does the ray escape?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: First find the critical angle: sin \u03b8<sub>c<\/sub> = 1.00 \/ 2.42 = 0.413, so \u03b8<sub>c<\/sub> = 24.4\u00b0.\n\nStep 2: Compare: the incidence angle, 35.0\u00b0, is greater than \u03b8<sub>c<\/sub> = 24.4\u00b0.\n\nStep 3: The ray therefore undergoes total internal reflection and stays inside the stone \u2014 one of the bounces that makes a cut diamond blaze.\n\n<strong>Answer: No \u2014 35.0\u00b0 exceeds the 24.4\u00b0 critical angle, so the ray is totally internally reflected.<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">Using n = c \/ v with c = 3.00 \u00d7 10&lt;sup&gt;8&lt;\/sup&gt; m\/s, calculate the speed of light inside diamond (n = 2.42).<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: Rearrange n = c \/ v to give v = c \/ n.\n\nStep 2: v = (3.00 \u00d7 10<sup>8<\/sup> m\/s) \/ 2.42.\n\nStep 3: v = 1.24 \u00d7 10<sup>8<\/sup> m\/s \u2014 light in diamond crawls at well under half its vacuum speed, which is why the bending is so severe.\n\n<strong>Answer: v \u2248 1.24 \u00d7 10<sup>8<\/sup> m\/s<\/strong>\n\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 8<\/div><div class=\"pf-problem-question\">Light in air hits a flat water layer (n = 1.33) at 40.0\u00b0, passes through it, then enters a crown glass slab (n = 1.52) whose surface is parallel to the water&#039;s. Find the angle of the ray inside the glass.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\n\nStep 1: At the first boundary: sin \u03b8<sub>2<\/sub> = (1.00 \u00d7 sin 40.0\u00b0) \/ 1.33 = 0.643 \/ 1.33 = 0.483, so \u03b8<sub>2<\/sub> = 28.9\u00b0 in the water.\n\nStep 2: At the second boundary: n<sub>2<\/sub> sin \u03b8<sub>2<\/sub> = n<sub>3<\/sub> sin \u03b8<sub>3<\/sub>, i.e. 1.33 \u00d7 0.483 = 1.52 \u00d7 sin \u03b8<sub>3<\/sub>, giving sin \u03b8<sub>3<\/sub> = 0.643 \/ 1.52 = 0.423.\n\nStep 3: \u03b8<sub>3<\/sub> = arcsin(0.423) = 25.0\u00b0. Notice that 1.33 cancels out: for parallel layers, n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> = n<sub>3<\/sub> sin \u03b8<sub>3<\/sub> directly \u2014 the middle medium only shifts the ray sideways.\n\n<strong>Answer: \u03b8<sub>3<\/sub> \u2248 25.0\u00b0 (and in general the intermediate layer drops out of the calculation)<\/strong>\n\n<\/div><\/details><\/div>\n\n<h2>Frequently Asked Questions<\/h2>\n\n<details class=\"pf-faq-item\"><summary>What is Snell&#039;s law in simple terms?<\/summary><div class=\"pf-faq-item-answer\">\n\nSnell&#8217;s law is the rule for how much light bends when it crosses between two transparent materials: n<sub>1<\/sub> sin \u03b8<sub>1<\/sub> = n<sub>2<\/sub> sin \u03b8<sub>2<\/sub>. Each material&#8217;s refractive index n measures how much it slows light, and the law says the product of index and the sine of the ray&#8217;s angle from the normal must match on both sides of the boundary.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>How do you calculate the angle of refraction?<\/summary><div class=\"pf-faq-item-answer\">\n\nRearrange Snell&#8217;s law to sin \u03b8<sub>2<\/sub> = (n<sub>1<\/sub> \/ n<sub>2<\/sub>) sin \u03b8<sub>1<\/sub>, substitute the two refractive indices and the angle of incidence, then take the inverse sine. Make sure both angles are measured from the normal and your calculator is in degree mode. If (n<sub>1<\/sub> \/ n<sub>2<\/sub>) sin \u03b8<sub>1<\/sub> exceeds 1, no refracted ray exists \u2014 the light is totally internally reflected instead.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Does light change frequency or wavelength when it refracts?<\/summary><div class=\"pf-faq-item-answer\">\n\nWavelength changes; frequency does not. Frequency is fixed by the light source, so when light slows in a denser medium its wavelength shortens in the same ratio, keeping v = f\u03bb satisfied. That is also why the colour of light does not change underwater \u2014 colour perception is tied to frequency, which the boundary leaves alone.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What happens if light hits the boundary head-on, at 0\u00b0?<\/summary><div class=\"pf-faq-item-answer\">\n\nIt passes straight through without bending. With \u03b8<sub>1<\/sub> = 0, Snell&#8217;s law gives sin \u03b8<sub>2<\/sub> = 0, so \u03b8<sub>2<\/sub> = 0 as well. The light still slows down and its wavelength still shortens inside the denser medium \u2014 there is simply no sideways asymmetry to pivot the wavefront, so the direction is unchanged.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Does Snell&#039;s law apply to sound and other waves?<\/summary><div class=\"pf-faq-item-answer\">\n\nYes. Snell&#8217;s law follows from any wave changing speed at a boundary, so it governs sound, water waves and even seismic waves. For sound the ratio of sines equals the ratio of wave speeds in the two media. Refraction of sound in layers of warm and cold seawater, for example, is a central problem in sonar design.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Do the angles in Snell&#039;s law have to be in degrees?<\/summary><div class=\"pf-faq-item-answer\">\n\nDegrees or radians both work \u2014 the law only involves the sine of each angle, and sin \u03b8 is the same number either way. What matters is consistency with your calculator&#8217;s mode, and that every angle is measured from the normal rather than from the surface. Mixing those two conventions is one of the most common ways to lose marks.\n\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Does the colour of light affect Snell&#039;s law?<\/summary><div class=\"pf-faq-item-answer\">\n\nSlightly, yes. A material&#8217;s refractive index rises a little at shorter wavelengths, so violet light bends marginally more than red \u2014 an effect called dispersion. The law itself holds for every colour; only the value of n shifts. Dispersion is what lets a prism fan white light into a spectrum and what paints rainbows in the sky.\n\n<\/div><\/details>\n","protected":false},"excerpt":{"rendered":"<p>Snell&#8217;s law, n\u2081 sin \u03b8\u2081 = n\u2082 sin \u03b8\u2082, predicts exactly how much light bends when it crosses from one material into another. Learn the formula, the critical angle and total internal reflection through worked examples.<\/p>\n","protected":false},"author":1,"featured_media":411,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2],"tags":[228,239,152,153,238,154],"class_list":["post-408","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mechanics","tag-critical-angle","tag-optics","tag-refraction","tag-refractive-index","tag-snells-law-2","tag-total-internal-reflection"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/408","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=408"}],"version-history":[{"count":2,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/408\/revisions"}],"predecessor-version":[{"id":548,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/408\/revisions\/548"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/411"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=408"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=408"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=408"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}