{"id":346,"date":"2026-06-28T19:43:45","date_gmt":"2026-06-28T19:43:45","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=346"},"modified":"2026-06-28T19:43:46","modified_gmt":"2026-06-28T19:43:46","slug":"archimedes-principle","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/archimedes-principle\/","title":{"rendered":"Archimedes&#8217; Principle and Buoyancy"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\n\nArchimedes&#8217; principle states that any object placed in a fluid is pushed upward by a buoyant force equal to the weight of the fluid the object displaces. The force is found with F_b = \u03c1Vg, where \u03c1 is the fluid&#8217;s density, V the displaced volume, and g gravity. An object floats when this upward force balances its weight.\n\n<\/p><\/div>\n<p>Drop a steel spanner into a sink and it plunges straight to the bottom. Yet a steel ship the length of three football pitches sits calmly on the ocean, carrying thousands of cars. Same metal, opposite fate. The rule that explains both \u2014 and the floating ice in your drink, and the lift under a hot-air balloon \u2014 is one of the oldest in physics.<\/p>\n<p>It came from a puzzle about a king&#8217;s crown more than two thousand years ago, and it still decides how submarines dive, how life jackets save lives, and how much of every iceberg hides beneath the waves. Once you can picture the fluid being <em>pushed out of the way<\/em>, the whole thing clicks.<\/p>\n<h2>What Is Archimedes&#8217; Principle?<\/h2>\n<p>Picture lowering a sealed box into a bathtub. The water has to go somewhere, so it rises \u2014 the box has <strong>displaced<\/strong> a certain volume of water. Archimedes&#8217; principle says the fluid pushes back: it shoves the box upward with a force exactly equal to the weight of the water that was moved aside.<\/p>\n<p>That upward push is the <strong>buoyant force<\/strong> (also called upthrust). It does not care what the object is made of, only how much fluid the object displaces and how heavy that fluid is. This idea is often written simply as the <strong>Archimedes principle<\/strong>, and it applies to every fluid \u2014 water, oil, even the air around you.<\/p>\n<p>So whether an object floats or sinks is a contest between two forces: gravity pulling it down by its weight, and buoyancy pushing it up by the weight of displaced fluid. Win the contest and it rises; lose and it sinks; tie and it hovers in place.<\/p>\n<p>The man behind it, Archimedes of Syracuse (c. 287\u2013212 BC), reportedly hit on the idea in his bath and shouted &#8220;Eureka!&#8221; The famous story has him testing a king&#8217;s gold crown for cheating. Whether he literally used a bathtub is debated by historians \u2014 a careful hydrostatic balance is the more likely method \u2014 but the physics he uncovered is rock-solid.<\/p>\n<h2>The Buoyant Force Formula<\/h2>\n<p>The size of the upthrust comes straight from the weight of displaced fluid. Since weight is mass times gravity, and the displaced mass is the fluid&#8217;s density times the displaced volume, the buoyant force is:<\/p>\n<div class=\"pf-formula\">F_b = \u03c1Vg<\/div>\n<p>Every symbol has a job, and each one carries an SI unit. Get the units right and the answer lands in newtons every time.<\/p>\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#142139;color:#FAF6EE;\">\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Symbol<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Quantity<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">SI unit<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>F_b<\/strong><\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Buoyant force (upthrust)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">newton (N)<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>\u03c1<\/strong> (rho)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Density of the <em>fluid<\/em><\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">kg\/m\u00b3<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>V<\/strong><\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Volume of fluid displaced<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">m\u00b3<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\"><strong>g<\/strong><\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Gravitational field strength<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">\u2248 9.81 m\/s\u00b2<\/td><\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>One trap worth flagging now: \u03c1 is the density of the <strong>fluid<\/strong>, never the object. Swap in the object&#8217;s density by mistake and the physics falls apart.<\/p>\n<h3>Apparent weight and the float fraction<\/h3>\n<p>When an object hangs submerged on a scale, the scale reads less than its true weight, because buoyancy lifts part of the load. That reduced reading is the <strong>apparent weight<\/strong>:<\/p>\n<div class=\"pf-formula\">W_app = W \u2212 F_b<\/div>\n<p>For something that floats, there is a neat shortcut for how deep it rides. The fraction of its volume sitting below the surface equals the ratio of the two densities:<\/p>\n<div class=\"pf-formula\">V_sub \/ V = \u03c1_obj \/ \u03c1_fluid<\/div>\n<p>This single ratio is why a denser object floats lower, and why ice \u2014 slightly less dense than water \u2014 barely pokes above the surface. You can run the numbers for any object and fluid with our <a href=\"https:\/\/physicsfundamentalsinfo.com\/calculators\/buoyancy\">Buoyancy Calculator<\/a>.<\/p>\n<h2>How Buoyancy Works<\/h2>\n<p>Where does the upward push actually come from? Pressure. In any fluid, pressure grows with depth, because deeper layers carry the weight of everything above them. The relationship is P = \u03c1gh \u2014 go deeper, and h grows, so the pressure climbs.<\/p>\n<p>Now think about a submerged block. The fluid presses on every face, but the bottom face sits deeper than the top face. So the upward push on the bottom beats the downward push on the top. That difference <em>is<\/em> the buoyant force.<\/p>\n<p>Put numbers on it. If the top face is at depth <em>d<\/em> and the block has height <em>h<\/em> and face area <em>A<\/em>, the bottom sits at depth <em>d + h<\/em>. The net upward force is the bottom force minus the top force:<\/p>\n<p>F_b = \u03c1g(d + h)A \u2212 \u03c1g(d)A = \u03c1g(hA) = \u03c1gV. The depth <em>d<\/em> cancels, leaving exactly \u03c1Vg \u2014 the displaced volume V = hA times \u03c1g. NASA&#8217;s Glenn Research Center walks through this same pressure-difference derivation in its <a href=\"https:\/\/www.grc.nasa.gov\/www\/k-12\/WindTunnel\/Activities\/buoy_Archimedes.html\" target=\"_blank\" rel=\"noopener\">Archimedes&#8217; principle activity<\/a>.<\/p>\n<svg role=\"img\" aria-label=\"A block submerged in fluid. Short downward pressure arrows act on its top face and longer upward pressure arrows act on its deeper, higher-pressure bottom face. A red weight arrow points down through the centre and a longer gold buoyant-force arrow points up, showing the net upward buoyancy.\" viewBox=\"0 0 640 400\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:560px;display:block;margin:18px auto;background:#0A1628;border-radius:8px;\">\n<defs>\n<marker id=\"pfDown\" markerWidth=\"10\" markerHeight=\"10\" refX=\"5\" refY=\"9\" orient=\"auto\"><path d=\"M0,0 L10,0 L5,10 Z\" fill=\"#C5D0DC\"\/><\/marker>\n<marker id=\"pfUp\" markerWidth=\"10\" markerHeight=\"10\" refX=\"5\" refY=\"1\" orient=\"auto\"><path d=\"M5,0 L10,10 L0,10 Z\" fill=\"#C5D0DC\"\/><\/marker>\n<marker id=\"pfGoldUp\" markerWidth=\"13\" markerHeight=\"13\" refX=\"6.5\" refY=\"1\" orient=\"auto\"><path d=\"M6.5,0 L13,13 L0,13 Z\" fill=\"#C8932A\"\/><\/marker>\n<marker id=\"pfRedDn\" markerWidth=\"13\" markerHeight=\"13\" refX=\"6.5\" refY=\"12\" orient=\"auto\"><path d=\"M0,0 L13,0 L6.5,13 Z\" fill=\"#C0414F\"\/><\/marker>\n<\/defs>\n<rect x=\"60\" y=\"34\" width=\"520\" height=\"332\" fill=\"#142139\" stroke=\"#D9CFB8\" stroke-width=\"2\"\/>\n<rect x=\"62\" y=\"96\" width=\"516\" height=\"268\" fill=\"#2c4f73\" opacity=\"0.5\"\/>\n<line x1=\"62\" y1=\"96\" x2=\"578\" y2=\"96\" stroke=\"#C5D0DC\" stroke-width=\"1.5\"\/>\n<text x=\"470\" y=\"90\" fill=\"#C5D0DC\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\">fluid surface<\/text>\n<rect x=\"258\" y=\"170\" width=\"124\" height=\"120\" rx=\"5\" fill=\"#C8932A\" stroke=\"#FAF6EE\" stroke-width=\"2\"\/>\n<text x=\"320\" y=\"236\" fill=\"#0A1628\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"14\" font-weight=\"700\" text-anchor=\"middle\">object<\/text>\n<line x1=\"288\" y1=\"138\" x2=\"288\" y2=\"166\" stroke=\"#C5D0DC\" stroke-width=\"2\" marker-end=\"url(#pfDown)\"\/>\n<line x1=\"352\" y1=\"138\" x2=\"352\" y2=\"166\" stroke=\"#C5D0DC\" stroke-width=\"2\" marker-end=\"url(#pfDown)\"\/>\n<text x=\"398\" y=\"150\" fill=\"#C5D0DC\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\">smaller pressure (top)<\/text>\n<line x1=\"288\" y1=\"348\" x2=\"288\" y2=\"294\" stroke=\"#C5D0DC\" stroke-width=\"2\" marker-end=\"url(#pfUp)\"\/>\n<line x1=\"352\" y1=\"348\" x2=\"352\" y2=\"294\" stroke=\"#C5D0DC\" stroke-width=\"2\" marker-end=\"url(#pfUp)\"\/>\n<text x=\"398\" y=\"334\" fill=\"#C5D0DC\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"12\">larger pressure (bottom)<\/text>\n<line x1=\"320\" y1=\"230\" x2=\"320\" y2=\"62\" stroke=\"#C8932A\" stroke-width=\"3.5\" marker-end=\"url(#pfGoldUp)\"\/>\n<text x=\"328\" y=\"76\" fill=\"#C8932A\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"14\" font-weight=\"700\">F_b (buoyant force)<\/text>\n<line x1=\"320\" y1=\"230\" x2=\"320\" y2=\"346\" stroke=\"#C0414F\" stroke-width=\"3.5\" marker-end=\"url(#pfRedDn)\"\/>\n<text x=\"328\" y=\"342\" fill=\"#E6A6AE\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"14\" font-weight=\"700\">W (weight)<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:4px;\">Fluid pressure is greater on the deeper bottom face than on the top, and that imbalance produces the net upward buoyant force.<\/p>\n<p>Try it yourself. In the lab below, change the object&#8217;s density, its volume, and the fluid. Watch the weight, buoyant force, apparent weight and submerged percentage update live as the block settles to float or sink.<\/p>\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Buoyancy Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/buoyancy.html?embed=1\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n<h2>Real-World Examples of Buoyancy<\/h2>\n<p>Archimedes&#8217; principle is not a textbook curiosity \u2014 it is doing quiet work all around you. Here are five places it shows up.<\/p>\n<h3>1. Why steel ships float<\/h3>\n<p>A solid lump of steel sinks because steel is far denser than water. A ship dodges this by being mostly hollow. Its hull encloses a huge volume of air, so the <em>average<\/em> density of the whole vessel \u2014 steel plus air \u2014 drops below that of water, and it floats. Overload it, and the average density climbs until it sinks.<\/p>\n<h3>2. How submarines dive and surface<\/h3>\n<p>Submarines play with their own weight on purpose. To dive, they flood ballast tanks with seawater, raising their average density above the surrounding water. To surface, compressed air blows that water back out, the average density falls, and buoyancy lifts them up.<\/p>\n<h3>3. Hot-air and helium balloons<\/h3>\n<p>Here the fluid is air, not water. A balloon rises when it displaces enough air to be lifted \u2014 that is, when its average density falls below the air around it. Helium does this because it is far lighter than air; a hot-air balloon does it by heating the air inside until it thins out.<\/p>\n<h3>4. Hydrometers<\/h3>\n<p>A hydrometer is a weighted float used to measure a liquid&#8217;s density. Drop it into a fluid and it sinks until it displaces its own weight. In a denser liquid it sits higher; in a thinner one it sinks lower \u2014 and the depth is read straight off a scale.<\/p>\n<h3>5. Icebergs<\/h3>\n<p>Ice is only slightly less dense than seawater, so an iceberg floats with just a sliver above the surface. Plug the densities into the float-fraction rule and the famous &#8220;tip of the iceberg&#8221; turns into a hard number \u2014 about 89.5% stays hidden underwater.<\/p>\n<svg role=\"img\" aria-label=\"An iceberg floating in seawater. A small jagged tip rises above the dashed waterline while a much larger mass sits below. Gold brackets mark roughly 10.5 percent of the ice above water and 89.5 percent below, matching the ratio of ice density to seawater density.\" viewBox=\"0 0 640 380\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:560px;display:block;margin:18px auto;background:#0A1628;border-radius:8px;\">\n<rect x=\"0\" y=\"0\" width=\"640\" height=\"150\" fill=\"#0A1628\"\/>\n<text x=\"40\" y=\"44\" fill=\"#C5D0DC\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\">air<\/text>\n<polygon points=\"305,118 326,134 348,120 374,140 390,150 438,212 420,296 360,340 300,344 242,308 222,228 252,166 264,150\" fill=\"#EAF0F6\" stroke=\"#C5D0DC\" stroke-width=\"1.5\"\/>\n<rect x=\"0\" y=\"150\" width=\"640\" height=\"230\" fill=\"#2c4f73\" opacity=\"0.55\"\/>\n<line x1=\"0\" y1=\"150\" x2=\"640\" y2=\"150\" stroke=\"#C5D0DC\" stroke-width=\"2\" stroke-dasharray=\"7 5\"\/>\n<text x=\"40\" y=\"172\" fill=\"#C5D0DC\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\">seawater<\/text>\n<line x1=\"470\" y1=\"118\" x2=\"470\" y2=\"150\" stroke=\"#C8932A\" stroke-width=\"1.5\"\/>\n<text x=\"478\" y=\"138\" fill=\"#C8932A\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" font-weight=\"700\">\u2248 10.5% above<\/text>\n<line x1=\"470\" y1=\"150\" x2=\"470\" y2=\"342\" stroke=\"#C8932A\" stroke-width=\"1.5\"\/>\n<text x=\"478\" y=\"250\" fill=\"#C8932A\" font-family=\"Manrope,Arial,sans-serif\" font-size=\"13\" font-weight=\"700\">\u2248 89.5% below<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:4px;\">An iceberg floats with roughly nine-tenths of its volume below the surface \u2014 the ratio of ice density to seawater density.<\/p>\n<figure style=\"margin:32px auto;max-width:640px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/06\/download.jpeg\"\n       alt=\"Iceberg showing the small portion above water and the large mass below, illustrating Archimedes' principle\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">Most of an iceberg&#8217;s volume sits below the surface, exactly as the density ratio predicts.<\/figcaption>\n<\/figure>\n<h2>Common Misconceptions About Buoyancy<\/h2>\n<p>Buoyancy is one of those topics where intuition leads people astray. Four wrong beliefs come up again and again.<\/p>\n<h3>&#8220;The buoyant force depends on the object&#8217;s weight&#8221;<\/h3>\n<p>It does not. Buoyancy depends only on the fluid&#8217;s density, the displaced volume, and gravity \u2014 the object&#8217;s own weight and material never enter F_b = \u03c1Vg. As Georgia State University&#8217;s <a href=\"http:\/\/hyperphysics.phy-astr.gsu.edu\/hbase\/pbuoy.html\" target=\"_blank\" rel=\"noopener\">HyperPhysics<\/a> notes, equal volumes of cork, aluminium and lead, fully submerged, all feel the <em>same<\/em> buoyant force. What differs is their weight, which decides whether they float.<\/p>\n<h3>&#8220;Heavy things always sink&#8221;<\/h3>\n<p>Weight alone settles nothing \u2014 average density does. A 100,000-tonne ship floats while a 5-gram nail sinks, because the ship&#8217;s average density (steel plus enclosed air) is below water while the nail&#8217;s is not. Compare the object&#8217;s average density with the fluid&#8217;s, never its raw mass.<\/p>\n<h3>&#8220;The buoyant force grows as the object sinks deeper&#8221;<\/h3>\n<p>For a rigid object in an incompressible fluid like water, it does not. Pressure rises with depth on both the top and bottom faces, but their <em>difference<\/em> stays the same, so F_b = \u03c1Vg is unchanged at any depth. (Gas-filled objects are the exception \u2014 they compress, shrinking V, and so lose buoyancy as they descend.)<\/p>\n<h3>&#8220;A sunken object displaces its own weight of fluid&#8221;<\/h3>\n<p>Only a <em>floating<\/em> object does that. A fully submerged object displaces its own <strong>volume<\/strong> of fluid, and the buoyant force equals the weight of just that displaced fluid \u2014 which, for anything that sinks, is less than the object&#8217;s own weight. Mixing up &#8220;displaces its weight&#8221; and &#8220;displaces its volume&#8221; is the single most common slip.<\/p>\n<h2>How Buoyancy Relates to Density, Pressure and Weight<\/h2>\n<p>Buoyancy never acts alone. It is really a story about density set against the fluid, pressure that builds with depth, and the weight it works against.<\/p>\n<p><strong>Density<\/strong> is the decider. If an object&#8217;s average density is below the fluid&#8217;s, it floats; above, it sinks; equal, it hovers. The table below shows where common materials land in fresh water.<\/p>\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#142139;color:#FAF6EE;\">\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Material \/ fluid<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">Density (kg\/m\u00b3)<\/th>\n<th style=\"padding:10px;border:1px solid #D9CFB8;text-align:left;\">In fresh water (1000 kg\/m\u00b3)?<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Helium (gas)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">0.18<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Rises (in air)<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Air<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">1.225<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">\u2014<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Cork<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">\u2248 240<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Floats<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Ice<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">917<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Floats<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Vegetable oil<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">\u2248 920<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Floats<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Fresh water<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">1000<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Reference<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Seawater<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">1025<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Sinks slightly<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Aluminium<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">2700<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Sinks<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Iron<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">7870<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Sinks<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Lead<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">11,340<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Sinks<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Mercury (liquid)<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">13,534<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Sinks<\/td><\/tr>\n<tr><td style=\"padding:10px;border:1px solid #D9CFB8;\">Gold<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">19,300<\/td><td style=\"padding:10px;border:1px solid #D9CFB8;\">Sinks<\/td><\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p><strong>Pressure<\/strong> is the engine. The buoyant force exists only because fluid pressure climbs with depth, pushing harder on the bottom of an object than the top. This is the same depth-pressure idea that governs how fast things fall through a fluid, where buoyancy and drag both resist gravity \u2014 see our guide to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/terminal-velocity\/\">terminal velocity<\/a>.<\/p>\n<p><strong>Weight<\/strong> is the opponent. Floating is simply the balance point where the upthrust equals the object&#8217;s weight \u2014 a state of equilibrium, exactly the kind of force balance covered in <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/newtons-laws-of-motion\/\">Newton&#8217;s laws of motion<\/a>. When the forces do not balance, the object accelerates, and the net force follows directly from <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/newtons-second-law\/\">Newton&#8217;s second law<\/a>.<\/p>\n<h2>Worked Problems<\/h2>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">A solid cube of volume 0.0025 m\u00b3 is fully submerged in fresh water (density 1000 kg\/m\u00b3). Find the buoyant force on it. Take g = 9.81 m\/s\u00b2.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\nStep 1: Use Archimedes&#8217; principle, F_b = \u03c1Vg.\nStep 2: Substitute with units: F_b = (1000 kg\/m\u00b3)(0.0025 m\u00b3)(9.81 m\/s\u00b2).\nStep 3: Solve: F_b = 24.525 N.\n<strong>Answer: F_b \u2248 24.5 N<\/strong>\n\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A 12 kg metal block of volume 0.0015 m\u00b3 hangs from a spring scale and is lowered fully into water. What apparent weight does the scale read? Take g = 9.81 m\/s\u00b2.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\nStep 1: True weight W = mg = (12)(9.81) = 117.72 N. Buoyant force F_b = \u03c1Vg.\nStep 2: F_b = (1000)(0.0015)(9.81) = 14.715 N.\nStep 3: Apparent weight W_app = W \u2212 F_b = 117.72 \u2212 14.715 = 103.005 N.\n<strong>Answer: W_app \u2248 103 N<\/strong>\n\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A block of wood with density 650 kg\/m\u00b3 floats in fresh water (1000 kg\/m\u00b3). What fraction of its volume sits below the surface?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\nStep 1: For a floating object, V_sub \/ V = \u03c1_obj \/ \u03c1_fluid.\nStep 2: Substitute: V_sub \/ V = 650 \/ 1000.\nStep 3: Solve: V_sub \/ V = 0.65.\n<strong>Answer: 65% of the wood is submerged<\/strong>\n\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">Ice has a density of 917 kg\/m\u00b3 and seawater 1025 kg\/m\u00b3. What percentage of a floating iceberg lies below the surface?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\nStep 1: Use the float-fraction rule, V_sub \/ V = \u03c1_ice \/ \u03c1_seawater.\nStep 2: Substitute: V_sub \/ V = 917 \/ 1025.\nStep 3: Solve: V_sub \/ V = 0.8946.\n<strong>Answer: \u2248 89.5% is underwater (only about 10.5% shows above)<\/strong>\n\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">A crown weighs 27.5 N in air and 25.4 N when fully submerged in water. Find its density and decide whether it is pure gold (gold density 19,300 kg\/m\u00b3). Take g = 9.81 m\/s\u00b2.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\nStep 1: Buoyant force F_b = weight in air \u2212 apparent weight = 27.5 \u2212 25.4 = 2.1 N. From F_b = \u03c1_water\u00b7V\u00b7g, the volume V = F_b \/ (\u03c1_water\u00b7g).\nStep 2: V = 2.1 \/ (1000 \u00d7 9.81) = 2.14 \u00d7 10\u207b\u2074 m\u00b3. Mass m = W\/g = 27.5 \/ 9.81 = 2.803 kg.\nStep 3: Density \u03c1 = m\/V = 2.803 \/ (2.14 \u00d7 10\u207b\u2074) \u2248 13,100 kg\/m\u00b3.\n<strong>Answer: \u03c1 \u2248 13,100 kg\/m\u00b3 \u2014 far below gold&#8217;s 19,300 kg\/m\u00b3, so the crown is not pure gold<\/strong>\n\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">A raft of volume 0.40 m\u00b3 and mass 120 kg floats in fresh water. What is the maximum extra load it can carry before it sinks? Take g = 9.81 m\/s\u00b2.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\nStep 1: Maximum upthrust occurs when the raft is on the point of full submersion: F_b(max) = \u03c1Vg = (1000)(0.40)(9.81) = 3924 N.\nStep 2: This supports a maximum total weight of 3924 N, i.e. a total mass of 3924 \/ 9.81 = 400 kg.\nStep 3: Subtract the raft&#8217;s own mass: 400 \u2212 120 = 280 kg.\n<strong>Answer: Maximum load \u2248 280 kg<\/strong>\n\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">A helium balloon has a volume of 5.0 m\u00b3 and a fabric mass of 2.0 kg. Using air density 1.225 kg\/m\u00b3 and helium density 0.1786 kg\/m\u00b3, find the net upward force. Take g = 9.81 m\/s\u00b2.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\nStep 1: Buoyant force from displaced air: F_b = \u03c1_air\u00b7V\u00b7g = (1.225)(5.0)(9.81) = 60.09 N.\nStep 2: Total weight = weight of helium + fabric = (0.1786)(5.0)(9.81) + (2.0)(9.81) = 8.76 + 19.62 = 28.38 N.\nStep 3: Net upward force = 60.09 \u2212 28.38 = 31.71 N.\n<strong>Answer: Net lift \u2248 31.7 N (about 3.23 kg of extra payload)<\/strong>\n\n<\/div><\/details><\/div>\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 8<\/div><div class=\"pf-problem-question\">An object weighs 8.00 N in air, 6.00 N in water, and 6.40 N in oil. Find the object&#039;s density and the oil&#039;s density. Take water density 1000 kg\/m\u00b3 and g = 9.81 m\/s\u00b2.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n\n<strong>Solution:<\/strong>\nStep 1: In water, F_b = 8.00 \u2212 6.00 = 2.00 N, so V = 2.00 \/ (1000 \u00d7 9.81) = 2.04 \u00d7 10\u207b\u2074 m\u00b3.\nStep 2: Object density \u03c1_obj = \u03c1_water \u00d7 W_air \/ (W_air \u2212 W_water) = 1000 \u00d7 8.00 \/ 2.00 = 4000 kg\/m\u00b3.\nStep 3: In oil, F_b = 8.00 \u2212 6.40 = 1.60 N, so \u03c1_oil = \u03c1_water \u00d7 (1.60 \/ 2.00) = 800 kg\/m\u00b3.\n<strong>Answer: Object density = 4000 kg\/m\u00b3; oil density = 800 kg\/m\u00b3<\/strong>\n\n<\/div><\/details><\/div>\n<h2>Frequently Asked Questions<\/h2>\n<details class=\"pf-faq-item\"><summary>What is Archimedes&#039; principle in simple terms?<\/summary><div class=\"pf-faq-item-answer\">\n\nArchimedes&#8217; principle says that any object in a fluid is pushed up by a force equal to the weight of the fluid it pushes out of the way. If that upward push is at least as large as the object&#8217;s weight, it floats; if not, it sinks. The principle works in liquids and in gases.\n\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>What is the formula for buoyant force?<\/summary><div class=\"pf-faq-item-answer\">\n\nThe buoyant force is F_b = \u03c1Vg, where \u03c1 is the fluid&#8217;s density in kg\/m\u00b3, V is the volume of fluid displaced in m\u00b3, and g is gravity (about 9.81 m\/s\u00b2). The result is in newtons. Note that \u03c1 is the density of the fluid, not the object.\n\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>Why do heavy ships float but a small nail sinks?<\/summary><div class=\"pf-faq-item-answer\">\n\nFloating depends on average density, not raw weight. A ship is mostly hollow, so its hull plus the air inside has an average density below water, and it floats. A solid nail has no trapped air, so its density stays well above water and it sinks.\n\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>Does the buoyant force depend on depth?<\/summary><div class=\"pf-faq-item-answer\">\n\nFor a rigid object in an incompressible fluid such as water, no \u2014 the buoyant force is the same near the surface as it is deep down. Pressure rises with depth on both the top and bottom of the object, but the difference between them stays constant, so F_b = \u03c1Vg does not change. Compressible objects, like gas bubbles, are the exception.\n\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>How much of an iceberg is underwater?<\/summary><div class=\"pf-faq-item-answer\">\n\nAbout 89.5% of an iceberg sits below the surface, leaving only around 10.5% visible. The figure comes from the density ratio: ice (917 kg\/m\u00b3) divided by seawater (1025 kg\/m\u00b3) gives roughly 0.895, the submerged fraction.\n\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>Is buoyancy the same in air as in water?<\/summary><div class=\"pf-faq-item-answer\">\n\nThe principle is identical, but the size of the force differs hugely. Air is about 800 times less dense than water, so it provides a far smaller buoyant force for the same displaced volume. That is why buoyancy is obvious in water yet noticeable in air only for very light objects like balloons.\n\n<\/div><\/details>\n<details class=\"pf-faq-item\"><summary>How did Archimedes use his principle on the king&#039;s crown?<\/summary><div class=\"pf-faq-item-answer\">\n\nThe story goes that Archimedes needed to check whether a crown was pure gold without melting it. By comparing the crown&#8217;s weight in air with its apparent weight in water, he could find its volume and therefore its density. A density below gold&#8217;s would reveal that cheaper metal had been mixed in.\n\n<\/div><\/details>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Archimedes&#8217; principle says an object in a fluid feels an upward buoyant force equal to the weight of the fluid it displaces. Here&#8217;s the Fb = \u03c1Vg formula, clear examples, worked problems and an interactive lab.<\/p>\n","protected":false},"author":1,"featured_media":348,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2],"tags":[190,191,192,186,193,166],"class_list":["post-346","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mechanics","tag-archimedes-principle","tag-buoyancy","tag-buoyant-force","tag-density","tag-floatation","tag-fluid-mechanics"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/346","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=346"}],"version-history":[{"count":2,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/346\/revisions"}],"predecessor-version":[{"id":350,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/346\/revisions\/350"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/348"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=346"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=346"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=346"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}