{"id":215,"date":"2026-06-11T23:17:30","date_gmt":"2026-06-11T23:17:30","guid":{"rendered":"https:\/\/physicsfundamentalsinfo.com\/blog\/?p=215"},"modified":"2026-06-11T23:17:31","modified_gmt":"2026-06-11T23:17:31","slug":"ohms-law","status":"publish","type":"post","link":"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/ohms-law\/","title":{"rendered":"What Is Ohm&#8217;s Law?"},"content":{"rendered":"\n<div class=\"pf-citation\"><div class=\"eyebrow\">Definition<\/div><p>\n<p>Ohm&#8217;s law states that the electric current through a conductor is directly proportional to the voltage across it, provided temperature and other physical conditions stay constant. Written as V = IR, it links voltage (volts), current (amperes) and resistance (ohms): voltage equals current multiplied by resistance. It is the foundation of almost all circuit analysis.<\/p>\n<\/p><\/div>\n\n<p>Flick a dimmer switch and a lamp fades; turn it back and the room brightens. Nothing about the bulb changed \u2014 you changed the circuit, and the current obediently followed. That obedience has a name.<\/p>\n\n<p>Every charger, kettle, fuse and phone in your house is designed around one tidy relationship between voltage, current and resistance. Get comfortable with it and circuits stop being mysterious. That relationship is Ohm&#8217;s law.<\/p>\n\n<h2>What Is Ohm&#8217;s Law?<\/h2>\n\n<p>Picture water in a pipe. Pressure pushes the water along, the pipe&#8217;s narrowness fights back, and the flow rate is the result of that tug-of-war. Electricity behaves the same way: voltage is the push, resistance is the fight, and current is the flow you actually get.<\/p>\n\n<p>Ohm&#8217;s law makes that picture precise. For many conductors held at a steady temperature, the current <em>I<\/em> is directly proportional to the potential difference <em>V<\/em> across them. Double the voltage and the current doubles; halve it and the current halves.<\/p>\n\n<p>The constant linking them is the resistance <em>R<\/em> \u2014 a measure of how strongly the material opposes the flow of charge. A short, fat copper wire barely resists at all. A long, thin nichrome wire resists fiercely, which is exactly why heaters are made from it.<\/p>\n\n<p>The law is named after Georg Simon Ohm, a German physicist who was teaching school in Cologne when he published his careful wire experiments in 1827. His reward, eventually, was the SI unit of resistance \u2014 the ohm (\u03a9) \u2014 carrying his name.<\/p>\n\n<figure style=\"margin:32px auto;max-width:600px;text-align:center;\">\n  <img decoding=\"async\" src=\"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-content\/uploads\/2026\/06\/Georg_Simon_Ohm_1789-1854.jpg\"\n       alt=\"Georg Simon Ohm, the German physicist who discovered Ohm's law in 1827\"\n       loading=\"lazy\"\n       style=\"width:100%;height:auto;border-radius:4px;\" \/>\n  <figcaption style=\"font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">Georg Simon Ohm (1789\u20131854), whose 1827 wire experiments revealed the law that now bears his name.<\/figcaption>\n<\/figure>\n\n<p>One honest caveat before the maths. Ohm&#8217;s law is an <strong>empirical relation<\/strong> \u2014 a pattern found by experiment \u2014 not a fundamental law of nature like conservation of energy. Plenty of materials obey it beautifully; some important ones don&#8217;t, and we will meet them below.<\/p>\n\n<h2>The Ohm&#8217;s Law Formula: V = IR<\/h2>\n\n<p>Here it is \u2014 three letters that run the electrical world.<\/p>\n\n<div class=\"pf-formula\">V = I \u00d7 R<\/div>\n\n<ul>\n<li><strong>V<\/strong> \u2014 potential difference (voltage) across the component, measured in volts (V)<\/li>\n<li><strong>I<\/strong> \u2014 electric current through the component, measured in amperes (A)<\/li>\n<li><strong>R<\/strong> \u2014 resistance of the component, measured in ohms (\u03a9)<\/li>\n<\/ul>\n\n<p>The units lock together neatly: one ohm is defined as one volt per ampere (1 \u03a9 = 1 V\/A). If a component lets 1 A flow when 1 V is applied, its resistance is exactly 1 \u03a9.<\/p>\n\n<p>Because the formula has three quantities, you can rearrange it to find whichever one you&#8217;re missing. The table below is the version worth memorising.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">To find<\/th>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">Formula<\/th>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">You need to know<\/th>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">Units check<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Voltage, V<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\"><strong>V = I \u00d7 R<\/strong><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">current and resistance<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">A \u00d7 \u03a9 = V<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Current, I<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\"><strong>I = V \u00f7 R<\/strong><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">voltage and resistance<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">V \u00f7 \u03a9 = A<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Resistance, R<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\"><strong>R = V \u00f7 I<\/strong><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">voltage and current<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">V \u00f7 A = \u03a9<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>Struggling to remember which way round it goes? Use the classic Ohm&#8217;s law triangle. Cover the quantity you want with a finger, and the layout of the other two tells you the formula.<\/p>\n\n<div style=\"max-width:420px;margin:32px auto;\">\n<svg viewBox=\"0 0 420 380\" role=\"img\" aria-label=\"Ohm's law triangle with V on top and I and R on the bottom row, used to rearrange V equals I times R\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;display:block;\">\n<rect x=\"1.5\" y=\"1.5\" width=\"417\" height=\"377\" rx=\"8\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"3\"><\/rect>\n<polygon points=\"210,42 368,300 52,300\" fill=\"#142139\" stroke=\"#C8932A\" stroke-width=\"3\" stroke-linejoin=\"round\"><\/polygon>\n<line x1=\"131\" y1=\"171\" x2=\"289\" y2=\"171\" stroke=\"#C8932A\" stroke-width=\"2.5\"><\/line>\n<line x1=\"210\" y1=\"171\" x2=\"210\" y2=\"300\" stroke=\"#C8932A\" stroke-width=\"2.5\"><\/line>\n<text x=\"210\" y=\"140\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"62\" font-weight=\"800\" font-style=\"italic\" fill=\"#FAF6EE\" text-anchor=\"middle\">V<\/text>\n<text x=\"168\" y=\"262\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"54\" font-weight=\"800\" font-style=\"italic\" fill=\"#FAF6EE\" text-anchor=\"middle\">I<\/text>\n<text x=\"254\" y=\"262\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"54\" font-weight=\"800\" font-style=\"italic\" fill=\"#FAF6EE\" text-anchor=\"middle\">R<\/text>\n<text x=\"110\" y=\"348\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"600\" fill=\"#0A1628\" text-anchor=\"middle\">V = I \u00d7 R<\/text>\n<text x=\"210\" y=\"348\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"600\" fill=\"#0A1628\" text-anchor=\"middle\">I = V \u00f7 R<\/text>\n<text x=\"310\" y=\"348\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"17\" font-weight=\"600\" fill=\"#0A1628\" text-anchor=\"middle\">R = V \u00f7 I<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">The Ohm&#8217;s law triangle: cover the quantity you want, and the remaining layout gives the formula.<\/p>\n<\/div>\n\n<p>In a circuit diagram, the three quantities each have their own instrument. The ammeter sits <strong>in series<\/strong> (in the line of flow) to read current; the voltmeter sits <strong>in parallel<\/strong> (across the component) to read potential difference.<\/p>\n\n<div style=\"max-width:700px;margin:32px auto;\">\n<svg viewBox=\"0 0 700 340\" role=\"img\" aria-label=\"Simple series circuit: a battery drives current I through a resistor R, with an ammeter in series and a voltmeter connected across the resistor\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;display:block;\">\n<rect x=\"1.5\" y=\"1.5\" width=\"697\" height=\"337\" rx=\"8\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"3\"><\/rect>\n<path d=\"M120,90 H326 M374,90 H580 M580,90 V150 M580,214 V290 M580,290 H120 M120,290 V200 M120,172 V90\" fill=\"none\" stroke=\"#0A1628\" stroke-width=\"3\" stroke-linecap=\"round\"><\/path>\n<line x1=\"96\" y1=\"176\" x2=\"144\" y2=\"176\" stroke=\"#0A1628\" stroke-width=\"4\"><\/line>\n<line x1=\"108\" y1=\"196\" x2=\"132\" y2=\"196\" stroke=\"#0A1628\" stroke-width=\"8\"><\/line>\n<text x=\"86\" y=\"182\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"18\" font-weight=\"700\" fill=\"#0A1628\" text-anchor=\"end\">+<\/text>\n<text x=\"86\" y=\"203\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"18\" font-weight=\"700\" fill=\"#0A1628\" text-anchor=\"end\">\u2212<\/text>\n<text x=\"20\" y=\"186\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-weight=\"600\" fill=\"#7A1F2B\">battery<\/text>\n<path d=\"M580,150 L564,158 L596,166 L564,174 L596,182 L564,190 L596,198 L564,206 L580,214\" fill=\"none\" stroke=\"#C8932A\" stroke-width=\"4\" stroke-linejoin=\"round\" stroke-linecap=\"round\"><\/path>\n<text x=\"544\" y=\"190\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"22\" font-weight=\"800\" font-style=\"italic\" fill=\"#0A1628\" text-anchor=\"end\">R<\/text>\n<circle cx=\"350\" cy=\"90\" r=\"24\" fill=\"#FAF6EE\" stroke=\"#0A1628\" stroke-width=\"3\"><\/circle>\n<text x=\"350\" y=\"97\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"20\" font-weight=\"800\" fill=\"#0A1628\" text-anchor=\"middle\">A<\/text>\n<path d=\"M580,150 H636 V158 M580,214 H636 V206\" fill=\"none\" stroke=\"#7A1F2B\" stroke-width=\"2.5\"><\/path>\n<circle cx=\"636\" cy=\"182\" r=\"24\" fill=\"#FAF6EE\" stroke=\"#7A1F2B\" stroke-width=\"3\"><\/circle>\n<text x=\"636\" y=\"189\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"20\" font-weight=\"800\" fill=\"#7A1F2B\" text-anchor=\"middle\">V<\/text>\n<polygon points=\"222,82 246,90 222,98\" fill=\"#C8932A\"><\/polygon>\n<text x=\"226\" y=\"72\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"20\" font-weight=\"800\" font-style=\"italic\" fill=\"#C8932A\">I<\/text>\n<polygon points=\"368,282 344,290 368,298\" fill=\"#C8932A\"><\/polygon>\n<text x=\"376\" y=\"284\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"20\" font-weight=\"800\" font-style=\"italic\" fill=\"#C8932A\">I<\/text>\n<text x=\"350\" y=\"324\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"13\" fill=\"#142139\" text-anchor=\"middle\">Ammeter in series reads I \u00b7 voltmeter across R reads V<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">Measuring Ohm&#8217;s law: a battery drives current I through resistor R; the ammeter reads I and the voltmeter reads V across R.<\/p>\n<\/div>\n\n<h2>How Ohm&#8217;s Law Works Inside a Wire<\/h2>\n\n<p>Why should current be proportional to voltage at all? The answer lives at the scale of atoms.<\/p>\n\n<p>A metal is a lattice of fixed positive ions bathed in a sea of free electrons. Apply a voltage and you set up an electric field along the wire \u2014 the same kind of electrical push described by <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/electromagnetism\/coulombs-law\/\">Coulomb&#8217;s law<\/a> \u2014 which drags those electrons along.<\/p>\n\n<p>But they don&#8217;t get far between collisions. Each electron accelerates briefly, smacks into a vibrating ion, loses its gained speed, and starts again \u2014 a kind of electrical <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/what-is-friction\/\">friction<\/a>. The net result is a slow average drift superimposed on frantic random motion.<\/p>\n\n<p>Here&#8217;s the key: that drift velocity turns out to be proportional to the field strength. Double the push, double the drift, double the current. Proportionality between V and I \u2014 Ohm&#8217;s law \u2014 drops straight out of the microscopic picture.<\/p>\n\n<p>Physicists write this microscopic version as:<\/p>\n\n<div class=\"pf-formula\">J = \u03c3E<\/div>\n\n<ul>\n<li><strong>J<\/strong> \u2014 current density (current per unit cross-section), in amperes per square metre (A\/m\u00b2)<\/li>\n<li><strong>\u03c3<\/strong> \u2014 electrical conductivity of the material, in siemens per metre (S\/m)<\/li>\n<li><strong>E<\/strong> \u2014 electric field strength inside the conductor, in volts per metre (V\/m)<\/li>\n<\/ul>\n\n<p>And a fact that surprises almost everyone: the drift itself is glacial \u2014 typically well under a millimetre per second in household wiring. The light comes on instantly because the electric field propagates along the wire at close to the speed of light, setting every electron in the loop moving at almost the same moment.<\/p>\n\n<p>Temperature is the catch in all this. Heat a metal and its ions vibrate harder, collisions become more frequent, and resistance climbs \u2014 for copper, by roughly 0.4% per degree Celsius. That is why the law&#8217;s small print says &#8220;at constant temperature&#8221;.<\/p>\n\n<p>Don&#8217;t just take the equation&#8217;s word for it. Drag the sliders below and watch the current respond: double the voltage, halve the resistance, and see I = V\/R play out live.<\/p>\n\n<div class=\"pf-sim-slot\"><div class=\"pf-sim-slot-header\"><span class=\"icon-dot\"><\/span><span class=\"label\">Ohm&#039;s Law Lab<\/span><\/div><div class=\"pf-sim-slot-body\"><style>.pf-sim-frame{width:100%;border:none;height:600px}@media(max-width:760px){.pf-sim-frame{height:1000px}}<\/style><iframe src=\"\/labs\/ohms-law.html\" class=\"pf-sim-frame\" loading=\"lazy\"><\/iframe><\/div><\/div>\n\n<h2>Ohmic vs Non-Ohmic: When Ohm&#8217;s Law Breaks Down<\/h2>\n\n<p>Plot current against voltage for a metal wire at steady temperature and you get the most reassuring graph in physics: a straight line through the origin. The gradient is constant, so the resistance is constant. That&#8217;s an <strong>ohmic<\/strong> conductor.<\/p>\n\n<p>Now try a filament lamp. As the current grows, the filament heats towards 2,500 \u00b0C and \u2014 as our guide to <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/thermodynamics\/heat-vs-temperature\/\">heat vs temperature<\/a> explains \u2014 those hotter, harder-vibrating ions scatter electrons more. Resistance rises with voltage, and the graph bends over.<\/p>\n\n<div style=\"max-width:700px;margin:32px auto;\">\n<svg viewBox=\"0 0 700 430\" role=\"img\" aria-label=\"Current versus voltage graph comparing an ohmic resistor, a straight line through the origin, with a filament lamp whose curve flattens as it heats up\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" style=\"width:100%;height:auto;display:block;\">\n<rect x=\"1.5\" y=\"1.5\" width=\"697\" height=\"427\" rx=\"8\" fill=\"#F5F2EA\" stroke=\"#D9CFB8\" stroke-width=\"3\"><\/rect>\n<path d=\"M200,90 V350 M310,90 V350 M420,90 V350 M530,90 V350 M90,280 H630 M90,210 H630 M90,140 H630\" stroke=\"#C5D0DC\" stroke-width=\"1\" fill=\"none\"><\/path>\n<path d=\"M90,70 V350 H650\" stroke=\"#0A1628\" stroke-width=\"3\" fill=\"none\"><\/path>\n<polygon points=\"84,78 90,62 96,78\" fill=\"#0A1628\"><\/polygon>\n<polygon points=\"642,344 658,350 642,356\" fill=\"#0A1628\"><\/polygon>\n<line x1=\"90\" y1=\"350\" x2=\"580\" y2=\"108\" stroke=\"#C8932A\" stroke-width=\"4\" stroke-linecap=\"round\"><\/line>\n<path d=\"M90,350 C150,248 205,205 320,185 C420,168 500,162 580,158\" fill=\"none\" stroke=\"#7A1F2B\" stroke-width=\"4\" stroke-linecap=\"round\"><\/path>\n<line x1=\"112\" y1=\"96\" x2=\"150\" y2=\"96\" stroke=\"#C8932A\" stroke-width=\"4\"><\/line>\n<text x=\"158\" y=\"101\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" fill=\"#0A1628\">Ohmic resistor \u2014 straight line, constant R<\/text>\n<line x1=\"112\" y1=\"124\" x2=\"150\" y2=\"124\" stroke=\"#7A1F2B\" stroke-width=\"4\"><\/line>\n<text x=\"158\" y=\"129\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"15\" fill=\"#0A1628\">Filament lamp \u2014 flattens as the filament heats<\/text>\n<text x=\"380\" y=\"248\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" font-style=\"italic\" fill=\"#142139\">gradient = 1 \/ R<\/text>\n<text x=\"370\" y=\"392\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"600\" fill=\"#0A1628\" text-anchor=\"middle\">Voltage V (volts)<\/text>\n<text x=\"38\" y=\"210\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"16\" font-weight=\"600\" fill=\"#0A1628\" text-anchor=\"middle\" transform=\"rotate(-90 38 210)\">Current I (amperes)<\/text>\n<text x=\"78\" y=\"370\" font-family=\"Manrope, Arial, sans-serif\" font-size=\"14\" fill=\"#0A1628\" text-anchor=\"middle\">0<\/text>\n<\/svg>\n<p style=\"text-align:center;font-size:13px;color:#1F2E47;font-style:italic;margin-top:8px;\">I\u2013V characteristics: an ohmic conductor gives a straight line through the origin; a filament lamp curves as its resistance rises with temperature.<\/p>\n<\/div>\n\n<p>Diodes are even less cooperative \u2014 they pass almost nothing until the voltage crosses a threshold, then conduct generously, and barely conduct at all in reverse. Devices like these are <strong>non-ohmic<\/strong>: V = IR still <em>defines<\/em> a resistance at any instant, but that R refuses to stay constant.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">Component<\/th>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">I\u2013V graph shape<\/th>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">Resistance behaviour<\/th>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">Obeys Ohm&#8217;s law?<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Metal wire at constant temperature<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Straight line through origin<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Constant<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\"><strong>Yes<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Fixed resistor (carbon or wire-wound)<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Straight line through origin<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Constant within its power rating<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\"><strong>Yes<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Filament lamp<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Curve that flattens<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Rises as the filament heats<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">No<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Semiconductor diode \/ LED<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Near zero, then a sharp rise (one direction only)<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Varies enormously with voltage and direction<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">No<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Thermistor (NTC)<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Curve that steepens<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Falls as it warms<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">No<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>At the extreme end sit superconductors: cool certain materials below a critical temperature and their resistance vanishes entirely. Current flows with no voltage needed to sustain it \u2014 a regime Ohm&#8217;s law simply wasn&#8217;t built for.<\/p>\n\n<h2>Resistance and Resistivity: What Actually Sets R<\/h2>\n\n<p>So what decides whether a component has 2 \u03a9 or 2 million? Three things: what it&#8217;s made of, how long it is, and how thick it is.<\/p>\n\n<div class=\"pf-formula\">R = \u03c1L \/ A<\/div>\n\n<ul>\n<li><strong>R<\/strong> \u2014 resistance, in ohms (\u03a9)<\/li>\n<li><strong>\u03c1<\/strong> (rho) \u2014 resistivity of the material, in ohm-metres (\u03a9\u00b7m)<\/li>\n<li><strong>L<\/strong> \u2014 length of the conductor, in metres (m)<\/li>\n<li><strong>A<\/strong> \u2014 cross-sectional area, in square metres (m\u00b2)<\/li>\n<\/ul>\n\n<p>The pipe analogy holds up perfectly here. A longer pipe resists flow more (L on top); a wider pipe resists less (A on the bottom). Resistivity \u03c1 is the material&#8217;s own personality \u2014 the property that makes copper a conductor and glass an insulator, regardless of shape.<\/p>\n\n<p>And the range of that personality is staggering. From silver to glass, resistivity spans more than twenty orders of magnitude \u2014 one of the widest ranges of any physical property.<\/p>\n\n<div class=\"pf-table-scroll\" style=\"display:block;width:100%;max-width:100%;overflow-x:auto;-webkit-overflow-scrolling:touch;margin:1.5em 0;\">\n<table style=\"width:100%;border-collapse:collapse;word-break:break-word;\">\n<thead>\n<tr>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">Material<\/th>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">Typical resistivity at 20 \u00b0C (\u03a9\u00b7m)<\/th>\n<th style=\"border:1px solid #D9CFB8;padding:10px;background:#142139;color:#FAF6EE;text-align:left;\">Where you meet it<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Silver<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">1.59 \u00d7 10<sup>\u22128<\/sup><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Best metallic conductor; specialist contacts<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Copper<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">1.68 \u00d7 10<sup>\u22128<\/sup><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Household wiring, motors, cables<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Gold<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">2.44 \u00d7 10<sup>\u22128<\/sup><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Corrosion-proof connector plating<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Aluminium<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">2.65 \u00d7 10<sup>\u22128<\/sup><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Overhead power lines (light and cheap)<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Tungsten<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">5.6 \u00d7 10<sup>\u22128<\/sup><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Lamp filaments (survives white heat)<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Nichrome (alloy)<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">\u2248 1.1 \u00d7 10<sup>\u22126<\/sup><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Heating elements in kettles and toasters<\/td>\n<\/tr>\n<tr>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Glass<\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">10<sup>10<\/sup> to 10<sup>14<\/sup><\/td>\n<td style=\"border:1px solid #D9CFB8;padding:10px;\">Insulators on pylons and circuit boards<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n\n<p>Treat these as good representative figures rather than gospel \u2014 published values shift slightly with purity, alloy composition and the reference used.<\/p>\n\n<h2>Real-World Examples of Ohm&#8217;s Law<\/h2>\n\n<p>Ohm&#8217;s law isn&#8217;t exam decoration. Engineers and electricians reach for it constantly, often without writing anything down.<\/p>\n\n<h3>1. The kettle in your kitchen<\/h3>\n<p>A UK kettle rated at 3 kW on 230 V mains draws I = P\/V \u2248 13 A, which means its nichrome element has a working resistance of about R = V\/I \u2248 18 \u03a9. All that current does one job: dumping thermal energy into the water \u2014 <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/thermodynamics\/specific-heat-capacity\/\">specific heat capacity<\/a> takes the story from there.<\/p>\n\n<h3>2. Fuses and circuit breakers<\/h3>\n<p>A fuse is Ohm&#8217;s law used as a bodyguard. If a fault slashes a circuit&#8217;s resistance, I = V\/R says the current must surge \u2014 and the thin fuse wire melts before the cables in your walls can overheat.<\/p>\n\n<h3>3. Sizing a resistor for an LED<\/h3>\n<p>An LED itself is non-ohmic, but the resistor protecting it is pure Ohm&#8217;s law. Hobbyists calculate the resistor that drops the excess voltage at the LED&#8217;s safe current \u2014 worked problem 6 below does exactly this calculation.<\/p>\n\n<h3>4. Your car&#8217;s 12 V electrics<\/h3>\n<p>Every bulb, heated seat and sensor in a car is designed around a 12 V supply. Knowing each component&#8217;s resistance tells designers the current it draws, which fixes the wire thickness and fuse rating for every circuit in the loom.<\/p>\n\n<h3>5. Why electricians fear wet hands<\/h3>\n<p>Dry skin can present tens of thousands of ohms; wet skin, dramatically less. Same mains voltage, far lower R, therefore far higher current through the body \u2014 which is precisely why electrical safety rules are unforgiving about water.<\/p>\n\n<h2>Common Misconceptions About Ohm&#8217;s Law<\/h2>\n\n<h3>&#8220;Voltage flows through the circuit&#8221;<\/h3>\n<p>It doesn&#8217;t \u2014 current flows <em>through<\/em>; voltage exists <em>across<\/em>. Voltage is a difference in electrical potential between two points, like the height difference between two ends of a slide. Nothing about a difference can &#8220;flow&#8221;.<\/p>\n\n<h3>&#8220;Ohm&#8217;s law applies to everything electrical&#8221;<\/h3>\n<p>Tempting, but no. It&#8217;s an experimental regularity that metals at steady temperature happen to follow superbly, while diodes, filament lamps and thermistors openly ignore it. Always ask whether the component is ohmic before trusting a constant R.<\/p>\n\n<h3>&#8220;R = V\/I means resistance depends on the voltage&#8221;<\/h3>\n<p>This one catches a lot of students. For an ohmic resistor, R is fixed by material and geometry (\u03c1L\/A); raising V raises I in exact proportion, and the ratio V\/I doesn&#8217;t budge. The equation lets you <em>measure<\/em> R \u2014 it doesn&#8217;t make R a puppet of V.<\/p>\n\n<h3>&#8220;Current gets used up as it goes around&#8221;<\/h3>\n<p>Charge is conserved: in a series loop, the current entering a bulb equals the current leaving it. What the bulb consumes is <em>energy<\/em>, delivered by the charges as they drop through a potential difference \u2014 the charges themselves carry on.<\/p>\n\n<h2>How Ohm&#8217;s Law Relates to Power and Circuit Analysis<\/h2>\n\n<p>Ohm&#8217;s law rarely works alone. Pair it with the power equation and you can answer almost any everyday electrical question.<\/p>\n\n<div class=\"pf-formula\">P = V \u00d7 I = I\u00b2R = V\u00b2 \/ R<\/div>\n\n<ul>\n<li><strong>P<\/strong> \u2014 power dissipated, in watts (W)<\/li>\n<li><strong>V<\/strong> \u2014 potential difference, in volts (V)<\/li>\n<li><strong>I<\/strong> \u2014 current, in amperes (A)<\/li>\n<li><strong>R<\/strong> \u2014 resistance, in ohms (\u03a9)<\/li>\n<\/ul>\n\n<p>Power is <a href=\"https:\/\/physicsfundamentalsinfo.com\/blog\/mechanics\/what-is-energy-in-physics\/\">energy<\/a> transferred per second, so these forms tell you instantly how hard a component is working. The I\u00b2R version explains why power lines run at huge voltages: pushing the same power at higher V means lower I, and losses that scale with I\u00b2 collapse.<\/p>\n\n<p>In bigger networks, Ohm&#8217;s law teams up with Kirchhoff&#8217;s two rules \u2014 currents into a junction balance currents out, and voltages around any closed loop sum to zero. Together they crack any series, parallel or mixed circuit; Georgia State University&#8217;s <a href=\"http:\/\/hyperphysics.phy-astr.gsu.edu\/hbase\/electric\/ohmlaw.html\" target=\"_blank\" rel=\"noopener\">HyperPhysics<\/a> walks through the trio with a handy interactive calculator.<\/p>\n\n<p>Quick reference for combining resistors: in <strong>series<\/strong>, resistances simply add (R = R\u2081 + R\u2082 + \u2026) and the current is the same everywhere. In <strong>parallel<\/strong>, the reciprocals add (1\/R = 1\/R\u2081 + 1\/R\u2082 + \u2026) and it&#8217;s the voltage that&#8217;s shared.<\/p>\n\n<p>And alternating current? Ohm&#8217;s law survives, generalised: V = IZ, where impedance Z bundles resistance together with the frequency-dependent opposition of capacitors and inductors. For a plain resistor on AC, Z = R and nothing changes at all.<\/p>\n\n<p>One habit worth stealing from working engineers \u2014 sanity-check magnitudes. A phone charging draws roughly 1\u20132 A; a kettle about 13 A. If your calculation says 400 A through a desk lamp, the physics isn&#8217;t broken; a unit conversion is.<\/p>\n\n<h2>Worked Problems<\/h2>\n\n<p>Method matters more than answers here. Write the formula, substitute with units, then solve \u2014 every time.<\/p>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 1<\/div><div class=\"pf-problem-question\">A 12 V battery is connected across a 4.0 \u03a9 resistor. What current flows through the resistor?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Current is the unknown, so use I = V \/ R.<\/p>\n<p>Step 2: Substitute: I = 12 V \u00f7 4.0 \u03a9.<\/p>\n<p>Step 3: Solve: I = 3.0 V\/\u03a9 = 3.0 A.<\/p>\n<p><strong>Answer: I = 3.0 A<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 2<\/div><div class=\"pf-problem-question\">A lamp connected to the 230 V mains draws a current of 0.50 A at its working temperature. What is its resistance at that temperature?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Resistance is the unknown, so use R = V \/ I.<\/p>\n<p>Step 2: Substitute: R = 230 V \u00f7 0.50 A.<\/p>\n<p>Step 3: Solve: R = 460 V\/A = 460 \u03a9.<\/p>\n<p><strong>Answer: R = 460 \u03a9<\/strong> (its hot, working resistance \u2014 cold, it would measure far less)<\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 3<\/div><div class=\"pf-problem-question\">A current of 25 mA flows through a 1.2 k\u03a9 resistor. What is the potential difference across it?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Convert to SI base units first \u2014 the classic slip is skipping this. 25 mA = 0.025 A and 1.2 k\u03a9 = 1200 \u03a9.<\/p>\n<p>Step 2: Voltage is the unknown, so use V = I \u00d7 R = 0.025 A \u00d7 1200 \u03a9.<\/p>\n<p>Step 3: Solve: V = 30 V. (Forgetting the mA conversion gives 30,000 V \u2014 a thousand times too big.)<\/p>\n<p><strong>Answer: V = 30 V<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 4<\/div><div class=\"pf-problem-question\">Resistors of 6.0 \u03a9 and 3.0 \u03a9 are connected in series with an 18 V battery. Find the current in the circuit and the voltage across each resistor.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: In series, resistances add: R = 6.0 \u03a9 + 3.0 \u03a9 = 9.0 \u03a9.<\/p>\n<p>Step 2: Apply I = V \/ R to the whole circuit: I = 18 V \u00f7 9.0 \u03a9 = 2.0 A. In series, this current flows through both resistors.<\/p>\n<p>Step 3: Apply V = I \u00d7 R to each resistor: V\u2081 = 2.0 A \u00d7 6.0 \u03a9 = 12 V and V\u2082 = 2.0 A \u00d7 3.0 \u03a9 = 6.0 V. Check: 12 V + 6.0 V = 18 V, matching the battery.<\/p>\n<p><strong>Answer: I = 2.0 A; 12 V across the 6.0 \u03a9 resistor and 6.0 V across the 3.0 \u03a9 resistor<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 5<\/div><div class=\"pf-problem-question\">The same 6.0 \u03a9 and 3.0 \u03a9 resistors are now connected in parallel across a 12 V supply. Find the current through each resistor and the total current drawn from the supply.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: In parallel, each resistor gets the full 12 V. Apply I = V \/ R to each branch.<\/p>\n<p>Step 2: I\u2081 = 12 V \u00f7 6.0 \u03a9 = 2.0 A and I\u2082 = 12 V \u00f7 3.0 \u03a9 = 4.0 A.<\/p>\n<p>Step 3: Total current: I = 2.0 A + 4.0 A = 6.0 A. Check via the combined resistance: 1\/R = 1\/6.0 + 1\/3.0 = 1\/2.0, so R = 2.0 \u03a9 and I = 12 V \u00f7 2.0 \u03a9 = 6.0 A. Consistent.<\/p>\n<p><strong>Answer: 2.0 A through the 6.0 \u03a9 resistor, 4.0 A through the 3.0 \u03a9 resistor, 6.0 A total<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 6<\/div><div class=\"pf-problem-question\">An LED operates safely at 20 mA with 2.0 V across it. What series resistor is needed to run it from a 5.0 V supply, and what power does that resistor dissipate?<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: The resistor must drop the leftover voltage: V = 5.0 V \u2212 2.0 V = 3.0 V.<\/p>\n<p>Step 2: Apply R = V \/ I with the series current 20 mA = 0.020 A: R = 3.0 V \u00f7 0.020 A = 150 \u03a9.<\/p>\n<p>Step 3: Power in the resistor: P = V \u00d7 I = 3.0 V \u00d7 0.020 A = 0.060 W, so a standard quarter-watt resistor is comfortably sufficient.<\/p>\n<p><strong>Answer: R = 150 \u03a9, dissipating 0.060 W<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<div class=\"pf-problem\"><div class=\"pf-problem-num\">Problem 7<\/div><div class=\"pf-problem-question\">What is the resistance of a 2.0 m length of copper wire with diameter 1.0 mm? Take the resistivity of copper as 1.68 \u00d7 10\u207b\u2078 \u03a9\u00b7m.<\/div><details><summary>Show Solution<\/summary><div class=\"pf-problem-solution\">\n<p><strong>Solution:<\/strong><\/p>\n<p>Step 1: Cross-sectional area: A = \u03c0d\u00b2\/4 = \u03c0 \u00d7 (1.0 \u00d7 10\u207b\u00b3 m)\u00b2 \u00f7 4 = 7.85 \u00d7 10\u207b\u2077 m\u00b2.<\/p>\n<p>Step 2: Apply R = \u03c1L \/ A = (1.68 \u00d7 10\u207b\u2078 \u03a9\u00b7m \u00d7 2.0 m) \u00f7 (7.85 \u00d7 10\u207b\u2077 m\u00b2).<\/p>\n<p>Step 3: Solve: R = 3.36 \u00d7 10\u207b\u2078 \u00f7 7.85 \u00d7 10\u207b\u2077 = 0.043 \u03a9. A sanity check: a tiny resistance, exactly as you&#8217;d hope for connecting wire.<\/p>\n<p><strong>Answer: R \u2248 0.043 \u03a9<\/strong><\/p>\n<\/div><\/details><\/div>\n\n<h2>Frequently Asked Questions<\/h2>\n\n<details class=\"pf-faq-item\"><summary>What is Ohm&#039;s law in simple terms?<\/summary><div class=\"pf-faq-item-answer\">\n<p>Ohm&#8217;s law says the current through a conductor is proportional to the voltage across it, as long as its resistance stays constant: V = IR. Think of water in a pipe \u2014 more pressure gives more flow, a narrower pipe gives less. Double the voltage and the current doubles; double the resistance and the current halves.<\/p>\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What are the three forms of the Ohm&#039;s law formula?<\/summary><div class=\"pf-faq-item-answer\">\n<p>The three forms are V = I \u00d7 R to find voltage, I = V \u00f7 R to find current, and R = V \u00f7 I to find resistance. They are one relationship rearranged three ways. The Ohm&#8217;s law triangle \u2014 V on top, I and R below \u2014 lets you read off the right form by covering the quantity you want.<\/p>\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Why doesn&#039;t Ohm&#039;s law apply to all materials?<\/summary><div class=\"pf-faq-item-answer\">\n<p>Because it is an empirical rule, not a fundamental law, and it only holds where resistance stays constant. In filament lamps, resistance rises as the filament heats; in diodes and LEDs, it varies hugely with voltage and direction; in thermistors, it falls with temperature. These non-ohmic devices give curved I\u2013V graphs instead of straight lines.<\/p>\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Does Ohm&#039;s law work for AC circuits?<\/summary><div class=\"pf-faq-item-answer\">\n<p>Yes, in a generalised form: V = IZ, where Z is the impedance \u2014 the total opposition combining resistance with the frequency-dependent effects of capacitors and inductors, measured in ohms. For a purely resistive component on AC, impedance equals resistance and the ordinary V = IR applies unchanged.<\/p>\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>Who discovered Ohm&#039;s law and when?<\/summary><div class=\"pf-faq-item-answer\">\n<p>Georg Simon Ohm, a German physicist, published the law in 1827 after systematic experiments on wires of different lengths and thicknesses, carried out while he taught school in Cologne. Recognition came slowly, but the SI unit of resistance \u2014 the ohm (\u03a9) \u2014 was later named in his honour.<\/p>\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What is the SI unit of resistance?<\/summary><div class=\"pf-faq-item-answer\">\n<p>The SI unit of resistance is the ohm, symbol \u03a9, defined as one volt per ampere: a component has a resistance of 1 \u03a9 if a potential difference of 1 V drives a current of 1 A through it. Larger resistances use kilohms (1 k\u03a9 = 1,000 \u03a9) and megohms (1 M\u03a9 = 1,000,000 \u03a9).<\/p>\n<\/div><\/details>\n\n<details class=\"pf-faq-item\"><summary>What happens to the current if the resistance doubles?<\/summary><div class=\"pf-faq-item-answer\">\n<p>At a fixed voltage, doubling the resistance halves the current, because I = V \u00f7 R makes current inversely proportional to resistance. For example, 12 V across 4 \u03a9 drives 3 A, but the same 12 V across 8 \u03a9 drives only 1.5 A. Halving the resistance does the opposite and doubles the current.<\/p>\n<\/div><\/details>\n","protected":false},"excerpt":{"rendered":"<p>Ohm&#8217;s law links voltage, current and resistance through V = IR. Master all three formulas with worked examples, an interactive circuit lab and the misconceptions that trip students up.<\/p>\n","protected":false},"author":1,"featured_media":217,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[87,84,82,83,86,85],"class_list":["post-215","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-electromagnetism","tag-dc-circuits","tag-electric-current","tag-electrical-resistance","tag-ohms-law","tag-vir","tag-voltage"],"_links":{"self":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/215","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/comments?post=215"}],"version-history":[{"count":1,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/215\/revisions"}],"predecessor-version":[{"id":218,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/posts\/215\/revisions\/218"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media\/217"}],"wp:attachment":[{"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/media?parent=215"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/categories?post=215"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicsfundamentalsinfo.com\/blog\/wp-json\/wp\/v2\/tags?post=215"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}