{"id":230,"date":"2026-06-14T23:07:12","date_gmt":"2026-06-14T23:07:12","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=230"},"modified":"2026-06-14T23:07:13","modified_gmt":"2026-06-14T23:07:13","slug":"distance-vs-displacement","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/kinematics\/distance-vs-displacement\/","title":{"rendered":"Distance vs Displacement Explained"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\nDistance vs displacement is the difference between the total path length an object travels and its straight-line change in position. Distance is a scalar measured in metres with size only; displacement is a vector with both size and direction. Distance is always positive, while displacement can be zero or negative.\n<\/p><\/div>\n\n<p>Picture walking the dog around the block and arriving back at your own front door. Your fitness tracker proudly reports 800 metres \u2014 yet you are standing exactly where you began. So how far did you really travel?<\/p>\n\n<p>That gap between the ground you cover and where you end up is the whole story of distance versus displacement. It sounds like hair-splitting. But mix the two up in an exam, or in a navigation system, and the numbers quietly fall apart. Let&#8217;s make the difference stick.<\/p>\n\n<h2>What Is the Difference Between Distance and Displacement?<\/h2>\n\n<p>Start with the everyday picture. <strong>Distance<\/strong> is how much ground you cover \u2014 every step and every twist of the route, added up. <strong>Displacement<\/strong> is narrower: how far you finish from where you started, and in which direction.<\/p>\n\n<p>A satnav quietly tracks both. The &#8220;route&#8221; figure that ticks upward as you weave through streets is distance. The &#8220;as the crow flies&#8221; arrow pointing straight from home to destination is displacement.<\/p>\n\n<h3>Distance: the ground you cover<\/h3>\n\n<p>Distance is a <strong>scalar<\/strong> quantity, which means it has size only \u2014 no direction attached. Walk 3 m in a straight line or 3 m in a tight spiral, and either way you have covered a distance of 3 m.<\/p>\n\n<p>Because it only ever adds up, distance can never shrink and never goes negative. The SI unit is the <a href=\"https:\/\/www.nist.gov\/si-redefinition\/meter\" target=\"_blank\" rel=\"noopener\">metre (m)<\/a>, the internationally standardised unit of length.<\/p>\n\n<h3>Displacement: where you end up<\/h3>\n\n<p>Displacement is a <strong>vector<\/strong>. It carries both a size and a direction, written as something like &#8220;5 m east&#8221; or &#8220;\u22124 m along the x-axis&#8221;. Reverse your direction and the displacement can fall \u2014 even back to zero.<\/p>\n\n<p>Formally, displacement is the change in position: your final position minus your starting position. Standard university courses classify <a href=\"https:\/\/phys.libretexts.org\/Courses\/Georgia_State_University\/GSU-TM-Physics_I_(2211)\/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools\/1.08%3A_Vectors\/1.8.03%3A_Scalars_and_Vectors\" target=\"_blank\" rel=\"noopener\">displacement as a vector quantity<\/a>, separate from the scalar distance, precisely because direction is built in.<\/p>\n\n<h2>The Displacement Formula<\/h2>\n\n<p>In one dimension, displacement is simply the change in position \u2014 where you end minus where you began.<\/p>\n\n<div class=\"pf-formula\">\u0394s = s_final \u2212 s_initial<\/div>\n\n<ul>\n<li><strong>\u0394s<\/strong> \u2014 displacement, the change in position, measured in metres (m). The symbol \u0394 (&#8220;delta&#8221;) means &#8220;change in&#8221;.<\/li>\n<li><strong>s_final<\/strong> \u2014 the final position along the line, in metres (m).<\/li>\n<li><strong>s_initial<\/strong> \u2014 the starting position along the line, in metres (m).<\/li>\n<\/ul>\n\n<p>The sign of \u0394s tells you the direction. Pick a positive direction first \u2014 say, east or &#8220;right&#8221; \u2014 and a result like \u22124 m simply means 4 m the other way.<\/p>\n\n<h3>Displacement in two dimensions<\/h3>\n\n<p>When motion turns a corner, displacement is the straight line joining start to finish. For a right-angled route, its size comes from Pythagoras&#8217; theorem.<\/p>\n\n<div class=\"pf-formula\">|s| = \u221a(\u0394x\u00b2 + \u0394y\u00b2)<\/div>\n\n<ul>\n<li><strong>|s|<\/strong> \u2014 the magnitude (size) of the displacement, in metres (m).<\/li>\n<li><strong>\u0394x<\/strong> \u2014 the horizontal change in position, in metres (m).<\/li>\n<li><strong>\u0394y<\/strong> \u2014 the vertical change in position, in metres (m).<\/li>\n<\/ul>\n\n<p>Distance, by contrast, has no formula to memorise. You simply add up the length of every segment of the actual path.<\/p>\n\n<svg role=\"img\" aria-label=\"Diagram showing a person walking 3 metres east then 4 metres north: the distance walked is 7 metres along the path, while the displacement is a straight 5-metre line from start to finish.\" viewBox=\"0 0 640 450\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:640px;display:block;margin:0 auto;background:#F5F2EA;border-radius:8px;\">\n  <defs>\n    <marker id=\"ddWine\" markerWidth=\"14\" markerHeight=\"14\" refX=\"12\" refY=\"7\" orient=\"auto\" markerUnits=\"userSpaceOnUse\"><path d=\"M0,0 L14,7 L0,14 Z\" fill=\"#7A1F2B\"\/><\/marker>\n    <marker id=\"ddGold\" markerWidth=\"16\" markerHeight=\"16\" refX=\"13\" refY=\"8\" orient=\"auto\" markerUnits=\"userSpaceOnUse\"><path d=\"M0,0 L16,8 L0,16 Z\" fill=\"#C8932A\"\/><\/marker>\n  <\/defs>\n  <text x=\"320\" y=\"38\" text-anchor=\"middle\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"20\" font-weight=\"bold\" fill=\"#0A1628\">Walk 3 m east, then 4 m north<\/text>\n  <path d=\"M276 350 L276 336 L290 336\" fill=\"none\" stroke=\"#142139\" stroke-width=\"2\"\/>\n  <line x1=\"140\" y1=\"350\" x2=\"284\" y2=\"350\" stroke=\"#7A1F2B\" stroke-width=\"6\" marker-end=\"url(#ddWine)\"\/>\n  <line x1=\"290\" y1=\"350\" x2=\"290\" y2=\"160\" stroke=\"#7A1F2B\" stroke-width=\"6\" marker-end=\"url(#ddWine)\"\/>\n  <line x1=\"140\" y1=\"350\" x2=\"285\" y2=\"157\" stroke=\"#C8932A\" stroke-width=\"6\" marker-end=\"url(#ddGold)\"\/>\n  <circle cx=\"140\" cy=\"350\" r=\"5\" fill=\"#0A1628\"\/>\n  <circle cx=\"290\" cy=\"150\" r=\"5\" fill=\"#0A1628\"\/>\n  <text x=\"132\" y=\"372\" text-anchor=\"end\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"14\" fill=\"#0A1628\">Start<\/text>\n  <text x=\"300\" y=\"146\" text-anchor=\"start\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"14\" fill=\"#0A1628\">End<\/text>\n  <text x=\"212\" y=\"374\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"15\" font-weight=\"bold\" fill=\"#7A1F2B\">3 m<\/text>\n  <text x=\"305\" y=\"258\" text-anchor=\"start\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"15\" font-weight=\"bold\" fill=\"#7A1F2B\">4 m<\/text>\n  <text x=\"192\" y=\"238\" text-anchor=\"end\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"15\" font-weight=\"bold\" fill=\"#C8932A\">5 m<\/text>\n  <line x1=\"150\" y1=\"410\" x2=\"184\" y2=\"410\" stroke=\"#7A1F2B\" stroke-width=\"6\"\/>\n  <text x=\"192\" y=\"415\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"14\" fill=\"#0A1628\">Distance (path walked) = 3 + 4 = 7 m<\/text>\n  <line x1=\"150\" y1=\"434\" x2=\"184\" y2=\"434\" stroke=\"#C8932A\" stroke-width=\"6\"\/>\n  <text x=\"192\" y=\"439\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"14\" fill=\"#0A1628\">Displacement = 5 m (\u2248 53\u00b0 N of E)<\/text>\n<\/svg>\n<p style=\"text-align:center;font-style:italic;color:#1F2E47;font-size:14px;margin-top:8px;\">The route covers a distance of 7 m, but the displacement is the straight 5 m line from start to end \u2014 found with Pythagoras&#8217; theorem.<\/p>\n\n<h2>How Distance and Displacement Work<\/h2>\n\n<p>The mechanism is easiest to feel with a single trip broken into steps. Keep two running totals as you move: one that only ever grows (distance) and one that tracks where you are relative to the start (displacement).<\/p>\n\n<p>Imagine a number line and a marker that starts at 0.<\/p>\n\n<ul>\n<li>Step right to +6 m. Distance so far: 6 m. Displacement: +6 m.<\/li>\n<li>Now step left to \u22122 m. You walked another 8 m, so distance is 14 m. But your position is \u22122 m, so displacement is \u22122 m.<\/li>\n<\/ul>\n\n<p>Notice the split. Distance counted both legs and climbed to 14 m. Displacement only cares about your final position, which sits 2 m to the left of the start.<\/p>\n\n<h3>Why a round trip gives zero displacement<\/h3>\n\n<p>Return to your exact starting point and the final position equals the initial position, so \u0394s = 0. The distance, meanwhile, is the full length you walked. That is why one complete lap of a track is the classic case.<\/p>\n\n<svg role=\"img\" aria-label=\"Diagram of a 400-metre oval running track showing that one complete lap gives a distance of 400 metres but a displacement of zero, because the runner finishes exactly where they started.\" viewBox=\"0 0 640 380\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;max-width:560px;display:block;margin:0 auto;background:#F5F2EA;border-radius:8px;\">\n  <defs>\n    <marker id=\"ddTrack\" markerWidth=\"13\" markerHeight=\"13\" refX=\"10\" refY=\"6.5\" orient=\"auto\" markerUnits=\"userSpaceOnUse\"><path d=\"M0,0 L13,6.5 L0,13 Z\" fill=\"#C8932A\"\/><\/marker>\n  <\/defs>\n  <text x=\"320\" y=\"38\" text-anchor=\"middle\" font-family=\"Georgia, 'Times New Roman', serif\" font-size=\"20\" font-weight=\"bold\" fill=\"#0A1628\">One full lap of a 400 m track<\/text>\n  <rect x=\"120\" y=\"90\" width=\"400\" height=\"170\" rx=\"85\" ry=\"85\" fill=\"none\" stroke=\"#142139\" stroke-width=\"18\"\/>\n  <line x1=\"268\" y1=\"99\" x2=\"330\" y2=\"99\" stroke=\"#C8932A\" stroke-width=\"5\" marker-end=\"url(#ddTrack)\"\/>\n  <line x1=\"320\" y1=\"234\" x2=\"320\" y2=\"268\" stroke=\"#C8932A\" stroke-width=\"5\" stroke-dasharray=\"6 4\"\/>\n  <circle cx=\"320\" cy=\"251\" r=\"7\" fill=\"#C8932A\" stroke=\"#0A1628\" stroke-width=\"2\"\/>\n  <text x=\"320\" y=\"292\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"14\" font-weight=\"bold\" fill=\"#7A1F2B\">Start \/ Finish<\/text>\n  <text x=\"320\" y=\"324\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"15\" fill=\"#0A1628\"><tspan fill=\"#7A1F2B\" font-weight=\"bold\">Distance<\/tspan> = 400 m (one full lap)<\/text>\n  <text x=\"320\" y=\"350\" text-anchor=\"middle\" font-family=\"Arial, Helvetica, sans-serif\" font-size=\"15\" fill=\"#0A1628\"><tspan fill=\"#C8932A\" font-weight=\"bold\">Displacement<\/tspan> = 0 m \u2014 you finish where you started<\/text>\n<\/svg>\n<p style=\"text-align:center;font-style:italic;color:#1F2E47;font-size:14px;margin-top:8px;\">A complete lap covers real distance, yet the displacement is zero because the finish point is the start point.<\/p>\n\n<p>Try it yourself. Adjust the legs of a journey below and watch the distance total climb while the displacement arrow stretches, shrinks, or vanishes back to zero.<\/p>\n\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Distance vs Displacement Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/distance-vs-displacement.html\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n\n<h2>Distance vs Displacement: Key Differences at a Glance<\/h2>\n\n<p>Five differences capture almost everything you need. Read across each row: it is the same journey, measured two ways.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr style=\"background:#142139;color:#FAF6EE;\">\n<th style=\"padding:10px 12px;text-align:left;border:1px solid #D9CFB8;\">Feature<\/th>\n<th style=\"padding:10px 12px;text-align:left;border:1px solid #D9CFB8;\">Distance<\/th>\n<th style=\"padding:10px 12px;text-align:left;border:1px solid #D9CFB8;\">Displacement<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\"><strong>Quantity type<\/strong><\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">Scalar \u2014 size only<\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">Vector \u2014 size and direction<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\"><strong>Direction<\/strong><\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">None<\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">Always specified (e.g. east, +x, 53\u00b0 N of E)<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\"><strong>Possible sign<\/strong><\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">Always positive (or zero)<\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">Positive, negative, or zero<\/td>\n<\/tr>\n<tr style=\"background:#F5F2EA;\">\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\"><strong>What it measures<\/strong><\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">Total length of the path actually taken<\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">Straight line from start to finish (change in position)<\/td>\n<\/tr>\n<tr>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\"><strong>SI unit &amp; symbol<\/strong><\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">metre (m); often <em>d<\/em> or <em>s<\/em><\/td>\n<td style=\"padding:10px 12px;border:1px solid #D9CFB8;\">metre (m); often <em>s<\/em> or \u0394x, shown bold or with an arrow<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>One relationship ties them together: the distance is always at least as large as the size of the displacement. They are equal only when the motion runs in a straight line and never doubles back.<\/p>\n\n<h2>Real-World Examples of Distance and Displacement<\/h2>\n\n<p>The cleanest way to lock this in is to watch the two quantities pull apart in ordinary situations.<\/p>\n\n<h3>1. Your morning commute<\/h3>\n\n<p>Your satnav says 12 km to the office, yet the office is only 8 km away &#8220;as the crow flies&#8221;. The 12 km is distance \u2014 every bend of the road counted in. The 8 km straight line is the magnitude of your displacement.<\/p>\n\n<figure style=\"margin:32px auto;max-width:640px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/06\/Distancedisplacement_VNn390U.png\"\n       alt=\"Winding mountain road showing how travel distance far exceeds the straight-line displacement between two points\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">A winding road adds distance with every bend, while the displacement stays the straight line between its two ends.<\/figcaption>\n<\/figure>\n\n<h3>2. One lap of the track<\/h3>\n\n<p>A 400 m runner who completes a full lap finishes on the same line they started. Distance covered: 400 m. Displacement: 0 m. Every metre of effort, zero net change in position.<\/p>\n\n<h3>3. A ball thrown straight up<\/h3>\n\n<p>Toss a ball 5 m up and catch it in the same hand. It travelled 10 m \u2014 5 m up, then 5 m down \u2014 so the distance is 10 m. It came back to your hand, so the displacement is 0 m.<\/p>\n\n<h3>4. A flight around bad weather<\/h3>\n\n<p>A plane diverting around a storm flies extra kilometres, and every one of them adds to the distance. The displacement \u2014 the straight line between the departure and arrival airports \u2014 does not change at all. Only the path did.<\/p>\n\n<h2>Common Misconceptions About Distance and Displacement<\/h2>\n\n<p>A handful of sticky errors trip up most learners. Clear these and the rest of kinematics gets noticeably easier.<\/p>\n\n<h3>&#8220;They&#8217;re just two words for the same thing&#8221;<\/h3>\n\n<p>They share a unit (the metre) and often share a value, which is exactly what fuels the confusion. But one is a scalar and one is a vector. A common student slip is to report displacement as a bare number and forget the direction \u2014 quietly losing half the answer.<\/p>\n\n<h3>&#8220;Displacement can&#8217;t be negative&#8221;<\/h3>\n\n<p>It can, and the minus sign is information, not a mistake. Once you pick a positive direction, a displacement of \u22124 m means 4 m in the opposite direction. Distance, though, is never negative.<\/p>\n\n<h3>&#8220;Bigger distance always means bigger displacement&#8221;<\/h3>\n\n<p>Not so. You can walk a huge distance and end with zero displacement \u2014 just complete any loop. Distance grows with every step; displacement depends only on the start and finish.<\/p>\n\n<h3>&#8220;Displacement is the shortest distance, so it&#8217;s a kind of distance&#8221;<\/h3>\n\n<p>The magnitude of displacement does equal the shortest straight-line length between two points. But displacement also carries direction, which distance never does. Treating it as &#8220;just a distance&#8221; is what derails people in vector questions.<\/p>\n\n<h2>How Distance and Displacement Relate to Speed and Velocity<\/h2>\n\n<p>Here is where the distinction earns its keep. Divide each one by time and you get the next pair of physics quantities.<\/p>\n\n<ul>\n<li><strong>Speed<\/strong> = distance \u00f7 time. A scalar, because distance is a scalar.<\/li>\n<li><strong>Velocity<\/strong> = displacement \u00f7 time. A vector, because displacement is a vector.<\/li>\n<\/ul>\n\n<p>So the same scalar-versus-vector split runs straight up the chain. If you are comfortable telling distance from displacement, you already understand the difference between <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/kinematics\/velocity-vs-speed\/\">speed and velocity<\/a>.<\/p>\n\n<p>The idea also explains motion in two dimensions. When a <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/projectile-motion-guide\/\">projectile arcs through the air<\/a>, its displacement splits into independent horizontal and vertical parts \u2014 exactly the \u0394x and \u0394y from the formula above.<\/p>\n\n<h2>Worked Problems<\/h2>\n\n<p>Work through these in order \u2014 each one adds a twist. Keep a positive direction in mind and carry your units the whole way through.<\/p>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">A student walks 10 m due east in a straight line. What is the distance travelled and the displacement?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>Step 1:<\/strong> The path is a single straight segment with no change of direction.<\/p>\n<p><strong>Step 2:<\/strong> Distance = total path length = 10 m.<\/p>\n<p><strong>Step 3:<\/strong> Displacement = change in position = 10 m, directed east.<\/p>\n<p><strong>Answer: distance = 10 m; displacement = 10 m east.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A runner jogs 8 m east, then turns around and jogs 3 m west. Find the total distance and the displacement.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>Step 1:<\/strong> Distance adds every segment, regardless of direction: 8 m + 3 m.<\/p>\n<p><strong>Step 2:<\/strong> Total distance = 11 m.<\/p>\n<p><strong>Step 3:<\/strong> Take east as positive. Displacement = (+8 m) + (\u22123 m) = +5 m.<\/p>\n<p><strong>Answer: distance = 11 m; displacement = 5 m east.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">An athlete runs exactly one full lap of a 400 m running track, finishing on the start line. What distance and displacement result?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>Step 1:<\/strong> Distance is the length of the path run \u2014 one complete lap.<\/p>\n<p><strong>Step 2:<\/strong> Distance = 400 m.<\/p>\n<p><strong>Step 3:<\/strong> The final position equals the starting position, so \u0394s = 0.<\/p>\n<p><strong>Answer: distance = 400 m; displacement = 0 m.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">A trolley moves +6 m along the x-axis, then \u221210 m back along the same axis. Calculate the distance and the displacement.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>Step 1:<\/strong> Distance ignores direction: 6 m + 10 m.<\/p>\n<p><strong>Step 2:<\/strong> Total distance = 16 m.<\/p>\n<p><strong>Step 3:<\/strong> Displacement = (+6 m) + (\u221210 m) = \u22124 m.<\/p>\n<p><strong>Answer: distance = 16 m; displacement = \u22124 m (4 m in the negative x-direction).<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">A hiker walks 30 m due east, then 40 m due north. Find the distance walked and the magnitude and direction of the displacement.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>Step 1:<\/strong> Distance = sum of the two legs = 30 m + 40 m = 70 m.<\/p>\n<p><strong>Step 2:<\/strong> Displacement magnitude uses Pythagoras: |s| = \u221a(30\u00b2 + 40\u00b2) = \u221a(900 + 1600) = \u221a2500.<\/p>\n<p><strong>Step 3:<\/strong> |s| = 50 m. Direction: \u03b8 = tan\u207b\u00b9(40 \u00f7 30) \u2248 53\u00b0 north of east.<\/p>\n<p><strong>Answer: distance = 70 m; displacement = 50 m at \u224853\u00b0 north of east.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">A car drives halfway around a circular track of radius 50 m, ending diametrically opposite its start. Find the distance and the displacement. (Use \u03c0 \u2248 3.14.)<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>Step 1:<\/strong> Distance is the arc length of a semicircle: half of 2\u03c0r, which is \u03c0r.<\/p>\n<p><strong>Step 2:<\/strong> Distance = \u03c0 \u00d7 50 m \u2248 3.14 \u00d7 50 = 157 m.<\/p>\n<p><strong>Step 3:<\/strong> Displacement is the straight line across \u2014 the diameter = 2r = 2 \u00d7 50 m = 100 m, directed across the circle.<\/p>\n<p><strong>Answer: distance \u2248 157 m; displacement = 100 m.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">Using the hiker from Problem 5 (70 m of path, 50 m displacement at 53\u00b0 N of E), the walk takes 50 s. Find the average speed and the average velocity.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>Step 1:<\/strong> Average speed = distance \u00f7 time = 70 m \u00f7 50 s.<\/p>\n<p><strong>Step 2:<\/strong> Average speed = 1.4 m\/s (a scalar \u2014 no direction).<\/p>\n<p><strong>Step 3:<\/strong> Average velocity = displacement \u00f7 time = 50 m \u00f7 50 s = 1.0 m\/s, directed 53\u00b0 north of east.<\/p>\n<p><strong>Answer: average speed = 1.4 m\/s; average velocity = 1.0 m\/s at \u224853\u00b0 north of east.<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<h2>Frequently Asked Questions<\/h2>\n\n<details class=\"pf-faq-item\"><summary>What is the difference between distance and displacement in simple terms?<\/summary><div class=\"pf-faq-item-answer\">\nDistance is how much ground you cover; displacement is how far and in which direction you end up from the start. Distance is a scalar (size only) and is always positive. Displacement is a vector (size plus direction) and can be positive, negative, or zero. They share the same unit, the metre.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Is distance always greater than displacement?<\/summary><div class=\"pf-faq-item-answer\">\nDistance is always greater than or equal to the magnitude of displacement \u2014 never smaller. The two are equal only when the motion is in a straight line without reversing direction. The moment the path bends or doubles back, the distance becomes larger than the straight-line displacement.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Can displacement be negative or zero?<\/summary><div class=\"pf-faq-item-answer\">\nYes. Displacement is negative when the final position lies on the negative side of your chosen positive direction, and zero whenever you return to your starting point. A full lap or an out-and-back trip both give zero displacement. Distance, by contrast, can never be negative.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Are distance and displacement measured in the same units?<\/summary><div class=\"pf-faq-item-answer\">\nYes, both are measured in metres (m) in the SI system, because both describe a length. The difference between them is not the unit but the type of quantity: distance is a scalar with size only, while displacement is a vector that also specifies a direction.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>How are distance and displacement related to speed and velocity?<\/summary><div class=\"pf-faq-item-answer\">\nSpeed is distance divided by time, and velocity is displacement divided by time. Because distance is a scalar, speed is a scalar; because displacement is a vector, velocity is a vector. The same size-only versus size-and-direction split carries straight through from position to rate of motion.\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Why can a long journey have zero displacement?<\/summary><div class=\"pf-faq-item-answer\">\nDisplacement depends only on your start and finish points, not the route between them. If you return to exactly where you began, your final and initial positions match, so the displacement is zero \u2014 no matter how many kilometres you walked. The distance still counts every metre of the path.\n<\/div><\/details>\n","protected":false},"excerpt":{"rendered":"<p>Distance vs displacement explained simply: distance is the total path you cover, while displacement is your straight-line change in position. Includes the formula, a comparison table, worked problems and FAQs.<\/p>\n","protected":false},"author":1,"featured_media":233,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[7],"tags":[100,103,102,43,101],"class_list":["post-230","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kinematics","tag-displacement-formula","tag-distance-and-displacement-examples","tag-distance-vs-displacement","tag-kinematics","tag-scalars-and-vectors"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/230","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=230"}],"version-history":[{"count":1,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/230\/revisions"}],"predecessor-version":[{"id":234,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/230\/revisions\/234"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/233"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=230"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=230"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=230"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}