{"id":386,"date":"2026-07-01T00:49:03","date_gmt":"2026-07-01T00:49:03","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=386"},"modified":"2026-07-01T00:49:05","modified_gmt":"2026-07-01T00:49:05","slug":"half-life-physics","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/modern-physics\/half-life-physics\/","title":{"rendered":"What Is Half-Life in Physics?"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\nHalf-life in physics is the time required for half the radioactive atoms in a sample to decay. It is written t\u00bd and linked to the amount remaining by N = N\u2080(\u00bd)^(t\/t\u00bd). Half-life is fixed for each isotope, ranging from microseconds to billions of years, and is essentially unaffected by temperature, pressure, or chemistry.\n<\/p><\/div>\n\n<p>Somewhere in your home, a smoke detector is quietly trusting a speck of americium that loses half its radioactivity roughly every 432 years. A hospital across town just injected a patient with a tracer that will be half gone before lunch. One single idea governs both.<\/p>\n\n<p>That idea is half-life \u2014 nature&#8217;s most reliable stopwatch. It tells us how to date a 5,000-year-old axe, why some nuclear waste stays dangerous for millennia, and how a medical scan lights up a tumour. Master it once and a huge slice of nuclear physics suddenly clicks into place.<\/p>\n\n<h2>What Is Half-Life in Physics?<\/h2>\n\n<p>Picture an enormous crowd of identical, unstable atoms. Each one will eventually break apart \u2014 &#8220;decay&#8221; \u2014 but never on a schedule you can set. There is no fuse and no countdown; each atom simply carries a fixed probability of decaying in the next second.<\/p>\n\n<p>Half-life is the time it takes for half of that crowd to decay. Start with a trillion atoms and one half-life later about 500 billion remain. Wait another half-life and roughly 250 billion are left \u2014 always half of whatever you had, never a fixed number subtracted each time.<\/p>\n\n<p>More precisely, the half-life (symbol t\u00bd) of a radioactive isotope is the time for the number of undecayed nuclei, or the sample&#8217;s activity, to fall to one half of its starting value. Decay is random for any single atom yet astonishingly predictable for trillions, so half-life behaves as a rock-solid statistical average.<\/p>\n\n<p>The key word is <em>constant<\/em>. A given isotope&#8217;s half-life never shifts: carbon-14 takes 5,730 years to halve whether the sample is hot, cold, crushed, or chemically locked into a molecule. That dependability is precisely what turns half-life into a usable clock. Georgia State University&#8217;s <a href=\"http:\/\/hyperphysics.phy-astr.gsu.edu\/hbase\/Nuclear\/halfli.html\" target=\"_blank\" rel=\"noopener\">HyperPhysics<\/a> defines it the same way \u2014 the time for half the radioactive nuclei in any sample to decay.<\/p>\n\n<h2>The Half-Life Formula<\/h2>\n\n<p>The core equation links how much is left to how many half-lives have gone by.<\/p>\n\n<div class=\"pf-formula\">N = N\u2080 \u00d7 (\u00bd)^(t \/ t\u00bd)<\/div>\n\n<p>Every term has a clear meaning and unit:<\/p>\n\n<ul>\n<li><strong>N<\/strong> \u2014 amount (or number of nuclei) remaining after time t; unit: same as N\u2080 (atoms, moles, grams, or becquerels, Bq)<\/li>\n<li><strong>N\u2080<\/strong> \u2014 the initial amount, present at t = 0; unit: atoms, mol, g, or Bq<\/li>\n<li><strong>t<\/strong> \u2014 the elapsed time; unit: seconds (s), but any time unit works if t\u00bd uses the same one<\/li>\n<li><strong>t\u00bd<\/strong> \u2014 the half-life of the isotope; unit: seconds (s)<\/li>\n<li><strong>\u00bd<\/strong> \u2014 the halving factor (dimensionless)<\/li>\n<\/ul>\n\n<p>Read the formula as a count of halvings. The exponent t\/t\u00bd is simply the number of half-lives that have passed; raise \u00bd to that power and you have the fraction left. After 3 half-lives, (\u00bd)\u00b3 = \u215b remains \u2014 no calculator required.<\/p>\n\n<p>The same physics can be written with the decay constant \u03bb, which is often more convenient for activity and dating problems.<\/p>\n\n<div class=\"pf-formula\">N = N\u2080 \u00d7 e^(\u2212\u03bbt),   where   \u03bb = ln 2 \/ t\u00bd \u2248 0.693 \/ t\u00bd<\/div>\n\n<p>Here \u03bb is the probability that any one nucleus decays per second (unit: s\u207b\u00b9), e \u2248 2.718 is Euler&#8217;s number, and ln 2 \u2248 0.693. A large \u03bb means impatient atoms and a short half-life; a tiny \u03bb means a near-eternal isotope. The two forms are identical \u2014 one counts in half-lives, the other in e-foldings.<\/p>\n\n<p>To turn the equation into a dating tool, rearrange it for time:<\/p>\n\n<div class=\"pf-formula\">t = t\u00bd \u00d7 ln(N\u2080 \/ N) \/ ln 2<\/div>\n\n<p>Measure how much is left as a fraction (N\/N\u2080), and this version hands you the elapsed time t directly. You can do the algebra by hand, or skip it and use our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/half-life\">Half-Life Calculator<\/a> to solve for the remaining amount, the time, or the half-life itself.<\/p>\n\n<p>One more quantity travels with half-life: the mean lifetime, \u03c4 = 1\/\u03bb = t\u00bd\/ln 2 \u2248 1.44 t\u00bd. It is the average time a single nucleus survives, and it always runs a little longer than the half-life.<\/p>\n\n<svg role=\"img\" aria-label=\"Graph of radioactive decay showing the fraction of a sample remaining against time measured in half-lives. The curve starts at 100 percent and falls to 50 percent after one half-life, 25 percent after two, and 12.5 percent after three, approaching but never reaching zero.\" viewBox=\"0 0 720 440\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:24px auto;\">\n<rect x=\"0\" y=\"0\" width=\"720\" height=\"440\" rx=\"6\" fill=\"#FAF6EE\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/rect>\n<text x=\"360\" y=\"30\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"17\" font-weight=\"700\" fill=\"#0A1628\">Radioactive Decay: Half the Sample Disappears Each Half-Life<\/text>\n<line x1=\"80\" y1=\"44\" x2=\"80\" y2=\"360\" stroke=\"#0A1628\" stroke-width=\"2\"><\/line>\n<line x1=\"80\" y1=\"360\" x2=\"692\" y2=\"360\" stroke=\"#0A1628\" stroke-width=\"2\"><\/line>\n<line x1=\"80\" y1=\"205\" x2=\"200\" y2=\"205\" stroke=\"#7A1F2B\" stroke-width=\"1\" stroke-dasharray=\"5 4\"><\/line>\n<line x1=\"200\" y1=\"205\" x2=\"200\" y2=\"360\" stroke=\"#7A1F2B\" stroke-width=\"1\" stroke-dasharray=\"5 4\"><\/line>\n<line x1=\"80\" y1=\"282.5\" x2=\"320\" y2=\"282.5\" stroke=\"#7A1F2B\" stroke-width=\"1\" stroke-dasharray=\"5 4\"><\/line>\n<line x1=\"320\" y1=\"282.5\" x2=\"320\" y2=\"360\" stroke=\"#7A1F2B\" stroke-width=\"1\" stroke-dasharray=\"5 4\"><\/line>\n<line x1=\"80\" y1=\"321.25\" x2=\"440\" y2=\"321.25\" stroke=\"#7A1F2B\" stroke-width=\"1\" stroke-dasharray=\"5 4\"><\/line>\n<line x1=\"440\" y1=\"321.25\" x2=\"440\" y2=\"360\" stroke=\"#7A1F2B\" stroke-width=\"1\" stroke-dasharray=\"5 4\"><\/line>\n<polyline points=\"80,50 140,140.8 200,205 260,250.4 320,282.5 380,305.2 440,321.25 500,332.6 560,340.6 620,346.3 680,350.3\" fill=\"none\" stroke=\"#C8932A\" stroke-width=\"3.5\" stroke-linecap=\"round\" stroke-linejoin=\"round\"><\/polyline>\n<circle cx=\"80\" cy=\"50\" r=\"5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/circle>\n<circle cx=\"200\" cy=\"205\" r=\"5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/circle>\n<circle cx=\"320\" cy=\"282.5\" r=\"5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/circle>\n<circle cx=\"440\" cy=\"321.25\" r=\"5\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"1.5\"><\/circle>\n<text x=\"74\" y=\"55\" text-anchor=\"end\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">100%<\/text>\n<text x=\"74\" y=\"210\" text-anchor=\"end\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">50%<\/text>\n<text x=\"74\" y=\"287\" text-anchor=\"end\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">25%<\/text>\n<text x=\"74\" y=\"326\" text-anchor=\"end\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"12\" fill=\"#0A1628\">12.5%<\/text>\n<text x=\"80\" y=\"382\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">0<\/text>\n<text x=\"200\" y=\"382\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">1<\/text>\n<text x=\"320\" y=\"382\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">2<\/text>\n<text x=\"440\" y=\"382\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">3<\/text>\n<text x=\"560\" y=\"382\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">4<\/text>\n<text x=\"680\" y=\"382\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#0A1628\">5<\/text>\n<text x=\"386\" y=\"412\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"14\" font-weight=\"600\" fill=\"#0A1628\">Time (number of half-lives)<\/text>\n<text x=\"24\" y=\"202\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"14\" font-weight=\"600\" fill=\"#0A1628\" transform=\"rotate(-90 24 202)\">Fraction remaining<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:4px;\">Figure 1: The exponential decay curve. Each half-life removes the same <em>fraction<\/em>, not the same amount, so the curve flattens and nears zero without ever touching it.<\/p>\n\n<h2>How Half-Life Works: Exponential Decay Step by Step<\/h2>\n\n<p>Why does halving keep producing a curve instead of a straight line? Because the number of decays in any second is proportional to how many unstable atoms are still present. More atoms, more decays; fewer atoms, fewer decays.<\/p>\n<figure style=\"margin:32px auto;max-width:600px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/07\/Ernest-Rutherford-oil-painting-J-Dunn-National-1932.webp\"\n       alt=\"Portrait of Ernest Rutherford, pioneer of radioactive decay and half-life\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">Ernest Rutherford, whose early work on radioactivity introduced the concept of a characteristic decay time.<\/figcaption>\n<\/figure>\n<p>Written as a rate, that statement is dN\/dt = \u2212\u03bbN: the sample loses nuclei in proportion to how many it still holds. Solving this gives the exponential N = N\u2080e^(\u2212\u03bbt), and setting N = N\u2080\/2 pins the half-life to t\u00bd = ln 2\/\u03bb.<\/p>\n\n<p>It helps to walk through the logic in stages:<\/p>\n\n<ol>\n<li>Start with N\u2080 nuclei. The decay rate at that instant is \u2212\u03bbN\u2080.<\/li>\n<li>As N falls, the rate falls with it \u2014 decay actually slows down over time.<\/li>\n<li>Equal time intervals therefore strip away equal <em>fractions<\/em>, never equal amounts.<\/li>\n<li>One half-life always removes exactly 50%, no matter where you sit on the curve.<\/li>\n<\/ol>\n\n<p>This is the engine of the whole idea: decay is multiplicative. Going from 100% to 50% takes one half-life; so does crawling from 2% to 1%. The clock ticks at the same rate near the start and near the very end.<\/p>\n\n<svg role=\"img\" aria-label=\"Five panels of sixteen atoms showing radioactive halving. At time zero all sixteen atoms are present. After one half-life eight remain, after two half-lives four remain, after three half-lives two remain, and after four half-lives one remains, corresponding to 100, 50, 25, 12.5 and 6.25 percent.\" viewBox=\"0 0 720 230\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:720px;display:block;margin:24px auto;\">\n<rect x=\"0\" y=\"0\" width=\"720\" height=\"230\" rx=\"6\" fill=\"#FAF6EE\" stroke=\"#D9CFB8\" stroke-width=\"1\"><\/rect>\n<text x=\"360\" y=\"26\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"16\" font-weight=\"700\" fill=\"#0A1628\">The Same Story in Atoms: Half Survive Each Half-Life<\/text>\n<circle cx=\"40\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"62\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"84\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"106\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"40\" cy=\"72\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"62\" cy=\"72\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"84\" cy=\"72\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"106\" cy=\"72\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"40\" cy=\"94\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"62\" cy=\"94\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"84\" cy=\"94\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"106\" cy=\"94\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"40\" cy=\"116\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"62\" cy=\"116\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"84\" cy=\"116\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"106\" cy=\"116\" r=\"7\" fill=\"#C8932A\"><\/circle>\n<circle cx=\"178\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"200\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"222\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"244\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"178\" cy=\"72\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"200\" cy=\"72\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"222\" cy=\"72\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"244\" cy=\"72\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"178\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"200\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"222\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"244\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"178\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"200\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"222\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"244\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle>\n<circle cx=\"316\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"338\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"360\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"382\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"316\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"338\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"360\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"382\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"316\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"338\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"360\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"382\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"316\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"338\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"360\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"382\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle>\n<circle cx=\"454\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"476\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"498\" cy=\"50\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"520\" cy=\"50\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"454\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"476\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"498\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"520\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"454\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"476\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"498\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"520\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"454\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"476\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"498\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"520\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle>\n<circle cx=\"592\" cy=\"50\" r=\"7\" fill=\"#C8932A\"><\/circle><circle cx=\"614\" cy=\"50\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"636\" cy=\"50\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"658\" cy=\"50\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"592\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"614\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"636\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"658\" cy=\"72\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"592\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"614\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"636\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"658\" cy=\"94\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"592\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"614\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"636\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle><circle cx=\"658\" cy=\"116\" r=\"7\" fill=\"#C5D0DC\" fill-opacity=\"0.45\"><\/circle>\n<text x=\"73\" y=\"150\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\">16 left<\/text>\n<text x=\"211\" y=\"150\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\">8 left<\/text>\n<text x=\"349\" y=\"150\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\">4 left<\/text>\n<text x=\"487\" y=\"150\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\">2 left<\/text>\n<text x=\"625\" y=\"150\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" font-weight=\"700\" fill=\"#0A1628\">1 left<\/text>\n<text x=\"73\" y=\"170\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#7A1F2B\">100%<\/text>\n<text x=\"211\" y=\"170\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#7A1F2B\">50%<\/text>\n<text x=\"349\" y=\"170\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#7A1F2B\">25%<\/text>\n<text x=\"487\" y=\"170\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#7A1F2B\">12.5%<\/text>\n<text x=\"625\" y=\"170\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"13\" fill=\"#7A1F2B\">6.25%<\/text>\n<text x=\"73\" y=\"200\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"12\" fill=\"#1F2E47\">start<\/text>\n<text x=\"211\" y=\"200\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"12\" fill=\"#1F2E47\">1 half-life<\/text>\n<text x=\"349\" y=\"200\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"12\" fill=\"#1F2E47\">2 half-lives<\/text>\n<text x=\"487\" y=\"200\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"12\" fill=\"#1F2E47\">3 half-lives<\/text>\n<text x=\"625\" y=\"200\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"12\" fill=\"#1F2E47\">4 half-lives<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:4px;\">Figure 2: Gold atoms are still radioactive; faded atoms have already decayed. Halving 16 \u2192 8 \u2192 4 \u2192 2 \u2192 1 is the discrete twin of the smooth curve above.<\/p>\n<p>For a single atom, decay is genuinely unpredictable \u2014 you can quote the odds but never the moment. In practice this never bites, because even a microgram holds quintillions of atoms, and the law of large numbers turns pure chance into a smooth, dependable curve. The same exponential law is laid out by <a href=\"https:\/\/chem.libretexts.org\/Bookshelves\/Introductory_Chemistry\/Chemistry_for_Allied_Health_(Soult)\/10:_Nuclear_and_Chemical_Reactions\/10.03:_Half-Life\" target=\"_blank\" rel=\"noopener\">LibreTexts<\/a> for any radioisotope.<\/p>\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Half-Life Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/half-life.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n<h2>Real-World Examples of Half-Life<\/h2>\n<h3>Radiocarbon dating<\/h3>\n<p>Living things constantly swap carbon with their surroundings, holding a steady trace of radioactive carbon-14. The moment an organism dies, that intake stops and its carbon-14 starts halving every 5,730 years.<\/p>\n<p>Measure how much carbon-14 is left, and you can read off the time since death. The method reaches back roughly 50,000 years \u2014 about nine half-lives \u2014 before too little carbon-14 survives to measure reliably.<\/p>\n<h3>Nuclear medicine<\/h3>\n<p>Hospitals pick isotopes by their half-life. Technetium-99m, the workhorse of medical imaging, halves in about 6 hours: long enough to finish a scan, short enough to clear the body quickly afterwards.<\/p>\n<p>Iodine-131 (t\u00bd \u2248 8 days) lingers a little longer to treat thyroid conditions, with the dose timed around its decay. Match the half-life to the job and you minimise the radiation a patient absorbs.<\/p>\n<h3>Nuclear power and waste<\/h3>\n<p>The very same principle becomes a centuries-long headache for spent fuel. Some fission products fade within years, but isotopes such as plutonium-239 (t\u00bd \u2248 24,100 years) hold their hazard for tens of thousands of years \u2014 which is why deep geological storage is engineered to outlast civilisations.<\/p>\n<h3>Dating the Earth \u2014 and the alarm on your ceiling<\/h3>\n<p>Uranium-238 halves every 4.5 billion years, close to the age of the Earth itself, so uranium-lead dating clocks the oldest rocks and meteorites. Closer to home, the americium-241 in a smoke alarm (t\u00bd \u2248 432 years) decays steadily enough to give many years of reliable service.<\/p>\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#142139;color:#FAF6EE;\">\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Isotope<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Half-life<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Main decay mode<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Typical use<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Technetium-99m<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">6.0 hours<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Gamma (isomeric)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Medical imaging<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Radon-222<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">3.82 days<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Alpha<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Indoor air hazard<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Iodine-131<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">8.02 days<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Beta (\u03b2\u207b)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Thyroid therapy<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Cobalt-60<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">5.27 years<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Beta + gamma<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Cancer therapy, sterilisation<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Carbon-14<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">5,730 years<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Beta (\u03b2\u207b)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Radiocarbon dating<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Plutonium-239<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">24,100 years<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Alpha<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Reactor fuel<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Potassium-40<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">1.25 billion years<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Beta \/ electron capture<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Rock dating<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Uranium-238<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">4.47 billion years<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Alpha<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Earth &amp; meteorite dating<\/td><\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:-6px;\">Half-lives span from hours to billions of years, yet every isotope obeys the identical exponential law.<\/p>\n<h2>Common Misconceptions About Half-Life<\/h2>\n<h3>&#8220;After two half-lives, it&#8217;s all gone&#8221;<\/h3>\n<p>Two half-lives leave a quarter, not zero. Each period removes half of what remains, so the amount shrinks toward zero but never quite arrives \u2014 three half-lives leave an eighth, ten leave about a thousandth.<\/p>\n<h3>&#8220;Decay is steady, like a leaking tap&#8221;<\/h3>\n<p>A leak loses the same volume each minute; radioactive decay loses the same fraction. That is why the curve bends \u2014 the first half-life might destroy billions of atoms while a later one destroys only a handful, yet both take exactly the same time.<\/p>\n<h3>&#8220;Heating or compressing a sample speeds up decay&#8221;<\/h3>\n<p>For nearly all isotopes, half-life is set by the nucleus and shrugs off temperature, pressure, and chemical bonding \u2014 the very things that easily change chemical reaction rates. A few decay modes (electron capture and internal conversion) show vanishingly small shifts, but for school and exam purposes, treat half-life as a true constant.<\/p>\n<h3>&#8220;You can predict when a given atom will decay&#8221;<\/h3>\n<p>You cannot. Half-life gives the odds for the crowd, never a schedule for any single nucleus. One atom might decay in the next second or outlast you by a billion years \u2014 only the average is knowable.<\/p>\n<h2>How Half-Life Relates to Decay Constant, Activity and Energy<\/h2>\n<h3>Activity and the becquerel<\/h3>\n<p>Activity is the number of decays per second, measured in becquerels (Bq). It equals A = \u03bbN, so activity tracks how many unstable atoms remain \u2014 and therefore it halves on exactly the same schedule as the sample. This is also why an old source is <em>less<\/em> active than a fresh one of the same isotope.<\/p>\n<h3>Decay constant and mean lifetime<\/h3>\n<p>Half-life, decay constant, and mean lifetime are three views of one clock, bound together by t\u00bd = ln 2\/\u03bb and \u03c4 = 1\/\u03bb. Quote any single one and the other two follow immediately.<\/p>\n<h3>Mass, energy, and where the radiation comes from<\/h3>\n<p>Every decay releases energy because the products weigh fractionally less than the original nucleus. That missing mass reappears as the kinetic energy of the emitted particles, exactly as set out by Einstein&#8217;s mass\u2013energy relation in our guide to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/modern-physics\/special-relativity\/\">special relativity<\/a>.<\/p>\n<p>The energy per atom is minuscule, but multiplied by the square of the <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/modern-physics\/speed-of-light\/\">speed of light<\/a> it becomes the vast output of reactors and stars. It is the same accounting that underlies every form of <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/what-is-energy-in-physics\/\">energy in physics<\/a>, from a falling apple to a fission core.<\/p>\n<h2>Worked Problems<\/h2>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">A radioactive sample has an initial mass of 80 g. How much remains after exactly 3 half-lives?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Use N = N\u2080(\u00bd)^n, where n is the number of half-lives.\nStep 2: n = 3, so the fraction remaining is (\u00bd)\u00b3 = 1\/8.\nStep 3: N = 80 g \u00d7 1\/8 = 10 g.\n<strong>Answer: 10 g<\/strong>\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A hospital receives 500 mg of iodine-131 (t\u00bd = 8.02 days). How much remains after 24 days?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Number of half-lives n = t \/ t\u00bd = 24 \/ 8.02 = 2.99.\nStep 2: N = N\u2080(\u00bd)^n = 500 mg \u00d7 (\u00bd)^2.99.\nStep 3: (\u00bd)^2.99 = 0.126, so N = 500 mg \u00d7 0.126 \u2248 63 mg.\n<strong>Answer: \u2248 63 mg (about one-eighth, since 24 days \u2248 3 half-lives)<\/strong>\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">Cobalt-60 has a half-life of 5.27 years. Find its decay constant \u03bb in s\u207b\u00b9.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: \u03bb = ln 2 \/ t\u00bd.\nStep 2: In years, \u03bb = 0.6931 \/ 5.27 = 0.1315 yr\u207b\u00b9.\nStep 3: Convert using 1 yr \u2248 3.156 \u00d7 10\u2077 s: \u03bb = 0.1315 \/ (3.156 \u00d7 10\u2077) = 4.17 \u00d7 10\u207b\u2079 s\u207b\u00b9.\n<strong>Answer: \u03bb \u2248 4.17 \u00d7 10\u207b\u2079 s\u207b\u00b9<\/strong>\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">A wooden artefact contains 25% of the carbon-14 expected in living wood. How old is it? (t\u00bd = 5,730 years)<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: 25% = (\u00bd)\u00b2, so n = 2 half-lives have passed.\nStep 2: t = n \u00d7 t\u00bd = 2 \u00d7 5,730 years.\nStep 3: t = 11,460 years.\n<strong>Answer: 11,460 years<\/strong>\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">A bone retains 30% of its original carbon-14. Estimate its age. (t\u00bd = 5,730 years)<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Use t = t\u00bd \u00d7 ln(N\u2080\/N) \/ ln 2 with N\/N\u2080 = 0.30.\nStep 2: ln(1\/0.30) = ln(3.33) = 1.204; ln 2 = 0.693.\nStep 3: t = 5,730 \u00d7 1.204 \/ 0.693 = 5,730 \u00d7 1.737 \u2248 9,950 years.\n<strong>Answer: \u2248 9,950 years (between one and two half-lives, as expected)<\/strong>\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">A technetium-99m source has an activity of 8.0 \u00d7 10\u2074 Bq and a half-life of 6.0 hours. Find its activity after 18 hours, and the number of radioactive atoms present initially.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Activity obeys the same law: A = A\u2080(\u00bd)^(t\/t\u00bd), with n = 18 \/ 6.0 = 3.\nStep 2: A = 8.0 \u00d7 10\u2074 Bq \u00d7 (\u00bd)\u00b3 = 8.0 \u00d7 10\u2074 \/ 8 = 1.0 \u00d7 10\u2074 Bq.\nStep 3: Initial atoms from A\u2080 = \u03bbN\u2080 \u2192 N\u2080 = A\u2080 \/ \u03bb, with \u03bb = ln 2 \/ (6.0 \u00d7 3600 s) = 0.6931 \/ 21,600 = 3.21 \u00d7 10\u207b\u2075 s\u207b\u00b9.\nStep 4: N\u2080 = 8.0 \u00d7 10\u2074 \/ (3.21 \u00d7 10\u207b\u2075) = 2.5 \u00d7 10\u2079 atoms.\n<strong>Answer: A = 1.0 \u00d7 10\u2074 Bq; N\u2080 \u2248 2.5 \u00d7 10\u2079 atoms<\/strong>\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">A detector measures 2,400 counts per minute from a fresh source. Twelve hours later it reads 600 counts per minute. What is the source&#039;s half-life?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Fraction remaining = 600 \/ 2,400 = 1\/4.\nStep 2: 1\/4 = (\u00bd)\u00b2, so 2 half-lives elapsed in 12 hours.\nStep 3: t\u00bd = 12 hours \/ 2 = 6 hours.\n<strong>Answer: 6 hours<\/strong>\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 8<\/div><div class=\"pf-problem-question\">Carbon-14 has a half-life of 5,730 years. (a) Find its mean lifetime. (b) What fraction of a sample remains after one mean lifetime?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<strong>Solution:<\/strong>\nStep 1: Mean lifetime \u03c4 = t\u00bd \/ ln 2 = 5,730 \/ 0.6931.\nStep 2: \u03c4 = 8,267 years.\nStep 3: After t = \u03c4 = 1\/\u03bb, the fraction is N\/N\u2080 = e^(\u2212\u03bb\u03c4) = e^(\u22121) = 0.368.\n<strong>Answer: \u03c4 \u2248 8,267 years; about 36.8% remains after one mean lifetime<\/strong>\n<\/div><\/details><\/div>\n<h2>Frequently Asked Questions<\/h2>\n<details class=\"pf-faq-item\"><summary>What is half-life in physics?<\/summary><div class=\"pf-faq-item-answer\">\nHalf-life is the time it takes for half the radioactive atoms in a sample to decay. Written t\u00bd, it is fixed for each isotope and connects to the amount remaining through N = N\u2080(\u00bd)^(t\/t\u00bd). Values run from microseconds to billions of years, yet the same exponential rule governs every one of them.\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>What is the half-life formula?<\/summary><div class=\"pf-faq-item-answer\">\nThe half-life formula is N = N\u2080(\u00bd)^(t\/t\u00bd), where N is the amount left, N\u2080 the starting amount, t the elapsed time and t\u00bd the half-life. The exponent t\/t\u00bd counts how many half-lives have passed. An equivalent form is N = N\u2080e^(\u2212\u03bbt), using the decay constant \u03bb = ln 2\/t\u00bd.\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>Does temperature or pressure change a half-life?<\/summary><div class=\"pf-faq-item-answer\">\nNo \u2014 for essentially all isotopes, half-life is set by the nucleus and is unaffected by temperature, pressure, or chemical bonding. That stability is what makes radioactive dating trustworthy. A handful of decay modes (electron capture, internal conversion) show immeasurably small shifts, but for school and exam purposes half-life is a true constant.\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>What is the difference between half-life and mean lifetime?<\/summary><div class=\"pf-faq-item-answer\">\nHalf-life is the time for half a sample to decay; mean lifetime is the average time an individual nucleus survives. They are related by \u03c4 = t\u00bd\/ln 2 \u2248 1.44 t\u00bd, so the mean lifetime is always longer. About 37% of a sample remains after one mean lifetime, compared with 50% after one half-life.\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>Can you predict when a single atom will decay?<\/summary><div class=\"pf-faq-item-answer\">\nNo. Radioactive decay is fundamentally random for any single atom \u2014 half-life only gives the probability for a large group. One nucleus might decay in the next instant or survive for billions of years. Only because real samples hold astronomical numbers of atoms does the smooth, predictable half-life curve appear.\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>Why is carbon-14 dating limited to about 50,000 years?<\/summary><div class=\"pf-faq-item-answer\">\nAfter roughly 50,000 years \u2014 close to nine half-lives \u2014 less than about 0.2% of the original carbon-14 remains, too little to measure accurately against background radiation. Older objects are dated with longer-lived isotopes instead, such as potassium-40 or uranium-238, whose half-lives reach billions of years.\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>How is half-life related to the decay constant?<\/summary><div class=\"pf-faq-item-answer\">\nThe decay constant \u03bb is the probability that one nucleus decays per second, tied to half-life by t\u00bd = ln 2\/\u03bb \u2248 0.693\/\u03bb. A large decay constant means rapid decay and a short half-life; a small one means a long-lived isotope. Both describe the same exponential decay from opposite directions.\n<\/div><\/details>\n","protected":false},"excerpt":{"rendered":"<p>Half-life is the time for half a radioactive sample to decay. This guide explains the half-life formula, the decay constant, worked examples and how carbon dating works.<\/p>\n","protected":false},"author":1,"featured_media":388,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[225,227,224,206,226],"class_list":["post-386","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-modern-physics","tag-carbon-dating","tag-decay-constant","tag-half-life","tag-nuclear-physics","tag-radioactive-decay"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/386","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=386"}],"version-history":[{"count":2,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/386\/revisions"}],"predecessor-version":[{"id":390,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/386\/revisions\/390"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/388"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=386"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=386"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=386"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}